At standard temperature and pressure (STP), one mole of any gas occupies 22.4 liters, and one mole contains exactly 6.022 × 10^23 particles (Avogadro's number). This fundamental relationship allows chemists to convert between mass, volume, and number of particles in chemical calculations. For example, 16g of O2 (0.5 moles) contains 3.011 × 10^23 molecules, while 4.4g of CO2 (0.1 moles) contains 6.022 × 10^22 molecules. The instructor demonstrates this through multiple practice problems involving gases, atoms, and molecules.
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Sir Jotin Live StreamAdded:
Okay.
Uh, okay.
0.05 question number.
Number of sodium.
Number of sodium.
Number of moles. Number of Number of 05 0.1 0.1 0.1 option number three. Question number 44.
Option number three 0.1 option.
Next one, two, three.
Question number question.
online question by one chemistry. Question number.
Which among the following occupies the maximum volume max2 number of moles 22.4 L number of moles 16.4 mass mass 32 oxygen 16 into 242.4 Number one max 0 to 5 into 22.4 L 22.4 number of given 0.2 2 into 103 given number 6.02 into 103 exactly 22.4 0.5 number of 0.5.
Last option volume 22.4 L 22.4 L option.
Option question number 45.
45 22.4 L2.
Yes. Yes. Yes. Correct. Thank you.
Thank you.
Okay. Max 22.4.
Okay.
Very good.
energy. Swing.
If na is the number then the number of oxygen atoms in one equivalent of oxygen number of oxygen atoms in one equivalent of oxygen oxygen equivalent mass of oxygen Oxygen. Oxygen. Oxygen.
Avocados number 32.
Uh, equivalent weight.
Foremost oxygen.
equivalent.
One equivalent weight of oxygen.
One equivalent equivalent.
Four equivalent 16 number one oxygen number one by add 1 by 8 n 1 by 8 n 1 by 8 n option 1 by 8 n 1 by 8 to do 0.1 2.1 0.1.
Okay.
Oxygen.
O2 load.
Uh number of atoms uh number of atoms the atomicity into number into number of moles.
Number of moles.
Number of moles.
Number of moles.
Number of moles.
Number of moles.
Given mass by mass oxygen given mass by mar mass given mass by mass by option two.
Option two.
Uh 1 g equivalent oxygen 1 equivalent number of moles number Question number 47.
If maticity at 273 and 180 pressure is 1 g. Find the mass of one atom.
If the mass of 224 ml of triatomic gas at 273 kelvin and 1 atm pressure is 1 g. Then find the mass of one atom high pressure.
temperature.
Volume 22.4 one.
Find a mass of one at My given condition atom Atomicity.
Uh, atomicity.
Question number 47.
Atoms. Number of atoms.
Number of atoms.
6.02 Num 2 4 - 10 - 3 L divided by 22.4 Number of atoms.
Number of atoms.
Uh 1.8 06 into 10 power 22 1.86 into 10 power 22 1.806 into 10 power 22 atom 1 by 1.806 806 into 102 1 / 1.806 5.54 5.54 into 10 power - 23 One right question.
1 2 3. Okay.
Question number 40.
Question number 48.
The race mass of an electron is 9.11 into 10^ - 31 kg mass of the electron the mass of an electron is 9.11 into 10^ -31 kg. Then mass of the electron is number 9.11 into 10us 31 mass of electron mass of electron. One electron.
One electron has mass of 9.11 into 10us 31 kg.
Number one number one.
Helium number 14 electron 14 number 6.023 2 into 103 9.11 into 10us 31 kg into 6.02 2 into 103 5.5 into 10^ - 7 to Yeah, you go.
5.5 to 10 - 7.
I should go. that.
Mhm.
Download.
Download. Download.ch.
Question number 49.
Morning.
Evening.
Okay. If a sample of ammonium phosphate contain 3.1 mole of hydrogen atom 49 49 Okay.
Question number Question number 439.
Question number 43.
Same way.
Question number 43.
I know.
She talk. She had 43 years old.
I 43 years old.
I 43.
43 years.
How many total number of atoms are present in 2.5.0 Number of atoms. Number 16.
27 number of 270 number of moles number of moles 25 - 3 gid mass mass of camper carbon 12 into 6 into hydrogen 1 into 16 oxygen 16 120 120 32 2 152 152 152 g per mole.
Okay.
27 26 23 6 into 10^ 21. Option number four.
This is not fair. Yes. Yes. Yes. Yes.
This is not fair. Of course. Of course.
Of course.
How many total number of atoms are present in 64 g of SO2?
Number of atoms.
How many number of atoms are oxygen number 64 given mass 64 mass 64 oxygen 16 into 22 64 3 into number 6.02 into 103.
Option number four question.
Find the total number of protons, electrons and neutrons present in 12 g of carbon.
Number of atoms in the formula.
Number of protons in the formula.
Number of electrons in the formula.
Number of neutrons in the formula.
Missing missing.
Same for number of electronic number.
Atomic mass number. Sorry.
Total number.
Okay.
There are four total numbers total numbers numbers equal to Number of number of moles 6.02 Uh 103 1.0 I option number one, two, three.
Hat.
Number of very good. Very good.
Number of calcium ion, chlorideion.
calcium 40 chlorine 35.5 35.5 into 21 71 71 Very good. The number of calcium plus numbers of chloride Number two screens capsul.
Capsula.
Uh question number 50 almost. We are very close.
34.2 gram of glucose are dissolved in 90 gram of water in a glass. How many oxygen atoms are present in the solution?
34.2 g of sucros are dissolved in 90 g of water solution.
How many oxygen atoms are present in the solution?
Okay.
34.2 oxygen atoms nuc 22 0 11 number of moles 34.2 mass 1 oxygen atoms in water.
Number of moles 90.5 nothing 90 / 18 pipe pipe Total oxygen oxygen 1.1 NA plus 5 NA 6.1 NA 6.123 option number three option number 3.66 66 into 10 power 24.
Option numbers 1 2 3.
Uh find the number of moles of water.
Find the number of moles of water present in 488 g of berium chloride.
Number of moles of water.
Okay.
Find the number of moles of water.
Number of moles of water in 48 g of berium chloride.
137.5 chloride moles of water.
for 137 35.5 into 2 71 18 into 2 16 7 14 10 13 14 244 g of berium chloride.
moles of water I divided by 244 into 4 Four.
Four moles of water. Option number 55.
56 56 4.4 g of carbon dioxide and 2.24 liter of H2 and STP are mixed in a container.
Ah okay.
Total number of molecules present in the container.
Carbon dioxide 4.4 H2.24. four.
Total Total Given mass given mass 4.4 mass carbon dioxide given volume 2.24 L 22.4 0.2.
Therefore, number of moles 6.02 02 into 10 23 number of moles number of moles 0.2 1.2 2 into 10^ 23 option number two.
Question number three question left.
Unlimited question.
Which of the following is the lightest?
less mass.
H24 number two.
given 6.023 into 10^ 22 22 6.02 2 into 103 given mass by mass 2.5 Number one mole of oxygen gasal.1 oxygen 16 into 232 0.4.2.1 0.17 sorry number 1 2 3 one Okay.
2 g of oxygen that contain number of atoms equal to Oxygen number of oxygen at oxygen contain number of atoms equal problems.
Oxygen oxygen gy means 1 by 1 by 8 1 by 8 atoms atomicity into oxygen atoms.
Number of moles option.
Option one.
Given mass 14 number of nitrogenity nitrogen Number mass mass nitrogen mass 14 N of sodium Na g of sodium sodium element 23 4 by 23 NA oxygen None of this option.
Option number.
Option number two.
Sorry, sorry, sorry.
Option number two.
Option number two. Option number two.
/ option number two of okay problem like who is only just two question lab gentlemen doctor Doctor, doctor, doctor, doctor, doctor, doctor, doctor.
10 g of each O2, N2 and Cl2 are given in three bottles. The correct order of arrangement of bottles containing decreasing number of molecules.
Number of number of molecules. Number of number of molecules.
number of moles. The number of moles number of moles 10 NA / 16 number sorry 16 into 32 N2 given 102 nitrogen 14 into 202 chlorinch.
N22 CL2 decreasing 59 59. Option four. 1 2 3.
Incorrect statement 14 g of carbon monoxide 14 g of carbon monoxide 2.2 22.4 L of moles number of moles 14 oxygen 16.
Sorry, sorry. 20 11 11 14 by 2 mean 0.5 in 11.2.2 Option number one 59 60 option number one.
Last last of the last of the last of the last. Which among the given gases contain equal number of molecules as that of 16 g of O2? 16 g of O2. Equal number.
The number of moles. 16 oxygen.
Which of the among given gases contain equal number of equal number of molecule as that of oxygen? for Okay.
16 by 32 Na by 2 by2 oxygen 32 32 64 1 by 22 option number two option number two. Thank God number two.
Thank you question.
Uh question number 37 37.
Question.
Question number 37.
37 33.
33. 37.
37 37 37 37 Uhoh.
37th 37th one at 1.8US 22 at my 1.8 into 10 - 22 into number 6.023 2 into 10 23 1.8 Add into 10 power minus uh 22 divided by huh divided by 1 into 6.02 02 into 10 power 23.
Congratul Yeah.
Race mass of an electron.
mass of the elect.
Evening question number Question number 27.
Okay.
Question number 27.
Export 27.
27 27 Okay.
27 No problem.
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