The integral ∫(cos⁴x - sin⁴x) dx can be simplified by recognizing it as a difference of squares, which factors into (cos²x - sin²x)(cos²x + sin²x). Using the trigonometric identities cos²x + sin²x = 1 and cos²x - sin²x = cos(2x), the expression simplifies to cos(2x), making the integral ∫cos(2x) dx = (1/2)sin(2x) + C.
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This “Impossible” Integral Becomes EASY | IB Math #math #calculus #trigonometryAdded:
Bismillah. This terrifying integral is actually easy. You start with cosine to the fourth X minus sine to the fourth X.
Most students try expanding everything.
Don't. Notice this is a difference of squares. So, we factorize cosine squared X minus sine squared X times cosine squared X plus sine squared X.
Now, here comes the key idea. On the unit circle, cosine squared X plus sine squared X always equals one. And cosine squared X minus sine squared X is the double angle identity for cosine 2X. So, the entire expression collapses beautifully into simply cosine 2X. Now, the integral becomes trivial. The integral of cosine 2X DX is 1/2 sine 2X plus C. And that's the whole problem.
One identity, one simplification, done.
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