INORGANIC CHEM -TEST-08 VIDEO SOLUTION FOR RE NEET-2026

Added: 2026-06-04

[00:00:00]Goal Nations [Music] Leading Institute.

[00:00:08]Hello Students, I am Sushil Kumar Chemistry Faculty in Gole Institute.

[00:00:12]Today I am going to discuss questions of Inorganic Chemistry which was asked in test number 8 for REET 2026 held on 31 of May. So come on kids, let us discuss the inorganic questions one by one. So the first question of inorganic is question number 142.

[00:00:33]Ok? Let's look at 142.

[00:00:36]Question number 142.

[00:00:39]This question asks, which of the following halides does not undergo hydrolysis at room temperature? Some halides are given. Isn't it? And the question is which of these will not show hydrolysis at room temperature. This is a question from children's P block.

[00:00:59]Its explanation is given in the carbon family. If you have read about carbon family p block then it has been told to you there and it is also given in NCERT that it is Sil4. Isn't it?

[00:01:13]You will find the same structure in NCERT as well.

[00:01:15]This is how Sil4 is. And with whom is this reaction being done? With water.

[00:01:24]You will see it exactly like this in NCERT. I'm trying to draw exactly that.

[00:01:28]So what is there here is that hydrolysis means what does this silicon atom have to do with this lone pair of oxygen? Have to accept it. Isn't it? The loan payer has to accept it. And then this SI and like this OH will be applied here. Then three chlorines will remain here and one HCL will be out from here and in the same way further by adding H2H2O again we will keep on removing each chlorine from it and ultimately in the end you will see it written like this that 3H2O is HCl- three times from here and in the end you will get SiOH hole four such compound which is also called silicic acid. Ok? This is silicic acid. Now [sound of clearing throat] kids, what's the concept here? The concept emerged that hydrolysis of these halides will occur only when there is some vacant space near the central atom to accept the lone pair of water and the lone pair of oxygen.

[00:02:32]And where is the space vacant? Silicon has this because silicon has a vacant d orbital.

[00:02:40]Whereas in the carbon family, carbon does not have a vacant orbital. Apart from these, everyone has silicon, germanium, tin and lead.

[00:02:49]So in this way the statement was made, it is written in NCERT that except carbon all tetrahedra undergo hydrolysis.

[00:02:58]Because they have vacant orbital to accept lone pair of oxygen. So children, I was asking in the question that whose hydrolysis will not happen, so whose hydrolysis will not happen, CCL4 will not hydrolyze, you must have understood, this is its answer, come children, now let us move on to the next question, let us see what is the next question after 142, the next question is 146, what is it saying in 146 that oxygen is more electronegative than sulphur, it is correct, the electronegativity of oxygen is more than sulphur. Yet H2S is acidic while H2O is neutral. Ok? It has been said that what is H2O like? This is neutral. Isn't it? That's correct. What is H2O like? It is neutral in its pure state. Isn't it?

[00:03:51]And he is telling H2S what is this? It is acidic. Ok? This is acidic. Ok?

[00:03:58]This is correct. Isn't it? Both things are correct. Now let us see what could be the reason for this? Let's talk about this.

[00:04:03]This is the reason why H2S is acidic.

[00:04:06]H2S is acidic because H+ will be easily removed from it. Now why will H+ be removed easily? Because the bond formed between sulfur and hydrogen will have a lower bond dissociation enthalpy. This can break easily. Only then will H+ come out from it. And it can break easily because what is the bond length here compared to oxygen and hydrogen? It is large. What is the length of the pay bond here? It is large. Therefore it will break easily.

[00:04:36]Similarly, we read that as we move from top to bottom in a group, the acidic character of hydrides increases. This will happen in every group.

[00:04:44]Like we know which will be more acidic than NH3? The pH will be 3. Similarly, AS3 will be more acidic. Similarly, it is in the water one. Similarly, it is in HF.

[00:04:56]HCl is more acidic than HF Which is the most acidic? HI happens. So down the group when we come the length of the bond increases. Bond dissociation enthalpy decreases. H+ is released easily and if H+ is released easily then the acidic character will increase. The reason for water being neutral is that its bond length is short.

[00:05:15]Due to the short bond length, this bond dissociation energy is high here. It does not break easily. So let us see here in the reason what is written that HS bond is weaker than OH bond. It is absolutely correct.

[00:05:27]This bond between oxygen and hydrogen is stronger as compared to the bond between hydrogen and sulfur. So this is its correct explanation.

[00:05:36]Our reason is also correct and with correct explanation. So, it is given here.

[00:05:40]Both assertion and reason are true and reason is the correct explanation of assertion. So the answer to this will be children third. Let us now look at the next question. What is our next question? After 146 is 149.

[00:05:56][nasal sound] 149.

[00:06:00][Sound of clearing throat] This looks like a question from the Chemical Bonding chapter.

[00:06:03]Let's solve this. Speaking of BF3 and NF3, let's draw the structure of BF3, kids. What is BF3 like? This would be BF3, right? This F and here F.

[00:06:20]What about hybridization? sp2. Its structure became triangular planar. Its structure became triangular planar.

[00:06:29]It is also an electron deficient molecule. There is also back bonding in this.

[00:06:33]It is stable due to back bonding BF3. Let's call it NF3. Children, the structure of NF3 will be like this. There will be a loan payer here.

[00:06:42]This will be fluorine. There will be fluorine and there will be fluorine. Its hybridization will be sp3 and its shape will be pyramidal. Isn't it? Pyramidal.

[00:06:56]Now let us see what is being said in the question that BF3 and NF3 both are covalent compounds but NF3 is polar whereas as BF3 is non polar it is being said that NF3 is polar. It is polar, meaning its dipole moment is not zero. This is polar. And he is saying what is its dipole moment? It is zero. That is, it is non- polar. It is non polar. So why is this? This is what he is asking you in the question. So I already drew the structure. It is very easy for you. In this, if children draw the direction of dipole moment, it will be from less electronegative to more electronegative element. From less electronegative to more electronegative.

[00:07:38]From less electronegative to more electronegative.

[00:07:40]Because this structure is trigonal planar. What will be the bond angle here? 120° and you know kids, you all are experts in vectors. Do you know that if three vectors are of equal magnitude and act at an angle of 120°, then what will be the resultant vector? It will be zero.

[00:07:58]Zero [sound of clearing throat] here comes the dipole moment, meaning it's become non-polar and come here. What will happen here? Less electronegative to more electronegative. Nitrogen to fluorine, nitrogen to fluorine, nitrogen to fluorine and there will be a vector towards the lone pair. From the central atom towards the lone pair. So, children, what will be its dipole moment? This is a different matter but it will not be zero.

[00:08:20]If we look at it according to the vector, then we can understand that its dipole moment will not be zero. So, let's see what options can be there in this? Let us see the reason for this.

[00:08:29]What have they thought? They thought that nitrogen atom is smaller than boron. It has nothing to do with this. And this is also wrong. Sorry, that's right. Ok. It is a fact. Nitrogen atom is smaller than boron. But that has nothing to do with it.

[00:08:42]NF bond is more polar than BF bond.

[00:08:46]NF3 is pyramidal. NF3 is pyramidal where as BF3 is trigonal planar. This will be the answer. This is why its vector sum is like this because the triangle is planar.

[00:09:00]Therefore its vector sum has come such that the dipole moment has become zero. Whereas its vector sum is such that its dipole moment is not zero. Meaning it has become polar. Children.

[00:09:09]Very easy. This has been written to you directly in the notes.

[00:09:14]You will get information about all these molecules directly in the copy.

[00:09:16]Let us now move on to the next question.

[00:09:20]Next is 153 Cyclo Trimeta Phosphoric Acid Contains P Block P Block Nitrogen Family Oxo Acids of Phosphorus, right?

[00:09:38]Wherever oxo acids of phosphorus have been taught, you have also been told about cyclometa phosphoric acid.

[00:09:45]Cyclo tri metaphosphoric acid, its formula is children H sorry sorry sorry sorry its formula is HP PO3 this is its formula. Cyclo tri meta phosphoric acid is the formula. Its structure is like this. P O P O P and here again O and like this. And with each phosphorus you have to put an OH and double bond O.

[00:10:25]One OH and double bond O have to be placed. Here also add one double bond O and one OH. Now count how many sigma bonds are there in it? How much is a sigma bond?

[00:10:39]This is one, this is two. This is three. This is four. This five, this six. Isn't it? This is six.

[00:10:47]Then look here, there is a seven, then here eight, then here nine, then here 10, then here 11, then here 12, this becomes 12 and after that you should also not forget that this OH is also actually O and H, so after 12, there is 13, after this there will be a 14 here and one here will be 15, that is, in total there are 15 sigma bonds in it.

[00:11:18]So this was a very easy question. But you can do this only when you know its structure well. Isn't it kids? Let's recreate its structure like this.

[00:11:27]Make it like benzene. This is how it happened. Then make double bond O and here O and H then double bond O and H double bond O and H like this. 15 sigma bonds will come.

[00:11:42]This is the answer. Now let us move on to the next question.

[00:11:49]After 153 is 154.

[00:11:53]The correct statement regarding Swerner's theory for coordination compounds is to state Werner's theory. So let us tell you children what Werner had told us. Werner had said that the central metal ion has two types of valency. One valency is primary and the other is secondary.

[00:12:14]Children, if we take a primary compound like this, if we take a coordination compound K4 Fe CN6, the charge on it is +4, the charge on the entire complex will be -4, here it will be -6, so here it will become +2, this +2 is the primary valency. Ok?

[00:12:33]What is primary valency? Is this oxidation state or oxidation number and which is secondary? This one is the coordination number. This is the coordination number. The second point in this will be that who satisfies this primary valency of +2? Anion satisfies and who satisfies it, children? The ligand satisfies. Which can be an anion, a cation and can also be neutral. What is the third point? This is because the anion satisfies it. That means there is a plus minus relation between these two.

[00:13:07]So it is ionizable. Isn't it? It is ionizable meaning it will ionize.

[00:13:13]Whereas this coordination secondary valency, its bonding with the ligand, never breaks.

[00:13:20]This is the definition of coordination compound that this complex ion obtained does not ionize in water.

[00:13:26]So what will we call this, children? It is non-ionizable. Isn't it? It is non-ionizable.

[00:13:34]What can we say about the fourth point? That the +2 charge that you see on this iron, that is the oxidation state that you see, is highly variable. It can be +2, it can be +3, it can be four, it can be six. But what will you see in this coordination number? It will look fixed. Isn't it? And what will this look like to you? You will see this variable. Another point is that this is non-directional. It is non-directional.

[00:14:01]While what is this? It is directional. So these were the five points Werner mainly told.

[00:14:06]Now let us see what is written in it. Here it is written that primary valencies are non-ionizable. What did I tell you? It is ionizable. So this went wrong.

[00:14:15]Secondary valencies are ionizable. No, it is non-ionizable. So the secondary valencies are ionizable. This is also wrong. Primary valencies are satisfied by negative ions and neutral molecules. No.

[00:14:29]Who will satisfy the primary only? The anion will satisfy because there will always be a plus charge on the primary and who will satisfy this plus, it is always satisfied by the anion, it is satisfied by the ligands which can be anionic, cationic and neutral as well, so our last one should be correct, what is written secondary valency is equal to the coordination number and is fixed for a metal, it is absolutely correct, what is the secondary valency equal to, it is equal to the coordination number and what is this normally, children, it is fixed. This is a very easy question.

[00:15:03]Werner's theory has been explained to you well.

[00:15:05]You might have remembered it too. You must have done everything right. We have full hope.

[00:15:09]Now let us move on to the next question.

[00:15:12]155 15 Come see, children. What is this question? It is a question of assertion and reason. The assertion states that the absolute magnet at H+ = 1 should oxidize water, but in practice the reaction is extremely slow. Permagnate means that MNO4 is minus, right? If any question comes about MNO4 minus permanganate and dimetal, then it will be from D block. Isn't it? He lives in D Block.

[00:15:52]When you look at the D block where permanganate has been mentioned or written in NCERT, you will see this line exactly written there that permanganate oxidises water.

[00:16:02]Oxidizes water. Isn't it? If water is oxidized, oxygen will be formed. Isn't it? Oxidizes water.

[00:16:11]But this is a very slow process. It happens slowly. Isn't it? So that's right. This happens slowly.

[00:16:18]Further, the reason states that the reaction is practically feasible only when either manganese ions are present and the temperature is raised. Children, a proper activation energy is required for every reaction to happen. Initial activation energy is required or proper temperature is required for any reaction to occur. Isn't it? And if the energy activation energy required for the reaction to take place or the temperature required is not present then the reaction will not take place. Isn't it? Or suppose there is activation energy but if the temperature etc. is a little low then the reaction will still not happen or will be slow. The same matter is here also. When it is oxidizing it, the bond formed between oxygen and hydrogen has to be broken and at the same time oxygen is being formed here.

[00:17:14]So here the temperature is required a little higher.

[00:17:17]So that is why this reaction is slow and to speed it up, the temperature will have to be increased a little or manganese plus two will have to be brought here which will work as an auto catalyst here. Isn't it? Auto catalysis will work. So, this statement of ours is both correct and the region below is also the correct explanation of the one above. You will find this statement written in D block. This is a fact. You have to remember that yes, it does oxidize water but you will have to increase the temperature there a little and to make the reaction a little faster, you will have to introduce Mn + 2 there as a catalyst.

[00:18:03]So here assertion and reason both are correct with correct explanation. So this option is our first one. Isn't it? Both assertion and reason are true. Reason is the correct explanation of a. Children, what happens here is that sometimes both assertion and reason are true and reason is the correct explanation. Sometimes he gives it in the first and sometimes he gives it in the third also.

[00:18:24]So many times children make mistakes because of this, it has become a habit for them that the first option would probably be that assertion is true, reason is false.

[00:18:34]The second would be Assertion is False. Reason is true. In this way he directly comes to the third option and in such a situation the question becomes wrong.

[00:18:40]So you have to read carefully what is written in which option. For example, in the same test paper, in the question at the back, ' Both assertion and reason are true reason is the correct explanation of a' was in option number three and here it is in option number one. So you have to take care of these small things also. So its answer became first. Now let us move on to the next question. Next is our children's question number 156.

[00:19:08]156 Let's see what he's saying? Which one of the following cannot act as an oxidizing agent?

[00:19:18]Which cannot act as an oxidizing agent?

[00:19:21]Children, who will be the oxidizing agent? Isn't it? What is meant by oxidizing agent? An oxidizing agent is something that will do what to an electron? Will accept. That means the electron acceptor is the oxidizing agent. So, since this is dichromate, you must have immediately remembered that it is dichromate. So this is an oxidizing agent. Why is it an oxidizing agent?

[00:19:45]Because here chromium has a +6 charge and this converts into chromium +3.

[00:19:51]That means it gains three electrons. Isn't it? That's why this would have happened. So it will gain electrons. Here, NO3-, NO3 minus, if you look at it, it is -6 here, so how much charge is there on it? Is +5.

[00:20:07]Nitrogen is in the +5 oxidation state. can gain electrons. Sulfur can be converted from sulfur to sulfur-2.

[00:20:16]Meaning it can also gain electrons. The electron acceptor will be the oxidizing agent and the electron donor will be the reducing agent. So the oxidizing agent, the electron acceptor, is accepting these electrons. He can do this also. He can do this also. But children, iodine is a member of the halogen family.

[00:20:35]Its oxidation state will be -1 followed by +1 +3 +5 +7. Meaning there will be only -1 in minus. Nothing else happens apart from this.

[00:20:43]So if it's already iodine minus, it can't accept any more electrons.

[00:20:51]Meaning it will not act as an oxidizing agent. So this is the answer.

[00:20:56]Whenever you come across oxidizing agent and reducing agent, use this concept. The one that you think can accept the electron right now will be the oxidizing agent and the one that can lose it right now will act as the reducing agent.

[00:21:09]Ok? So this is the answer.

[00:21:11]Let us now move on to the next question. Our next question is 159.

[00:21:23]159 Which of the following sets all the species are diamagnetic in nature? In which everything is diamagnetic. Isn't it? Total of the total is diamagnetic. So this is a question of molecular orbital theory. You will have to count the electrons and fill them in the box and after filling them in the box you will know which one has paired electrons. The one in which all the electrons are paired will be diamagnetic and the one in which all the electrons are not paired will be paramagnetic.

[00:21:49]Children, the concept is that if it is diamagnetic then what will all the electrons be in it? Will be paired.

[00:21:56]And what if there are children? If it is paramagnetic, it will have unpaired electrons. There will be unpaired electrons. Isn't it? Now let us check this and see. Like this is how you can create molecular orbitals.

[00:22:12]This is how it is made. Isn't it? There are many tricks etc. too, children. But you should try to solve the question by following the original pattern, then the chances of getting it wrong are very less. Only one question comes in the exam. It is not that every question is like this that we get so nervous that we start using tricks in all of them. Isn't it? The question that came in the exam is just one question. Yes, okay.

[00:22:38]If we have to make 20 similar questions on a large scale, then we should use tricks there.

[00:22:44]But if a question comes in the exam then we will have to take out time for it. It is possible that you may have taken very little time in the previous question. So you will have to give time to one or two questions otherwise you may get it wrong. So like kids, this is σ1s. This is Sigma Star 1s. Then this is sigma 2s.

[00:23:02]Then this is Sigma Star 2s. And in this way, by doing this, pi 2px pi 2py sigma 2pz and in this, both of these are made the same. Sorry, the one above made this wrong. It stays like this in it and cut it and do it like this. This is for more than 14 electrons. This is for those over 14.

[00:23:23]This is for under 14s. Now let's look at this one in C2. So how many electrons do you have in C2? There are 12 electrons. Isn't it? So how do you fill 12 electrons? 1 2 3 4 5 6 7 8 9 10 11 12 All the electrons are paired. Once paired, our C2 becomes diamagnetic. After that there is O2 - 2. So for O2, you will have to write it down and fill it in. You will have to fill it in this side. There is a slight difference in this type of thing here. Isn't it?

[00:23:55]Because there are more than 14 electrons.

[00:23:58]This one is for 14 or under 14. And this one is for the over 14s. Now fill in this is oxygen-2. So how many electrons does it have? O2 - becomes 2 16 and 2 18. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 What is this also for you, it has become diamagnetic, right? And after that N2 plus is left, so how many electrons will be there in N2+, it will be 12 electrons only, so it will also be like carbon, so these three, these three of ours, what have come out, they have come out diamagnetic, so this is the answer to it, children. Isn't it?

[00:24:44]Similarly, you could have checked the rest also. Let us now look at the next question.

[00:24:53]Next is our question number 160.

[00:24:59]160 The Group 15 Elements The property which decreases down the group which decreases as we move from top to bottom.

[00:25:07]Electronegativity Nitrogen Phosphorus Arsenic Antimony and Bismuth Children, broadly speaking, if we come from top to bottom in any group, then what is electronegativity? Decreases.

[00:25:21]Ok? So this must be correct. A.

[00:25:24]Ours is correct. Stability of the -3 oxidation state. If we move from top to bottom in the nitrogen family, what is the stability of the -3 oxidation state? Decreases. Why does it decrease? As we move down the group, the metallic character increases. Isn't it kids?

[00:25:41]What is metallic character? Increases.

[00:25:44]What is bismuth? It is metal. So the metallic character will increase. As the metallic character increases, the stability of the negative oxidation state will start decreasing. So okay, what is this statement of ours, it is correct and there is one more thing here, in this the stability of +5 also decreases down the group, this one decreases because the metallic character increases and that of +5 decreases due to inert pair effect, inert pair effect, the stability of higher oxidation state also decreases due to inert pair effect and that of minus one decreases because the metallic character increases, so you should keep this one in mind also, after that the acidic nature of oxides. Acidic nature of oxides is telling what is happening?

[00:26:29]Decreases down the group. Correct. The acidic nature of oxides also decreases.

[00:26:33]Because as we come down, the oxides start becoming amphoteric. Isn't it? So the acidic nature also decreases. The one above is acidic nitrogen of phosphorus. After that the acidic nature of the oxides starts decreasing.

[00:26:46]So this is also correct. Last written is Reducing character of hydrides.

[00:26:51]No reducing character of hydrides.

[00:26:54]NH3 PH3 ASH3 come from top to bottom, right?

[00:26:58]Hydrogen ions are removed quickly. And what happens to their reducing character when it comes from top to bottom? It increases. Isn't it? So the reducing character increases.

[00:27:10]This statement is wrong. So what are our A, B and C? Correct. Isn't it? The property which decreases down the group.

[00:27:19]Electronegativity decreases. The stability of the -3 oxidation state decreases. Acidic nature of oxides decreases. The reducing character of hydrides increases. So the answer is A, B and C. Come on kids, let's move on to the next question.

[00:27:35]Next is 165.

[00:27:38]165 children, this is a question taken from halogen family or sorry you can say inert, this is a question taken from inert family.

[00:27:45]In NCERT, in the inert family of the p block, in group number 18, you will find written that the ionization enthalpy of molecular oxygen is almost identical with xenon. And some of its compounds will also be visible there. One experiment that will be seen is of a scientist and this statement is written there. So, this is a fact based thing.

[00:28:06]You will have to memorize this by heart that the ionization enthalpy of molecular oxygen is almost identical with what? With Zenon. Come on kids, let's move on to the next question.

[00:28:22]Next up is our question 166.

[00:28:26]Set of amphoteric oxides is amphoteric oxides which is? Isn't it? And it is written as a member of the carbon family. So carbon became CO. One is like this, CO2, SiO2, GO2, SnO2 and PBO2 and the dioxide which is formed is CO2, SiO2, GO2, SnO2 and PBO2, children, in this one all these three are acidic. All three are acidic and what are these two? It is amphoteric. Ok? It is amphoteric. And in this one, this one is your neutral. These two are your acidic and these two are your what's the bottom? It is amphoteric. Now I am asking you to tell me only amphoteric. So, this is not amphoteric, right? After that this is also not amphoteric, GEO2, after that SNO2, this is there but CO is not there. Come here SiO2 it is not. This is acidic. GEO2 is not even this. What will be the answer now?

[00:29:43]SNO2 and PbO2 Very simple. You should remember this, though. Isn't it? Come on kids, let's move on to the next question. The next question is our question number 169.

[00:29:57]In 169, children are saying that the correct order of electronegativity has to be told. Isn't it? So tell me the correct order of electronegativity in this. For example, carbon, sulphur and iodine have electronegativity of 2.5.

[00:30:17]of phosphorus and hydrogen is equal to 2.1. So look here, which one do you see more phosphorus in? If it is made of carbon then it is wrong. After that, phosphorus is visible more here also from whom? From carbon.

[00:30:32]This is also wrong. Here carbon is visible more than phosphorus. And then you have your statins and you have bromine.

[00:30:41]Bromine's derivatives are fluorine, chlorine, bromine, and iodine. So bro fluorine's electronegativity is kids four.

[00:30:51]Chlorine has three and bromine has 2.8 and iodine has 2.5 so bromine has the highest in it, so this will be the answer to it, bromine, carbon, statin and then there is phosphorus, this is the answer to it, now let us move on to the next question, next is our 1170, the number of lone pair of electrons on the central atom and shape of SF4 molecule is SF4, SF4 sulphur has six electrons in its valence shell, out of six electrons four electrons are consumed, one lone pair is left, so lone pair will be one, now what has happened to its hybridization, four bonds have been formed, it has four sigma bonds with fluorine and one lone pair, so four and one five, that is sp3d, sp3d bonds are trigonal, gonal, bipyramidal. Isn't it? Trigonal by pyramidal.

[00:31:54]But when a loan payer comes, you show it to the loan payer like this here. If you show the loan pair, then this remaining shape of yours can also be called inverted K.

[00:32:05]It is also called pie or its most famous name is bachche si. Isn't it? Sis. C is a swing like this which is kept in the school. Children swing on it like this. It comes down to this.

[00:32:20]It goes up. This is C. Isn't it? So there will be a oyster with a loan pair. This is the answer to it.

[00:32:30]Let's look at the next question. 177 A complex is given. This is very easy.

[00:32:40]Given a complex and asking which isomerism it will show? So kids, linkage isomerism occurs when there is a ligand whose linking atom changes.

[00:32:54]So the linking atom is not changing here.

[00:32:56]You have to check both of these. Like this given NH3 6 and this CR CN6, we have to consider this and then we have to consider this here CRNH36 and this CO CN6, is it okay? So what has happened in this is that the central metal ion has been exchanged.

[00:33:23]Ligands are also exchanged. The central metal ion is exchanged between two different complexes and this type of isomerism is called coordination isomerism. So this is coordination isomerism. I sincerely hope that all the children have answered this question correctly.

[00:33:37]Let's see, this is a very easy question.

[00:33:39]Let us now look at the next question.

[00:33:42]No next question, children. That was the only question. Your REET is about to happen.

[00:33:47]Your preparation must be going very well. This is what we hope.

[00:33:51]Keep studying with full concentration, enthusiasm and zeal and on 21st you have to show the same performance once again. You have to perform even better than that and secure a seat for yourself in NEET in a good manner.

[00:34:04]Okay kids? Thank you.