To solve exponential equations with fractional exponents, convert radicals to fractional exponents (√ becomes ^1/2), apply the quotient rule of indices (a^m / a^n = a^(m-n)), and when bases match, equate the exponents to find the solution. For example, in 5^x / √5^x = 25, this becomes 5^(x - x/2) = 5^2, simplifying to 5^(x/2) = 5^2, so x/2 = 2, giving x = 4.
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The Math Olympiad Question Anyone Can Solve (With This Trick!)Added:
touched the solution to this equation. I am going to show you every bit of a step I am taking to get my final answer. So the question reads as 5 to the^ of x or 5 / the roo<unk> of 5 all to the^ x is equal to 25.
Now to solve to solve this observe that this x or this bracket covers up this fraction which means that this x belongs to five and root of five.
But before we proceed there is something that we need to reduce which is the root of five because among this equation the complex form of a team is the root of five. So root of five need to reduce first before any other thing. So to reduce this we are going to introduce a lot of indices that will help us to to reduce this um sort.
Now look at this. If you have the square root of a this can be written as a to the^ of 1 / 2.
So this will help us to reduce this which means we shall have 5 / 5 to the^ of 1 / 2. This five has a natural power of 1 all to the power of x is equal to 25.
Now look at this. This is five and this is five.
Yes. Then if this is true, this five is dividing this five. Then let's recall a law of indices that will help us to solve this. And that law of indices state that if you have a to the power of b divide um dividing b or a to the power of c. This is the same thing as saying a to the power of b minus c because the same base is dividing.
So what am I trying to do? I'm trying to reduce this fraction which means we can express this as 5 to the^ of 1 - 1 / 2 to be equal to 25.
Most students cannot reduce this cannot solve this. Let me show you how to solve this fraction first.
Now we have 1 - 1 / 2.
You can call this over one for the sake of your LCM.
The LCM here is 2. 2 / 1 is 2 * 1 is 2.
You put a minus. 2 / 2 is 1 is 1. 1 * 1 is 1. So 2 - 1 is 1 / 2. So whenever you are you are subtracting a half from one you always have and half which is 1 / two. So of course this become 5 to the power of 1 / 2. Remember I supposed to cover this with all to the power of x which means this is all to the power of x to be equal to 25.
This fraction can multiply this x. We shall have 5 to the^ of x / 2 is equal to 25.
Now look at this. This 25 can be expressed in the base of five.
Then we shall have 5 to the^ x / 2 is = 5 ^ 2.
The same base we shall have x / 2 is = 2. For the sake of cross multiplication call this over one then you cross multiply.
This cross multiply x * 1 is x which is equal to 2 * 2 is 4. So our final answer is four.
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