This video demonstrates how to solve the cubic equation m² - m³ = 3/64 by expressing both sides as powers of 1/4, rearranging to form a difference of squares and difference of cubes, factoring using algebraic identities (a² - b² = (a-b)(a+b) and a³ - b³ = (a-b)(a² + ab + b²)), and applying the quadratic formula to find the three solutions: m = 1/4, m = (3 + √21)/8, and m = (3 - √21)/8.
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Olympiad Mathematics | Indian | Can You Solve This One?Added:
Hi, everyone.
Can you solve this one?
Okay, so we have m squared minus m cubed equals 3 over 64.
Okay, so how do we solve this?
We are going to focus more on the right-hand side, okay?
So we have m squared minus m cubed equals this 3 over 64.
You know, we can write it as 4 minus 1 over 64.
Okay. Now we proceed to go and write it as 4 over 64 minus 1 over 64. Still the same thing.
Look at that. Still the same thing. And then we now have m squared minus m cubed being equal to m 4 over 64 is the same as 1 over 16.
Then we have 1 over 64.
So if you look at the left-hand side and the right-hand side, we can now express them in the same form.
Yes, we can express what we have there in the same form.
So that here we have m squared minus m cubed and is equal to here now. You know, we can write this as 1 over 4 to the power of 2.
This is the same thing as 1 over 16.
Then 1 over 64 is the same thing as 1 over 4 to the power of 3.
Now the left-hand side and the right hand side can be m balanced.
But before then, let's bring what we have on the right to the left so that we can have m cubed.
Okay, we have m cubed.
Oh, [snorts] this is m squared then minus m cubed.
Then I'm bringing this here now, so this becomes minus 1 over 4 to the power of 2.
Then this becomes plus 1 over 4 to the power of 3.
And all of this will be equal to zero.
Everything will be equal to zero. So, the next thing we'll do is to reposition. We're going to write m squared minus this is 1 over 4 in bracket, this will be squared.
Then we have minus there we have m cubed.
Then this is plus 1 over 4 again to the power of 3 being equal to zero.
You have to pay attention to this um to what we are doing right now.
Now, look at this. We can group what we have so that m squared minus 1 over 4 squared will be a group.
This is a group now, right? Then we have minus we open this for this to be a group as well. So, we write m cubed and negative times positive is negative. So, here we have 1 over 4 to the power of 3 as a group and it's all equal to zero.
Okay? So, look at that.
So, at this point now, here we have difference of two squares and here we have difference of two cubes.
Okay, so here we are. We are going to work this in two ways.
I mean, separately. We are going to deal with this one first and then deal with this one after.
For this one here, this is going to be giving us m from difference of two squares. We have m minus 1 over 4.
into m plus 1 over 4 for the difference of two squares. So, this is what we have here.
Then here, we are going to use um difference of two cubes, right? And we know that a cubed minus b cubed can be written as a minus b into a squared plus ab plus b squared.
Right?
And according to this now, our a is m.
Okay? Our a is m.
And I'm writing this here.
a minus b is now m minus 1 over 4.
Then into a squared is m squared.
plus a a is m.
Multiply by b. b is 1 over 4. I'm working from the difference of two cubes there.
So, b is 1 over 4. Then plus here, we have b squared. And that is going to be 1 over 4 squared, which is 1 over 16.
So, we do this.
Now, we are going to bring this and this together, right? And we are taking the difference between the two of them.
So, let's set it very well.
Okay, so now we are going to have um um m - 1 over 4 into m + 1 over 4. This is for the difference of two squares. My does for the difference of two cubes. Now we are writing this one. Everything here.
So we open bracket, we write m - 1 over 4.
Right? And this is going to multiply this, which is m squared + Okay, m * 1 over 4, that's the same as m over 4.
Then plus um 1 over 6, right? 1 over 16.
So this is what we have. And we equate everything here to zero.
Everything will be equated to zero. Now looking at this, we have a common factor, which is m minus 1 over 4. So let m - 1 over 4 come out as a common factor.
Then here I have m + 1 over 4.
Then this negative will open the whole of this. Remember this is out already.
So this negative will open this and we'll have negative m squared.
Then we have negative m over 4 and negative 1 over 16.
So this is equal to zero.
Interesting.
So we continue from here.
What do we do at this point?
Okay, before we simplify this, before we simplify everything here, let's apply our zero product rule. So we are saying that m - 1 over 4 is equal to zero or this one here is equal to 0.
But, let's get our M from here first.
So, M from here will now be 1/4 if we collect like terms.
So, we now have the value of M.
Okay? Now, to get the other solutions, we will bring down this um expression here.
Let's bring it down here.
We have M + 1/4 - M squared M over 4 - 1/16 and we will equate to 0.
Okay, so let me pick this and then solve this completely.
Okay, so from here now we will simplify what we have. The LCM is 16. 16 * M, that will be 16 M.
Right? Then, we have plus 16 / 4, that is 4. 4 * 1 is 4.
Then, - 16 * this is 16 M squared.
Then, 16 / 4 is 4.
4 * M, that will be - 4 M.
Then, here we have - 1 cuz 16 / 16 is 1.
1 * 1 is 1. And everything is equal to 0.
So, let's rearrange what we have here.
16 M - M, that will be 12 M.
Okay?
Then, we have 4 - 1, that will be + 3.
Then, we have - 16 M squared which is equal to 0.
Now, we are going to write this one first. - 16 M squared + 12 M plus three equals zero.
So, we now have a quadratic equation.
Multiply all through by -1.
So, that will give 16 m squared to make this -12 m, make this -3, and everything is equal to zero.
So, from here, what should we do?
We will apply um we'll use quadratic formula for this.
So, our A is 16. That is the coefficient of m squared.
Then, [snorts] our B is minus 12.
Coefficient of m. And C is the constant, which is minus three.
C is a constant, which is minus uh three.
Okay.
So, we are using the quadratic um um formula, which is m equals minus B plus or minus we have B squared minus 4 AC.
And this is over 2 * A.
So, once you know the formula, you put in your values of ABC.
So, our m will be negative B is supposed to be 12, right? Minus 12.
So, negative negative will give us just positive 12.
Then, we have plus or minus we have here Okay, let's jump a step, right? Here, we have B squared, which would be minus 12 squared, which would give us 144.
4 Okay.
To give us 144, then we have minus Well, four our four Okay, let me write that.
We have 4 * A, which is 16, then times C. C is minus three.
So, this is all over two multiplied by 16 because A is 16.
And now from here, our M is equal to we have um 12 plus or minus 144 plus cuz negative negative is positive and 4 * 16 * 3 will give us 192. So, we have 192.
And all of this is over two.
So, our M will now be 12 plus or minus square root of 336.
This is over Okay, this is 32.
Yes, because 2 * 16 is 32. So, here we have everything over 32.
Now, let's break our 336.
Okay, so to break that, we're going to have M being equal to we have 12 plus or minus square root of 16 * 21.
That will give us the same 336. This is divided by 32.
Okay, now let's go on from here.
Okay, so um from here, M will be 12 >> [sighs] >> plus or minus square root of 16 is four, then multiply by 21.
Remember, everything here is over 32, right?
Now, there's something else we can do.
Our M will be four into three plus or minus this four is already out. We have square root of 21.
And everything is over 32.
Okay, so that from here M will be 4 into 32 is 8. So, we have 3 plus or minus square root of 21 over 8.
So, this right now is our value of M.
But, this is a two-in-one value.
Right? Now, the three solutions that we have now are M to be equal to 1/4 from the first part.
Then, M again is from here 3 plus square root of 21 over 8.
Right? Then, our third solution Our third solution will be 3 minus the square root of 21 over 8. So, these are the three solutions to the equation.
Thank you for watching.
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