NECO 2026 CHEMISTRY PRACTICAL SALT ANALYSIS.

[00:00:00]Hello my lovely viewers.

[00:00:03]In today's video, we want to look at NECO 2026 chemistry practical salt analysis. We have already determined the end point and the table that is given in part one. This is part two of the practical and the part two is salt analysis. All right? Now, if you are watching on Facebook, watching on Instagram, watching on TikTok, a complete video of this is already uploaded on my YouTube channel. Look at Ojay Mike TV. Just go there, search for NECO 2026 chemistry practical salt analysis by Ojay Mike. It's there on my YouTube channel. All right? Now, in this salt analysis, already you know the format of reporting salt analysis.

[00:00:50]You You have what we call test.

[00:00:55]You have observation.

[00:01:00]And you have your inference.

[00:01:05]Now, what is the salt given? The salt given is copper two tetraoxosulphate six.

[00:01:12]And copper two tetraoxosulphate six is what?

[00:01:16]C u s o 4.

[00:01:20]This is copper two tetraoxosulphate six.

[00:01:25]All right?

[00:01:26]Now, this copper two tetraoxosulphate six it is an hydro salt.

[00:01:31]And since it is an hydro salt, it is very very hygroscopic. Hygroscopic means that it absorb water and turns to moisture. All right? Now, it is very difficult for you to see this salt or being stored in the laboratory. So, the one that is being used, remember this one is an hydro salt. It means that it does not contain any water.

[00:01:53]The one that is used in the The is copper two pentahydrate.

[00:02:03]So, this is what? This is a hydrated form of it normally used in the laboratory because it is crystal. It already contain water of crystallization, all right? Now, this determine these two salts will help you to know the kind of test you will be doing, all right? Now, based on the reagent given, we are given sodium hydroxide aqueous sodium hydroxide, ammonia, we are given barium chloride, we are given dilute hydro- hydrochloric acid, we are given source of light.

[00:02:32]Source of light means that we are going to heat this salt.

[00:02:36]All right? We are going to heat this salt. So, the salt that you will be analyzing, this one is white in color.

[00:02:42]Anhydrous form of it is white in color.

[00:02:43]Why this one is what? It is blue in color. So, the one that is normally used in the laboratory is what? It is the hydrated form of it.

[00:02:53]All right? So, when you are analyzing this hydrated form of it, there are two major things that is used here.

[00:02:59]Analyzing for sulf- uh copper ion, analyzing for sulfate ion, and also looking at the source of heat, that is removing this water from it, all right?

[00:03:10]By that, let's go straight to uh in the analysis of this salt.

[00:03:15]Remember, here we have uh The first thing you will be asked to do is that Remember, this is these are predictions, and my predictions are always 99% accurate, 99%, all right? So, don't worry. I'm giving I'm giving I'm going to give you in different ways so that whichever way it goes, you can write it out or perform the practicals like that.

[00:03:44]Now, we are we will be asked to divide these salts.

[00:03:47]It is either they will ask you to divide this salt into two, all right? Into two half.

[00:03:52]Divide this salt into two halves. The first half you are going to heat it, while the second half you are going to dissolve in water and use it for the for the analysis of the ion. Is that understood? So, let's take the first half.

[00:04:05]So, you say that the first one is what?

[00:04:11]This is A.

[00:04:13]Under A, you say first half of C.

[00:04:26]This one is your C.

[00:04:28]Remember, your acid is your A, your base is your is your B, and your salt analysis is your what? Is your C. You are going to label it as what? As C.

[00:04:37]First half of C plus strong heat.

[00:04:47]Plus strong heat.

[00:04:49]By the time you you get the first portion of this one, that is the first half of this one, then you now heat it.

[00:04:56]When you heat it, what are you going to see?

[00:04:59]Changes from blue to white anhydrous salt.

[00:05:17]C changes from blue to white anhydrous salt.

[00:05:22]Now, in your inference, what are you going to reply?

[00:05:25]You are going to report that C loses its water of crystallization.

[00:05:45]C loses its water crystallization.

[00:05:49]All right?

[00:05:50]Now, this is the first part of it.

[00:05:53]It is either they ask you this first part or the second part which we are going to look at now.

[00:05:59]Now, you draw your line.

[00:06:04]This one will have B I.

[00:06:08]The second portion now, remember you are asked to divide this salt into two halves.

[00:06:13]The second portion now, you will now be asked to what? To dissolve the second portion in what? In water.

[00:06:20]All right? So, you now say C plus water.

[00:06:23]C plus distilled water.

[00:06:31]It is either they start from here and or they start from here. So, C plus distilled water.

[00:06:39]You are now going to say that C dissolve dissolve dissolve to give a blue solution.

[00:06:58]C dissolve to give what? A blue solution or C dissolve in water to give a blue solution. You can say let's just say C dissolve in water to give to give what?

[00:07:18]A blue a blue solution.

[00:07:27]So, it is either you start from here.

[00:07:29]They will ask you to start from either this one or this one. All right? I'm just giving the two in case anyone is being given. All right? So, now You now what you are going to report is that C is a soluble salt.

[00:07:47]C is a soluble salt.

[00:07:49]Are you following? Now, the next thing you are going to do is that now you will be asked to divide this C.

[00:07:56]Because you have already made a solution of it, you will now be asked to divide it into three three major portion, all right?

[00:08:02]Divide it into So, the first portion I say first portion of C plus aqueous sodium hydroxide in drops.

[00:08:22]Plus what?

[00:08:24]Plus aqueous sodium hydroxide in drops.

[00:08:26]That is the first portion. What you are going to see is that you are going to see blue gelatinous precipitate.

[00:08:44]Blue gelatinous precipitate. It is like a gel, all right? It's like a aluminum and zinc that they form gel. So, blue gelatinous precipitate form.

[00:08:58]All right? It is formed. Okay? Now, remember this is in drops. Then in excess.

[00:09:08]Then in excess. In each of the line, always write it as separate.

[00:09:12]Then in excess. Then in excess, now I will now come and write here precipitate precipitate insoluble.

[00:09:30]Precipitate insoluble in excess sodium hydroxide Precipitate is what? Insoluble. And the ion that is present is what?

[00:09:45]Copper two ion present.

[00:09:51]Copper two ion present.

[00:09:53]Are you following? Are you following?

[00:09:54]This is what you are going to be seeing or this is what you are going to be asked, okay? Now, the next thing is that after that, YOU WILL NOW BE ASKED TO heat this solution.

[00:10:05]It is either they ask you in the first one or this second part because there is source of heat.

[00:10:12]All right, there is source of heat. You say you provide what? A strong heat in the reagent given. So, you they will ask you to heat this one. So, you now say um solution plus heat.

[00:10:24]You now say plus heat.

[00:10:28]Plus heat. If you heat it, what you are going to see is that a You must always make sure they are in the same line. The blue gelatinous precipitate Blue gelatinous precipitate turn black.

[00:10:53]If you heat it, the gelatinous precipitate will do what? Will turn black. So, since it turns black, you say that copper two ion is what?

[00:11:04]Is confirmed.

[00:11:09]Copper two ion is what? Confirmed or present, all right? So, it is either they ask you to heat in this first part or you heat it because what? They are asked to provide what? A source of what?

[00:11:22]A source of heat.

[00:11:24]Okay? You are asked in the reagent given that you should provide what? A source of light. You can heat the salt. It is either they will ask you in this one or they will ask you here.

[00:11:34]Are you following? So, if they don't ask you here, you are going to start here and proceed. But, if they say you should uh you should heat the salt first to know whether the salt contain water of crystallization, you must start with this one.

[00:11:48]Do you understand?

[00:11:50]Now, the next thing we are going to test it with what? With aqueous ammonia. So, I'm going to wipe this side, okay? Just take a look at it.

[00:12:00]So, now, the second portion, look at now will be now B I I. Remember, the B I was what? Was the first portion. So, we now say second portion.

[00:12:12]Second portion of C.

[00:12:16]Second portion of C plus aqueous ammonia in drops.

[00:12:27]You are going to put it in drops. What you are going to observe is light.

[00:12:32]You are going to see it light blue precipitate.

[00:12:40]This one is no longer gelatinous. So, don't report gelatinous in this one. So, light blue precipitate form.

[00:12:49]Form.

[00:12:51]Or observe. You can say observe or or form. So, what you are going to see is what?

[00:12:57]Copper two ion is what? Is present.

[00:13:00]All these one they are still what? Test of what? Copper. Copper two ion is what?

[00:13:04]Present.

[00:13:06]Now, remember they say in drops. Now say then in excess.

[00:13:15]Then in excess.

[00:13:17]In excess. In excess, you will say precipitate precipitate dissolve.

[00:13:26]Remember, in sodium precipitate does not dissolve. But here, give a deep blue. You're going to see deep blue.

[00:13:37]Deep blue solution.

[00:13:45]Precipitate dissolve to give a deep blue solution. That is to confirm that copper copper ion is present.

[00:13:54]Copper two ion confirmed.

[00:14:01]That is a general test for copper, all right? You are done with copper. So, we will now analyze for sulfate ion.

[00:14:12]So, here we have what? B I I I.

[00:14:16]Remember, the B I is for sodium sodium hydroxide. The B I I is for what? It's for ammonia. And the last one is for what? For for sulfate. So, you now say third portion now.

[00:14:30]Third portion of C.

[00:14:37]Third portion of C. That is solution of C. Remember, solution of C plus barium chloride.

[00:14:50]When you add a test of sulfate, when you add barium chloride to it, what you're going to see is that white precipitate. This one is not yellow. White pre cip itate. White precipitate observed.

[00:15:10]Observed, or you can say white precipitate formed.

[00:15:17]White precipitate observed, or white precipitate formed. So, the ion you are going to suspect is we have sulfate ion.

[00:15:26]We have sulfite ion.

[00:15:30]You have sulfite ion. Remember, we have t e and d e.

[00:15:36]So, sulfite ion.

[00:15:39]We have even carbonate ion.

[00:15:44]Carbon ion are what present.

[00:15:48]All these ion are what are present. Now, remember, sorry.

[00:15:54]When you add this, the next one is what?

[00:15:56]Plus aqueous plus aqueous hydrochloric acid.

[00:16:06]So, what you are going to report there is precipitate.

[00:16:11]Precipitate.

[00:16:13]Precipitate remain.

[00:16:17]You can say precipitate remain or you say no visible no visible change.

[00:16:26]And and precipitate precipitate is soluble.

[00:16:39]If this This is to confirm that c s o 4 ion is what?

[00:16:47]Present.

[00:16:51]So, this is what you should expect in your NECO practical 2026.

[00:16:58]For more of this video, do well to like.

[00:16:59]Importantly, subscribe to my YouTube channel for the latest update on the world of chemistry.

[00:17:05]Thank you and God bless you.