To find the shaded area of a semicircle inscribed in a right triangle with given tangent lengths (AP = 8, CP = 9), apply the tangent property (PA = PB), use the Pythagorean theorem to find the triangle's hypotenuse (BC = 15), then apply the Secant-Tangent Theorem (CP² = CQ × CB) to solve for the radius (x = 24/5), and finally calculate the shaded area by subtracting the semicircle area (πx²/2) from the triangle area (1/2 × BC × AB = 60), yielding 60 - 288π/25.
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90% Failed to Solve This Math Question!追加:
Given a semicircle inside a right triangle and AP is 8, CP is 9.
And we have to find shaded area.
So, in any circle from any point P, if we make two tangent, suppose this point is A and this point is B, then PA and PB, they will be equal.
So, from point A, AP and AB, they will be equal.
And AP is 8.
That means AB, it will be also 8.
And now, in triangle ABC, AB is 8, AC is 8 + 9, that is 17.
So, we can find BC.
BC squared, it will be AC squared minus AB squared.
And BC squared is 17 squared minus 8 squared.
And BC is squared is 289 minus 64.
So, BC is squared is 225.
That means BC it will be 15.
BC is 15.
Now, suppose the center of the semicircle is O and the radius is X.
Then, BO it will be X and QO it will be X.
And now, BC is 15. BO is X. QO is X. So, CQ it will be 15 minus 2X.
And in any circle from any point P if PT is a tangent and AB is a chord, then PT is squared it is PA times PB.
So, from point C CP is a tangent and QB is a chord.
That means CP is it will be CQ times CB and CP is 9 is squared CQ is 15 minus 2x times CB is 15 and it is 81 is 15 minus 2x times 15 and 3 times 27 is 81 3 times 5 is 15 so 27 divided by 5 it is 15 minus 2x so 2x it will be 15 minus 27 divided by 5 and it is 75 minus 27 divided by 5 that will be 48 divided by 5 and 2x is 48 divided by 5 that means x will be 24 divided by 5 now shaded area it will be area of ABC minus area of semicircle and area of ABC it will be 1 over 2 times base is BC and height is AB minus area of semicircle it will be pi times radius is x s squared divided by 2 and it is 1 over 2 times BC is 15 AB is 8 minus pi over 2 times x is 24 divided by pi x is 24 divided by pi s squared and 2 times 4 is 8 so it is 60 minus pi over 2 times 576 divided by 25 and 2 times 288 is 576 so it will be 60 minus 288 pi divided by 25 and this is the final answer >> [music]
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