When objects fall from the same height, they reach the same velocity, so momentum (mass × velocity) is directly proportional to mass; a 25-unit mass will have 25 times the momentum of a 1-unit mass, causing it to compress a spring 25 times more than the lighter mass.
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Uh, so my thinking was to ask the guy to let both masses fall from the same height uh uh onto the spring. Same velocity, so no contention over karate chop. What's this What's this doesn't even make any sense.
You're arguing from the same height then they're not doing the same mass, so that's so let both masses fall from the same height.
Yeah, well we're going to know what the velocity is, all right? Then you're going to have uh velocity different, that's going to be 1 to 5. So, what's the point?
Uh, now in that case we could say we have one unit of energy for one unit of mass and 25 units of energy for 25 mass.
Uh So, you're saying you're going to drop a one mass and a 25 mass?
I don't think that was the experiment.
No, it was 1 to 5 is that enough.
Um, we can predict how much more the spring will compress for 25 x the energy.
So, yeah, that's why you can't do the experiment because there's not going to be a spring that's going to be sensitive enough to do one and durable enough to do the other. That's too big a range.
You can't measure on the same scale 25 lb and 25 oz.
It's just not likely.
Uh, but this would also be a 1 to 25 ratio for momentum also and draft sign only deals in momentum. I wondered what you guys think his prediction would be in terms of a compression of the spring.
Well, obviously if it's 25 times the mass and it's the same velocity, yes, it's 25 times the momentum.
So, my prediction is is that yes, 25 lb on a scale will release go really far and 1 lb on a scale won't go very far at all.
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