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IMU-CET 2026 Chemistry Mock Test | 20 Questions | Day 7 | MNOPTA |Added:
In the channel. Like children, your mock test series of Chemistry is going on. By now you have completed day six and today is day seven. Let's start quickly.
See, the first question is if 4 gr. Of NaOH read the question carefully and tell the answer what will happen? A is 4 grams of NaOH. This is a base. What is? The base is the solution.
Its base molecular mass is given as 40. 4 grams of Na This is your acid. Ok? Are mix in a water and reserve solution will be.
What will be its solution? If you find out their number of moles. Look, let us assume that the concentration of both is the same. Ok?
However, you can also find out from the concentration.
But we are going by the values of both because nothing was said about concentration.
So let us assume that the concentration of both of us is the same. Let's look at the moles.
How many moles will it have? 44 / 40 Given mass upon molar mass. It will come exactly one mole. Ok? If we calculate it, it will be 14 / 36.5 i.e. its value will be 1 point something. Let's assume it will be 1.1. More will come from the forest.
Ok? It will come more than A1.
1.01 Anything can happen. It has one eye.
So looking at the number of moles, acidic acid is more. The number of moles will be higher for a slightly acid because its value is 36. If it has one then it will have a value greater than one.
So, what kind of solution will be yours? It will become acidic. Ok? Let me tell you one more thing. Here if you ever get this you can do molarity * volume = m1 * m2 okay? Ok? You can also check with molarity.
At present, molarity was not given in it.
Come on, see the next one. The Root Mean Square Value. This is your ah kinetic theory of gases question. The root mean square value of a gas molecule is given. I have given you the formula.
urms Root Mean Square Value of.
Ok? Just remember this. These Vrms, these urms is the root mean square value under root 3RT R. Which gas is here? T is. is the temperature in Kelvin and m is the molar mass. The same temperature. I have told you the temperature is the same.
And tell me whose RMS value will be the highest? Whose velocity is going to be the highest?
Ok? Ok? That means who will have the highest score in question number two? Look, this is the temperature constant, this is the T constant, this is the gas constant, m is the molar mass. That means the one with the highest molar mass will have the lowest VA value.
So see which one has the highest molar mass? If you want to tell more, then look at the lowest value because the one which has the lowest value will have the same high V or U RMS value. Do Mean Square Value. Ok? So look, if I talk about oxygen, the mass of oxygen is 32. Nitrogen has 14 for one, 28 for two, hydrogen has 2 and its mass is 44, so which one has the least mass?
Hydrogen has the least mass, then the value of v RMS or u RMS is inversely proportional to the molar mass, okay, under the root of the molar mass, the more it is, the less it is, the less it is, the more it is, so that means hydrogen is the answer, so what will be the second option, C option, okay, tell me quickly, what will be the answer to the third, this is the thermodynamics, at 100° Celsius the liquid water is equilibrium.
Look, I said equilibrium. Ok? It became an easy question. It is called equilibrium, which means that your water which is in liquid state is changing into solid state. Solid or gas? It is happening in the gas.
And this is in equilibrium. Both are in equilibrium. So what would be true in equilibrium? What? The value of Given's free energy in equilibrium is deltaG, meaning the value of Given's free energy will be greater than zero. That means it will be positive. Will it be less? It will be equal to zero or less than, meaning the value of entropy will be less than one. Look, there cannot be entropy because here the liquid is changing into gas, so the entropy is increasing. I had asked you the question yesterday itself when the state was changing. Coming from liquid to vapor. If randomness is increasing then the entropy value of s will be positive.
Ok? So you have to tell me what will be the value of delta g at equilibrium? So at equilibrium the value of delta g is zero. Ok? The value of deltag is zero. Ok? So you tell me in the comments when will this happen?
In which process is this delta greater than or less than, spontaneous or non- spontaneous, what value will it have in spontaneous, what value will it have in non-spontaneous, okay I need the answer to this.
Ok? Let's come to the next question.
Question number four Which of the following salt is produced on the basic solution when basic solution is dissolved in water? When you dissolve a basic solution in water, which of the salts? Well, which salt will give you a basic solution? After dissolving in which salt water will you dissolve them in water? Which salt will give you a basic solution if dissolved in water? Ok?
Again it is a question of ionic equilibrium.
Now the question is how was this salt formed?
For example, if we talk about NH4Cl, how is this salt formed? Let's talk about this first. Ok?
If I talk about NH4Cl, then NH4 is a salt, so it must be formed by the combination of acid and base.
So in this we might have taken acid, we might have taken base. This is okay?
So this is a strong acid. Strong acid is made up of strong acid and weak base. It is made from a weak base. Let's write it in short like this.
Talking about NaCl, NaCl is formed by combining Na OH plus HCl. That means both are strong acids or strong bases. When strong acid combines with strong base. So what is salt like? It is neutral. So this is a neutral salt. What kind of salt is this? This is from your strong acid. So it is acidic salt.
Ok? If we talk about this, what would yours be made of? This will be your NaOH which is your strong base and we added acid H2CO3 carbonic acid this is your weak base sorry weak acid okay it is going together with weak acid and strong base so this salt will be basic and this is again made of HCL and FeOH. That means the acid present in it is strong acid.
Strong acid has been used in this also. So what will be the solution to whatever your weak string base is made of? This will be your basic. So you have been asked about basics only, so basic is your C option. Ok? Let's come to the next question. Question number five.
Tell me the answer to the fifth question quickly. Which of the following pairs shows the positive deviation from the Draize law. Ok? What does Roy's Law say? Whatever partial vapor pressure is created is directly proportional to what? Mole Fraction K. Ok? The pressure of any component is directly related to its mole fraction. Now whoever follows Roy's Law. Ok?
They are called ideal solutions. Those who follow Roy's Law are called ideal solutions.
Ok? Whoever follows the law. Ok? Whoever follows the law is called the ideal solution. And what are examples of ideal solutions?
Whatever similars are like similar n hexane. Ok? N became hexane and N became heptane. Ok? n-hexane and n- heptane. Such examples are bromo benzene, chloro benzene.
How will this happen? Ideal solution. The second are your non-ideal solutions.
Those who do not follow the Royal Law. Non- ideal solution. Non-ideal solution. And there are two types of non-ideal solutions.
One is your positive deviation shower, the other is your negative deviation shower. Ok? Negative. So you have been asked in the question that which positive deviation will show?
Which one will show positive? Ok? So if we talk about positive, look at whatever is inorganic acid plus water. Ok?
How does acid plus water generally show you? Negative deviation. Which one is it? Negative deviation. This is also a negative deviation. Chloroflow Plus Acid. You have to remember that you have negative deviation.
Ethanol plus water. Ethanol plus water. Ok? So how does this happen? This shows your positive deviation. Positive deviation.
Acetic acid and water again negative deviation. Ok? So the answer you were asked about positive deviation is C. Ok? So your C is for fifth. Let's come to the next question.
Question number six. Ok?
From electrochemistry. Callus's law states that the infinite dilution molar conductivity of an electrode is a sum of. Ok?
Hello Yuvraj.
Let me tell you what will be your answer to six using the calculated molar conductivity of water. What does your molar mean, Koller ratio brought to infinity, that is, molar concentration of infinite dilution.
What does it mean?
Whose molar concentration of infinite dilution do you want to tell? If you want to tell of water, then we wrote H2O, what will it be equal to, molar concentration at infinite dilution of H positive ion plus molar concentration at infinite dilution of OH negative ion. So whenever we have to write coal stall, whatever ion it is, like if we talk about NaCl here, then there would be Na here, then there would be plus, then there would be Cl, so the separate molar conductivity of the separate ions is summed up to give the molar conductivity of the entire electrolyte, okay, so what value of molar conductivity at infinity have you been given for H positive, this 349.6, how much is yours? 198.6 If you add these two, you will get your answer. Ok? Let's add it quickly. 9.6 this is 198.6 okay? 2 1 8 10 of 1 14 of one four and 5 so this becomes 5 4 8 5 48.2 option number A.
Ok? So please revise the call once.
What was it? Well, I have already told you.
Infinite dilution is equivalent to any electrolyte. If you add all the ions of its constituent ions, you will get the total amount of the electrolyte. Ok? This is called Cold's Law. Next comes question number seven. For the first order reaction the integrated equation.
What will be the integrated equation? Look, it doesn't get any plus. Ok? Which one should you eliminate? A log t no t does not come here. t will come down to you.
Ok? So these two will not be there. These two will not happen. Now look here it is written k = 1 / t so what happens for any first order k = 1 / t here it is written ln.
ln means natural log, you can write it like this 2.303, okay? log base 10 gives you your initial concentration and your final concentration, the remaining concentration, over the t time frame. Ok? So what will be your answer? This will happen. Ok? Up comes the knot. Below comes t. Here t is not given. Ok? So option number will be A.
A of Seventh. Let me tell you about question number eight.
Again this is your question from solid state. You already know in classes what is the difference between Frenkel defect and Scotted defect? Ok? Your question here is Frankel defect is not found in NaCl. Why is there no Frenkel defect in NaCl? NaCl: If we talk about NaCl, then let me first tell you that in NaCl you get to see Scott defect.
Scott defect is visible. Ok? Scott defect is visible. In which? In NaCl.
What happens in Scotty defect? Ah, as much as the cation and anion, that is, the positive and negative wire, both disappear from their place.
Therefore, because of the density of the scattered defect, the density of the overall crystal decreases.
Ok? Because the size of both of them is different. Now the meaning is similar to scouting defect.
Why doesn't it happen now? Because what is the size of Na, Cl and Cl? It is similar. It is a similar size.
So Na cannot fit in the interstitial space. What happens in faecal impaction? Whatever interstitial space is there in Finkel defect, the cation comes and enters in the space that is left in the middle.
Ok? The cation starts from one place, say here, and comes to the interstitial space in between.
Ok? But this cannot happen with NaCl because both are similar in size.
So for this reason, Schotted defect is seen in NaCl and not Frenkel defect.
Ok? There is no density change in a Frenkel defect. The density remains the same.
Density decreases in scattering defects.
Ok? Your answer to question number eth is B. Let's come to question number nine.
Ninth is your question, please tell me which question is it? If you are talking about ninth then write ninth and tell me. The Hybridization of Central Atoms SF6 What will be the hybridization of SF6? If you look at sulfur, there are 1 2 3 4 5 6 six in sulfur.
And fluorine is connected in all these places.
Fluorine is attached to it. That means no loan payer is left. How many sigma 1 2 3 6 sigma so for six sigma the hybridization is sp3d2 sp3d2 if I talk about its geometry then the geometry is octahedral okay the geometry is octahedral so which one is sp3d2 option number C of ninth is C okay Rahul Gupta Rahul which one are you telling tell me by writing question number B which one are you telling let's tell me of 10th quickly bleaching powder is a mixture of this is a simple question bleaching powder is a mixture of what? of sodium calcium hypochlorite and CaCl2. Ok? This is C of 10th. There is no need for any explanation in this. Whose mixture is it? that'll be. Let's talk about 11th.
Which of the following is the correct configuration of Chrome Chromium Z2? Let me tell you about this. Tell me which one will be for 11th? Yes, yours. The answer for ninth is C.
You told the answer for ninth as C. Ninth of C. Yes, that's right. Let me tell you about 11th. Which of the following is a correct configuration of CR? What will be its correct in configuration? Look at the 11th one, which of the following is chromium, I have already given you the atomic number of chromium, although it is 24. So it has the configuration 1s2 2s2 2p6 3s2 ah 3p6. So till here it is complete. Even the organ has been used.
See the story after this. How many are left after this? Till now 18 electrons have been completed. After that comes your 4s. Ok? And then comes 3d. Now the question is how to fill it here? So here the electronic configuration is one and in 3d it is five here. Because what will happen with this?
This also makes D half-fielded.
Should this also have been halved? This should have happened. Should have been 4s2. 3d three should have been 3d 4.
Ok? This should have happened but it did not happen. This is the one. Ok?
What is an exception? Because here because of this it also became half field. And because of this it also went to half the field. So half field has more stability as compared to this. Rahul B of 11th, okay, absolutely correct, so which one will be 3d5, it will be 4sg, absolutely correct Rahul, next tell me in which of the complexes of 12th, in this complex you have to tell what is the oxidation state of iron, it is a coordination compound, tell me quickly, it is an easy question, tell me quickly, what will be the answer of 12th, you have to find out the oxidation state of iron, you have to x-let iron, what is the cn of cyanide, how many are oxidation-1, six, these six will be written below, okay and what is the equation-3 above, okay? So how much will you get when you subtract x? Your x will be +3, that is, what is its oxidation state? What will be +3? It will be +3. That is, let me tell you a question from here. All you have to do is write its IUK name and tell it. Iupak Name You have to tell the Iupak name of this compound in the comment. Ok? It's easy. First you have to write the name of the league. Ok?
Before that you have to write this. How many are there in Legrand? It's six. So, we have to write hexa. Then the name of the leader has to be written. Then you have to write iron. Ok? This is negative. So what will come here?
Will iron come or ferret? Ok?
You have to see that. So whatever answer you have, you have to post it in the comments. Ok? So what did we tell you? A of 12th is correct. Let's come to 13.
13 of Which of the following is Earth Alkaline Metal? Earth alkaline metal does not form stable bicarbonate in solid state. Look, you must have seen everyone's bicarbonate.
Meaning of bicarbonate is calcium HOCO3. For example, let's talk about magnesium. Whole Twice of HCO3. Like this here whole twice. Ok?
Ok? If everyone has two in such a stadium then it will be the same.
But the question is which one is not stable in the solid state? It is not stable in solid state.
Which will not be stable in solid state? The one which has more charge, higher charge density, is not stable. So if we talk about the smallest size, then magnesium comes first. Ok? This also happens to bring up your beryllium. Then comes beryllium and magnesium. Ok? Then calcium works like this. So your magnesium carbonate is not stable in the solid state.
Due to the charge density. Because its charge density is very high. The size is small, the charge is high, so due to high charge density it does not exist in solid state.
Hexaneto ferrate third ion will not be cyanido cyanato. It will be cyanide.
Ok? and ferrate third ion. That's ok.
Excellent. 14 I told you about 13. D turned 13. Look at 14.
Which of the following has the maximum number of bond angles?
Which has greater bond angle? If we look at hybridization, it is sp3, which one will it be? In this you will have to check how many are left. It has sp3. Ok?
And let's check this also. If we look at it, then sulphur has 1 2 3 4 on one side hydrogen on the other side hydrogen. This is done for you. Ok? So here it becomes 1 2 3 4 sp3. Ok? It also has sp3 hybridisation. Now the question is which one will have the maximum bond angle? Ok? The angle in sp3 hybridisation is 119.5. Ok?
If there is no loan payer then if there is no loan payer.
But just like there is lone pair in water, similarly there is same lone pair hybridization in this also. There is only one loan pair in it. Ok? Now we will have to look into it. The phosphorus in this, how many phosphorus are there in total 1 2 3 4? See.
1 2 3 4 5 6 There are six here too. Ok? So two of the three have your chlorine attached and one lone pair. Three chlorines and one lone pair will be visible in it. So if we look at it, its angle becomes 107 due to the bond having only one lone pair.
Ok? This becomes your 10 because it is a loan pair, so due to 104.5 repulsion the VS pair also reduces in this and its near about becomes 100. Ok? Its near about stomach is also less.
Ok? Near about is like this. So who will tell us the most? It will be of ammonia. of NH3. Ok? Because either A or C in NH3. Good sir.
C of 14. Ok? So what about ammonia? And if there was methane here, do we know how much methane there is? It is 119.5°.
Ok? Let's come to question 15. The Increasing Order of the Stability of Carbocations. The order of stability of carbocations is simple. The most stable carbocation is 3°. Then it becomes 2°. Then it becomes 1°. Then you have methyl carbohydrazine. Then you have methyl carbohydrazine. Methyl carbocation.
You have to remember this order. Like As It Is to remember. The most stable is 3° and the least stable is methyl carbonate.
Ok? This is your Carboton.
Same your free radicals. What will happen to the free radicals? and carboanions. The same thing happens with free radicals.
3°, 2°, 1° and last comes methyl carbocation. Methyl free radical. Methyl free radical.
Ok? So you have to see which is 3°?
asked the most stable. What is stability? Increasing order will be lowest to your methyl one. Ok? The methyl one has the least. Methyl, primary, secondary and tertiary. Ok? This A option will be of Rs 15.
This increasing order was asked, this is the least stable. This is more than that, this is more than that. You can tell its stability by +i effect or by hiber conjugation.
By hiber conjugation or by plus i effect.
Ok? He is 15 years old, that's absolutely right Rahul.
Tell me about 16. A phenol reacts with a bromine. It has to be reacted with bromine water.
Ok? With bromine water. Look, you tell me here. Let me tell you one more thing.
Here if you have phenol.
You are reacting phenol with bromine. Ok? Ok?
With bromine water. With bromine water. So in this case the Br that gets added gets added to all the positions. Ok? OH will come here, that means it will be ortho para and ortho. Ok? It will connect everywhere. That means if you write its name then it will be 2 3 4 5 6 i.e. 2 4 6 tri bromo tribromophenol.
Now one more thing to keep in mind is that if your beans are giving this phenol only.
But in this case, instead of giving you water with Br2, you were given CH2. If carbon disulphide is given inorganic then two will be formed in this case. A case of major and minor will be made. That means on one side this will be your Br which will be the major product and the second case will be yours. That means Br will join with OH here. This will become your minor case. Ok? So keep in mind the question is given CH2, so this will become major minor. If water was given then all three will join. So in this case we were given water.
Ok?
+i effect. So let's tell you in the next class.
What is your +i effect? A, see which one will be yours? 2 4 3 / Bromoethane. Ok? The +i effect is called inductive effect. Let me tell you at last. Look, this had your yes inductive effect. Like you have a carbon chain here. This is a carbon chain.
Ok? You have placed a group here and what is this group doing to the electron, it is pushing it towards this side.
Ok? He is pushing towards this side.
Due to which it will have a negative charge. Positive charge will come on this and negative charge will come on this in this chain. So this polarization starts inside the chain.
The polarization in the carbon chain is due to the electron donating group and the electron withdrawing group. Ok?
This is called inductive effect. If the group placed here is donating the electron, a donating group is placed, then this will be your +i. And if within this carbon chain, you have placed a group which is pulling the electron by withdrawing it, then due to this, it will become negative and the entire chain will start getting positive charge, delta positive, delta positive, so we will call this -i effect, okay, so that means polarization starts within any carbon chain, okay, next tell me what will happen to your 17, the reaction of an acetaldehyde in excess methyl in the presence of dry SC, so what is formed, hemi acetal acetal methyl acetate, and when formaldehyde reacts with methanol, what happens to formaldehyde? Yours is formaldehyde acetaldehyde sorry okay this will be your CH3 CHO it has to be reacted with methanol CH3OH okay if you react with this then what will be formed yours will be acetal what will be formed yours 1 2 diethoxyethane is formed okay acetal is formed okay 17 is done with you B next comes 18 The order of reactivity of halides in SN2 nucleophilic substitution of order two what is the matter I don't know which will react the fastest SN2 reaction now see your alkyl halides are given in all of them.
Like you have given it, CH3 I have given it. Then you have given CH3, let's write it like this. Br CH3 is written in the same way.
Chlorine comes up first. Then comes chlorine. Then you will remember bromine properly. And then comes iodine. Ok? Who will break this soon? SN2 reaction.
Ok? What happens to you in SN2? The stung nucleophile will attack from the back side and the one in front will go away.
So who will be able to break the bond sooner?
Will its bond break sooner or will its bond break sooner? Due to its large size, its bond energy is low.
Its bonds break easily. It does not break because its size is small. So what is the reactivity that is happening when it comes from top to bottom? It is increasing. Reactivity is increasing. That means it will show the earliest and it will show the least. So what will be the order? Start with I and end with F. I Br Cl. Ok? So this will be your B option. B of 18. Next comes the linkage between amino acids in the protein, this is an easy question, it is a question of biomolecule [sound of deep breathing] and brother, how do we see alpha carbon and beta carbon in any carbon chain, alpha carbon beta carbon, see if there is a carbon chain here, any functional group is attached to the carbon chain here, any functional group is attached here, okay, any one is attached, you can add OH, any one. The carbon attached to it is alpha carbon.
Its equivalent is beta carbon. The next one is delta carbon.
Ok? Ok? So alpha beta, gamma like I wrote here CH3 CH2 CH2Br okay? Let me put Br here. I changed the question a little bit. Ok? So if we place it here like this, then in this case, which carbon is this? It is connected to this. So this would be the alpha carbon. This will have beta carbon on this side. There will be beta carbon on this side also. So the carbon to which the functional group is attached is alpha. Its equal beta. Ok? Like here, someone is so connected here. So this will be alpha. Then this beta, then this delta. Ok? I hope you have understood this.
So tell me quickly. The linkage between the two amino acids in the protein. What is the name of the linkage between amino acids in a protein?
We call it a peptide bond. Peptide linkage. It is not called bond, it is called peptide linkage.
That is CONH linkage.
What is a peptide linkage? CONH linkage is called peptide linkage which joins amino acids to form peptide.
Peptide after polypeptide.
Protein is formed after polypeptide.
Which of yours has glycocytic linkage? The linkage with O is glycocytic linkage. This is found in carbohydrates.
In carbohydrates. Ok? Carbohydrates like you have glucose, glucose will have a glycoside linkage. Ok? Your sucrose will be formed by the formation of glycosidic linkage between glucose and fructose.
Which will have phosphoty ester linkage? And hydrogen bonding, you know, in what?
Phosphoty ester linkages are found within the nucleic acids in your DNA. Ok? DNA is done, RNA is done. It contains phosphotyrosine ester linkage.
Hydrogen bonding, so wherever you find hydrogen and the most electronegative element, that's your hydrogen bonding. Ok? So your C option becomes 19. Ok? Correct.
Tell me next. Next 20 Which of the following is an example of non-ionic detergent? This is Chemistry in Everyday Life. You should remember this because there are only a few examples of non-ionic detergents. That is your span and that twin. Ok? Or you can say poly diethylene glycol ester. These are what we can call non-ionic. It does not have an ion part. Generally, detergents are those that contain long chains of fatty acids with any ionic part. Ok? There is soap and detergent. But it does not contain any ionic part. Ok? So these were today's 20 questions. I hope you understand. If you have any doubt, please do so in the comments and answer the questions asked to you in the comments. Ok? Okay, thank you.
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