GAS Sudoku Walkthrough - Less Taxing Math by Philip Newman (2026-04-15)

Added: 2026-05-04

[00:00:00]Good morning my friends. I'm Clover. Uh this This is Benny.

[00:00:05]And today we are solving less taxing math by Philip Newman. Oh, this is This is genuinely approachable Sudoku, by the way, in case you knew here.

[00:00:15]Um this is a killer Kropki pair Sudoku.

[00:00:20]So we have normal Sudoku rules, meaning that we're placing the digits 1 through 9 once each in each row, each column, and each outlined 3 by 3 region.

[00:00:28]And on top of that, there are some dashed outline cages in the grid. Each of those cages has a clue in its top left corner, and the clue tells you what the digits in the cage have to sum to.

[00:00:41]And then there are also some black dots and some white dots in the grid.

[00:00:45]Wherever you see a white dot, the two surrounding digits are consecutive, and wherever you see a black dot, the two surrounding digits are in a 1 to 2 ratio. In other words, one of them is twice as large as the other.

[00:00:58]And that's it. So let's solve.

[00:01:02]So I'm going to start up here with this three cage because it's always one and two.

[00:01:08]Nine would normally be either four and five or three and six, but the two digit digits have to be in a 1 to 2 ratio, so that's three and six. That means the 15 can't be 6 + 9, so it's 7 + 8.

[00:01:19]Seven isn't in a 1 to 2 ratio with any other Sudoku digits. That's going to be an eight, making this a four and a nine, and our last digit in the in the row is a five.

[00:01:28]Now this has to be consecutive, so this guy can't be a one because that would mean we had two twos in the region. So that's going to be a two three four, and our last digit in the 15 cage is going to be an eight.

[00:01:42]Four is in the ratio with a two or an eight, and there's already a two in the region. So that's going to be an eight.

[00:01:49]Those have to be seven and nine to finish the 24 cage.

[00:01:53]The three in the 15 cage makes this a six, and then these are from 5 7 or 9.

[00:02:00]All right. Now our remaining digits are going to sum 1 5 6 and 7 and 9. So that is a total of 5 6 and 7 is 18 + 1 is 19, so that's a total of 28. These have to sum to 19, so the missing digit is nine.

[00:02:19]And this has to be either six or eight, and there's already a six in the column, so that's going to be an eight, making this a four.

[00:02:26]These will be our 5 6 and 7 like that, and then there's our one, which tells us how this resolves.

[00:02:33]2 + 4 is 6, so to finish off to go to 14, we have to place an eight.

[00:02:38]Now these three um three digits that are all in a 1 to 2 ratio can't can either be 1 2 4 or 2 4 8. 2 + 4 + 8 is way too big to be a 12 cage, so that's going to be a 1 2 4, making our last digit a five.

[00:02:55]Five is consecutive with four and six.

[00:02:57]There's a four there, so that's going to be 5 6 7. 6 + 7 is 13. To make 16, we add a three. That's a nine.

[00:03:05]These guys have to be 6 7 and 8.

[00:03:10]Like that, and then that's going to be a three with a two to sum to five.

[00:03:14]Our last two consecutive digits are going to be five and six, and then we have a one right there.

[00:03:19]Seven is consecutive with eight, which makes this cell a four.

[00:03:22]These are going to be one and nine.

[00:03:25]4 + 8 is 12, and so I need a nine here.

[00:03:28]There's a seven in that region, so that's nine, that's seven.

[00:03:34]Seven will always be 1 2 and 4.

[00:03:37]This cell can't be two or four because those are already in the row, so that's a one. It's in a 1 to 2 ratio with a two, and then that's a four.

[00:03:45]These are going to be 2 6 and 8. Neither of these can be eight by Sudoku.

[00:03:51]So that'll be my eight.

[00:03:55]Um in this cage Well, actually we can't quite do that just yet, not easily anyways. So these are going to be 1 2 3 4. One can't be in those cells, so that's a one. Four can't be in those cells, so there's a four, three, and two.

[00:04:11]These are going to be 3 5 6 and 9 to finish their region. Those can't be threes, that can't be a six.

[00:04:19]These are going to be 3 7 and 8, and these are going to be 2 and 5, which resolve.

[00:04:29]That can't be three or eight, so that's a seven. These sum to 12, that must be a six.

[00:04:36]Eight and a three there.

[00:04:38]Five to finish off this column, so we eliminate five from here. We also eliminate six from here.

[00:04:45]And that finishes the left part of the grid.

[00:04:48]To finish this row, we're going to need a seven and a six, which will go like that.

[00:04:54]And here we need a three and a five to finish the region.

[00:04:58]We need 1 2 3 and 9 to finish this region.

[00:05:02]This can't be three or nine.

[00:05:07]And that finishes the right half of the grid, and then classic Sudoku should take us home. We still need a one and a seven there and there.

[00:05:16]And that is how you solve Philip Newman's less taxing math.

[00:05:19]Hope you guys liked that one. The link to solve it yourself is in the description of this video, and I will see you again in three days.