JEE(Advanced) 2026-ORGANIC CHEM(Part-1)🤯

Added: 2026-05-25

[00:00:01]Advancry inorganic information.

[00:00:29]for download.

[00:00:45]So considering LIBH4 reduces an estester group. LIB is 4K in lithium bon to the corresponding alcohol alcohol and does not reduce a caroxilic acid.

[00:01:13]The correct statement about the major product PQRS Mixed concept.

[00:01:41]Question number four.

[00:01:56]Fore and wet CH3 then CO2 acid group double bone that's C double bond O so C2 H5 LIH4 lithium plus B HC Yes, we can consider like a nucleophile.

[00:03:34]So then group alcohol simplech.

[00:03:58]Wait, sorry, sorry, sorry.

[00:04:06]C2 H5 So good living group.

[00:04:25]Okay.

[00:04:33]C double bond Oage C2 H5.

[00:04:45]Okay.

[00:04:47]H+ C2 H5 alcohol prodep mechanism like CO alihide M CO H. Okay. Then again, LIBH4.

[00:05:57]Okay. LiH4th aluminium hydide. LiH4 lithium aluminium hydide reducing ability.

[00:06:19]here. Okay. Then then H minus sorry leading group we have this Okay. And here C minus hydrogen H+ okay then we will get this thing advanced levelcept here. CH2 here like this. Okay.

[00:07:41]Acidic medium.

[00:07:43]Okay.

[00:08:02]acid H+.

[00:08:05]Okay. So, okay.

[00:08:37]Okay, then get this done.

[00:09:13]Then here like this. Still we have an hydrogen here. Okay. Then remove just take out the water and this water.

[00:09:40]Okay.

[00:09:43]Okay.

[00:09:51]like this.

[00:09:54]Here CH3 and here C double bond O here like this. Okay, this is the uhification RC.

[00:10:26]Then this thing is the product.

[00:10:44]BH.

[00:10:52]So reducing aluminium but we can use still use as reducing agent.

[00:11:24]Okay.

[00:11:27]Here CH3 and here dot dot dot C double bono O.

[00:11:35]Here is C.

[00:11:42]Okay.

[00:11:46]BHG.

[00:11:49]Okay.

[00:12:07]You will get something like this and C H2 like this C O2 and transfer H minus this thing can be written as something like this.

[00:13:08]hydrogen here. O BH2 like this. Okay. Then steel CO2.

[00:13:20]Okay. And again Yeah, here here. So, CH3 and here C H O B H2 here B H2.

[00:13:57]So, here CO2 E.

[00:14:02]So H.

[00:14:19]So in this situation uh BH2 by2 and you can have this thing CH3 here C H and here we C double bone.

[00:14:55]Okay. Then H+.

[00:15:03]Okay. Then group.

[00:15:09]Okay. This is the byproduct and linkage.

[00:15:19]You can have this thing here, here, here, C E H2 and C double bond O like this. Okay. So this is the correct.

[00:15:45]Okay. question.

[00:15:54]Mom image.

[00:16:22]So conclusion P N QR.

[00:16:41]Okay.

[00:16:46]Option A B C D Ident.

[00:17:09]This is the mechanism.

[00:17:30]Maybe CHG here.

[00:17:53]C O2 EN then LH4in LIBH4 CH3 here C Um H2 O CI you will get this kind of thing.

[00:18:45]C H2O C.

[00:18:57]Yes. This thing. Okay.

[00:19:02]Then final product.

[00:19:28]So you can have this thing here. CH3 here C H the sorry C double bond O O C C H2 like this. Okay.

[00:19:51]Okay.

[00:20:03]SR.

[00:20:08]Okay.

[00:20:22]That's the first problem. And the next one number eight, organic chemistry section.

[00:20:54]So in the following reaction sequence, statement.

[00:21:18]This is very uh interesting um chemical reaction.

[00:21:24]So here okay this is a kind of salty. Okay. Then reaction class 11 preparations of ketones.

[00:21:57]Okay, that's the first thing you have to know. And sorry you will get you can get this thing.

[00:22:16]This is sodium salt of that caroxilic.

[00:22:26]Okay.

[00:22:50]Hat electricity. Light to light.

[00:22:58]electric.

[00:23:09]So electrolyis.

[00:23:13]Okay.

[00:23:33]You have to take this.

[00:23:35]Okay.

[00:23:37]Then chemicals Quick reaction and two moles of this thing.

[00:24:11]radical.

[00:24:14]So chemical reactions.

[00:24:22]Okay.

[00:24:30]Okay.

[00:24:35]combines.

[00:24:39]It is the removal of CO2.

[00:24:41]Okay.

[00:24:45]CO2 and also plus this radical. Okay.

[00:25:04]1 2 3 4 5 6. Okay.

[00:25:09]Preparations of alkane reaction.

[00:25:25]V25.

[00:25:28]V2 V25.

[00:25:32]Okay. So, metal oxide venadium oxide 500° centigrade 500° centigrade and 10 to 20 polymerization like no cyclic formations of aromatization reaction 500° which is very high temperature break this thing.

[00:26:18]Okay.

[00:26:32]Okay. Then we can have a further reaction.

[00:26:40]Okay. Further reaction. Oh.

[00:26:45]Yes.

[00:26:57]hydrogen. Okay, then just break it with the radical.

[00:27:09]like this. Okay. Then also here and also here.

[00:27:41]This is called okay advanced Foreign Okay. Then in the presence of this CL like this. Okay. Then you can have this thing double bone.

[00:28:53]Cop minus like this. Okay.

[00:28:58]Yes. This is the electrofiling.

[00:29:00]Okay.

[00:29:07]Okay. Mechanism electrophilic substitution reaction and here. Okay. Then you can have this thing here. Here.

[00:29:33]Here.

[00:29:48]like this.

[00:29:50]Okay.

[00:29:52]Then we have here still some drink and aromatic nonaromatic.

[00:30:10]Okay.

[00:30:23]Okay. Then you can have this thing and your bone bone and here double bone double bone.

[00:30:42]Okay.

[00:30:45]This is the product R PCL5 potassium pentacloride.

[00:30:59]Okay. Potassium chloride.

[00:31:02]Yes. Nucleic substitution. It's a very easy one.

[00:31:09]Okay.

[00:31:22]PH here C O and Okay then. Here, here, here, then then here.

[00:31:41]Here, here.

[00:31:49]Then this thing.

[00:31:53]Okay. So, H2 with BD BO4. Okay.

[00:32:11]This is if you want reduction. Okay.

[00:32:20]Okay. acid derivative but it cannot reduce. It cannot reduce ketone.

[00:32:48]Acid chloride chloride.

[00:32:54]So reduction very easy.

[00:33:06]So you can have this thing here. PH here double bond O and here.

[00:33:22]Next reaction and Okay.

[00:33:49]product SH2 and also hydrogen NH2 NH2 come on reduction ations of basic then Okay. So, H2. Okay.

[00:34:45]Take out this thing and take out this thing also.

[00:34:54]Two moles of H2O. H2O. Sorry. Two moles of H2O.

[00:35:03]Okay.

[00:35:12]Sorry. Sorry.

[00:35:19]And here double bone. Here double bone.

[00:35:21]N you can have this thing.

[00:35:29]This is our Then equation and okay s on where is s where is s this one.

[00:36:16]Sorry.

[00:36:22]Yes.

[00:36:30]Wait. It's okay.

[00:36:38]Then S on then silver nitrate Agn so result in the formations of silver mirror. So the thing is silver mirror test silver mirror test.

[00:37:00]Sorry A for silver.

[00:37:17]Okay.

[00:37:21]This is correct.

[00:37:28]Then option B. Option B Q on treatment with chlorine excess then UV gate gives gamma. Okay.

[00:37:45]Yes. Benzene on react with benzene onreact with Cl2 excess.

[00:37:53]Okay.

[00:38:06]addition.

[00:38:10]Okay.

[00:38:18]You will get this thing many many CL here. Cl C Cl and CL. Okay. This thing is called gamma Zam6.

[00:38:38]So statement B option B.

[00:38:42]So next C option C. Come on. T is a heteroscyclic compound.

[00:38:55]Heteroscyclic compound cyclic compound like this. Okay.

[00:39:30]nitrogen. Here we have two nitrogen. So that's why this one is also heteroscyclic compound. This one is heteroscyclic compound. Very nice.

[00:39:40]Okay. Then another one option R on acid catalyze intramolecular uh cyization.

[00:39:58]What is R?

[00:40:17]alihide then.

[00:40:22]Um yes yes yes.in uh on treatment by zinc amalgam zinc amalgam with hydrochloric acid 9 dihydroxy and It's okay here. Here. Here. And what else? Here.

[00:41:05]Here.

[00:41:11]Then Z N Hg HC.

[00:41:23]Okay.

[00:41:24]Clemenson reduction reducing agent. So this is Clemen reduction. Okay. Clemenson reduction.

[00:41:35]Clemenson.

[00:41:42]11hide and chemical properties compoundshide.

[00:41:57]It can reduce alihide and ketones into Okay. So you can reduce this thing and you can reduce this thing that the product will be something like this.

[00:42:23]Okay then.

[00:42:38]So hydroxy group is wrong. Okay.

[00:42:48]A B C D