ORGANIC CHEMISTRY best questions / guaranteed for RE-NEET/ check your revision

Added: 2026-05-15

[00:00:01]Hey all my dear students, welcome once again to HSV and world of chemistry. Now I'm here to give you two mind map road map such type of questions which you can say top to choice and these people were giving answer just in 15 seconds but for you people you are being beginner I'm taking you as beginner because for reit beginner so time limit is 1 minute let me tell you which type of students you see tanish kayad AIR1 715 marks me a third rank Chatanya Mittal a fourth rank shar need fifth rank 715 marks so let's see how is your preparation for reit because in reit of 2026 questions will be moderate to tough side so let's check it out this is your question in front of you my dear students You can see now once you take the screenshot of it or pause the video do it take your copy do it check yourself now I'm going to provide the answer of this you have to find out what is being said so let's see methane on doing the chlorination what will you get just find it out methane on doing chlorination what you will kits. Check it out yourself.

[00:01:38]Methane on chlorination. What you people are going to get? Do let me know.

[00:01:45]So I hope you have got it. This will be your methile chloride and we call it FRSR free radical substitution reaction. So methile chloride is the answer. And what do you call it? This is known as free radical substitution reaction. Sodium dry ether woods reaction.

[00:02:12]What will be the product? Definitely doubling of this. So ethane will be the answer.

[00:02:20]Now once again FRSR ethile chloride.

[00:02:26]Now, KOH aquis nucleophilic substitution reaction NSR.

[00:02:33]So, you will get ethile alcohol as the answer.

[00:02:40]Now, ethile alcohol on reaction with concentrated H2O acidic dehydration ethine will be the answer.

[00:02:52]Br2 E A R electrofphilic addition reaction anti-addition.

[00:02:59]So, CH2B Br2 Britine bromide. Still electricity is not there.

[00:03:10]Sweat too much sweat. Okay. But I have promised you to help you out throughout the process. This Baba is saying who was fighting for the transparency and justice against NTA.

[00:03:23]Now, NaNH2. And now let's see Na2. 1 mole of NaNH2. Na will take bromine and NH2 negative will take propton. Just see this will snatch bromide and that will snatch H positive. So it will be venile bromide CH2 double bond CHBR 1 N2 has gone dehydrohalogenation.

[00:03:50]Now once again Na+ will take away this bromide and NH2 negative will take away this proton you will get acetylene 2 Na and H2 got consumed previous question people were asking how four moles so see one Na will snatch this proton Na can't snatch this proton so NH2 negative will snatch this proton so what will happen n2 H2 negative will become ammonia and this there will be Na once again NH2 will snatch that proton.

[00:04:27]So this is di sodium acetylide. Remember that this is being diodium acetylide. Till now I think it's clear now methile chloride access. So both the side methile chloride NCL will eliminate out and you will get CH3 C triple bond CH3 but 2ine. Now, Lindelar's catalyst will do dehydrohalogenation or what? Dehydrohalogenation or partial hydrogenation.

[00:05:00]Partial hydrogenation. So you'll get cis but 2 in cis but 2 in on reaction with Br2 anti- addition anti-a c a rmmic mixture you will get resmic mixture CH3 CHB R CHB R CH3 remic and its mirror image age. Now dehydrohalogenation anti-elimination anti-elimination of resmic. So once again you will get cis alken cis butine oonolysis. So while doing oonolysis break this bond and put oxygen on both the side. So you'll get two moles of acetihide CH3 CHO. Is it clear now? So strong oxidizing agent you will get CH3 CO. Now soda lime reaction you will get methane CH4.

[00:06:13]So here you will get CH3 CO Na once NaOH acid base neutralization and this is your decarboxilation that is soda lime reaction or lab method preparation of alkan. So you'll get methane over here. Now Cl2 once again FR SR you will get methile chloride. Now this is Fredal craft alkalation.

[00:06:40]Fredalcraft alkalation. So you will get toine.

[00:06:44]Now once you got tolene this is side chain oxidation you will get benzoic acid.

[00:06:51]You got benzoic acid. PCL5 you will get benzoil chloride. C6 H5 CO benzoil chloride. Now Rosen Mund reaction this is your roen mund reaction. So you'll get a benzaldihide C6 H5 CHO and that reduction C6 H5 CH2O.

[00:07:16]Now PCC mild oxidizing agent you will get benzaldihide.

[00:07:25]Now HCN benzelihide syinohydrine and then mandelic acid mandelic acid C h because cyanide will attack from above the plane below the plane so you'll get eumar mixture of remic mixture optically inactive so its name is mandel you know father of genetics mandelic acid Mandelic acid in place of benzaldihide. If it would have been acetalihide then you would have got lactic acid. So if you want to take a screenshot of it you can take and if you're not able to do this question remember that your revision is still lagging. You need more revision right now. Once this is done, second question. This is okay. The same one. Now here is the toppers.

[00:08:28]Second question. Now see once again you are supposed to find out zed. See to the question whatever you want to take a screenshot or whatever or pause the video you can do that. Now I'm going to explain it. What is zed? Okay your answer is right or wrong. Okay, let's see. Don't worry, in the starting you will take time. You will require time.

[00:08:54]Everyone won't be able to do in the starting but slowly slowly slowly slowly you people will be able to definitely do it. Now see now this is your benzene nitration. This is known as nitrating mixture. Remember that nitrating mixture both together will produce NO2+ known as nitronomium. Remember that nitro neium ion. Now you will get nitroenzene.

[00:09:30]Nitroenzene on reduction you will get analene. Analene on dotization you will get benzene daonium chloride. Then send me reaction you will get chlorobenzene.

[00:09:45]I hope up to here it's clear. Once again nitroenzene reduction analene dotization ice cold solution 0 to 5° C benzene daonium chloride sendmir reaction will give you very good yield of the product send mere chlorobenzene. Now methile chloride woods fittig reaction this is known as woods fetig reaction it's not wood kalipi it's woodfig so you'll get tolene tolene now tolene is doing what this cr2 is chrom chloride chrom chloride itard reaction so it is your itard reaction you will get benzelihide it.

[00:10:37]Now, benzaldihide nothing is written over here. I think one step is missing.

[00:10:41]So, you can take it to be like this.

[00:10:45]This is benzile alcohol.

[00:10:50]PCC is being more mild oxidizing agent benzihide.

[00:10:59]This is grigard reagent. So, you will get compound like this.

[00:11:06]C H CH3 now concentrated H2SO4 so you will get compound this is known as styrene what is this compound styrene styrene styrene now Br2 CL4 anti-addition CH Br2 Br. Now once again NH2 equivalents. So two equivalents dehydrohalogenation you will get compound like this. Now this is known as OMDM of alkine. So maroonops rule how to do that just see negative part of the reagent will go to that double bonded carbon which is having less number of hydrogen. So directly I'm writing the product otherwise first enol will form that will undergo torization but I'm writing this compound directly. You see trick baba HSP trick your answer is ac is acettophenolon acettophenono test. So yellow PPA is CHI3 and this is your sodium benzoate. Sodium benzoate and sodium benzoate on soda lime reaction will give you benzene my dear friends. Now benzene on this g oonolysis reductive oonolysis three moles of glyioxil you will get.

[00:12:49]Now three moles of glyioxil its name is glyoxil.

[00:12:55]Now reduction so glycol you will get ethyline glycol which is added to radiators in cold countries glycol.

[00:13:06]Now in glycol this is this step is very very dangerous. Pinnacle Pinolone rearrangement pinnacle pinacolone rearrangement will take place and this is your acetal deihide remember that this is your acetal dehide till now I hope it's clear now from here my dear students zinc amalgam clemensense reduction you should know clemenson's reduction so you will get ethane now my dear students once again FR R SR ethile chloride KO alcoholic E2 dehydrohalogenation ethine.

[00:13:50]Now this ethine my dear friends this ethine HBr R22 but this is symmetrical no marco neither marco nor antimarco so you will get CH3 CH2 Br now benzene and added fridal craft alkalation ethilebenzene and ethilebenzin on side chain oxidation benzoic acid now benzoic acid with Haxis and calcium soda line reaction your answer is benzene. So zed is being benzene. Now it's time for your homework. Take the screenshot if you want to have. Now this is your homework. It's three questions you have to write down the answer in the comment section. And if you're really enjoying these mind maps first you can take the screenshot of it very very dangerous question and I would like to say whatever you will think they will not be the answer. So moderate to tough question I will rate moderate to tough this time they will ask in need 2026 that is read neat rene 2026. Now if you're really enjoying these mind maps even if you're not enjoying because if your homework is not proper you can't enjoy. So do proper homework and then do these questions. Once if these mind maps, these sequence type questions are looking easy then only think that your study is in progress. You are going to achieve 180 on 180 otherwise selection even selection will be in danger. Your medical seat, government seat will be in danger. Now it's top choice and I will say that was the topest choice at that time but it is the requirement for each and everyone. So do it. All the best.

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