🚨 RE-NEET 2026 Chemical Bonding | Top 10 Most Expected Questions 💯

Ajouté : 2026-06-04

[00:00:01]Hello my dear students these are 10 questions from chemical bonding most expected for renit 2026.

[00:00:09]I will cover up your whole chemistry physical oric and onic in this way with most expected question and mark my words you will get your all the questions from this guest paper only. Yeah, I will give you so much quality questions then definitely it will come from here right and even I will not go to the jail okay right okay let's it go check yourself question number so which of the following set of molecules will have zero dipole moment now you see number of compounds are there so this question is looking lengy now let's see boron trilouide in the first option And I see okay one for dchlorovenenzene carbon dioxide. So the first option is looking like every all the options or all the compounds they are having zero dipolement. So this A is the correct answer. Let me show you. If you see the BF3 this is B F3 here florine its dipolement is zero because this vector and this vector will cancel out upper one vector. Now carbon dioxide this vector will cancel out this vector.

[00:01:25]Okay, are you getting my point? Now B A E A F2 how they have written the structures first you have to find out that for that you are supposed to find out the steric number. You see barrelium fluoride bef2 sigma bonds are there two sigma bonds are indicating that the steric number is two and steric number is two that means it's hybridization will be sp once you got the hybridization that means it's linear structure now if you see dchlorobenzene this lone pair this lone pair this lone pair and this lone pair this lone pair and this lone pair so this mole molecules dipole mment is also zero. So all their dipole mment is zero.

[00:02:11]It's I have explained it my dear students. So you can see clearly your answer is a. Now next question you see 39th question try to do it and let's check it out what they are asking.

[00:02:30]Identify the incorrect statement about P P statement about it's it should be PCL5 it's florine is not there PCL5 okay about so let's see what should be the answer the the PCL5 if I draw the structure of PCL5 then you see PCL5 will be like this now how to get this structure PCL5 now one chlorine is extra there just remove this chlorine this chlorine will not be there one chlorine should not be there now see how this structure is correct let's see my dear students how many sigma bonds are there in PCL5 there are five sigma bonds so five sigma bonds and no lone pair so steric number will come out five means sp3 dehybridization So electronic geometry will be trional by pyramidal. So remember that three equatorial bonds and three equatorial bonds. This is equatorial. This is equatorial bond.

[00:03:43]This is even equatorial bond. Equatorial bond length is less. Why? Because the bond angle is more. Whenever more is the bond angle, less will be the bond length. So this bond angle is 120°. So bond length is less.

[00:04:02]So three chlorines will occupy equatorial position and two will occupy axial position. Their bond length is more right. If I talk about it is 202 pometer bond length and that is 2 4 pometer approximately. So you can see that now what structure about let's see the options three equatorial PCL5 make and bond angle true this is true but they are asking which statement is incorrect false two exel PCL and angle 180° with each other yes you see the red one the pink one they are at 180° to each other so this is also true not the answer and So now the C1 axial PCL PCL bonds are longer than definitely axial one are longer. Why they are longer? Let me tell you. If you split this sp3d we will see it is sp2 plus pd. Now you see the s character in equatorial is 33% whereas in there exel one there is no s character.

[00:05:19]So the bond is weak. That bond is weak.

[00:05:23]That's why in PCL5 always break PCL5 like PCL3 and Cl2 2 Cl2 they are weaker.

[00:05:30]They will immediately go eliminate out.

[00:05:33]So D is the correct answer because this is wrong. This is false. Why it is false? PCL5 molecules is nonreactive. It is highly reactive. It can react with alcohol RO to give RCL plus P3 plus HCl RC. So now question number 22 just see on your screen question number 22 this is also looking a lengthier one. Now see which option will be correct don't go and see the answer my dear students.

[00:06:04]Question number 22.

[00:06:08]See first is the correct answer. Let me tell you why. Always remember the XC F6.

[00:06:15]Now do it and try to do it in the air. X E F6. Just try to see xenon. If I say zenon lies in which group? Eighth group.

[00:06:27]That means it is having 1 2 3 4 5 6 always go like this. XC F6. It has found how many sigma bonds? Just C. Florine florine florine and florine. How many sigma bonds my dear students? 1 2 3 4 5 and 6 one lone pair is there. So steric number is always equal to number of sigma bonds plus number of lone pairs localized means not taking part in resonance. So what is steric number is coming my dear students. So steric number is coming 6 + 1 that is 7 7 that means sp3 and d2 hybridization will come sp3 d2 pentagonal pip parameal is the electronic geometry but this lone pair will not allow that means one position will remain vacant so it must be distorted octahedron Right distorted because if six is the stoic means if six is the steric number then it would have been your octahedral but there no lone pair would have been present but here one due to one lone pair it should be distorted octahedral. Let's come back to the question.

[00:07:56]So what was the question mass the compounds in this? So XC F6 is distorted octaal. We got one thing that it is being distorted octahedral. Now let's see another one my dear students.

[00:08:12]Another one X EO3.

[00:08:15]Let's go and find out X EO3.

[00:08:18]Let's see to it once again.

[00:08:22]Xenon I have told you 1 2 3 4 5 6 7 8.

[00:08:27]So double bond O, double bond O and double bond O. Now see how many sigma bonds are there. Pi bond will not find out the hybridization. Always go for sigma bond. Now three sigma bond and one lone pair. Four means electronic geometry must be tetrahedral but one lone pair. So it will be pyramidal shape. Shape will be pyramidal. So let's come back. Let's come back to the same question. X E O3. So pyramidal pyramidal B1 is fourth. Now check it out. B1 is sorry third. It's given third. Pyramidal is on third. So you see only one option is getting matched. And see for your understanding I have shown the structures also the correct explanation is given. Now see XE F6 is exactly given like this. So it will be little bit tilted not exactly octahedral distorted.

[00:09:33]This lone pair will try to push. Now see X² parameter XO4 XC F4. Now you can get it. How to get it? XO3 XE. It's over here XE. And the shape is looking like pyramidal but it should be like this. X E loan pair double bondo double bondo and double bondo it should be like this. So team has made a little bit um what to say discrepancy is there. Now XC F4 this C F how many F are there? Five F are there but let's see X E F4 should be yeah just you can do it in air zenon is eight electrons four have gone so two lone pairs are left two lone pair and four sigma 1 4 + 2 six so it's hybridization is coming sp3d2 so electronic geometry is supposed to be what octadral but two positions will be occupied by lone pair so x f4 square plane planer this florine should not be there rest is okay it's square planer got it x4 now try to get it in the air this structure is right or wrong just see my dear students x f4 xenon is having eight electrons in the outermost orbit out of a four taken by florine two taken by oxygen 4 + 2 6 one lone pair is left but how many sigma bonds florine four and one oxygen Five sigma bond and one lone pair six. So six is indicating sp3d2 hybridization and that is indicating the electronic geometry should be octa heal. But you know there are five one position is occupied by lone pair. So square pyramidal one pyramidal. So one position at one position lone pair is there x f4.

[00:11:36]So if I say this is oxygen. If this is oxygen then this will be lone pair. So you see shape is given just by sigma bonds. Pi bond never gives the shape.

[00:11:48]Lone pair never gives the shape. Shape is always given by sigma bonds. So your answer you got it because it was a lengthy one I would like to say. So you should know how to do it in the air otherwise in the examination you are going to waste your time. So remember what's the way to find out the shape and the dipole moment always find out the steric number after steric number find out hybridization after hybridization find out electronic geometry after electron geometry always find out shape and after shape you can find out dipole mment so this is your sequence for doing question I hope you got it now let's go back to are questions. So this one we have done. Now see another question. Question number 16th. Just see to it this question everyone. On heating which of the following releases carbon dioxide most easily? So the correct answer let me tell you a why a remember that bond of equality is good. Equality means smaller is stable with the smaller.

[00:13:00]Small kine is stable with small anion.

[00:13:02]Big kine is stable with big anion.

[00:13:05]Carbonate. Carbonate is multi-atomic anion. So bigger anion with bigger bigger is stable. Will not thermally undergo decomposition. Big kine is stable with big anion. But they are asking which will release carbon dioxide most easily. That means they are asking which is thermally least stable. So small kine large anion. Carbonate is large anion and magnesium as you know know that magnesium beta mangu caserbara barelium magnesium calcium stium berium radium so moving down the group kine size increases so smallest is magnesium so this is the correct answer I hope everyone got it magnesium carbonate or you can see the stability is given about this is the explanation if you heat it then you will get this state now these questions are specially designed for you now next Question. Question number 10th.

[00:13:59]Just see question number 10. Which of the following? 10th. Which one of the following entity has plain triangular shape? Means trional planer shape they are asking. So these are the options you just see to it. Question number 10th.

[00:14:14]Everyone see on your screen. Everyone just see on your screen.

[00:14:27]Got it? Now let's see if you say nitrate. Nitrate because this is linear.

[00:14:34]This is not the answer. Nitrate. If you see this is trional planer. So B is the correct answer. Now five questions we have done. Five more questions. Now let's see question number 41. Now this to easily you can do just now I have told you which is the correct and this you can say not only chemical bonding it is a question of P block also which is the correct thermal stability order for H2E now hydrogen is small that is common smallest stable with the smaller one who is the smallest one oxygen so definitely oxygen sulfur selenium to oipo so what should be the answer 41st answer is saw um which of the correct thermal stability order. So definitely H oxygen, sulfur, selenium, telenium. C will be the correct answer. Got it? Now next question. You see explanation is also given over there. Now question number 35.

[00:15:35]Consider the following entity. Which one of these will have highest bond order?

[00:15:39]Now this type of question definitely will come in examination. Definitely.

[00:15:44]Now remember the trick is you must know that number of times I must have told you that n to Now remember that the total number of electrons in N2 is 14 and its bonder bond order we know very well it's three 16. So keep on moving in the decreasing order the 3 2 1 0 3 2 1 0. Now if any entity is having electrons for example 15 then its bond order will be in between 2 and three that will be 2.5 like this you have got it the trick this is the trick now see how to solve this question number of times I have shown you that trick if you see the total number of sum of electron sinide sinide uh this sinide negative see carbon Six and nitrogen 7 7 6 13 13 and 1 14 this is 14 this is one cone so 12 this here 15 and carbon six and this 13 so maximum bond order should be off you can see it's very clear 35th question 35th questions which one is the correct answer so it's Yes, you see very clearly which of the phoning which one of the have the highest bond order. So definitely CN negative it's given clearly will have the highest bond order. I hope you got it everyone got it? Now once again the same type of question decreasing order of the stability more is the bond order more is the bond strength more will be the bond stability and least and uh bond length will be least right decreasing just see in O2 16 electrons so two 17 electron electrons 16 and one gone 15 electron and two more so 18 electrons. So O2 negative is 18 17 15. So you can see very clearly the trick I have told you if total sum of electron is 14 the bond order is three.

[00:18:40]Now less than 14 or more than 14 means 15 or 13 they will have bond order 2.5.

[00:18:48]Right? Now just check it out. What should be the correct answer?

[00:18:54]Yes, check it out. Everyone just check it out. Got it? No. So see if I say O2+ is having 15 electrons. So the bond order will be 2.5. You see the bond order O2 plus is 2.5 and O22 negative is 1. Can you see? So the correct answer is C. You got failed or pass just to let me know. Now see in the option there is one error uh O22 negative. This should be O22 negative right? O2 plus 15 then 16 bond order is 2 that is 2.5 this is 17 of electron is 17. So 1.5 and 18 so one.

[00:19:44]Next question. Question number 12. Once again, which of the following options represent the correct bond order? So once you have done it, you can do it because this type of question will come for sure. So it should be which of the following options the correct bond order. So you know that O2 sum of electron is 16. The bond order will be 2 O2 + 2.5 and O2 negative 1.5. So B should be the correct answer. Right? You should know that O2 is 16 electrons. So two this is 15. So 2.5 this is 17. So 1.5 exactly option. Now last but not the least which of the following is a polar molecule. Now once again you have to find out the steric number and then you have to find out the dipole moment each and everything. So just do it by yourself. This question is your for your homework. Bye-bye tarta right every day in the morning and the evening I will come like this with 10 10 10 questions right just after this video if you're really liking it and you have to like it because this is for your life this is for your selection this is for your garment seat try it out and just the way I have told you find out the sting number and then go up to the dappel mment then you will see if the structure is looking disbalanced then dappment should be there now this is the hint given for this question everyone do it and do let me know in the comment section. I'll be putting such type of questions very very short and precise sessions. Right? Bye-bye. Tata take care my dear strings.