RE-NEET 2026 Physics 🔥 | Top MCQ Questions Practice | Most Expected Questions 🚀

Added: 2026-05-24

[00:00:13]Hello my dear students welcome to Okay. Comment.

[00:00:40]Good afternoon. Good afternoon. Good afternoon.

[00:00:45]Hi. Hi. Good afternoon, ma.

[00:00:49]Okay. So, thank you. Thank you.

[00:00:53]Okay.

[00:00:57]Hi. Hi. Hi. Namaskar.

[00:01:00]Namaste. Namaste. So you know most repeated top 45 questions. Okay. So 45 question.

[00:01:09]So approach. Okay. So questioning.

[00:01:20]Okay. Ready? Yes, I'm doing good. I'm doing good. Yes.

[00:01:28]Okay. So, start.

[00:01:30]Yes. Start send.

[00:01:38]Okay. Now, yes.

[00:01:41]Yes. Come on. Come on.

[00:01:48]Namaste. Namaste. So ready.

[00:02:00]Okay. So let's get started.

[00:02:09]45 questions and almost similar type of questions like we have started with so we have started with okay lectures question. Fine. Okay. So, let's get started with the top MCQ questions of physics. Okay.

[00:02:48]Top 45 questions. Duration one and a half hour. Okay. So, one and a half hour.

[00:02:53]Ready? Yes. Let's get started.

[00:03:04]Okay. Right. So, let's get started with the very first question. A ball of mass 0.5 kg is dropped from a height of 40 m.

[00:03:14]The ball hits the ground and raises to height of 10 m. The impulse imparted to the ball during its collision with the ground is impulse change in momentum. Okay. So definition the large force acting in a short interval of time simplification we will get to know that it is nothing but a change in momentum.

[00:03:44]Okay. Yes. Change in momentum. What is the change in momentum? Yes. Any idea sir? Change in momentum that is nothing but Okay. So that is a P2 minus P1.

[00:03:54]Okay. So final momentum minus initial momentum the ball is dropped dropped dropped it in velocity zero.

[00:04:05]Okay the ball hits the ground and raises to the height that is 10 m. The impulse imparted. Okay.

[00:04:17]First of all, momentum momentum is nothing but the product of mass and velocity. Am product of mass and velocity. Yeah. Very good. Already students already answer.

[00:04:28]Super. Okay. V. So two cases. First one.

[00:04:33]So this question is the independent of time.

[00:04:39]Therefore equations of motion. Okay. What is that third equations of motion? If you remember, you tell me. So that is U square V square that is equ= to U square + 2 GH.

[00:04:51]Yes sir. So first V1 sir V1 square. Okay. So that is V1 square. Okay. So what is that? Okay. So V1 square. So V1² initial velocity that is equals to 0 and 2 * of G gore 9.8.

[00:05:08]Okay. So that is 9.8 into Okay. So 9.8 8 into Hight 40 m. Okay. So 40 m. Okay. Yes sir. So V_sub_1 that is equals to V1 square that is equals. So simplification.

[00:05:24]So 2 into Okay. So that is a 2 into 2 into 9.8 into Okay. So that is the 2 into 9.8 into into 40. So that is 787.

[00:05:37]So 2 into 9.8 8 into that is a 40. So that is 784. Okay. So that is 784 root 28. Okay. So that is a v1 value that is 28 m/s. Okay. So that is m/s.

[00:05:53]Okay sir.

[00:05:55]Done. And the next one. Okay. So next one. So next one that is v_sub_2. Okay.

[00:06:01]So v_sub_2² that is equals to 0² + 2 * of 9.8 8 into height it is H2 value that is 10 m okay 10 it is 196 196 into 9.8 okay so that is 9.8 8 into 10. Okay. So that is 196 14. Okay. So V_sub_2 value that is a 14. If you want to calculate you do it. Okay. So 14.

[00:06:27]Okay. So V2 value that is 14 m/s. Okay sir. So done. Yes sir. P1 and P2 find.

[00:06:35]Okay. So that is delta P that is equals to is a mass into V_sub_2 minus V_sub1.

[00:06:42]Done. Yes sir. Delta P that is equals to mass is 0.5. So bracket of v2 is to this it is a 14 correct? Yes sir. 14. And the next one V1. So it is 28. Okay. So 28.

[00:06:54]So 28. Okay. So 28 minus. Okay. So V_sub_2 V_sub_2 minus V1. Correct. So final minus initial. Okay. So final minus initial 14 14 into 0.5. Okay. So 14 into 0.

[00:07:09]So let me consider this is P1 that is equals to mass as mass into V1. Okay. So this is initial velocity. I mean mass is to 0.5 into V value that is 28 it is 28 okay so that is 28 into 0.5 14 okay so this is yes this is P1 that is equals to 14 so that is new second already okay so that is a second okay so that is a second okay sir so Okay sir. What about P2? Sir P2 that is equals to Y. Okay. Say into V2. So M it is 0.5 into S it is a 14. Okay. So 14.

[00:07:57]So 14 into 0.5. Okay. So that is 0.5 7. Okay. So 7. Okay. So P2 sub P2. Okay.

[00:08:06]So P2 and the next one. So P2 that is a 7. Okay. So seven. Done.

[00:08:14]as it is moving upward if I consider that change in momentum that is P2 minus P1. Okay. So P2 S P2 that is 7. Okay. So 7 minus and minus of 14. Okay. So minus of 14 s as it is coming down and moving up both are opposite in direction. It is 7 + 14 it is 21. Okay. So that is the 21. Okay.

[00:08:43]So this is 21 Newton second. So that is delta P. So both are opposite in direction. So 21 Newton second. Okay. So that is 21 Newton second. That is option C. Answer.

[00:08:58]Okay. Now huh.

[00:09:00]Yes sir. Uh on sulpa speed session and solving please. Okay. So if you are asking then definitely I'll do. Okay. Right. So next question. The kinetic energy of two similar cars A and B are 100 joule and 225 joule respectively. And applying brakes. A car stops 1,000 m and a car B stops after 15 1500 m. If FA and FB are the forces applied by the brakes on a car A and car B respectively then ratio of FA and FB according to the work energy. Okay. So according to the work energy it is force into displacement. Yes sir force into disment similar. Okay so respectively stops after. Okay.

[00:10:02]Okay sir.inetic Kinetic energy of A and kinetic energy of a B car and force of A car into displacement of A car. So divided by force of a B car into displacement of a B car. Substitute a 100 j it is 225 j a okay so that is f a into displacement so it is 1,000 m okay so 1,000 m so divided by sb it is 1500 m okay so that is 1500 m fb okay so that is 1500 m okay sir sir 2 get cancel okay so okay so Cross multiply it is F A divided by FB. So that is equals to 3 into 100 divided by 2 into 225.

[00:10:55]225 it is 300. Okay. 300.

[00:11:01]Okay.

[00:11:13]Okay. So 225 divided by 50 4.5 okay so 3 into okay so 15 it is you know 225 divided by 5 it is 45 okay so this is 45 okay so that is 2x3 okay so that is 2x3 Right. So 2x3 poll yeah.

[00:11:47]Okay. So 2x3 is the right answer. Okay.

[00:11:49]So 2x3 is the right answer. Next question.

[00:11:52]Pilence and Gamer and Yash and Jagadish and Anu and Okay. Right.

[00:12:20]Yes, sir.

[00:12:22]Next question. Next question.

[00:12:25]Right. The question the current passing through the battery in a given circuit. Okay.

[00:12:32]Okay.

[00:12:39]So this is A and this is B and this is C and this is D. Right. So A.

[00:12:46]So A B. Okay. So this is A B and this is C. Oh, A B C D E F. Okay, so this is A and this is B and this is C and this is D and this is E and this is F.

[00:13:02]It looks like a wheat stone bridge balanced bridge. Unbalanced bridge but it looks like a balanced bridge.

[00:13:11]There are two types of a bridge balanced bridge unbalanced bridge. So it is R1. Okay. And this is R2.

[00:13:20]And this is okay. So this is R3 and this is R4. You balanced sir it is R1. Okay. R2. So this is R1.

[00:13:33]Okay. Yes sir. This is R1. Ratio R1 / R2 that is equals to R3 / R4.

[00:13:41]R1 that is 5 by3 and it is 2.5id 1.5 multiply by 10 it is 25 15 and 5 by 3 on the right hand side yes so balance bridge okay so balance bridge okay so balance bridge balance okay middle.

[00:14:15]Okay.

[00:14:21]Right.

[00:14:31]Okay. So, this is one resistor.

[00:14:36]Right.

[00:14:38]Okay.

[00:14:41]Yes, sir.

[00:14:43]Okay.

[00:14:48]And 2.5 and it is three. Okay.

[00:15:01]Yes, sir.

[00:15:04]wires. Okay. So, okay. So, therefore, okay.

[00:15:16]So, it is flowing through the same.

[00:15:26]This is series combination and this is also series combination.

[00:15:44]It is 8 ohms 2.5 and 1.5 that is 4. Okay. And simplification what is the combination combination because current is dividing so 4 into 8 / 4 + 8 is 4 into 8.

[00:16:22]Okay.

[00:16:24]So it is true the resistance is to it is 8 by 3 ohm. Okay. Now okay. Okay.

[00:16:49]8 by3. Okay. So this is 8 by 3 ohms.

[00:16:52]Okay. So next to either next to it is 1.5 s. Okay. So this is 1.5 ohm right.

[00:16:58]So this is 1.5 and sir it is 5.5. Okay.

[00:17:03]So this is 5.5 ohm and battery. Okay. So battery. Okay. So this is battery. Okay.

[00:17:09]So the battery it is a 5 vol and it is one by Okay. So that is it is 1x3. Okay. So that is 1x3. Okay.

[00:17:18]So that is 1x3. 1.5 is 3x2 5.5 it is 11 by 11 by 2. Okay sir. What is the combination now sir? It is series combination. Series combination sir series combination. Okay. So series combination sir it is 8x3 and 1x3. Okay.

[00:17:40]Yes sir. And 3x2 and 11 by 2 right? Yes sir. Further simplification it is 9x3 + 14 by 2 and it is the three and this is seven. Total 10 ohm.

[00:17:57]So total resistance of this circuit.

[00:17:59]Okay. So total resistance of the circuit that is a 10 ohm.

[00:18:03]So current that is equals to V / R. So V it is a five and R value that is a 10 it is 1 by 2 A 0.5 A sometimes lengthy questions. Okay. So lengthy questions. Okay. So right answer 0.5 0.5 is the right answer. Okay. So that is 0.5 is the right answer. Okay. Right.

[00:18:29]So 0.5 answer that is option D is the correct answer. Okay. So option D is the correct answer.

[00:18:36]Okay. So option D is the correct answer.

[00:18:44]Clear? H.

[00:18:51]Yes.

[00:18:58]Okay.

[00:19:02]Okay. Now, done. Yes. Now, let's move on to the next question. Okay. So, next question. Answer. Next question is two monochromatic light waves of amplitude 3 3 A and 2 A interfering at a point having phase difference 60°. The intensity at a point will be proportional to the intensity. Okay.

[00:19:23]Intensity intensity amplitude. So how does amplitude and intensity are related? So intensity is directly proportional to the square of the amplitude. Okay. So directly proportional to intensity is directly proportional to square of the amplitude.

[00:19:40]Okay. So that is square of the amplitude. Done. Yes sir. Square of the amplitude. Okay. So first amplitude resultant resultant resultant a1 square it is a2² + 2 * of a1 and a2 so divided by cos 5 okay now yes sir so r that is equals to a1 value is there let me consider this is a1 and let me consider this is a2 and five is 60° just substitute okay so 3 a whole square and 2 a So all square + 2 * of 3 a and the next one is it is 2 * of a into cos 60°.

[00:20:23]Okay. So cos 60°. Okay sir. Further simplification.

[00:20:28]Okay. A square.

[00:20:33]So 22 get it 6 a square. So 19. Okay. So that is 19. Okay.

[00:20:42]Underscore it 19 a square. Okay. 19 a square in directly proportional square of the square.

[00:20:54]Okay. So that is 19 a right. So 19 a square. Okay. So this is 19 a square right? Yes. 1x2 r a into a a square that is 19 a square.

[00:21:10]So 19 a square is the right answer.

[00:21:11]Option D. Option D is the correct answer. Okay. So, option D is the right answer. Okay. So, option D is the right answer. Okay. So, option D is the right answer. Very good. Now, let's move on to the next question. Okay. So, next question.

[00:21:25]The question in some appropriate in units time t and position x. Relation of a moving particle is given by t= x² + x.

[00:21:34]The acceleration of the particle. First thing of velocity function of a position velocity function of time that= x² + x. So first velocity velocity that is rate of change of position distance.

[00:22:05]Okay. So differentiate with respect to tiff differentiate.

[00:22:11]Okay. So with respect to time t. Okay.

[00:22:14]Say dt divided by dt. And sir it is differentation x 2x into dx / dt. Okay.

[00:22:24]Now it is dxid dt. Okay sir. dx / dtid dt it is one. And 2x. Okay. So 2x. Okay.

[00:22:34]So this is 2x + 1 into dx / d. Okay. So dx divided by dt. Okay sir. So 1 that is equals okay. So that is 1 that is equals to 2x + 1 into v. So v that is equals to 1 / 2x + 1. So that indicates velocity is the function of a position.

[00:22:57]Velocity is the function of a position.

[00:23:00]again dvid dt v into dx dvid dx. So function velocity is the function of a position.

[00:23:12]So acceleration that is equals to v into dv / dx. Okay. So v into dv divided by dx.

[00:23:21]Okay. Now so yes sir v value that is equals. Okay. So that is v value that is equals to 1 / s is 2x + 1. Okay sir into d / dx. Okay.

[00:23:35]So d / dx. So it is a 2x + 1us value it is 1 / 2x + 1 2x + 1 - s acceleration that is = 1 / 2x + 1 okay it is different it is 2x + 1 so power 2 - 2 into 2. So simplification - 1 into 2. So it is - 2 / 2x + 1 2x + 2 2x 2 2x + 1^ 2. So therefore it is three. So right answer for this question acceleration - 2 / 2x + 1^ 3.

[00:24:34]That is option D is the correct answer.

[00:24:35]Okay. So option D is the correct answer.

[00:24:37]Option D is the correct answer. Okay. So option D is the correct answer. Very good. Now let's move on to the next question. Okay. So next question. Next question.

[00:24:49]Yes.

[00:24:57]In the given circuit frequency. Yes. To resonant frequency. Resonant frequency.

[00:25:03]Res frequency. We know that. Okay. So resonant frequency we know that Z is 1 / 2 pi underscore L into C. Okay sir. So resonant frequency that is equals to 1 / 2 into 3.14.

[00:25:17]Okay. into 0.5 okay so into 20 okay so 20 into 10^ - 6 okay yes sir so resonant frequency that is equals to 1 divided by 2 into 3.14 into 10us 10us 68.

[00:25:50]Okay. So that is 6.28 into 10 - 4. Okay.

[00:25:54]So this is 10^ 4. So divided by 6.28.

[00:25:58]Okay. So that is equals to that is equals. Okay. So 1 divided by Okay. So 1 divided by 6.28.

[00:26:05]So that is 0.159.

[00:26:08]Okay. So 1592 into 10^ 4. Further simplification.

[00:26:13]Further simplification 1.59 into 10^ 3 resonant frequency that is equals to 15 92.

[00:26:26]Okay. So answer okay 159 to 1592 Hz. Okay. So that is 1592 Hz that is option C.

[00:26:38]Okay. Now so that is option C will be the right answer. Okay. So option C will be the right answer. Okay. is option C will be the right answer. Very good. Now let's move on to the next question.

[00:26:47]Okay. So next question. Next question.

[00:26:50]A disc is a placed on a surface of a pond which has a refractive index 5x3.

[00:26:55]Okay. So which has a refractive index 5x3. A source of light is placed 4 m below the surface of the liquid. The minimum radius of the disc will be so will be so light is not coming out not coming out under total internal reflection. Okay. So light must be traveling from minimum radius. So minimum radius that is h / square it u square minus 1. Okay.

[00:27:29]So radius that is equals to h value there. H value that is a four and refractive index is there. So it is a 5x3. Okay. So that is a 5x3 square minus one. Okay. 53 squareus is a 4 / so 25 - okay so that is 25 - 9 so divided by 9 so divided by it is 16 divided by 9 okay it is 4 / 3 4 get cancel that is a three so radius minimum radius it is 3 m.

[00:28:09]Okay. So that is the 3 m. So 3 m is the right answer. Okay. So 3 m is the right answer. Done. Okay. So that is option B.

[00:28:19]Option B is the right answer. Okay. So option B is the right answer. Okay. So option B is the right answer. Very good.

[00:28:24]Now let's move on to the next question.

[00:28:25]Okay. So next question. Okay. Next question.

[00:28:29]Drogly wavelength of electron orbiting in the n is equals to two state of the hydrogen atom is a close to close to drogly 2 pi r= to lambda. Yes sir 2 into r2 that is equals to 2 lambda.

[00:28:55]Okay. So this two this two get cancel.

[00:28:57]Okay. Okay. So lambda value. Okay. So lambda value. So lambda value that is equals to 3 into r2 into this one can be written as r into n². Correct? Yes sir. So lambda that is equals to 3.14 into it is 0.052 nanome. Okay. Nanometer. Therefore n² it is a two square. Okay. So this is two square. And further simplification sir it is 3.14 into 0.

[00:29:30]So this is 3 that is 3.14 3.14 into 0.052 into 4.

[00:29:45]So 3.14 into 0.052 into 4 to 0.6 0.6 653 okay 0.653 nanome okay 0.653 nanome okay 0.653 0.653 approximate 0.67 and 67.

[00:30:05]Okay. Now right so clear so right answer option D. Option D is the right answer.

[00:30:12]Okay. So option D is the right answer.

[00:30:13]Now let's move on to the next question.

[00:30:16]Next question. Next question. The question an electromagnetic wave is traveling in X direction that is the positive X direction. Okay positive X direction with electric field vector given by EY that is equals to E sin of K X minus omega T gcap. The correct expression for magnetic. Okay. So for a magnetic for magnetic field vector equation. Okay. So equation sir E vector cross B vector. So that is equals to C B vector. Okay. So V vector C vector. Okay sir. EP.

[00:30:50]Okay. So this is vector according to the according to the screw. Soap.

[00:31:06]Iap. Okay. So that is IAP. Okay. So IP.

[00:31:09]So that means IP. Okay. So IP. Okay.

[00:31:28]option.

[00:31:32]Okay. So this is Yap Y ais Z ais and X ais Y ais. Therefore it is also eliminated.

[00:31:43]Right answer that is option option D is the correct answer. Okay. So E / C sin of Kxus omega t Kap that is option D is the correct answer. Okay. So option D is the correct answer. Done.

[00:31:56]Option D is the correct answer. Okay.

[00:31:57]So, option D is the correct answer. Very good. Now, let's move on to the next one.

[00:32:03]Now, next question. To an AC power supply of 220 volt and 50 Hz, a resistor of a 20 ohm and capacitor of reactance 25 ohm and an inductor reactance 45 ohm are connected in a series. The corresponding current in a circuit and a phase angle between the current and voltages. Okay. So simple simple.

[00:32:28]So first thing that is equals to V / Z. Okay. So V / Z power supply Z. Okay. So Z it is under square root it is R² + XL - X C².

[00:32:46]Okay sir. Substitute the values.

[00:32:49]Z that is equals to R is there. So relay resistor R 20 ohm. Next one capacitor reactance that is XC and inductor reactance that is XL. Okay. So 20² so plus XL is there is a 45us 25 so square. Okay sir. So Z is equals to square one followed by two zeros. Okay. So four followed by two zeros followed by two zeros s 2 * 400 okay so 400 that is equals to that is 2<unk> 20 okay so 20 <unk>2 okay so 202 ohms okay so 20 <unk>2 ohms okay so 20 <unk>2 ohms okay yes sir current okay so current that is equals to sir it 220.

[00:33:47]So divided by Z. Okay. So 220 divided by Z value is there. So it is 20 <unk>2.

[00:33:53]Okay. So 20 <unk>2, right? Yes sir.

[00:33:56]Simplification.

[00:33:58]Simplification.

[00:34:00]It is 22 get cancel. Okay. So 22 get cancel 22 / 2. Okay. So divided by 1.414 7.77. Okay. 7.77 7.77 amp 7.77 option A option B gone okay option A and option B gone and the next one phase difference okay so phase so it is the tan inverse of okay so that is the tan inverse of okay so that is XL minus XC divided by R tan inverse of okay so that is the tan inverse of XL it is 45 - 25. Okay. So 45 - 25 divided by that is a 20. So 20 and 20 get cancel. Okay. So 45 - 25 20 divided by 20 it is a 1. Okay. So tan tan inverse of 1. Okay. So tan inverse of 1 is equals to 45. Okay. 45°. So 45° 7.8 and 45° that is option D. Right. So 45°. Okay. So 45° that is option D.

[00:35:11]Okay. So that is option D is the correct answer. Done. Okay sir. Very good. Now let's move on to the next one. Okay. So next question. Yes. Next question. Next question is which of the following option represent the variation of photocurren with the property of light?

[00:35:27]Intensity. Okay. So it is done. So we know that intensity is directly proportional to the photocurren. Yes sir. As intensity is increasing the photocurren is also increasing.

[00:35:38]Photocurren. Intensity intensity intensity of light wrong. Okay. And the next one. Okay. So next one photocurren does not depends upon frequency. So frequency photo does not depends upon frequency.

[00:36:00]Direct answer a only. Okay. So that is A only. That is option C is the correct answer. Okay. So option C is the correct answer.

[00:36:11]Done.

[00:36:13]So option A is the correct answer.

[00:36:17]Sorry. A only correct answer. That is option C. Okay. Now right sir. So that is that is option C only.

[00:36:26]Now let's move on to the next question.

[00:36:27]Okay. So next question.

[00:36:30]Next question is a pipe open at both ends has the fundamental frequency.

[00:36:36]Okay. So this is for open open. So open that indicates fundamental. So normal fn that is equals to v / 2 fundamental s= to only they have given. Okay. So that is equals to v / 2. Okay sir. The pipe is now dipped vertical in a water drum.

[00:37:01]Okay.

[00:37:10]closed pipe column to half of its length. Okay.

[00:37:16]Half of it length. Okay. The fundamental frequency of the air. So closed pip is 2 minus one L / V / 2 L. Okay. So that is v / okay s frequency 1 it is 2 into 1 so minus1 into v / 2 * okay so into 2 so 22 get cancel okay so v okay so v divided by half of it length okay so half of it get vid okay so sorry okay 4 okay so this is 4 L. Okay. So this is the 4 L. Okay. So that is a 4 L dash. So V into S 4 into L dash it is L divided by 2. So 2 get cancelus one. So that is V / 2 L. Okay. So final so frequency of this one that is equals.

[00:38:19]So same. Okay. So frequency remains same that is option D. Okay. So option D is the correct answer. Okay. Hm.

[00:38:35]Any doubt?

[00:38:43]Yes.

[00:38:46]So that is option D is the correct answer. Option D is the right answer.

[00:38:50]Okay. So option D is the correct answer.

[00:38:51]Now let's move on to the next question.

[00:38:53]Okay. So next question. The output y of the given logic implementation is similar to the output of an dash gate.

[00:39:00]Okay. So input a okay sir input b s a + b bar complment and this is a bar.

[00:39:19]So a + b bar. Okay. So into so ablification it is a so double bar it is a bar plus b bar okay a bar plus b bar okay so a bar plus b bar simplification bar okay so y that is equals to a sub bracket of a + b okay a b Okay. So a plus.

[00:39:52]Okay.

[00:39:54]Okay. So done. Okay. So that is option B is the correct answer. Okay. So option B is the correct answer. Option B is the correct answer. Now let's move on to the next question. Next question. A physical quantity P is related to four observations A, B, C and D as follows. P is equals to A power 3 B power 3 divided by C under square root D. The percentage error of the measurement N A B C and D are 1% 3% and 2% and 4% respectively.

[00:40:29]The percent error. Okay. So delta P divid P into percent.

[00:40:40]So power into percent. Okay. Power into percentage.

[00:40:44]Okay. The power into percentage. Okay.

[00:40:46]Power into percentage. First one. First one it is a a power to s three a power three and a percent plus b power two and b percent it is 3%. Okay.

[00:41:04]C it is power one. So one c the percent is 2%. Suppus. Next dest 2 into B percentage.

[00:41:25]Okay. So plus 1 into C percentage plus 1 by 2 into D percent. Okay. So D percent. So 3 into 1 percentage.

[00:41:38]Okay. So bracket close plus 2 into B percentage. It is 3 percentage plus 1 into C percentage s it is a 2 percentage so plus 1 by 2 into okay so 1x 2 into D percentage 4 percentage okay yes sir simplification s 3% plus 6% plus 2% okay plus 2% then it is 2% okay so 2% 13% okay so total is to 13% okay so 13% so total is to 13% 13% sir it is option A okay now option A is the right answer okay so option A is the correct right answer okay so clear 3 into 1% and next one 2 into 3% and next one into 2% and next one half into 4% okay four that is a two 6 + 2 + 2 that is a 10 10 + 3 that is 13 Okay. So 13 is the right answer. Okay.

[00:42:41]So 13 is the right answer. 13 option A is the correct answer. Okay. Right. Now let's move on to the next question.

[00:42:47]Okay. So next question.

[00:42:49]Next question. The radius of Martian orbit around the sun is about four times the radius of the orbit of a Mercury.

[00:42:57]The Martian year is a 687 Earth days.

[00:43:00]Then which of the following length of the one year of a Mercury? Okay. So length of the oneear Mercury. So direct formulas. So directly proportional to AQ. Okay. Now yes sir. So compar orbit around the sun is about four times that is the radius of orbit of mercury.

[00:43:20]Okay. So Martian Martian all square divided by mercury.

[00:43:26]Okay. So mercury hg. Okay. So hg. So that is equals to radius. Radius of Martian that is a cube and radius of mercury that is also Q. Okay. So concentration radius of Martian. Okay. So radius of Martian. So that is a four times of radius of the orbit of mercury. Okay.

[00:43:52]Mercury right? Yes. Next it is RM. Okay.

[00:43:58]So this is RM. So divided by Okay.

[00:44:01]already okay RM okay so this is RS it is a four times of radius of the mercury so divided by RHG so RH get cancel okay it is tid hg² okay so that is equals to 64 it is T M divided by T HG. So that is equals to underscore 64. So that means it is a 8. Okay.

[00:44:40]Length of the Okay. So length of the oneear mercury. Okay. So length of the oneear mercury. Okay. So length of the oneear mercury. Okay. So length of the oneear mercury.

[00:44:49]S length of the oneear mercury. Okay. So TH Okay. So THG. So that is equals to T M.

[00:44:56]So it is 687.

[00:44:59]Okay. So 687 divided by 8 687 divided by 8 687 divided by 8. So that is 85 85 85.

[00:45:11]So then which of the following is the length of the one year on a mercury?

[00:45:15]Okay. So length of the one year on a mercury. So mercury tm 687 r².

[00:45:25]Okay. So 4 4 into 4 into 4 that is 64.

[00:45:30]Okay. So 64 square root it is 8.

[00:45:35]Okay. So this is so that is nearby value 687. So divided by 8. So 85. So nearby value. Okay. So nearby value 88. Okay.

[00:45:50]So nearby value that is 88. Okay. So that is option C.

[00:45:55]Option C is the right answer. Okay. So, option C is the right answer.

[00:45:59]Done. Now, huh? Now, let's move on to the next question. Before that, option C is the correct answer. Now, let's move on to the next question. Okay. So, next question.

[00:46:10]Next question. Okay. So, next two question. A photon and an electron have the same energy E. The ratio of Okay. So wavelength of photon wavelength of electron of their drogly wavelength is okay. D wavelength. Okay.

[00:46:26]First photon. Okay. So photon this is photon energy. Okay. So photon energy energy that is equals to HC divided by lambda.

[00:46:38]S lambda lambda. So photon that is equals to HC divided by E. Okay sir. And the next one electron. Okay. So electron. Okay. So electron.

[00:46:50]So electron is the lambda that is equals to Okay. So that is lambda that is equals to okay so electron that is equals to h / under square root so 2 * of e where energy in both cases same right yes sir ratio so wavelength of photon divided by wavelength of electron wavelength of photon s2 it is hc divided by e okay so that into it is ratio that is undersc right sir. So lambda p that is equals to lambda e that is c * of so it is a 2 m divided by e n okay right answer right answer okay okay so right answer c underscore it 2 m divided by e done okay so that is option A option A is the correct answer okay so option A is the correct answer now let's move on to the next question next Question an electron mass 9 into 10^ - 31 kg and charge 1.6 into 10 - 19 moving with the speed C divided by 100 that is speed of light is injected into the magnetic field B of the magnitude 9 into 10^ - 4 Tesla perpendicular to its direction of a motion. We wish to apply an uniform electric field together with the magnetic field so that electron does not deflect from its path. Okay.

[00:48:49]So perpendicular to the magnet field and it magnitude is 27 as it is and it is 9 into 10^ 4 okay so 9 into 10 - 4 okay so 10^ - 4 C value okay V value okay V value C. Okay. Yes sir. And simplification is 3 into 10 and 10. Okay. So E value that is equals to it is 3 into 10 - into 9 into 9. So finally electric field that is equals to 10. Okay.

[00:49:46]volt per meter okay and electric field perpendicle to the B and it's a magnet is 27 into 10^ 4 10 - 2 okay so 10^ 2 okay so per meter so right answer for this option D okay so option D is the correct answer how many questions are total 45 already we are in 18th question okay so 18th 17th question option D is the right answer okay so option B is the right answer. Now let's move on to the next question. Okay. So next question.

[00:50:21]Elimination method follow. The electric field in a plane electromagnetic wave is given by EZ is is equals to 60 cos 5x + 1.5 into 10^ 90 per meter. Then expression for the corresponding magnetic field is is okay.

[00:50:38]So expression for corresponding magnet.

[00:50:41]So you know screw E cross B. Okay. E cross B that is equals to V right? Yes sir. Electric field in a plane electromagnetic wave is given by E that is K.

[00:50:56]Okay. So okayitive positive positive. Okay done.

[00:51:11]And what about this this one? What is that? V V that is okay. So that is Iap. Okay. So I done that. Okay. So why according to the rle that is positive xaxis already okay?

[00:51:54]Okay. So, and the next one I already K then I and this is okay.

[00:52:25]Y and yes sir. So E that is equals to C / B.

[00:52:35]So B value that is the 60 divided by C 3 into 8us.

[00:52:44]Okay. So simplification it is 2 into 10 - 7. So that's it. Okay. So 10 - 7.

[00:52:51]Okay.

[00:53:00]Okay. So, so direct that is option D is the correct answer. E cross B formula.

[00:53:08]Okay. Now, done.

[00:53:20]Option D is the correct answer. Okay.

[00:53:21]Okay. So option D is the correct answer.

[00:53:22]Okay. So option D is the correct answer.

[00:53:25]Any doubt here? Elimination respond.

[00:53:51]Right. Okay. Now let's move on to the next question. No doubt. Fine. Next. A body weighs 48 Newton on a surface of earth and the gravitational force experienced by the body due to earth at a height equal to the height equal to okay. So at a height equal to the one/ird of the radius. Okay. So yes height height that is equals to radius of earth height.

[00:54:20]So G that is equals to G S on the surface. So 1 + H / R². Okay. Now mass mg that is equals to mg. Yes sid 1 + h value it is 1 / 3. Okay. So 3 r².

[00:54:44]Okay.

[00:54:45]Yes sir. It is weight of the body at a height and weight of the body at a surface. So get so 5 by3. Okay. So 5 by3 square weight of the body at the surface weight of the body at the surface 48. Okay. So that is 48 Newton and this is 25. Okay. So simplification it is a 48 into 9 divided by 25. Okay. Yes sir. Simplification that is 48 into 9. So divided by 25.

[00:55:20]Okay. So divided by 25.

[00:55:23]48 into 9. So 432. So divided by 25.

[00:55:30]17 point. Okay. So 17. Okay. So okay that is equals to okay so 4x3 square it is 48 Okay. So that is weight of the body at a height that is equals to 27 Newton.

[00:56:07]So 27 Newton. Okay. So that is 27 Newton. That is option D. Option D is the right answer. Okay. So option D is the right answer.

[00:56:16]Priam. Namaste.

[00:56:26]Let me check.

[00:56:31]Congratulation 156. That is a wonderful score.

[00:56:36]Let me check.

[00:57:20]So now let's move on to the next question that is option D.

[00:57:26]Okay. So now let's move on to the next question. Yes. In a question. The next question. An unpolarized light beam traveling in a air is incident on a medium of refractive index 1.73 and a brester angle. So tanals tan that is equals to 1.73 it is 60° okay so 60° so 60° 60 both reflected and transmitted light are perfectly polarized wrong statement transmitted light is completely polarized with the angle Angle of refraction 30° 30° 60° reflected light is completely polarized at the angle of refle and angle of the refle reflection is close to the 60°.

[00:58:21]This is the right answer. Reflected light is a partially reflected light is completely polarized. Therefore, so option C is the correct answer. Okay.

[00:58:31]So this is the brester law. Okay. So brevester law done clear. So that is option C.

[00:58:40]Options C is the correct answer. Okay.

[00:58:42]Now let's move on to the next question.

[00:58:45]Next question.

[00:58:47]Next question. A 2 ampere current A is the flowing through the two different small circular copper coil having radi 1 is to 2. The ratio of the respect to magnetic moment.

[00:59:01]So magnetic moment it is magnetic moment that is equals to I circular loop. Okay.

[00:59:10]Okay. Magnetic moment of one and magnetic moment of two.

[00:59:15]Number of Okay. So number of number of turns and number of turns number of mirectly proportional area and this area is nothing but r². Yes.

[00:59:34]R1² r2.

[00:59:37]So that is 1 square this is the two square it is 1x4 okay so that is 1x4 answer okay the right answer that is 1x4 okay so 1x4 is the right answer okay so directly proportional the magnetic moment so that is 1x4 is the right answer 1x4 1 is to 4 option C option C is the right answer option option Option number of it is a constant same 2 directly proportional to a a r² because they have given circular copper coil right that is 1 is to 4 that is 1 is to 4 Okay.

[01:00:41]Done. So that is option C is the correct answer.

[01:00:44]Option C is the correct answer. Okay. So option C is the correct answer.

[01:00:57]Okay. Now let's move on to the next question. Next question.

[01:01:02]Yes.

[01:01:03]Two ordinary satellites are revolving around the earth in a same elliptical orbit. Same elliptical orbit. Same then which of the following quantities is conserved in a circular zero because angular momentum that is a constant.

[01:01:30]Okay. So angular momentum is a constant.

[01:01:33]Option C.

[01:01:35]Option C is the correct. Option C is the correct answer. Okay. So option C is the correct answer. Very good. Next question. Next question. Given below are two statements. One is labeled as assertion and other is labeled as a reason. R assertion A. Assertion A.

[01:01:55]The potential at any axial point at a 2 m distance from the center of the dipole of a dipole moment vector P of magnitude okay magnitude that is a magnitude 4 into 10 - 6 is a plus or - 9 into 10^ 3 take 1 / 9 into 10^ 9 unit first so dip moment okay so potential due to dip that is KP cos theta So divided by r². Okay sir. K value is there it is 9 into 10^ 9. Okay. So this is plus or minus. Okay. So plus or minus k value it is 9 into 10^ 9 and p value it is 4 into 10^ - 6. Okay. So 4 into 10 - 6 into cos that is equals to 0= 1 r² r².

[01:02:47]So 2 square.

[01:02:53]Okay.

[01:02:55]9 - 6 it is 3. So plus or minus 9 into 10^ 3. Okay. So that is option. So assertion is right sir. And the next one reason. Okay. So reason sir potential is plus or minus 2 pid 4 r². If formula wrong. Okay. Say formula two. This is wrong. So therefore assertion is correct but reason is wrong. Okay. Assertion is correct but reason is wrong. assertion is true but reason is a false so that is option B right so that is option B is the correct answer okay so option B is the correct right 21% next one okay question the mass of the planet is 110th that of the earth okay so mass of the planet is there sir mass of the planet 110th of the mass of earth it's a diameter under a radius is directly proportional to the diameter. Okay, diameter is okay. So diameter is half of the earth. Okay, so half of the earth. The acceleration due to gravity of that planet. Okay, so acceleration due to gravity of the planet. Okay, so gravity of the planet is gid r². Okay, so gid r² g as it is mass. So mass of the planet and radius of the planet is 1 / it is d / 2. Okay. So d / 2 r okay r².

[01:04:37]Okay.

[01:04:40]Okay. So that is 2 / 5 into G M / R². Okay. G Mid R² GP that is equals to 2 / 5 into approximately. Okay. So what is the value of this set?

[01:05:02]Okay. So m/s square. Okay. So 4 m/s square 4 m/ second square is a three. So 3.92 m/s square. Okay. So 3.92 m/s. Okay. So second square. Okay.

[01:05:23]So 3.92 m/s square. Okay. That is the right answer. That is option C. Okay. So that is option C is the correct answer.

[01:05:31]Done. 25% on the short break.

[01:05:35]Okay. So short break.

[01:05:38]Okay. So 10 minutes.

[01:05:40]Okay. So that is 10 minutes.

[01:15:54]Hello. Hello.

[01:15:58]Hello. Hello. Hello.

[01:16:35]Okay. So, thank you. Thank you for the confirmation.

[01:16:43]Start mad. Yes. The question is at any instant at any instant of a time at a t the displacement of any particle is given by 2tus 1 si unit and of force of 5 newton the value of instantaneous power is okay instantaneous power s instantaneous power that is equals to dw / dt but force disment Okay. So this is the disment.

[01:17:18]Yes sir.

[01:17:20]Force into disment. Okay. So force intoce= to 2tus 1 it is dx / dt.

[01:17:37]Okay. So p that is equals to 5 newton into 2 m/s. So P is equals to so that is the 10. So 10 SI unit. Okay.

[01:17:48]So 10 SI unit that is what? Okay. So that is what fine.

[01:17:55]Now let's move on to the next one that is the option D is the correct answer.

[01:18:00]Let's move on to the next question.

[01:18:03]Next question. A particle moving with a uniform speed in a circular path maintains. Okay.

[01:18:09]particle circular motion.

[01:18:23]Okay.

[01:18:24]So this is V. Okay. So this is V. So velocity. Okay. So velocity constant velocity. Okay. So velocity.

[01:18:36]So velocity for every right? Yes sir.

[01:18:57]So velocity keep on changes. Therefore acceleration cannot be constant because of direction. And the next one constant velocity because direction is changing varying velocity and varying acceleration because of a direction.

[01:19:12]So that is the because of a direction.

[01:19:14]Okay. So because of a direction that is option C.

[01:19:18]So option C is the correct answer. Okay.

[01:19:20]So option C is the correct answer. Next question. Next question. Match list one with the list two. The choose the correct answer from the options given below. Okay. So first one diagnetic substance magnetic susceptibility is negative two match and magnetic susp much much much more than one much much more than one that is matching with the three and the next one paramagnetic paramagnetic it is a very small and but positive okay so very small but positive four non that is equals to zero that is one matching. So 2 3 4 1 2 elimination elimination 2.

[01:20:10]So two three four that means it is a D.

[01:20:16]So option D is the correct correct answer. Okay. So option D is the correct answer. Okay. So option D is the correct answer. Option D is the correct answer.

[01:20:23]Okay. Now let's move on to the next question. Okay. The next question for ideal transformer the turns ratio is NPID NS is equals to 1id 2. The ratio of VS V is to VP is equal to bracket symbols carry the usual meaning and NP NP number of turns in a primary coil number of turns in a secondary.

[01:20:48]Next one Vid that is you know voltage across secondary call and voltage across a primary call according to the condition voltage across secondary call divided by voltage across primary call number of turns in a secondary call number of turns in a primary call that is 2 / 1. Okay so two divided by one is the right answer. Okay so two divided by one 2 is to one that is option A.

[01:21:14]Option A is the correct answer. Okay. So option A is the correct answer. Okay.

[01:21:20]Option A is the right answer. Okay. So option A is the right answer. Okay. So option A is the right answer. Yes. That is option A.

[01:21:29]Done. Now let's move on to the next question. Yes. A tightly wound 100 tons coil of a radius 10 cm carries a current of 7 amp. The magnet of a magnetic field at the center of the coil is magnetic field. Okay. So magnetic field sir magnetic field due to call that is mu n into i divided by 2 * r. Okay. Now yes sir. Where mu not you can consider as a 2 pi into 10^ minus 7 into number of turns. Number of turns that is 100 into i value. I value that is the seven.

[01:22:03]So all divided by two into r value. R value that is 10 cm. Okay. So 10 into 10 powerus 2 simplification.

[01:22:13]Okay. So simplification 1 get cancel two get cancel okay so 2 into 2<unk>i into 10^ - 7 okay into 10 into 7 so 10^ 2 okay yes sir so simplification 628 628 okay so 628 okay so six okay simplification.

[01:22:45]So 2 into Okay. So 2 into 3.14 into 7. So that is 43. Okay. So 43.

[01:22:53]Okay. So that is a 43.96 into the power 10^ - 4. Okay. So B that is equals to. So it is 4.39 into 10^ -3 Tesla B is equals to 4 approximately 4.4 4 milll 4.4 millla 4.4 milll 4.4 Tesla that is option Besla okay so that is Tesla is the correct answer okay 4.4 4 mill Tesla is the correct answer. Done. So that is option B is the correct answer. Okay. Option B is the correct answer. Now let's move on to the next question. Okay. So next question. Yes. Next question. That is the combination of a capacitor in the following circuit. The equivalent capacitors between terminal A and terminal B. First similar to the wheatstone bridge. Okay.

[01:23:50]Similar to the stone bridge whether it is a wheat stone balance unbalanced.

[01:23:56]So same way. So 2 / 2 1 2 therefore it is eliminated. And what is the combination combination? Okay. So combination series combination series combination series combination C divided by two is 1 microfarad. And the next one.

[01:24:21]Okay. So series combination.

[01:24:24]So total combination 1 + 1 that is 2 microfarad.

[01:24:30]So bridge individual values. For example 33 that will be the three answer four that will be the four answer 6 that is the final answer will be six.

[01:24:51]Okay individual values. Okay. So that is the two is the right answer that is option D.

[01:24:56]Option D is the right answer. Okay. So option D is the right answer. Right.

[01:25:00]Very good. Now let's move on to the next question. Okay. So next question.

[01:25:04]Next question. A maximum elongation of a steel wire of a length 1 m. If the elastic limit of a steel and its model is respectively 8 into 10^ 8 Newton per me square and 2 into 10^ 11 Newton per me square. Maximum elongation elast square. Okay.

[01:25:46]mod that is equals to stress divided by strain stress divided by ang 2 into 10 11 okay now 10^ 11 and 10us 3 okay yes sir strain change in length divided length okay so change in length divided length elongation elongation delta into epsilon into L. Okay. Now yes sir. Epsilon value it is 4 into 10^ minus 3 into L value it is 1. So final elongation so it is a 4 mm. Okay. So 4 mm is the right answer.

[01:26:29]Okay. So 4 mm 4 4 mm. Option D. Okay. So option D is the right answer. Okay. So option D is the right answer. Option D.

[01:26:40]Very good. Now let's move on to the next question. Okay. So next question. An unpolarized light beam light. Okay. An unpolarized light beam strikes the glass surface at a bister angle. Bister angle reflected ray completely polarized.

[01:26:55]Refracted transmitted partially polarized as per the brester law. The refracted ray refracted light will be completely polarized. Wrong. Both reflected and refracted refracted light will be completely polarized. Wrong. The reflected light will be completely polarized but refracted light will be partially polarized. Yes, this is right.

[01:27:16]The reflected light will be partially polarized. This is wrong. So, right answer that is option C.

[01:27:23]Okay, option C is the right answer.

[01:27:27]Now, let's move on to the next question.

[01:27:30]Next question. A bob is a word in a horizontal plane by means of a string with the initial speed omega rpm means angular velocity. The tension in the string is a t. If the speed becomes two two times of omega while keeping the same radius the tension in the string is so tension the string acts as a centrial force. Okay.

[01:27:57]M omega² into r. Okay. So m omega square into okay sir tension okay omega tension the string is a t speed becomes a two times while keeping the same radius okay same radius and the same okay so mass is same and radius is also same so in place of fc omega square r okay so t is directly proportional to omega square omega omega 2* directly proportional to omega square.

[01:28:37]So that indicates it is 2 * of omega square it is a 4 omega square. Okay.

[01:28:44]Then simplification it is a four * of t.

[01:28:46]That's it. Okay. So four times of t that is option a. Option a is the right answer. Okay. So option a is the right answer. Okay. So option a is the right answer. Option a is the right answer.

[01:28:58]Yeah. Answer.

[01:29:01]Next question. Next question. A thermodynamic system is taken through the cycle A B C D A. Okay. A B C D A.

[01:29:09]Okay. The work done by the gas along the path BC. Okay. So along the path BC BC is this one. Okay. So BC work.

[01:29:20]So work done that is equals to P into DV.

[01:29:25]Okay. So volume remains same. there is a change is a zero. So zero work done will be zero. Okay. So work done will be zero. Okay. So because there is no change in the volume. Okay. So there is no change in the volume. Therefore work done is equals to zero. Okay. Now work done is zero. That is option D is the right answer. Option D is the right answer. Last 10 questions. Okay. So last 10 questions. So let's move on to the next question. The output g output Y of the given logic gate similar to the output of Sir, it is a there. So this is a bar and the b and this is a b bar and a bar plus b bar. Okay. A bar plus b bar ngate.

[01:30:09]Okay. So that is norate. Okay. So that is norate. Okay. So ngate is the correct answer. Option A. Done. Okay. So that is option A is the correct answer. Answer.

[01:30:20]Option A.

[01:30:43]Now let's move on to the next question.

[01:30:46]Yes. Two bodies A and B of a same mass undergo completely inelastic one-dimensional collision. The body A moves with velocity V_sub1. The body B is at rest before the collision. The velocity of the system after the collision is V. The ratio of v_sub_1 is to v2. So first first mass of the body a. Okay. So mass of the body a okay mass and so a body a body. Okay. So mass of the body a that is a one. Initial velocity that is initial velocity of a body a that is a v1. Okay. So in case of u1 that is they have given v_sub1 and b body. Okay. So b body that is m2. Okay. So that is m_sub_2 identical body same. Okay. So same as therefore it is m1 that is equals to m and m_sub_2 that is also initial velocity that is equals to v_sub_1 and v_sub_2 that u2 that is equals to in okay and the velocity of the system after the collision is inelastic inelastic.

[01:31:57]Okay. Yes. Initially initial moment that is equals to final moment. Okay sir. So m1 u1 the plus m_sub_2 u2 so that is equals to m1 v1.

[01:32:09]Okay. So m1 combine m1 + m2. So divided by v. Okay.

[01:32:16]So v. So final velocity velocity of the system. Okay. So velocity of the system.

[01:32:21]Velocity of the system. Okay. M1 that is equals to m and this is v1. Okay. So plus m_sub_2 that is y initial velocity that is equals to 0 that is equals to 2 * of m into v_sub_2 okay sir and m_sub_1 and 2 m v_sub_2 okay so 22 get cancel and v_sub1 divided by v2 okay so v_sub_1 divided by v_sub_2 that is equals to 2 divided by 1 okay so that is the 2 is to1 so that is option a okay so 2 is to 1 that is option a is the correct answer okay option a is the correct answer option a is the correct answer Okay. So option A is the right answer. Okay. Now let's move on to the next question. Last seven questions. Okay. So last seven questions. A horizontal force. Okay. So that is a horizontal force 10 Newton is applied to the block A as shown in the figure. The mass of the block A and B are 2 kg and 3 kg. Okay. So three.

[01:33:18]So 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by a block E and a block B.

[01:33:25]Okay. So first acceleration.

[01:33:29]Okay. So what is the acceleration?

[01:33:30]Acceleration of the block first. So acceleration of the block that is equals to total force divided by total mass. So total force it is 10 newton. So total mass it is 2 + 3. 10 / 5 that is equals to 2 m/s squared. Okay.

[01:33:49]Force exerted by block A and a block B.

[01:33:51]Okay. So block A and a block B. Say block.

[01:33:56]Okay. So that is F. Okay. Yes.

[01:34:03]So force force B. Okay. So due to E force on B due to A. Okay. So number of masses pushed that is mass of the B and acceleration of the entire system is F FB A that is equals to mass B that is the three acceleration that is two that is the 6 Newton. Okay. So that is a 6 Newton. So right answer that is a 6 Newton. Okay. So right answer that is the 6 Newton. That is option B. Okay. So option B is the right answer. Okay.

[01:34:50]foreign.

[01:35:01]Okay. So please Okay.

[01:35:29]Okay. Right. Now, so that is option B is the correct answer. Okay. So, option B is the right answer. Now, let's move on to the next question. Okay. So, next question. Next question. If X is equals to 5 sin of pi T plus by 3 m represents a motion of a particle executing simple harmonic motion SHM. the time. Okay. So, x= a of sin omega t + a yes sinated eliminated. Okay. Possibility option option possibility. and time period. So time period in it is omega divided by 2 pi. Omega is still there is a pi. Okay.

[01:36:20]So that is 2 pi divided by omega right.

[01:36:23]So 2 pi divided by omega. Okay. So 2 pi divided by omega. Okay. So 2 pi divided by omega. Omega.

[01:36:30]So omega. So pi pi pi get cancel that is the 2 seconds. Okay. So 2 seconds. Okay.

[01:36:37]So pi pi get cancel that is the 2 seconds. Okay. So 2 seconds.

[01:36:41]So 2 seconds is the right answer. Okay.

[01:36:43]So 2 seconds is the right answer. Wrong.

[01:36:45]So option A is the correct answer. Okay.

[01:36:47]So option A is the correct answer. So overall option A is the correct answer.

[01:36:51]Okay. Right. So option A is the correct answer.

[01:36:56]Done. Very good. Now let's move on to the next question that is the last five questions. Okay. Last five questions in the given circuit. Peak voltage. Okay.

[01:37:06]So peak voltage. Okay sir. peak voltage CL and R 30 volt, 110 volt and 60 volt respectively. The RMS value of voltage okay RMS value of voltage so RMS value of voltage that is V divided by <unk>2 0.707 into V. Okay. So V so V that is equals to un V R² + V L minus V C all square. Okay. Yes sir. And the next note so that is a V that is equals to V R² R that is 60. Okay. So that is 60. This is the V C and this is V L and this is V R. Okay. Yes sir. V R that is equals to 60 square and V L is 110us 30 square. Okay. Yes.

[01:38:03]10,000. Okay. So 10,000. So this is 100 plus two zeros. Okay. So 10,000 that is 100. Okay. 100. Fine. Yes sir.

[01:38:14]So V RMS. Okay. So V RMS. Okay. So already so V RMS 0.707 into 100. So finally 70.7 volt 70.7 volt. Okay. So that is option C. Okay.

[01:38:33]So option C is the right answer. Okay.

[01:38:35]So option C is the right answer. Okay.

[01:38:38]Option C is the right answer.

[01:38:40]Last four questions.

[01:38:42]Note a thin sperical shell is a charged by some source. The potential difference between two point charge that is C and P. Okay. So C P. Okay. C potial difference. So let me consider this is VC and this is VP not V is KQ / R².

[01:38:59]Okay. So R² and VC. So similar to the surface. Okay. Similar to the surface similar to the surface VP. So that is VCU V because potential surface inside. So inside potential that is equal to on the surface any point inside okay any point inside that will be equal to the potential at the surface according to the potential gradient.

[01:39:32]Okay so either answer option D. Okay so answer is to option D. Okay. So answer option D. Clear sir normal force.

[01:39:52]Okay. So block force block A and block Balm.

[01:40:00]Okay.

[01:40:03]Okay. So then FB.

[01:40:05]Okay.

[01:40:07]Right. So that is option C.

[01:40:12]Option C.

[01:40:14]Now let's move on to the next question.

[01:40:17]Yes. If the if C is the velocity of a light in a free space, the correct statement about a photon photon among the following. The energy of the photon is E= H. That is right answer.

[01:40:30]The velocity of photon is a C. Whatever it is a medium or in free space it is remain same. The moment of a photon is h new divided by c. Yes that is also right answer. And in photon okay normal. Okay.

[01:40:42]So normal eals. Okay. So eals hid right. Yes sir. Hid lambda. Okay. Right.

[01:41:02]In photon electron collision both total energy and momentum are conserved. Yes, that is also right answer. Photon possess a positive charge. Either wrong because photon is a chargeless.

[01:41:12]Electrically neutral. Okay. So it is electrically neutral. So A B C D are the correct. Okay. So A B C D are the correct. Okay. So A B C D are the correct. Okay. So A B C D are correct. E A Okay. Say E A done. Yes sir. That is option A.

[01:41:29]Option A is the right answer. Okay. So option A is the right answer.

[01:41:34]Option C.

[01:41:35]Now let's move on to the next question.

[01:41:39]Last second question. Given below are two statements. Statement one. Statement one sir. Statement one. Atoms are electrically neutral as they contain equal number of positive charge and negative charge. This is right statement. Statement two.

[01:41:58]Statement two. Atoms of each element are stable and emits their characteristic spectrum. Spectrum.

[01:42:07]Okay. So unstable atoms unstable.

[01:42:15]So therefore it is wrong statement.

[01:42:17]Statement one correct. Okay. So both eliminate statement one is correct.

[01:42:21]Statement two is uh statement two is incorrect. Okay. Say statement is statement two is incorrect. Therefore option B is the correct answer. Okay. So option B is the correct answer. Option B is the correct answer. Okay. Now let's move on to the next question. Okay. So next question.

[01:42:38]Yes. The terminal voltage. Okay. So that is the terminal voltage of the battery whose emf is a 10 volt and internal resistance that is 1 ohm when connected through an external resistance of 4 ohm as shown in the figure.

[01:42:53]Okay. So terminal and internal resistance. Okay.

[01:43:00]And the next one.

[01:43:03]Okay.

[01:43:05]Okay. So I into R.

[01:43:09]But what about I sir? I that is equals to Eid R + R. Okay. Yes sir. E value 10 and R value is a four one. So 10 divided by five. It is a two. So current that is equals to 2 ampere. Okay. So that is current that is equals to 2 amp. Right?

[01:43:26]Yes sir. And next V that is equals to I.

[01:43:29]I value two. R value it is four. The terminal voltage that is equals to 8 volt. Okay. So 8 volt is the right answer. Okay. Option B 8 volt is the right answer. Okay. So 8 volt is the right answer. Okay. So 8 volt is the right answer. Okay. So 8 volt is the right answer. B.

[01:43:49]Very good. And the last question. Okay.

[01:43:51]So last question. Last question of the session. The quantities which have same dimension same dimensions as of those solid angid.

[01:44:15]angle dimensionless. Okay. So what is the dimension of you know solid ang right? So stress force force per unit area okay and therefore right answer. So that is option D. Okay. is option D is the correct answer right so dimensionless therefore option D is the correct answer got my point okay so total 45 questions are okay yes that's for you know today's session okay so that is for today's session okay now if you have any question please do let me know okay so if you have any question please do let me know if not we can wind up the session Yes.

[01:45:21]Answer option D 13%.

[01:45:30]Option D.

[01:45:40]Right.

[01:45:44]Rajasri and Kiri and Rajasri and Rajas different names and Islam and Dya and Niha. Okay. Niha and Kella.

[01:46:04]Okay. So congratulations top three and top 10. Okay. Right. Fine. So that's it for today's session. Next class. Till then take care. Bye-bye.