This session offers a highly efficient blueprint for exam success by distilling complex chemistry into predictable, manageable patterns. It is a masterclass in tactical preparation that prioritizes strategic shortcuts over deep conceptual exploration.
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NEET 2026 Chemistry PYQs 🔥 | Most Repeated Questions & Asked QuestionsAdded:
Hello students. So welcome to today's session. As I already told each and every one of you in today class we are going to discuss most repeated questions of NEAT examination.
When it comes to NEAT in the last two days actually we are we discussed a number of concepts in our marathon session. So in today class exactly what we are going to do is when it comes to these most repeated questions some of the students are asking kan. So before that yes subashri henry Robin yadav for everyone very good afternoon my dear students. Yes very good afternoon. Uh one thing yeah some of the students are asking me sir where is your 12th marathon and physics thought part two of top 50 concepts that also not there in YouTube channel it will be there okay I will check and then I will let you know yes so once again very good afternoon very good afternoon my dear students so okay hello sir yes good afternoon yogsana very good Afternoon. Very good afternoon. So when it comes to this session, this particular session of most repeated question, see whatever the exam, if I talk about J main examination, the question paper setter will follow certain trend actually while framing the question. In the same way when it comes to chemistry also automatically we will be having certain model questions we will be having. So these questions are of very very high priority. Why? If I take atomic structure chapter, how many model questions will be there? Either they may ask question based on quantum number or we can expect questions from automatically hydrogen spectrum or the basic part of atomic structure like photoelectric effect drogly wavelength uncertainty principle. Only from these parts the question paper setter can frame a question. In the same way if I talk about electrochemistry what are the different ways as a question paper setter they may frame question based on Daniel cell or E not cell calculation.
One more possibility is reduction potential oxidation potential calculation with the help of nurse equation. Apart from this where exactly they may frame question Faraday law of electrolysis or else the last part of batteries fuel cells some direct question or else molar conductivity equivalent conductivity infarad law of electrolysis they may club the concepts molar conductivity at infinite dilution.
So from these concepts only they may ask us question like this for each and every chapter we can able to predict like this for each and every chapter we can able to tell yeah this particular chapter we can expect question from this this particular chapter yes this is important on what basis exactly I'm telling this means please do keep in mind my dear students the very important thing is understand we are not the paper prediction or guest paper most repeated questions what are the how on what basis we are doing means whoever it is as a students if you sit and analyze last 10 to 15 years paper automatically we can able to see the trend so short in from chemical bonding we will get hybridization based question no doubts in that everyone know in the same way if I talk about coordination complex definitely one question will be there based on hybridization it is sp3 d2 or d2 sp3 or sp3 or dsp2 definitely question will be How? In the same way when it comes to basic concepts of organic chemistry definitely one questions will be there in UPSC nomenclature definitely one question will be there based on structural isomeism another question will be based on optical isomeism either the trans easy or or relation between two compounds like that they may ask us any question but for all the things what is very very important is we need to understand what are the different model questions questions are there again I'm telling this is the only thing I will be always telling in all the classes if I talk about number of question number of questions from one chapter if we decide we can able to solve even thousand plus questions we can able to solve even thousand plus questions from a single chapter but tell me do you really have the time to solve thousand questions now for one question 1 minute also thousand question thous0 and minutes. So automatically tell me my dear students is that possible?
It is possible but time consuming. Then where is the time to prepare for biology? Where is the time to prepare for physics? But instead of that what is the smart way to solve all the questions to discuss all the question means approaching the subject with respect to different model. Approaching the subject with respect to different model. The moment we start to solve different model questions in a particular chapter automatically we can able to understand all the concepts. What exactly I'm trying to say through different model question my dear students different model means it is nothing but one model is equal to another concept. So one model means indirectly we are preparing for one particular concept. If in a particular chapter I'm discussing 13 model questions means how many concepts we are having only 13 concepts.
So today class it's going to be like that only I'm going to give different model questions on what basis means different model question based on the most repeated concepts in our exam. It is nothing but most repeated question.
Now the exclusively next three to four will be continuously question solving session. So maximum try to tell the answer on your own. It is fine. So once again now few students joined Amu Rahul Kumar. Very good afternoon my dear students. Okay shall we start? Is everyone is ready to solve the question.
How the session is going to be means I will display the question. I will give maximum of 1 minute time. Automatically I will start the poll. Try to tell your answer. Once you guys can able to tell automatically we can able to understand the things.
Still sir I can't able to answer the question. I'm feeling very tough. I got lost in calculation. Don't worry why I'm standing here. I will try to help you guys out. This clear. But these questions are very very important model question. You guys can expect in examination also.
Sir your 12th marathon for chemistry and physics are taught part two for physics topic wise also that video is not there in channel.
Okay, ammo I will just check actually after this class even I think morning you contacted me through telegram so definitely I will uh personally respond to you I will also let you know where exactly the videos are there if possible I will share a screenshot too yes good afternoon Vicki shall we start everyone is ready first question for the day so maximum I will keep top 45 to 50 questions will be there so try to solve first question for the What will be mass of glucose in which 600 molecules are present? First question is from basic concept of chemistry.
Yes, 600 molecules are present.
I want everybody to tell the answer.
See, take it like a mock test and try to solve. Good afternoon, Shila. Very good afternoon.
Yes. What? Robin wiser.
Yes.
Yes. Yes. Yes.
I think calculation part every it is time consuming.
Yes, yes, yes. Everyone is getting option B and C are same. Oh my god.
See, I need to say thanks to my uh DTP operator. Okay, B and C are same. Either if you people get C or B, it will be the right answer. So, majority of the students are selling C. So, I'm also giving here it as C. But since both the options are same, my dear students, I'm very sorry, both the options are same.
Just learn the approach quickly. I will tell we will move into the class. So, what will be the answer? 600 molecules are present. If molecule is given, how to find out number of moles? Yes. Number of moles is nothing but given number of molecules given number of molecules divided by avagadro number. So if I substitute this 600 molecule upon avagadro number automatically we will be getting number of moles. Once we know number of moles, how to calculate the mass of glucose?
Very simple. Mass is nothing but mass is nothing but number of moles into molar mass. So automatically we will get the answer. But remember one thing the unit will be in gram. Right? Because what is the general formula for number of moles? Number of moles is nothing but given mass in gram upon molar mass.
Molar mass is nothing but g per mole. So automatically we will be getting the answer. Good. I'm happy. Next question.
Again any same option is there. No. Yes.
In X ml of water 4.8 into 10 ^ 25 number of electrons are present then value of X will be yes.
In X ml of water this many number of electrons are present. Now they are asking what will be the value of X.
Click.
Yes. Yes. Yes.
Hey Robin, actually already we discussed the complete theory part in last two marathon. Some parts are pending. I will discuss those theory parts also. Don't worry because in between we need to solve questions also. Right? That is the reason just like a practice option B. Everyone is getting yes. So once again option B is the right answer. Option B is the right answer. No doubt in that. How we can able to solve this? We know very well. If I take one molecule of water. If I take one H2O molecule.
One H2O molecule contains how many electron? Hydrogen atomic number is 1.
Twyden is there two. Oxygen atomic number is eight. So total 10 electrons will be there. Now how many ml of H2O in X ml of H2O? this many number of electrons is there. So automatically this many number of electrons are there means what 4.8 into 10 ^ 25 electrons are there means how many molecules will be present just cross multiplication right so if we do what we will be getting 4.8 8 into 10 ^ 25 upon 10 am I right? So automatically what exactly we will be getting?
Yes. So this means 10 ^ 24 4.8 10 ^ minus 1 so 10 ^ 24 molecules will be present. Now molecules we know how to calculate number of moles divided by avagadro number. So approximately itself I can tell avagadro number is 6.023 into 10 ^ 23.8 so 8 moles. So how many moles will be there 8 moles but they are asking ml. So what is the thing actually first we will find out what we can able to find out mass we can able to find out right. So mass of H2O is nothing but number of moles into molar mass. Am I right? So mass is nothing but number of moles into molar mass. Molar mass of water is 18.
So 144 g is the mass. What will be the density of water? 1 g per ml. So automatically 144 g is 144 ml. Option B is the right answer.
It is clear.
Okay. Majority of the students want marathon I feel right. Okay. If you are also feeling the one once the class get over please do let us know in the comment section of this class automatically we will consider we will do the remaining parts also. Don't worry it's all about your wish only. Next question.
Yes. 50 kg of N2 and 10 kg of hydrogen are mixed to produce NH3 gas. Calculate mass of NH3 formed.
Yes, tell me.
Yes.
Okay.
70. Everyone is getting the answer.
Everybody is getting.
Listen carefully.
What is the concept exactly here? We are dealing with I mean stop stop N2 plus H2 gives NH3 gas. Now what is the thing they told? 50 kg of N2 and 10 kg of H2 are mixed to produce NH3. Calculate mass of NH3 obtained. It is very simple. So we can use the mole concept. What exactly we know? N_sub_2 how many grams we will be having 28 g of N2 reacts with 2 g of hydrogen according to stochometric coefficient we will be getting 17 g of NH3 now here they are dealing in kg right so automatically 50 kg that means I can take it as 50 into 10 ^ 3 kg of N_sub_2 is reacting with 10 into 10 to the^ 3 g g of H2 to give how much amount of NH3.
So basic mathematics now we can able to do. Yes. Now with the help of basic mathematics we can able to do. So automatically now we can able to find out moles of N_sub_2. Right? We can able to find out moles. How to find out moles? Moles is nothing but given mass divided by molar mass. Molar mass is 28.
Number of moles given mass divided by molar mass. So what what is the value we will be getting? 5 into 10 ^ 3. Here we will be getting 28 2's are 56. So 28 1's are 28. So we can keep uh balance 28 1's are 28 uh 38 48 22 will be there.
So I can go with uh 7 time 7 8 are 56 7 2's are 14 196 yes exactly 1.7 into 10 ^ 3 mole now how to find out we know what are all the reactants getting participated in the reaction at the same time we know its moles also concentration what we can do the concept is based on limiting limiting reagent.
Now what is the shortcut? I told you guys how to find out limiting reagent.
Whatever the value we are getting number of moles divided by stochometric coefficient one divided by stochometric coefficient one. So automatically which is smaller value? This is the smaller value. Right? Automatically the smaller value is the one limiting reagent.
Larger value is excess reagent. Now whatever the amount of product getting formed that depends on the limiting reagent only. So it is very simple. Now now how many moles actually we are getting here 1 mole of N2 will give 1 mole of NH3. But in the question how many moles we are taking? 1.7 into 10 ^ 3 moles will give 1.7 into 10 ^ 3 moles of NH3. So from stochometric equation number of moles of NH3 is 1.7 into 10 ^ 3 moles. Now how to find out the weight?
We weight of NH3 in gram it is nothing but mole into molar mass. So molar mass of NH3 is 17. So automatically what we will be getting 1.7 into 10 ^ 17.
Once again once again see what is the silly mistake I did. I need to balance the equation. No. N2 + 2 NH2 N2 + 3 H2 1 mole of N2 will give 2 mole of NH3. So from the balanced equation 1 mole of N2 will give 2 moles of NH3. So how many moles we got? 1.7 into 10 ^ 3 moles of N2 will give 1.7 into 10 ^ 3 moles of NH3 into 2 So 1.7 into 2 is 3.4 right. So automatically now we can able to find out the weight. How to find out the weight of NH3? Weight of NH3 is nothing but 3.4 into 10 ^ 3 into 17. So automatically what will be the answer?
3.4 into 10 it is nothing but 34. 3.4 4 into 7 7 4s are 28 7 3's are 21 22 23 so 23.8 8 we will be getting right so automatically 57 8 so what will be the correct answer we will be getting 56 kg we will be getting 56 kg option C is the correct answer now whatever the value we will be getting we will be getting in gram we need to convert this into kg option C is the correct answer right Okay. Shall we move into next question?
It is clear or not? Please do let me know. My dear students, let me drink water. I'm feeling very suffocated. I'm sweating like anything. Yes. Tell me my dear students. Is it clear or not?
Please do let me know. Is it clear?
Yes. Done. Perfect.
Okay. Done. Next question.
Which of the following is the wrong statement?
Which of the last question answer is option C. Which of the following is the wrong statement? Clear sir. Clear sir.
Yes sir. Yes. When it comes to statement type question, my dear students, please be very very careful.
Here only the tendency is more to do mistake. Please be very careful.
Yes. And one more thing my dear students I can able to see some students are are actually interacting with me in Hindi.
Some students are interacting in Tamil.
Some students are talking in your own tongue mother tongue. But whatever. So I'm not supposed to use any other language. So that when it comes to the response I will be giving only in English. Okay. Please don't mind.
Yes.
Quick.
What which of the following is an incorrect statement?
Curui roti very simple question what is the answer correct answer is option D why option D is the correct answer they are asking wrong statement here if you see an empirical formula represents the exact number they told what is the empirical formula what what The empirical formula simplest whole number ratio simple whole number ratio. So that is not the exact number. So option D is the right answer. Yes. Next question.
A compound contain seven carbon atom, two oxygen atom and this much gram of other element. Molecular mass of compound. NA value we can keep it like 6 into 10 ^ 23.
Yes.
A compound contain seven carbon atom, two oxygen atom and this many gram of other element.
Okay, everyone is getting D. So shall we check how to do seven carbon atom? So carbon is 7 into 12 two oxygen atom. So 2 into 16 that many gram of other element. So how to find out number of moles of other elements? Number of moles of other element is nothing but given mass. So the given mass in g divided by avagadro number. Now 10 ^ minus 23. So what exactly we will be getting? 3.32 into 10 ^ -23.
So what exactly we will be getting?
Yes.
I think that should be plus my dear students. That should be plus. Yeah, that should be plus what exactly we will be getting? So 10 ^ 20.
Yes.
So once we find out number of moles from that we can able to find out one second one second what they given gram they given right okay directly I can find out mass no okay okay what I'm doing I can directly find molecular mass only no I want so how to find out molecular mass molecular mass is there and then what is given gram is given so automatically I can multiply by avagadro number so yes what exactly we will be getting there so now we can able to do it so automatically molecular mass if I want to calculate how I can calculate 3.32 into 10 ^ -23 - 23 into a row number 6 into 23. So how much we will be having? So the value comes out to be 6 2's are 12 6 3's are 18 19. Okay 19.92 I can keep it as approximately 20 minus 23 and + 23 will get cancel. So automatically what we will be getting now just I need to add everything 84 32 + 20. So 6 8 9 10 11 12 136 is the answer. Just we need to add all these things. It is clear. Option D is the correct answer.
Option D is the correct answer. Option D is the correct answer.
Clear.
Next question.
How many moles of methane are required to produce 22 g of CO2 after combustion?
Yes.
How many moles of methane are actually required to produce 22 g CO2 after combustion?
So how many moles of methane required to produce CO2? What is the formula? CH4 plus O2 will give CO2 plus H2O. So I will be getting 2 moles of CO2 1 mole.
And then how many moles of O2? We will be getting X + Y by4. So 3 moles of O2.
No, no, no, no, no.
3x2 I will be getting right. X + Y by 4.
So X is 1. Y by 4.
Yes. X + Y by 4. 4 4x4 is 1 2. It is clear. Now the question is all about methane and then CO2. What is the mole ratio we are having? mole ratio is 1 is to1 mole ratio. Now 22 g of CO2. So 22 g of CO2 means how many moles of CO2?
44.5 moles of CO2. So how many moles of CH4 is required? Automatically.5 moles of CH4 is required. So.5 mole. Option D is the correct answer.
Option D is the correct answer. It is clear. Option D will be the correct answer. Next question.
On heating K2 SO4 XH2O loses its 34%age weight then find out molecular formula of this crystalline salt.
Yes, by option elimination method we can able to do this question.
By option elimination method we can able to do this question.
Yes.
How one person is getting A, one person is getting D, others.
Yes, everybody.
Route to Jimmer Fzana.
So, what is the correct answer? We need to cross check. 34%age weight is getting lost means that 34%age is what exactly X moles of water right so usually water only will get evaporate water lost is 34%age now which option will give 34%age let me take option D since everyone is telling five moles of water 5 moles of water water molecular mass is 18 g per mole so five moles of water means automatically 5 into 18 how much I will be getting n T. So let me cross check N T divided by what is the entire molar mass of this particular substance will be there? K2 SO4. So K2 SO4 mar mass is not given in the question. So potassium 2 sulfur around 174 will come right 174 + 90. Take percentage and calculate how much we are getting my dear students. If I solve this 90 upon 174 + 90 we will be getting 34. So now tell me this is matching with this value or not? It is matching. So option D is the correct answer. Option D is the correct answer.
Very simple question. So these are all the different model questions we can expect. A sample of phosphorus that weighs 12.4 4 g exerts a pressure 88m in a 0.821 lit closed vessel at this temperature. Molecular formula of the phosphorus. Very simple question.
How we can able to solve this particular question?
Yes.
A sample of phosphorus that weighs 12.4 g exert a pressure 880m.
Are you sure guys? D wrote to Jimmer official.
See instead of Robin Robin you are not giving me the answer but you are giving answer only to Subashri.
Here sir is struggling by solving question as such I am having method neat examination but Robin is giving a response to Subashri.
Yes.
Yes sir.
But parallelly solve question that is also very important right?
How to solve this question? First to find out the molecular formula. So basically we need molar mass. Now from the given data it is possible for me to calculate number of moles. How to calculate number of moles? PV is equal to N RT. N is equal to PV by RT. What is the pressure? 8 atm. What is the volume?
0.821.
What will be the R value? Since we are dealing in liter atm. R value will be 0.0821 into temperature. What is the temperature they given? 527.
So 527 means it is how much kelvin?
800 kelvin. So into 800 if I solve this automatically I will be getting number of moles.
Yes, I will be getting number of moles.
So what will be the number of moles?
number of moles will be.1 I think yes because 100 * 10² if it comes here means minus2 so this will be I can write this as 10 ^ -1 so 10 ^ minus1 means 10 ^ minus1 so automatically I will be getting 0.1 yeah number of moles what we will be getting number of moles is nothing but.1 now it is easy for us to calculate molecular mass Yes.
How to find out molecular mass? Given weight. Number of moles is nothing but given mass upon molar mass. Now I need a molar mass. So what I can do? Rearrange this expression. Molar mass is equal to given mass 12.4 divided by.1. So what will be the molar mass value?
Keep this as 124 into 10 ^ minus1. So molar mass is 124. Now we are dealing with phosphorus 124 divided by for one phosphorus atom it is 31 atomic mass.
Right? So how many times we are getting four times. So the molecular formula is P4. Option D is the right answer. Option D is the correct answer. It is clear.
Option D is the correct answer. All right.
So these are all very very important model question. Next question. Which of the following is incorrect statement?
You people can observe. I started from basic organic chemistry. Now I switched into atomic structure.
Which of the following is incorrect statement?
Yes.
Yes. Road to Jimmar. Very good afternoon.
Yes, a direct theory based question.
Option D is the correct answer. Why?
When it comes to anode, exactly anode rays are emitted from the surface of the anode. My dear students, no exactly it emitted from the gas which we are taking inside the discharge tube.
Right? They originate from the gas, not from the surface of anode. So that is the incorrect statement.
Next question. As the orbit number increases, what will happen to kinetic energy and potential energy of an electron?
As orbit Rajeshwari, good afternoon sir.
Very good afternoon ma. Tell me my dear students. As orbit number increases kinetic energy potential energy for an electron it will increase or decrease what exactly will happen?
So those students who is joining in between the class my request is from the beginning just go and watch 40 minutes completed. So in 2x speed also you guys can watch because I started from basic organic chemistry we solved very good question now I'm in atomic structure.
Yes. What will happen?
As orbit number increases, what will happen to kinetic energy and potential energy?
Remember kinetic energy decreases, potential energy increases. This is very very important. Kinetic energy decreases, potential energy increases.
So please do remember these are all very very important.
Next question.
Yep. Option D. Yes. Yeah. Proton and an alpha particle in the last I will show the leaderboard. A proton and an alpha particle are accelerated through the same potential difference ratio of their drogley wavelength. So just direct formula based question not only pq rajeshwari it's all about most repeated model question from different papers h we can call it as pq also but in pq also I looked exactly for the different model question you tell me otherwise in atomic structure how many questions we can solve so only different model questions So what if all D answers means what is the problem? when I'm framing question my correct answers will be always option D because initially when I'm framing I will think for the wrong answers right same potential difference yes yes for same potential difference. So what exactly we can write?
Drogly wavelength is inversely proportional to root of M. Now they are asking proton and then alpha particle.
So ratio of their debrogly wavelength.
Yes. Proton and then alpha particle is nothing but what is alpha particle?
Alpha particle is nothing but helium nuclei. That is so root of mass of helium upon mass of proton. So <unk>4 upon 1. It is nothing but 2 by 1.
So what is the answer? We are getting option 2 is to 1. How everyone is telling answer D?
Yes.
Yes.
How everyone is getting 2<unk>2.
Yes.
Sir, do you know Telugu? Huh? Yes, ma'am. I know.
Okay. Okay. I missed the charge. I missed the charge. Okay. Okay. Yeah.
Yeah. Yeah. So root of m 2 m q into e v 2 m qv right same potential difference. Yeah. Charge will be there, right? Okay. Okay. So automatically I need to consider the charge. So charge means actually here I will be getting two. So here I will be getting eight.
Okay. Okay. Fine. So, option D is the right answer. I left out the charge.
Option D is the correct answer.
It is clear.
Next question.
See, Robin is not listening to the class, but he's asking there.
Next question. E by M ratio of particle of charge 2 unit and mass 4 amu. Very easy question.
Yes.
E by M ratio of particle of charge 2 unit and mass 4 amu.
Yes.
Everybody getting the answer?
Yes, it is clear.
Hey, very sorry. I received one call regarding meat. Okay. E by M ratio of particle. So, what is the charge 2 unit divided by mass is 4 amu. So, all these are known values for us. Right? So if we substitute unknown values automatically we will get the answer. So I need to give one homework question right? Take this simple direct question as the homework question. Take the simple direct question as the homework question. Let me give normal answer. So some dummy answers. Next question. A photosensitive surface is receiving light of wavelength 5,000 strong at a rate of 10 ^ -7 jou/ second. Number of photons received per second.
Yes.
Number of proton received per second.
Your photosensitive surfaces receiving light of wavelength.
They given the wavelength is 5,000 astron at a rate what is the speed 10 ^ -7 joule per second rate is given now they are asking number of photons received per second this is also per second only yes what is the approach we can use Okay.
Everyone is getting hello sir. Hello entry. Yes.
What happened in everyone is getting a shall we check?
What is the formula we need to use? Just a direct formula. What we know when it comes to energy is equal to HC by lambda. Now understand one thing we need to find out number of photon also energy per photon. So what exactly we know lambda is 5,000 amstrong. So 5,000 amstrong means in meter that is 5,000 into 10 ^ -7 m I can write. Yes.
Yes. Lambda value we know.
And then they told at the rate of 10 ^ - 7 joule per second.
So finally if you substitute everything automatically we will get the answer.
Uhhuh. Here some fight is going on. So automatically if you use the formula and just direct substitution we will get the answer as option A. Just direct substitution my dear students that's all nothing other than that just a direct substitution.
Next question.
For which orbit in H plus ion the circumference is 26.5 Armstrong?
Just use the formula that up to the decoding formula is chemistry. After that formula know it's full mathematics.
Yes.
For which orbit in H plus ion the circumference is 26.5 amstrong.
Yes. Quick.
C C everyone is getting C how to check circumference it's nothing but 2 pi R is equal to 26.5 amstrong RN what is the value we know 2 pi R N is nothing but 0.529 radius formula 0.529 into N² by Z N² by Z is equal to 26.5.
Now automatically we can able to solve this. Yes, automatically if we solve n value comes out to be four. Option four is the right answer. Who is the telling you? Option four is the correct answer.
So when it comes to atomic structure all these formulas are very very important.
When electrons are deexiting to the ground state from nth orbit of hydrogen atom 15 spectral lines are formed. The shortest wavelength among these will be very good question.
This is one of the very important model question.
One of the important model question.
When the particular electron is getting deexiting, how many spectral line we are getting? 15 spectral line. The shortest wavelength they are asking.
Yes.
How to exactly do this? First electron is coming from nth orbit to ground state that is n is equal to 1.
What is the number of spectral line formula from the nth orbit? If it is coming to ground state the value will be n into n -1 right n into n -1 / 2. So that will be equal to 15. So automatically if I solve this what is the value we will be getting? N value comes out to be quadratic equation right n² minus n is equal to 30. So I need to get 30.
Yes, n is equal to 6. Quadratic equation n value comes out to be 6. So automatically now they are asking shortest wavelength. So what we know wave number formula that is nothing but r into z² hydrogen atom. So one only value 1x n_sub_1² minus 1x n_sub_2² what we know exactly my dear students if wavelength is more energy will be less energy is inversely proportional to wavelength. So they are asking shortest wavelength. Shortest wavelength means energy should be very high. when energy will be very high from sixth orbit to first orbit then energy will be very high. So automatically what we will be getting wave number R into 1 by so we will be getting uh 36 - 1 35 by 36 am I right 35 by 36 ah one second one second 35 by 36 no no no 36 by 35 yeah yeah it is clear yes so option D is the correct answer option Option D will be the correct answer because N_sub_2 value should be always greater than N_sub_1 value. N_sub_2 should be always greater than N1 6 square 36. So here we will be having 36. So 36 - 1 35 by 36. Okay.
What happened to me? Oh my god.
35 by 36. But this is reciprocal of wavelength. Wave number. Now they are asking wavelength. So wavelength will be 36 by 35R. It is clear everybody is getting an idea.
So option D will be the correct answer.
Option D will be the correct answer.
Option D is the correct answer. Here we will be getting 35 by 36 because wave number is nothing but reciprocal of wavelength. In question they are asking wavelength. So we need to take it as a reciprocal.
Next question. The following electronic transition occurs when lithium atom is heated in hot flame. Lithium atom.
Okay. Which of these transition would result in emission of light?
Yes. Which of the transition will result in the emission of light?
Raj Hmon. Hi, afternoon sir. Afternoon.
Afternoon Raj.
How to find out these type of question?
Very simple. Listen carefully.
When actually light emission will happen if transition happens from higher energy level to lower energy level.
When transition happens from higher energy level to lower energy level then emission of light will takes place. So just calculate 2s to 2p. This is lower energy. This is higher energy. Emission will not happen. 2 P to 3D this is lower energy this is higher energy N plus L rule also we can follow so it will not happen 3D to 3P if I talk about 3D to 3P yes automatically from higher energy N plus L rule N value is 3 L value is 2 5 here four so higher energy level to lower energy level next 3p 4S what is exactly happening 3P 4S once again it is from n + l rule. If I calculate for this 3 + 1 4 this is also 4 + 0 4. If n + l value comes out to be same we need to check the principal quantum number. So once again this is from lower energy level to higher energy level 4 s to 3p what exactly we are getting n + l value 3 + 1. Once again I'm getting four but according to principle quantum number this is higher energy level. So higher energy level to lower energy level emission of light will take place. So three and five option B is the correct answer. So the simple thing what we need to remember is whenever transition is happening from higher energy level to lower energy level automatically emission of light will takes place. Just now you people are getting an idea directly they won't ask which is higher energy lower energy like this indirect way of framing a question.
Next possible number of electron for which in n = 4, l= 3, s is equal to + 1 by2 yes possible number of electron a why this many b rament one time you just enter b automatically it will capture no need to mention this many time. It is not required.
Yes.
N= 4, L= 3 and S is equal to + 1 by 2.
Sir M name Joti Singh. Okay. Joti Singh.
So very simple. N is equal to four.
Four. L value three means it talks about which is subshell. 0 1 2 3 4 F. So 4F means how many orbital we will be having? In 4F subshell we will be having maximum number of electron is seven.
Yes. So maximum electron is 1 2 3 4 5 6 7 because S is equal to + 1 by 2. So one spin - 1 by 2 means then we will be having anticlockwise also. So only clockwise spin only clockwise spin. So clockwise spin means 1 2 3 4 5 6 7. So automatically option B is the right answer.
Option B is the correct answer. Next question. Which of the given line has maximum wavelength? Remember wavelength should be maximum means energy should be less.
Wavelength should be maximum means the energy should be less wavelength should be maximum energy should be less. So very simple we can check third line of Lyman series. Layman series means n is equal to 1. So in the same way Balmer series means two Pascan Lyman Balmer Pascan bracket PN series. Now when it comes to third line of layman series 2 to1 is first line 3 to1 is second line 4 2 1 line of balmer series 32 second line of passion 4 to 3 5 to 3 first line of bracket series first line of bracket series means 5 to 4 now we need to check Mahesh Raja sir when will you take remaining chapters as a marathon.
Okay, next to marathon uh not yet decided ma I will uh just let you know after talking with the team otherwise do one thing if you guys whoever watching this lecture if you guys really want the again 12 hours last marathon means after this class get over under this video put it in comment section so backend team also will observe even I can able to convey to the backman team students are asking for the marathon it's clear fine now tell Yes.
What? Which one will be having the shortest? Which one they are asking?
Maximum wavelength.
Yes. Yes. Yes.
Hey, but that will be not in English, right? Okay.
Yes. So, automatically with the help of what we can use this lambda that is 1x lambda is equal to r z² they didn't tell anything. So 1x n_sub_1² minus 1x n_sub_2². So with the help of this formula we can able to calculate. So which one will be the correct answer? Option D will be the correct answer. Option D is the correct answer. We can able to tell it.
Next which of the following statement is incorrect. Now I'm coming into periodic property.
Which of the following is incorrect?
Which of the following is incorrect?
Yes.
Which of the following is incorrect?
Easily we can able to tell because it is one of the important exception in any period. Which one will have greater atomic radius helium will sorry not only helium the entire noble gas will have higher atomic radius in their respective period. If you people listen to my periodic properties lecture there I explained in detail. So remember it is an exception option D. Incorrect is option D.
Exception is in a respective period at least from now onwards remember in a respective period always the inert gases will have greater radius the inert gas will be having greater size.
Next question. Which of the following statement is incorrect regarding diagonal relationship between aluminium and berilium?
Yes.
Which of the following statement is not correct regarding diagonal relationship between aluminium and berilium?
Yes.
Which question? Ma Raj Hand.
Which question?
What is the correct answer?
Both can form complexes with same maximum coordination.
So option C is incorrect. Option C is incorrect.
Aluminium and berilium will give which carbide same gas which gas it will give methane gas.
Yes.
So option C is the correct answer. Next question. Select correct statement.
Select correct statement.
+ 4 and six. Yes, exactly.
Select correct statement.
Yes.
Lanthnoid and actid belong to F block and element having atomic number 31 belongs to third period. General outermost shell electron configuration of DB block element. All actides are man-made elements.
Read the question carefully what they are asking. Select correct statement they are asking.
B C B what we know correct statement lanthanide and actides belong to D block they are not F block. So it is an incorrect statement. After lanthanum only it is lanthnoids. So exactly why it got the name lanthanoid because after lantham but LA and AC belongs to D block element having atomic number 31 belongs to third period. No it belongs to fourth period. General outermost shell electronic configuration of D block element is ns1 to2 n to1 d1 to 10. All actinides are man-made elements. No, they are all actinites are not man-made elements. So correct statement is option C is the correct statement. They are asking correct statement.
Option C is the correct answer.
Right?
Tell me after zinc is 30. So 31 means it will be becomes third period.
First period is hydrogen, helium, second period is boron, carbon, nitrogen, third period is aluminium, magnesium, everything.
It is clear. So option C is the correct answer. Next question. Which of the following conclusions are correct?
Correct. They are asking regarding the element having atomic number equal to 113.
Particular element atomic number is 113.
Which conclusions are correct? They are asking.
Which conclusions are correct?
Yes.
Thank you.
Hi sir, you completed some chapters through two marathons. What about remaining sir? Please take remaining also. Yeah sure I will take. Don't worry.
So that's what again and again I'm telling you if you people want marathon once this class get over in the same video under the comment section please do let us know so that we will also come to know how many students want marathon because time is very less right so I just need your support also in planning the things accordingly so please do let me know how many people want the marathon once this class get over under the comment section Yes, everybody.
So, what is the correct answer?
It is present in group 13. That is true.
Correct. It is a P block element. That is correct. So, 2 and three should be there. So, which option is having two and three? Option B. So, 2, three and then four. Remember it present in which period it will present? Tell me my dear students. 113 it will present in which period?
113 it will come under which period my dear students?
113 comes under which period?
Yes. Yes. Let me check how many of you can able to tell this question. 113 comes under which period?
7th period. Yes, exactly. So, it will come in seventh period. So, basic periodic table question. Next, which of the following is incorrect match? Which of the following is incorrect match?
Which of the following is incorrect match?
What happened? Feeling very tough this question.
Why?
How many of you feeling this question is very tough?
Okay. according to Rajment B. Why B is incorrect? Ma group 2 B, 3 B, 4 B and then here we are having 2 A.
Yes.
Okay.
Okay. Ro to Jimmer B.
It's Subashri very stupid question. It is.
Yes. I think C sir no one thing is very sure you people not aware of periodic table right. Look at the electronic configuration. With the help of electronic configuration we can easily able to tell the answer.
we can easily able to tell the answer.
So what will be the answer for this option B is the correct answer. But okay. So what I want you guys to do means check and then let me know in the let me know the answer in the comment section. Check take the responsibility because my dear students periodic table is very very important. So definitely you guys can expect these type of questions in exam.
So please be very very careful. Please do read periodic table otherwise in next marathon session I will be taking one short no marathon. In that I will discuss how to complete this periodic table. I will discuss don't worry but this is the homework question. Why simple question? Actually you people are feeling it is tough. That is dummy answer. Which of the following set is not correct?
Chemical bonding hybridization based question family members are very toxic.
Yes.
Which of the following set is not correct?
Yes.
Yes sir. D is incorrect. Spelling mistake is there a shape.
So what will be the answer? We know very well XC F4. If I take XC F4 what is the shape? Four bond pair two lone pair shape will comes out to be square plane but what they given tetrahedral. So D is incorrect. Option D is the correct answer. Option are get ready in the regular batch. I will frame questions from periodic table more because I understood even some students are taking dropper also this much problem is there with respect to periodic table. That is very bad my dear students.
Next question.
The species exhibiting maximum number of lone pair around central atom.
Yeah sure sure amu after this class I will check the telegram I will respond to your message don't worry species exhibiting maximum number of lone par electron maximum number of lone pair electron Yes.
Yes.
Yes, that definitely you put PDF. Okay. Now sir, PDF I'm sharing to you guys daily in WhatsApp.
I think you people are not in our WhatsApp group. PW need English in the uh in the channel in the channel please do join everybody maximum number of lone pair they are asking so automatically xf3 minus because florine valency is one only but when it comes to oxygen and oxygen we will be having valency is two so option C is the correct answer which of The following statement is true for aside ion. Remember they are asking true statement. They are asking correct statement not incorrect statement.
Yes.
Okay. Okay sir. Because my brother completed second year. Oh okay Rob Rabin I will just check.
We'll check. He's preparing neaten EMC.
Okay.
The oxidation state of nitrogen in aside ion is minus1.
Yes. Tell me my dear students.
First thing they are asking true it is called a pseudo hallide or not aid. ion tell me that particular statement stoppool it has a nonlinear structure that is incorrect aid ion is having nonlinear structure so basically aid is actually having linear structure so it is a linear structure they're asking true statement it is pseudoide I am ready with that then it is iso electronic with N2 how How many electrons will be there? 7 3's are 21 + 1 22. So here we will be having 16 + 7 23 but there we will be having 22 electron. So it is not iso electronic.
This is also wrong statement. Oxidation state of nitrogen is minus1. My dear students tell me oxidation state of nitrogen is minus1.
Yes tell me what will be the oxidation state we will be having it is suloid oxidation state comes out to be min -1 by3 average oxidation state. So correct answer is option B is the correct answer. It is basically a pseudoide. Why we will be calling it as pseudohhalide?
It resembles the property of hallide ion. Remember why we are we will be calling acid ion as pseudohhalide because we will be calling it because it will be resemblance. It is having minus1 charge valency. It it resembles the it resembles the property of group 17 ion. It is sudo hallide. It is clear how? If you look at the structure also the terminal nitrogen we will be having the terminal nitrogen's right. Terminal nitrogen will have the oxidation state + one. Sorry terminal nitrogen will have the oxidation state minus1. Central will have the oxidation state + one. So which one they are talking anything they told terminal nitrogen or central nitrogen any clarity is given in the statement no clarity right the reduced time off pole yeah sure now everybody is getting an idea hsana here anything they mention particularly central nitrogen or terminal nitrogen nothing is mentioned so in that case how we can able to consider like that Okay. So, option B is the right answer.
Next question. Which of the following order is incorrect?
Which of the following order is incorrect?
Tell me the same question I will ask there also.
Don't worry.
Yes.
Ionic character.
Thanks for informing me, sir.
Yes.
polarizability.
Oh my god. TL minus, Br minus, I minus.
So polarizability is directly proportional to size of anion. directly proportional to size of anion.
Polarizing power is directly proportional to charge of cation.
Charge of cation. Coalent character.
Coalent character is directly proportional to charge of cation.
Size of inversely proportional to size of kion. But kation is same. Look at the anion directly proportional to charge of anion. Charge of anion is minus1 then size. S size of anion greater the size more coalent thing. Now they are asking incorrect order. So incorrect order means option A is incorrect. Remaining all three is correct. Option A is incorrect.
Next question. When coalent character is more here greater the charge of cation more will be the polarizing power. More polarizing power means more coalent character. More coalent character means ionic character will be less. That's all.
So option A is the correct answer.
Option A is the correct answer. Which of the following interaction lies in the range of 8 to 12 kilojoule per mole?
Yes, good afternoon Ana. Which of the following interaction lies in the range of 8 to 12 kilojoule per mole?
G sther.
Yeah.
Which of the following interaction lies in the range of 8 to 12 kiloj per mole?
Yes.
Yes.
Yes. What will be the answer?
See normally in the question what they are asking us which of the following interaction lies in the range of 8 to 12 kiloj per mole.
8 to kiloj per mole is possible for hydrogen bonding interaction.
Hydrogen bonding interaction.
So basically in which of the following we will be having hydrogen bond formation that will be the answer.
Everybody getting an idea. So automatically with the help of that we can be able to tell 8 to 12 kilojoule is hydrogen bond.
Yes.
And then so where and all hydrogen bond is possible here also possible.
Yeah. Here also hydrogen bond is pos.
Okay. Two options are coming.
Okay. Then it is multis select question.
Huh. Unknowingly came in. Nita. It is not pyq. Which of the following lies in the range of 8 to 12? Okay. Generally hydrogen bond means what? 8 to 42 will be the general hydrogen bond. Then since here they mention 8 to2 can I consider it as weak hydrogen bond? So weak hydrogen bond means F will not be the answer. Then D will not be the answer.
If I compare B and C then I will go for C since there will be a interaction.
Usually calcium magnesium comes means hydrogen bond interaction will be less.
So here in options some mistake is there. Okay. Okay. In options some mistakes are there. So let us leave the question because I think maybe DTP operator while preparing the options uh she would have done some mistake.
Nothing other than that. Okay don't worry. Let me keep some dummy answers.
We will move to next question.
Which of the following statement is not true for the given species?
Which of the following statement is not true for the given species?
Which of the following statement is not true?
All species have linear shape. All species have some dipole movement. All species are electro iso electronic. All species have identical bond order and they are diiamagnetic in nature.
Yes.
All species are iso electronic. That is true. They are asking not true.
Some dipole moment will be there.
All species have linear shape.
Yes, since everything is iso electronic they have identical bond order at the same time since even number of electron they will be diiamagnetic in nature. So which is correct? Wrong option B is wrong. have some dipole moment. No.
Next. So, option B is the right answer.
Next question. In which of the following d orbitals are not used by central atom in hybridization?
Yes.
In which of the following d orbital is not used by central atom in hybridization.
Come on.
Come on.
CCC. Yes sir. Small doubt sir. What is the doubt? We can write and check the exited state electronic configuration.
In that case PBR5 if you take PBR5 it is not used by central atomic hybridization. D orbital will not be used.
Good afternoon sir. Yes. Good afternoon mavana.
This clear. So just what we need to do.
Hey Henry.
I am there. It is clear right.
So this is very very important.
Yes, in PBR5 only D orbital is not used.
Just write the electronic configuration and check automatically in exited state where and all we will be use actually this should not be PBR5.
This should be PBR3.
Yes, it should be PBR3.
Then only it will be the option C. Okay.
So, till now how many questions we completed? Till now nearly 29 questions completed. So, let me move further.
Yes. Next, I'm moving into thermodynamics.
The respective examples of extensive and intensive properties are the examples of extensive and intensive properties.
I guess extensive property and intensive property.
Yes, very easy question. So, it is very easy question. So, answer will be option C will be the answer. Entropy and temperature. We know all thermodynamic functions are extensive property. Now when it comes to intensive property we will be having temperature which does not depends on mass.
Next question once more. Yeah.
A system absorbs 10 kiloj of heat and does 4 kilojoule of work. The internal energy of the system.
Yes.
We can use deltaU formula right? DeltaU is equal to Q + W absorbs 10 kiloJ of heat that is + 10 kiloj does 4 kiloj of work. Work is done by the system - 4 kiloj. So delta U is equal to 10 - 4. DeltaU is equal to 6 kiloJ. Since we are having positive sign, automatically option B is the correct answer. Option B will be the correct answer.
Next question. For the given reaction, A gives D. Delta H is equal to X. Steps involved are this one, this one, this one. Okay, we need to find out delta H2.
Yes.
How do you feel like that?
Yeah, very simple question. So, option A will be the answer. What we know? A D just I need to add the equation. So if I'm adding delta H total will be equal to delta H1 plus delta H2 plus delta H3 what they told this is X is equal to X1 this I need to find out plus X3 so delta H2 will be equal to X - X1 - X3 so - X1 - X3 automatically option A will be the Answer yes option A will be the correct answer.
Next question. If the heat of formation of N2 is X.
Okay. The heat of reaction N2 + O2 gives 2 N is Y and the heat of reaction 2 N + O2 gives 2 N2 is Z. Then which is the correct answer?
Yes.
How we can able to do this?
Hello.
Amen.
What is the answer? We are getting D.
How we will be getting D. Correct answer will be option C will be the correct answer. Option C will be the correct answer.
Right? So how I can able to form NO2 from these two equations?
Yes. So why are X value they are asking how we can able to form? So in the given reaction NO2 is X. So let me write half N_sub_2 plus O2 gives N O2. This is formation.
Heat of formation of NO2 is X. Heat of reaction they given N_sub_2 + O2 gives 2 N O2 that is heat of reaction will be Y 2 N + O2 gives 2 N2 for this heat of reaction is Z. How I can able to form above equation from this? First of all no reverse and all happening. This first equation I can multiply by half. So I will be getting half O2 I will be getting 1 mole. Yes, first equation I am multiplying by half.
Second equation once again I will be multiplying by 2 N 2 N. So first equation if I multiplying by half I will get one. So here also I will be multiplying by half. 1 N 1 N will get cancel/ O2/ O2. So I will be getting nothing but 1 by O2. Here also 1 N2. Yeah 1 n2 second equation also I'm multiplying by half so automatically x if I talk about x will be equal to y + 2 + z by 2 it is nothing but 2x = y + z so y will be equal to 2x - z so option c is the correct answer option c will be the correct answer next question the difference between delta Delta H and Delta E for the reaction.
Yes, temperature is 25° C.
What will be the answer for this question?
How to solve this particular question?
But I think compared to other classes students are enjoying chemistry class. I can able to see that happiness in the chat section. Huh.
There are different chemistry classes going on.
uh see uh Jay Kumar for for actually in chat if any of the back end team or any students are know it is like uh chemistry love story is happening in the chat but in neat examination it's going to be a horror story exam is approaching H enjoy our flow. Ah that's what okay tell me my dear students how we can able to do delta h enthalpy internal energy what is the relation we know between enthalpy and then internal energy very simple we know delta h is equal to deltau plus delta pv otherwise I can write delta h is equal to deltau plus delta ng rt because pressure and volume term is not given in the equation so if this comes this side delta Delta H minus delta U is equal to delta NG RT. Now what exactly they are asking? Delta NG it is applicable only for number of moles of gas. How many moles of gas is there in the product side? 12 minus in the reactant side how much I'm having 15. So 12 - 15 means -3 into R value. We are dealing in kilojoule. So kilojoule means if I want to write 8.314 that is joule per kelvin per mole right.
So 8.314 joule per kelvin per mole. Otherwise for simple purpose how we can able to take this as we can take this eight value how we can able to take yes 8.314 for calculation purpose how we can able to take 8.314 anybody?
Yes.
Temperature 25° C means in kelvin how much we will be having? It is nothing but 298 kelvin. So 298 into R value what we can able to take 25 by3. Yes exactly for calculation purpose we can take it as 25 by3. Now approximately 33 will get cancelled.
Keep this as 300. So it is nothing nothing but 75,000 7,500 yeah 25 3s are yeah 7500 will be there 7,500 what will be the units we will be having this is kelvin this is mole so 8.314 joule per kelvin per mole so final answer we are getting in joule so automatically kiloj means approximately 7.5 - 7.5 option Option A will be the correct answer. That's all.
Directly we can able to do it. Option A will be the correct answer. Next question. Volume of gas expands by 0.25 m cube at a constant pressure of oneness.
Yes, exactly. Approximation.
No, I just want to take I just want to check even 25 by3 students know or not.
That is also very important.
Volume of gas expands by this much volume at constant pressure of one.
Yes.
Yes. Yes. Yes. Tell me.
Only unit is matter in this questions I can't even able to ask one question sir.
Yeah.
Yes.
Volume of gas expands by 0.25 m cube at a constant pressure of 1. What is the expression we will be having? Pressure is mentioned, volume is expansion, volume of the gas is expanding. So automatically I think they are asking work done. Yeah.
So question is incomplete. Work done they are asking. So pressure of 1 what will be the work done? So what formula we can use W is equal to minus P external DV what is external pressure 1 DV change in volume is 0.25 so work done is 0.25 25. Now this is very very important. What we are having?
Yes. Jewel watt or newton. What will be the answer?
Yes. What will be the units?
BB BB.
So we will be having what? Newton jewles? I will be taking 250 joule. How exactly I'm writing it is in jewel because we know very well 18 atm means how many pascal will be approximately 101325 pascal right. So automatically we will be getting the answer just conversion. So option B is the correct answer.
Let me move into next question. Shall we move into organic part my dear students?
Okay let finish this question then we will move into organic part. When 1 g of anhydrous oxylic acid is burnt at 25° C, anhydrous oxylic acid CH the amount of heat liberated is this much enthalpy of combustion they are asking.
Yes. Enthalpy of combustion they are asking.
Enthalpy of combustion.
When 1 g of anhydra oxylic acid is burnt at 25° C, amount of heat liberated is this much. Now, delta H combustion.
Yes.
G yeah G what we will be getting heat they given right. So enthalpy of combustion is nothing but heat liberated upon number of moles. So how much heat is liberated? 2.835 kilojoule. Number of moles. How much gram? 1 divided by what is the g molar mass of oxylic acid? Uh 12 2's are 24 + 2 + 4 oxygen right uh 64 64 90 Yes. 1 by 90. Now 2.835 into 90 what exactly we will be getting?
So into 100 means we will be getting 283.5 right into 100 means we will be getting 283.5. So this is 90 lesser than 283.5 but correct answer will be option A minus of heat liberated.
Yes. So option A will be the correct answer. Option A will be the correct answer.
Done. Fine. Next.
An atala takes 100 g of glucose of energy equivalent to 1560 kilojoule.
How much amount of energy is up taken by 1 g molecule of glucose? Very easy.
Basic concepts of chemistry.
Mole concept based question.
Yes, this question is completely based on mole concept.
Next actually we are moving into redux reaction.
Yes.
So what is the answer? We will be getting just a mole concept. Think in this way 100 g of glucose how much energy we are getting 1560 kiloj of energy. Here it is in kilogj only. So automatically 1 g of glucose. Here molecule is given.
Listen carefully. Gram molecule that means moles of glucose. Gram molecule.
Here the question is about gram molecule. So 1 g glucose will give how much amount of energy? So we'll be getting 1.56 kilojoule. Here the question is 1 g molecule of glucose.
Yes.
The question is about gram molecule.
Huh? So 1 g molecule is nothing but mole. So 1 mole of glucose automatically will give 15.6.
For 1 g it is this much means then for one mole what is the molar mass actually we will be having 180. Right? So 15.6 into 180.
So 15.6 6 into 180. What will be the answer?
So we can write it as 156 into 10 ^ minus one. I think option B will be the answer. It is clear. Everybody getting the point. How to solve this question?
Yes, everybody getting an idea. So one of the very very important question blindly please don't do option B is the correct answer.
Next I moving into redux reaction. I'm moving into redux reaction. Which of the following group will behave as oxidizing as well as reducing agent?
Tell me my dear students which of the following group will behave as oxidizing as well as reducing agent.
Yes.
So oxidizing as well as reducing HN means it should not present in highest oxidation state or lowest oxidation state. K2CR27 highest oxidation state.
Next MN O4 minus highest oxidation state. So it will act it will undergo only reduction. and how it is possible to undergo oxidation. So option C will be the answer. Option C will be the answer.
Option C will be the answer. Next question.
Half mole of Cr2O3 releases this many number of electron then probable product will be very important model question.
Very important model question.
Yes.
Half moles of CR23 releases 1.5 into 10 ^ 23 number of electrons. Then probable product will be what will be the probable product.
Yes.
Sure. Everybody option D is the answer. How? Option D is the answer. Tell me anybody can able to give the reason why option D is the answer.
Yes.
Option B.
So what is the correct answer? Correct answer will be option D will be the correct answer. Option D will be the correct answer. How?
First calculate if I take CR2O3.
So what is its oxidation state here plus 3? C R23.
CR23 exist in half state. They clearly mentioned half mole releases this many number of electron. They clearly told half moles release this many number of electron. So let me first calculate number of moles of electron.
So number of moles of electron how we will do number of electron divided by avagadro number I will take it as 6 into 10 ^ 23. So number of moles of electron comes out to be 1 6 upon 0.25.
Yes 0.25 25 is the number of moles of electron is getting released from half mole. Since they told half moles of CR23 tell me in half mole of C in half moles of PR2O3 how many moles of chromium is present in one mole of CR23 in one mole of TR23 how many chromium is present?
two chromium. So in half moles of CR23 how many chromium will be present? One chromium will be present. Right? So automatically according to them one mole of chromium is releasing this many number of electron. One mole of chromium is releasing.25 moles of electron. So now change in oxidation state. How I can able to calculate change in oxidation state?
Very simple. Change in oxidation state how many moles of electron is getting transferred 1.5 into 10 ^ 20 sorry how many moles of so.25 25 moles of electron is getting transferred. How many chromium atom we are having? One chromium atom. N factor. So how I will write always n factor change in oxidation state. It is nothing but number of electron transferred into how many chromium atom is there? One chromium atom because half mole only we are taking. So 0.25 is the change in oxidation state.
Change in oxidation state is 0.25.
So initially what is the oxidation state we are having exactly? So partial oxidation is happening. Right? Partial oxidation is happening. Now if that is the case tell me my dear students what exactly we will be having.
Yes.
Yes.
You see no one is listening to the class. Everyone is staying there.
Everyone is chithatting happily.
After this let me do few questions then I will finish up. Ania sir. Yes ma'am.
Tell me.
there in a very interesting way that is going on. So in half moles of Cr2 what is the change in oxidation state? We are getting the change in oxidation state as.25.25 is the change in oxidation state. Now automatically they are asking what is the probable product.
The question is all about finding out the probable product. So automatically imagine if I talk about half mole of CR23 is releasing this much. So the change in oxidation state is.25.
So automatically what I will be getting?
Yes.
Now we can able to do it right it is clear and then so they are asking probable product from general stometric equation we know very well so CO4 2 minus what will be the state plus 6 here what will be the state plus 6 so based on that we can able to tell it is clear yes next Hydroine reacts with Kaio3 in presence of HCl. Equivalent mass of N2 H4 and KiO3. They are asking very simple calculate the N factor and then we can able to do right road to Jim. Yeah. after this class I need to decide maximum now evening I'm having another one bridge course class right so I will just uh go outside have and then I will come back sir please give us a break for lunch okay sure after redox reaction I will give a break so after After that only few organic chemistry questions will be there. Take it as a homework and try to solve. I will share the PDF because already in marathon also organic chemistry is completed right. So you guys can able to do it N2 H4. So we need to calculate the change in oxidation state in KIO3. What will be the change in oxidation state? Very simple. X oxygen oxygen will be -2. So X - 6 is equal to -1. X will be equal to + 5.
Here iodine exist in + state. Here iodine exist in +1 state. So what will be the change in oxidation state? + 5 + 4 + 3 + 2 + 1 change in oxidation state is four into one iodine atom. So n factor is four. Now what they are asking equivalent mass when it comes to K IO3 what will be the equivalent mass of Kio3 we can calculate right? So molecular mass divided by N factor. So automatically we will be getting in the same way for N2H4 also you guys can able to do it.
Yes then so molecular mass divided by N factor. just to do molecular mass divided by n factor then you guys can solve this question.
All right. So let me move into organic chemistry. Still some questions are there but that will be a basic questions my dear students. See arrange the in the decreasing order of oxidation state of nitrogen. Basic oxidation state calculation you guys can able to do oxidation number of oxygen in these are all very very important question take it as a homework and try to solve oxidation state of nitrogen in analine and nitroenzene this is also very important question decomposition of Kcl3 is an example of what intermolecular redux reaction intermolecular okay this is inter this is intra disproportionation All of this like this general questions actually I'm giving here. Take it as a homework and try to solve. Now I'm moving into Now I am moving into organic chemistry.
Is everyone is ready to solve organic chemistry question?
Yes.
Is everyone is ready to solve?
Since okay only few questions are there in organic chemistry so try to solve it will be very simple only.
So let me start from this question.
Yes. First question.
Acid deformed in the above reaction is they are starting from alkyhalide. They are starting from alkyhalide C2 H5 Br.
Yes. Quick organic chemistry is very interesting only few questions. So after that we can go for lunch. That's it. I will also finish the class. Now organic I think everybody can able to you do in a very happy way.
C option sir everyone is sure no correct answer is option B we will be getting seninic acid if I treat with al alcoholic KOH alpha beta elimination I will be getting Alken broine in presence of CL4 I will be getting dyromo product if I treat with KCN I will be getting now what exactly we'll be getting with excess of water automatically we will be getting we will be getting senic acid we will be getting senic acid it is here. So remove CN and then we need to put P. That's all. CH2 CH2 H. The correct answer is sinic acid.
Okay. Now onwards I will start with the poll time of 40 45 seconds. 30 seconds.
Next question. Match the list only 30 seconds. Quick 30 seconds match the following from ali ketone caroxilic acid.
Yes.
Yes. Exactly. Option B is the right answer. But time got over. So option B is the correct answer. For A we can use with the help of DBLE diol. How in presence of DBOL H actually will be happening where the bond breakage will happen between this hydrogen hydrogen. Then B for B actually what we will be using? We will be using zinc amalgam and concentrated HCl. So remove the C bone instead of that we need to add CH2 then for C it is 1. Yeah for C it is one. So option B is the right answer. Next question. Identify the following reaction product.
Yes, you can see it in the live session. Noma Santos, go to the channel, look into the live session already. The classes has been scheduled. You can see that.
Identify the product in the following reaction.
Yes. What exactly we are using?
Zn Hg automatically this C double bond O this C double bond O will be get reduced. Option D will be the correct answer. Option D will be the correct answer. No one is answering in less than 45 seconds. Very bad. So, option D will be the correct answer.
Next question. The number of correct reaction among the following.
The number of correct reaction among the following.
Yes.
Number of correct reaction among the following.
One of the naming reaction is there one naming reaction that is the clue.
What is the correct answer? Option C is the correct answer. Option C will be the correct answer. But here what how exactly the reaction will happen? Here we will be getting H. Here we will be getting O. Here in presence of H2 reduction. Yes. So they are asking correct one. So this and all incorrect one. So the correct one is option C is the correct one. Here this will get positive charge. This will get minus charge. So reaction will be different.
Option C is the correct reaction.
Next question. Consider the given chemical reaction. Identify product A. Kmen4 in presence of H2SO4 benzene.
Direct question. These questions are direct questions.
Tomorrow and day after tomorrow in live that's why I'm asking class is there.
Once again I will check the channel.
Once again, my dear students It is scheduled.
It is scheduled in the channel. Just now I check. Yeah, exactly.
Santo Sha now he got today evening uh first class of Subrats is there in white live evening 6:00 24th Ambikam class is there everything is scheduled yes for this what is the correct answer direct question adipic acid we will be getting so direct question we know very well automatically what exactly we'll be getting adipic acid next question so last question option D is the answer why polar is not taking I don't know.
Identify A and B in the chemical reaction.
Yes. Quick.
Identify A and B in the chemical reaction.
Yes.
Automatically the correct answer is option C. How? If I take here here positive charge minus charge. So A will be C double bond O CH2 CH2 CO H then B reduction I am doing so automatically what I will be having this C double bond O will change into CH2. So option C will be the correct answer. Next question.
Identify A in the following reaction. So they are having ketone. So what they are doing ketone in presence of N2 H4 followed by ethylene glycol KOH. So automatically C double bond O. We will be getting option B. Direct question. These are all very direct question. Consider the given reaction. Identify major product P. So first they are treating with poor reagent. The starting thing is acetic acid. So what I will be telling first actually we are treating this with what? We are treating this with lithium aluminium hydide. So reducing agent acid will give what? We will be getting corresponding alcohol. Next I am treating this with PCC. So automatically what now I will be getting with the PCC. with PCC we will be getting corresponding alihide.
Yes, we will be getting the corresponding alihide CH3 C double bond O. Next I'm treating this with HCN. Now what will happen? So automatically we will be having PH3 CH O CN TH3 CH O H CN Now finally what I am doing I'm treating this with water in presence of O minus so automatically I will be getting CH3 CH so option D will be the correct answer option D will be the correct Answer. It is clear right. So with the PCC automatically we will be getting alihide.
Next question.
Which among the following alihide is most reactive towards nucleophilic addition reaction? So very simple question. So I'm telling this answer.
Next question. Identify product P in the following reaction. Before identifying the product, what is the reagent they given? Bromine in presence of red phosphorus. Tell me broine in presence of red phosphorus means what is the name reaction? What is the name reaction involved here? My dear students, please do let me know what is the name reaction involved here.
B for biran. What is the name reaction involved here? My dear students, please do tell me.
What will be the name reaction?
We will be getting HVZ reaction. I am telling no based on this HVZ reaction even in our J exam 2026 we got question J 2026 April month they framed one question based on HVZ reaction. So HVZ yes exactly wrote to Jimmar. So HVZ reaction means automatically what will be the product we will be getting.
Yes, very simple. Here hydrogen will be there. Remove this hydrogen and add bromine. Option A will be the correct answer. Option A will be the correct answer. Very simple HVZ reaction.
Next question.
Identify major product X formed. Just now we discussed CIO HCl in presence of anhydrris Al3 what we will be getting product X will be benzaldihide.
We know this very well right. So option C will be the correct answer. Ben benzaldihide.
Next. Which of the following compound give positive iodo form test? Ah to give positive iodo form test. Which one will give positive iodo form test?
Yes.
Yes. Yes. Yes.
Exactly.
B will give. So when the compound treated with aquest Koh followed by what I am using potassium hypoiodide. So I will be getting yes. So methyl ketone group will be there automatically iod for test is possible. Which of the following compound will give silver mirror with ammoniaal silver nitrate?
Yes.
Formic acid, formalihide, benzaldihide, ketone. Which one will give? Ammonia, silver nitrate test except ketone, formaldihide, formic acid, benzaldihide. All these three will give silver mirror test. Option B, A B C is the correct answer.
Yes. Once again naming reaction this reduction is known as what? Like this question comes means it is a happy news for us. Hydrogen in presence of padium BSO4 Rosenman reduction it is nothing but Rosenman reduction.
Next identify the name reaction once again from benzene to benzaldihide in presence of cocl it is called as what is the name reaction?
Gatman coach reaction. Option C is the correct answer. It is called as Gatman coatman coach reaction. This reaction is called as Gatman coach reaction.
Next statement type question.
All the following compound react with paratuline sulfonyl chloride. Their products in the above reactions are soluble in aquis na.
Yes.
Quick. Now the question is from amine chapter.
Guys only organic chem basic concepts of chemistry atomic structure chemical bonding then followed by thermodynamics thermmochemistry chemical equilibrium then aliate ketone caroxilic acid now I'm discussing amines See he's asking to other girls do you think you look beautiful here I am teaching uh very very important thing but he's enjoying from starting of the class let him enjoy both statements are false yes option A is the right answer product A and B formed in the following reaction first nit nitrating mixture followed by tin HCl then Na2 dasetization next reaction is with phenol what will be getting formed very simple with a nitrating mixture we will be getting nitroenzene with a tin HCL I will be getting anine with the diasization I will be benzene dasonium chloride. Benzene dasonium chloride reacts with phenol to give parahhydroxy aobenzene.
Which reaction is this my dear students?
The reaction is coupling reaction. Parah hydroxy aobenzine.
A B C D. Yes. Aneline. Parah hydroxy aobine. Option C will be the correct answer.
Next question. The final product A formed in the following multi-step reaction sequence.
No problem ana take care whenever time is there watch as a recorded lecture otherwise better download the notes from the WhatsApp try to solve.
Sir how can I contact you on telegrams?
Uh yeah there are some discussion groups are there for yeah other state students like uh PW Tamil Nadu discussion group all those things in the telegram channel I will be there even morning one more student contacted me in telegram if that student is there listening means please uh tell the thing to ba so that she can contact me what we'll be getting once again arhalide the question is from arilhide is the reactant Yes.
First if I treat with magnesium ether.
So what I will be getting?
I will be getting penile ring mgbr.
Then I am treating this with what? Ether then CO2 in presence of H+. So automatically I will be getting benzoic acid. Now benzoic acid I am treating this with ammonia. So I will be getting benzamide.
Next with Br2 in presence of NaOH. So automatically I will be getting analene.
Preparation of analine. Option B is the correct answer.
It is clear. Next. Following is a confirmatory test for aromatic primary amine.
Aneline diatization scarlet red. What will be a from analine to benzene dasonium chloride? We know very well na2 in presence of hcl.
Now benzene daonium chloride with what actually I will be getting? Scarlet red dye.
Yes.
With what I will be getting scarlet red dye.
Yes. Today onwards classes are dma for luxury neat English batch. First batch will be in the uh YT live as well as app but first class will be the free class.
Even after that you guys can enroll. If uh you like the classes definitely you guys will like. Today Subraat sir will be taking that first live class. Yeah you will get all the details in the app only in the app. Go to the announcement section automatically you guys will get all the updates.
Yes. So A I told B C D find out this and let me know the answer. Very very important. Take it as a homework question. Okay. So I am reaching the final stage. Only few more questions are there. Which of the following reactions is correct?
Which of the following reactions are correct? They are asking not incorrect.
They are asking correct reactions.
They are asking correct reaction.
Yes, B. Exactly. So the correct answer is option B is the correct answer. Other than this this and all incorrect. We also know very well this and all incorrect. It is clear, right?
Then okay, next one. the source of nitrogen in gabriel synthesis of amine.
What will be the reactant source of nitrogen?
Yes. What will be the Gabriel synthesis in the name only it's there? What is the full name of the reaction? Gabriel talomide synthesis. So where Gabriel talide potassium talomide very simple even we know this reaction as Gabriel talomide synthesis only know. So what will be the reactant? I will be taking only. So option D is the correct answer.
Next question.
The best reagent for converting two phenile propanomide into two phenile propanamine. Listen carefully. From amide to amine. They are asking what is the best reagent? What I can use?
From amid to amine what we will be using very simple amide to amine. So we need to do reducing agent. What is the better reducing agent? Lithium aluminium hydide in ether. We can use that and then we can reduce the amide C double bond O to CH2.
Reduction of aromatic nitro compounds using here F HCL gives. Yes. If I take aromatic nitro compounds what exactly I will be getting reduction aromatic nitro compounds will give aromatic primary amine that's it that N2 reduction remove oxygen put hydrogen instead of NO2 I will be adding NH2 so automatically what will be the answer option C will be the answer which of the following compound will not undergo a coupling reaction under benzene Daonium chloride we know very well hydrogen should be there right analine will undergo phenol will undergo what about anol yes anole and nitroenzene which will not undergo anol also will undergo why because basic mechanism is electrofphilic substitution reaction plus some group should be there so which will not undergo nitroenzene which will not undergo nit Nitro been seen it is clear based on this we can able to tell next question okay that's all my dear students that's all so all the questions I discussed in between I given some of the homework question right so in today class how many questions we discussed means okay it is uh organic chemistry question I didn't use the timer so nearly 50 questions in today class we discussed so my Only thing is practice more and more question. These are all the different model question different model repeated questions. I didn't discuss all the questions. These are all the model questions we can expect in our neat examinations on. So it is clear my dear students. So with this I'm finishing. So only one thing I just want to tell download the notes from the WhatsApp.
Okay. So kindly download the notes from the WhatsApp that is very very important. Some of the homework questions I given know try to practice that. One more main thing if you people really want long marathon like how I did in last two classes please understand.
If you people want now after this class get over let me know in the comment section how really you people want marathon means please do let us know definitely we will plan because we are running out of time right. So whatever your requirement please do let us know in the comment section. Definitely I will also respond back end team also will respond. Okay. Okay my dear students tell me your IPL prediction sir.
No I will tell in the next class definitely I will tell what will be my IPL prediction. Before that you also let me know what is your IPL prediction.
Okay. Okay. Thank you so much Ro Jimar Henry Raj everyone. Yes very happy. Okay Ana no problem. You just go and watch the recorded lecture. It's not a big deal. But one more thing today evening 6 p.m. what class we are having? We are having physics first class of Lakshai need batch live is scheduled. So it is a free class first class. Watch that lecture till any of you due to any reason not enrolled means after that class definitely you people will understand how much important physics class how that next one year is going to be you people will definitely enroll in that batch. Okay. Okay my dear students take care. Bye-bye. These are all the different model question. Again I'm telling don't ask me sir the same question will come up. These are all the different model questions we can expect because these many years the same model question repeated number of time from limiting reagent from amine name reaction. So particularly I selected those question practice more and more question. I will be meeting all you guys in the next class. Okay take care.
Bye-bye.
I'm beat, bro.
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