This video demonstrates a classic redox reaction sequence where copper(II) sulfate (blue solution) reacts with potassium iodide to form copper(I) iodide precipitate and iodine (brown color), and then hydrogen peroxide further oxidizes the iodine, producing visible brown coloration and iodine vapor fumes, illustrating the principles of oxidation-reduction chemistry through observable color changes.
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CuSo4+KI+H2O2 --- ??๐ค(details ๐) #chemistry #facts #experiements #science #educationHinzugefรผgt:
This is the classic redux reaction demo where we use copper sulfate, potassium iodide and hydrogen peroxide. Okay, [music] let's uh understand this experiment step by step. In step first, copper sulfate solution I positive gives a blue color of Cu positive ions in water. Okay, in step second adding potassium iodide reaction we will see copper plus arodine it gives copper iodide plus I2. Okay, Cu positive blue gets reduced to copper positive white precipitate CUi. Okay, I negative colorless get oxidized to I2 which shown in the experiment brown color that's why solution turn brown plus cloudy. Okay, in step third adding hydrogen peroxide H2O2 reaction we will get I2 plus H2O2 it gives I plus O2 plus hydrogen. Okay, color chemistry magic you can see in the experiment color brown plus sorry blue plus brown plusing plus smoke. Okay, you can clearly see in the experiment.
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