To solve exponential equations like 4^x + 4^x = 44^x, first rearrange the equation to set it equal to zero, then factor out the common exponential term using the law of indices (a^b / a^c = a^(b-c)), and finally solve the resulting equation using logarithms by taking the log of both sides and applying the logarithm power rule (log(a^b) = b·log(a)).
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The "Impossible" Math Problem That Only 1% Can Solve!Added:
Do you believe that most students do not accept the solution to this amazing exponential equation.
I don't know. But by the end of this video, you will like the solution to this amazing equation.
Watch this.
Now, the question says 4 to the power of x + 4 to the power of x is equal to 44 to the power of x. Let me show you how to solve this. Watch it to to the end.
Now, what we are going to do is that we are going to move this 44 to the power of x to the left-hand side. Of course, this is positive. Crosses over equal sign, changes to minus 44 to the power of x. So, we shall have 4 to the power of x + 4 to the power of x - 44 to the power of x is equal to 0.
Let me show you how to solve this.
Now, do you believe that 4 to the power of x is a common factor to each of this term?
Let me show you.
Now, I can choose No, not choose. 4 to the power of x is a common factor, which means this can divide this without remainder. Of course, 4 to the power of x divided by the four divided by 4 to the power of x is one because without remainder.
This divided by this is um one without remainder.
Now, you put the minus.
Let me show you that this is true.
Okay? Let me show you that this is true.
If you have 44 to the power of x divided by what? By 4 to the power of x. Let's see whether this is the common factor to this.
There's a law of indices that that that say that if you have a to the power of b divided by a to the power of b.
Okay, let me use this this as c.
This can be written as a over c all to the power of what?
Of b.
So, this can be singled out as what?
44 divided by 4 all to the power of X.
And 44 divided by 4 is 11.
So, this is equal to 11 to the power of X.
So, that means um 4 to the power of X is a common factor to 44 to the power of X. So, that means this is minus 11 to the power of X. All this is equal to zero.
Right?
Now, let's continue this.
Now, this become 4 to the power of X multiplied by 2 minus 11 to the power of X to be equal to zero.
Now, when you have something like this, it is either 4 to the power of X is equal to zero or 2 minus 11 to the power of X is equal to zero. First, we say that 4 to the power of X is equal to zero, but X here is an element of non-empty set. So, we are going to ignore the solution to this.
All right?
So, now for 2 minus 11 to the power of X is equal to zero, this can also be written as 11 to the power of X to be equal to 2.
Now, what we are going to do is that we are going to introduce log to both side in base of 11.
So, we shall have the log of um 11 to the power of X in base of 11 is equal to the log of 2 base of 11.
Right?
Now, there's a law of logarithm that state that when you have something like this, this X Okay?
This X will multiply the whole of this log, so we shall have X multiplied by the log of 11 base of 11. This X multiply the whole of this log, so this is equal to the log of of 11 or the log of two base 11.
Now, the whole of this is one because if you have the log of A base of A, this is equal to one. So, this is the same thing as this. So, the whole of this is equal to one, so we shall have X * 1 is equal to the log of two base of 11.
X * 1 is X, so we shall have X to be equal to the log of two base of 11. So, this happens to be our final answer to this amazing equation. Please, air pulse to share this video, follow us, and subscribe to our channel for more math tips like this. I hope this video is interesting. Thank
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