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This Log Equation Looks Impossible Until You See this Trick.
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234 views20likes10:45NonsoMathsOriginal Release: 2026-06-05

To solve logarithmic equations, apply logarithm laws (product rule: log A + log B = log(A×B), power rule: log(A^x) = x·log A) and use substitution to transform the equation into a simpler algebraic form; for example, the equation log₅(3^(2x)+6) = log₅(3^x) + 1 can be rewritten as 3^(2x) + 6 = 5·3^x, then solved by substituting D = 3^x to get D² - 5D + 6 = 0, yielding solutions x = 1 and x = log₃(2).

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