Revision class for 2026 utme candidates 🔥

Added: 2026-05-05

[00:00:38]Understand?

[00:01:00]Okay.

[00:01:06]All right.

[00:01:10]Hello guys.

[00:01:15]I hope you can hear me. I hope you can hear me. So, how many people have joined the daily press for LGB?

[00:01:28]All right. Now, good evening, guys.

[00:01:35]Okay.

[00:01:37]All right.

[00:02:07]Now, so good evening guys. How are you doing now? So, tonight will be what be doing reisions on chemistry, physics, biology. So that's what we'll be doing today. So revision on what on physics, chemistry and what and biology.

[00:02:28]I hope we are ready for tonight's session.

[00:02:31]So let's see how many people have joined.

[00:02:36]Okay. Now many people have joined.

[00:02:40]First of all, we are starting from chemistry.

[00:02:44]We are starting from chemistry.

[00:02:47]We are starting from chemistry.

[00:02:50]We are starting from chemistry.

[00:02:53]We are starting from chemistry. Now which part are we starting from chemistry? We are starting from stometry.

[00:03:03]We are starting from stometry.

[00:03:07]We are starting from stoometry.

[00:03:10]So the part of the chemistry that we are working on today is stokometry. So we are going to solve question.

[00:03:18]Then other what? under acid base and salt. I think I've dropped videos on that one. We are going to talk about electrolysis.

[00:03:27]Then after electrolysis we have what we have we are going to talk about gas laws. After gas laws I've dropped videos on the reactions we going to talk about dropped a video on solo chemistry all those energetics we're going to drop we are going to talk on it. Then we move to organic chemistry and I will solve questions on each question under organic chemistry. Then after the chemistry we can now move towards physics. Then from physics I move toward to biology. So I hope you guys are with me. I hope you guys are with me. I hope you guys are with me.

[00:04:08]Now we are starting from the stometry.

[00:04:12]We are starting from we are studying fromumentary.

[00:04:21]Now without wasting much of our time today I won't divine documentary I only give you what are the formulas to know on documentary. Now what are the important formula to know under this documentary? Because without this formula you cannot do anything. Without this formula you cannot you cannot do anything. I firstly list those formula for you that you need for your exam. I do the formula that you need for your exam. The first one is what? Number of mole is equal to mass. Anywhere you see small M, I'm talking about mass.

[00:05:04]Anywhere you see capital M, I'm talking about mass. Anywhere I write small M is what is your small is your mass. But anywhere you see what capital M is what is your mass. So that's the first what?

[00:05:19]The first formula under what? Under the stoometric that you have to know. Number of M is what is the mass over mass. So anywhere you see M the M stand for what?

[00:05:30]M stand for the what? M stand for the small mass. Y capital M stand for what?

[00:05:37]For the m what? Molar mass. Now that's the first one. The second one is what is number of mole is equal to concentration?

[00:05:49]Concentration time volume over 1,000.

[00:05:56]This one you tell me ask this one very very well. You tell me what they usually ask this formula very very well number is equal to concentration. You see my concentration is in mole per dmq.

[00:06:11]My concentration is what is in mole per dmq. So sometime I can call it marity. I can call it marity.

[00:06:21]Sometime I can call it marity. So this is what is mole per what mo per dmq. So number of mole equal to what concentration multip by volume. Now if your volume is given in cm cube we are going to convert it what to dmq by what?

[00:06:38]By dividing by by 1,000. Do you get it now? So number of mole equal to what?

[00:06:43]Concentration volume over 1,000. So making how many formulas? Two formulas.

[00:06:48]So number three is what? Number of mole equal to number of particle or let me say number of atom over a constants number of mode is equal to number of divided by a constant. So making how many? Making three. The first one is what? Number of is equal to what? Mass over mass. I told you when you see your small M that's the mass. When you see your capital M that's the mass. So that's the first one. Second one concentration time volume over 1,000.

[00:07:29]Now when can we use this formula is when your volume is given in 30 m cube. But if your volume is given in what? In dmq.

[00:07:39]You're going to use N= to ZV if your volume is given in dmq. But if your volume is given in cm cube, what are you using? We using this one. Number of equal to concentration time volume one. I hope you are following me. Now that's it. Now number three is what?

[00:07:59]Number of mode is equal to number of atoms over a constant over avocado constant. But do not forget that.

[00:08:10]Do not forget that now a constant avocado constant we use NA to represent avocado constant. What we use NA to represent a constant we use N to represent a constant. So anywhere you see N E is our avocado's number or constant. So which is equal to what?

[00:08:32]6.02 * 10^ 23. That's that's the unit of that's what the value of a constant. So number of now what? Number of atom divided by 6.02 power 23.

[00:08:52]Are we there? So now that's what that's number three. That's number three. Now number four number of mole is equal to PV / T.

[00:09:07]Number of is equal to P V /. Now where my P is pressure, my V is volume. My R is gas constant. Now P is pressure.

[00:09:22]P is pressure.

[00:09:24]V is volume.

[00:09:28]How is what is gas constant?

[00:09:33]How is gas constant? Why T is what is temperature?

[00:09:40]Now, so number of is called what? P V / T. What's what's the P? P is the pressure. What's the V? V is the volume.

[00:09:48]What's the R? Gas constant. What is the temperature? So now the temperature, the what? The rate, the gas constant. The gas constant is 0.0821 ATM dmq.

[00:10:08]Just put the value. Just put the value.

[00:10:10]There's nothing concerned with your unit. So this is what this is the value of the gas constant. So the value for the gas constant is what? 0.0821 because j minus give you what might not give you the what? The value of what? Of the gas constant. So now we can just say this we can just say the gas constant is equal to 0.0821 that's the that's the value of the gas constant. So the number five formula is what the last one is what number of is equal to volume over volume at SDP.

[00:10:52]the volume of gas over volume at STP. So that's the last formula. So number of is equal to volume of gas over volume.

[00:11:04]Now that is the volume given. The volume given if they give you volume and they now ask you to calculate your what your number of mole just know that the volume they give you divided by volume at STP and volume at STP volume at STP is equal to 22.4 4 dmq or 22,400 cm cube. So the volume at STP is what is 22 what4 dmq or what or 22,400 cm cube. I hope you are following me now. Hope you can hear what I'm saying.

[00:11:52]I hope you can understand everything we are doing. If you can understand what I'm doing and you can hear me clearly, please type I can hear you. Type I can hear you. And please like it. Press the what? The like button. Please like it.

[00:12:06]Before we continue, right? Can you hear what I'm saying now? Can you hear me?

[00:12:11]Can you hear what I'm saying?

[00:12:15]Can you hear what I'm saying?

[00:12:18]Please, I want you to talk. Can you hear me? Okay. I praise I can hear you, sir.

[00:12:23]Okay. Okay.

[00:12:25]Okay.

[00:12:27]All right.

[00:12:28]Now, very good. Now, so you can hear me now. Let's continue. Let's continue. So, what we have been saying since morning is what is number of move. Now, I want to write the formula again. I want to write the formula again because some people are just joining. I want to write the formula again. So, what I call the first one? The first one is number of mole mass. That's mass over mass. Second one, number of mole= to concentration time volume 1,000. So number three, number of mole equal to number of atom over a constant over a constant. So number four number of mole is equal to PV over RT. The last one number of mole equal to volume of gas divided by 22.4 dmq. So as a jam bank you have to know all these formula before we can proceed before you can do anything under what under stoometry you have to know all these given formulas number one number of mole is equal to mass over mass number two concentration time volume over 1,000 number three number of atoms over a constant what's avocado constant Avocado constant is equal to 6.02 * 10^ 23. Number four, number of mole is equal to period * volume over gas constant multip.

[00:14:17]Number five, number of mole equal to volume of gas volume of gas at STP which is equal to 22.4 dm. Now do you know do you know something? I can equate all of them together. I can equate the together. It mean that I can say mass over mass mass over mass can be equal to this one CV over 1,000. I can also say mass over mass can be equal to number of atom over 6.02 * 10^ 23. I can say mass over mass can be equal to volume of gas over 22.4 and four. Why? Because they are both number of number of you can equate all of them together depending. So you can equate any of them together. I get now. So I can equate number of mode. The first one I can equate to be what to be to be equal to the second one. Why? Because this number of this number of mode this number of mode this number of mode this number of mode. You can equate all of them together. Since they are the same thing they are both number of modes. So I can equate them together. So the first one number of molecules mass over mass can be equal to concentration time volume over what over 1,000. The second one I can say what massar mass equal to what number of atoms overall constant. I can say mass over mass can be equal to volume of the gas over 22.4 dmq. Can we continue now? So less of question under it. Less of question that is less of question that is less of UTM question under it because the people actually it was they saw question they actually saw question under stoometry today. So how can we do it when we see question two?

[00:16:33]Okay. Now equation is that okay what is the mass?

[00:16:45]What is the mass of sodium hydroxide?

[00:16:49]Now question number one.

[00:16:53]What is the mass of sodium hydroxide dissolve in 1.8 g of water?

[00:17:22]If the Okay.

[00:17:31]What is the mass of sides that dissolve?

[00:17:46]Let's let's start from the simplest one.

[00:17:49]Let's start from the simplest one because this one let's start from the simplest one. So there are something else to talk about. Okay. Now let's start from this one.

[00:18:02]Okay.

[00:18:06]How many moles?

[00:18:12]How many moles of aluminum?

[00:18:23]Aluminium is in 3.01 01 * 10^ 23 atom of aluminum.

[00:18:46]Now let's take this question together.

[00:18:50]Let's take this question together. Now how many moles of aluminium is in 3.01 01 * 10^ 23 atoms of aluminium. Now you see this question what I going to do solution. Now how many moles that is number of mole is what is unknown now of aluminum. Now number of atoms how many moles of aluminum is in 3.01 01 * 10^ 23 atoms that is number of atom number of atom is equal to what 3.01 * 10^ 23 I get it now but don't forget that avocado constants is equal to 6.02 02 * 10^ 23 that means number of mole = aro constants are you there? So that means number of equal to so what's your number of atom they give you that is 3.01 * 10^ 23.02 2 * 10^ 23. So you cancel that number of equal to 6.02= 1 this year 2. So you going to have 0.5 moles.

[00:20:27]So that's how to calculate it. Now do you understand it? Do you understand what you did? Any question? Let me check. Maybe you have any questions. Do we understand it? How we get number of moves before we continue to the next one? Any question before we move to the next one? Any question before we move to the next one?

[00:20:49]Any question, please? Can you hear what I'm saying? Any question? Do you do you understand how we get 0.5 more?

[00:20:58]Do you understand how we get 0.5 more?

[00:21:01]Okay, Ftoria, you understand?

[00:21:05]How about another person? Do you understand how you get 7.5 mole?

[00:21:09]Now Ty, you don't understand why. Okay, check the question again. Check the question again. He said, how many moles of aluminium is in 3.01 * 10^ 23 atoms.

[00:21:26]Okay, you understand? Okay. Okay. Okay.

[00:21:30]Okay. Okay. Okay. Now that means we can move So if you understand you can move to the next questions. So we can move to the next questions. So question number two.

[00:21:44]Question number two.

[00:21:47]Question number two.

[00:21:49]Question number two.

[00:21:52]Question number two. Okay. Now the volume the volume occupied of a gas at STP is 500 cmq.

[00:22:22]What is the molar mass?

[00:22:36]of the gas. This is a UTM question.

[00:22:41]This is what ut is uter question. So how can we attempt this question? Now let's check it very well.

[00:23:02]The volume occupied by 1.58 g of a gas at STP is 500 cm. What is the mar mass of the gas? Now very simple. What do we need? Write it down. What do we need?

[00:23:18]Now they said the volume occupied the volume. The volume is what? Is 500 cm.

[00:23:26]The volume they give us is what? Is 500 cm. And the mass the mass is in gram.

[00:23:33]The what? What is in gram? The mass is in g. So we given the mass in g 1.58 g. The mass is in g 1.58 g. Are we there? Now what is the mar mass? Mass mass capital m is unknown. We don't know it. And they now mention something that at STP now class what are you going to do at STP? Who can tell me? Who can tell me? They mention at STP it means that what are you going to do? They said the volume occupy.58 g of a gas at STP. Now what happened at STP class? What happened at STP? Who can tell me what happened at STP? Anybody?

[00:24:18]What happened at STP? Anybody?

[00:24:22]The mention at STP what happen? What are you going to write? They mention at STP to write at STP. Now the temperature will be 273 Kelvin while per will be 180. Yes. But in this question we don't need it. Just give me the volume at STP.

[00:24:43]Your volume at STP volume at STP is= to 2. Sorry, 22.4.

[00:24:54]But go and look at what they give you.

[00:24:57]The value the volume they give you in the question is in cm cube. That means the volume must also be in cm cube. That's what 22,400 cm cube. That's what we need. That's what we need. Exactly. Thank you. So the volume will be 22.4 dmq. Exactly. Now class now don't forget that I told you that we can relate the two the two formulas together that is no we have for for the first one it will be mass over mass right second one it will be volume over 224 0. So you can equate the two together.

[00:25:43]I hope you are getting that. So if you look at it now, we can what? We can use number of equal what? Mass over mass. So we can now equate it together. That is mass over mass must be equal to volume over 22,400 cm cube. So what's the mass? The mass they give me is what? 1.5 is over. What is the mass is unknown? We don't know it is equal to what they give me 500 over 224 0. We going to cross multiply. That means you have what.58* 224 0 = to 500 m. So the 5 by 500 by 500. So 500,500. So m will now be equal to now if you press calculator don't forget that your UTM has calculator. So if you press calculator 1.58 * 224 0 now that will give us 35 392 / 500. So our mass our mass will now be to what? Nowipide by 500. So we have something like 70.78.

[00:27:08]Now 70.78 approximately 71 g per mole. So approximately 71 g per mole. So option 28 32 option say 44 option D 71. So that is what that is the best answer. So 71 is the correct answer. So anybody any question any question you don't understand which part sir please I don't understand what formula did you use I already told you that the formula we use the first one is what mass over mass second one is what volume over 22400 I told you that just write down your parameter when you write when you write your parameter I told you earlier I hope you join us from the beginning that you can equate the volume we can equate the what you can equate the two the two what formulas of number of mole you can equate the two together so you can equate mass over mass you can equate it together with with volume over 22,400 cm cube so the mass has been given to be 1.58 the mass is what they asking us to calculate that is unknown so it can be equal to now 500 over 22 2,400 cm cube. Why? Because I can use volume of a gas divided by volume at STP to know the number of moles. At the same time, I can use the what? Mass over mass to know number of mole. By the time you press the two, it must be equal to what we have in the in the left hand side.

[00:28:47]That is right hand side must be equal to the left hand side. Now I mean if you press 1.58 1.58 over 70 over 71 you're going to get 0.02 you're going to we going to what we are going to get 0.02. Now if you check 500 over 22,400 we going to get 0.02.

[00:29:14]It means that we must have the same value for the number of moles irrespective of the value or the formula you use. That's the meaning what it give us. It must be the same thing as over volume at STP. So it must be the same value. Hope you get what I'm saying. Now if you can hear me please press I can hear you sir. Press I can hear you sir. Please I want you to what?

[00:29:39]To write I can hear you and I understand everything we have been doing. Please very very important. I'm waiting for you. Can you hear what I'm saying? Can you hear me? Can you hear me? Can you hear what I'm saying? And do you understand what you are saying? I am waiting for you. Can you hear me? We have a long way to go. We have many things to do.

[00:30:01]We have many to do. We have a long way to go. All right. I can hear you and I understand. Okay. I can hear you and I understand everything, sir. I can hear you, sir. I can hear I can hear you and understand. Very good. Now, let's continue to the next question. The next question. Let's continue to the next questions. To the next question to the next questions to the next questions now. All right.

[00:30:29]The next question say okay calculate number three. Calculate the volume.

[00:30:49]Calculate the volume in cmq in cmq of 1.4 mo per dmq solution.

[00:31:09]Solution of hydrochloric acid that will react that we react with 3.35 g of that will react with 45 g of a solution solution of HCl option A 67.77 option B 6 743 option C 67 43 option D is 0.6 6 743.

[00:32:26]Now, anybody who can attempt this question, who can attempt this question?

[00:32:32]Who can attempt this question? Let's see who will get the the question. Who will get it correctly? Let's see who can attempt the question.

[00:32:42]I give you just 2 minutes to solve it and let's see who will get who get the I'm waiting 2 minutes to stop the pressure.

[00:33:05]I am waiting 2 minutes to solve the question.

[00:33:11]Okay, it is not clear.

[00:33:14]Okay, let's let's see other people. I will drop the solution. I don't the solution but let's see other people let's other people let's see what they can what they can get it is blow it is not it is not blow this is not blow now how about like this can you now see like this can you see it clearly how about like this can you see like can you see like Emmanuel see like this now.

[00:33:58]Emmanuel, how about you? Can you see it clearly?

[00:34:03]Okay. Very good. All right. So, attempt this question. Let's see who we get it.

[00:34:10]2 minutes. You know, in your question, in your exam, you only have what? You only have h 40 seconds to answer one question in your exam. You only have what? 40 seconds to answer a question.

[00:34:22]So let's go. Who will attempt this question and give me the answer?

[00:34:26]Assuming that your exam know your exam is tomorrow. Assuming that this is what you see in your exam. Assume that this this is the kind of question you make your exam. So what will be the answer?

[00:34:44]I'm waiting.

[00:34:47]The time is going.

[00:34:50]What is the answer?

[00:34:54]Okay, Victoria. A Victoria said she pick a Victoria says she pick a. Okay.

[00:35:04]Victoria says he pick a. Who else?

[00:35:08]Who else? She says she pick a Victoria said she pick a. So who else?

[00:35:14]I'm waiting. Who else says she pick a say he pick a? So who who is the next person? Unice are fat. Tell me like what's your answer?

[00:35:33]What is your answer?

[00:35:37]What is your answer?

[00:35:40]Okay. Emmanuel Emanuel Pix C.

[00:35:44]Emmanuel P.

[00:35:46]Emmanuel Pixie. Okay. Victoria P.

[00:35:50]Emmanuel Pixie. So, we are waiting for many people. We are waiting for many people to pick their own answer. We are waiting for many people to pick their answer before we can drop a solution and move to the next one.

[00:36:15]How about orders?

[00:36:26]I'm waiting for you guys.

[00:36:33]So pick A, Emanuel pick C. So who will pick D and who will pick B and if okay Anifa A.

[00:36:52]All right let's continue.

[00:36:56]Solution solution calculate the volume in cmq our volume is unknown our volume is unknown of 1.4 mo per dmq that is my concentration 1.4 4 per dmq.

[00:37:24]That is my concentration C. My C is a M per MQ. Now of HCl. Now what we going to do here is that we are going to calculate the molar mass of HCl. First mar mass of ACL. You see J will not give you their mass their mass number. You have to know it off hand. So the mass the mass number of hydrogen is one plus the mass number of chlorine is 35.5.

[00:38:02]So if you add the two together you're going to have 36.5 g per mole. So what I calculate here is called my capital mass.

[00:38:14]Are you getting that? And my mass, my small mass has been given to be 3.35 g.

[00:38:24]So now which formula can we use? I told you you have your mass, you have your mass, you have your C, you have your F.

[00:38:32]So which formula you going to use? And your volume, your volume is in cube.

[00:38:37]That means we using this formula mass over molar mass equal to CV over 1,000.

[00:38:49]This is the formula we're going to use.

[00:38:51]Now if I ask you that why do we use that formula? If I ask you that why do we use that formula? Anybody? Why do we use CV over 1,000 and not CV alone? Why do we divide by 1,000? Anybody? Why did I divide CV by 1,00? Why did I divide it by 1,00 and not CV? Anybody? Why?

[00:39:14]Anybody? Why did I divide it by 1,000?

[00:39:21]Why?

[00:39:23]Why? Why do we divide our CV? Why do we divide it by 1,000? Why can't we just leave it as CV? Why do we divide by 1,000? Anybody? I'm waiting.

[00:39:37]Because it is same. I love you. I love you. I love cook. I love you guys. Victoria love you because they said we should calculate our volume in cm cube. Very very very simple. But assuming is in dm cube now you are going to leave it as CV. Now so what is my mass? My mass is what is 33.35 / what's my mass last? Mass mass is 36.5 equal to what is my concentration? 1.4* what's my volume is unknown over 1,000.

[00:40:22]So you multiply here I'm going to have 3.35 * 1,000 = to what? 36.5 * 1.4 * V. So we going to divide all by what?

[00:40:37]Okay. Now if you press your calculator now you're going to have you press your calculator very well. Now 3.35 * 1,000 * 1,000. So it give us it give us 3350 equal to now 36.5 * 1.4 4. So that will give us 51.1 V. So divide by 51.1 51.1.

[00:41:14]So this one this one V equal to what? So now 335 3350 51.

[00:41:24]So it give us 60. Now is this.5 + 1.

[00:41:37]Now times 1.4 is 1.5. Nowide by 51.1.

[00:41:53]So we get 65.5 57 cm cube.

[00:42:03]This is the answer. Now this is the answer. But in the options that means none of the option is correct.

[00:42:13]None of the option is correct. Let me check.

[00:42:27]So none of the option is correct. Yes, that's correct. Now who got who got the same thing?

[00:42:36]Who got the same thing as 65.557?

[00:42:41]Who got the same thing as 6557?

[00:42:47]Yes, that's correct. That's correct. So in the options that means they they the they they put wrong options. So they put wrong option. Do you know what do you know what they did? Do you know what they did? So they use 35.5.

[00:43:03]So they not add that of uh they not add that of the hydrogen. So they use only that of chlorine which is not possible.

[00:43:12]So then exactly if you are in exam if you if you have this kind of question in your exam. So if you have this kind of expression in your exam like you calculated your own to be like maybe 70 and in the youns the answer is 65.557.

[00:43:46]So let's continue. Next question.

[00:43:50]Next questions.

[00:43:52]Next questions.

[00:43:54]Next questions.

[00:44:00]Next question.

[00:44:05]Next questions. We given that's number four.

[00:44:14]A 433 cm cube of A 0.6 75 molar solution.

[00:44:38]Solution of Na2 SO3 contains what mass in gram of solute. Good.

[00:45:10]Given that sodium is 23, sulfur is 32, oxygen is 16.

[00:45:25]Option A, we have 3 0 1 33.

[00:45:34]B we have 515 C we have 36.8 8 B we have 3 6 9 0 0 now so who can attempt this can attempt this yes I said assuming you you meet it you meet this kind of question your exam go for the one that looks similar which is A so look at the one that's that looks similar so A looks familiar like it's very very similar how to is very very similar to what you get. So you're going to pick the one that has the higher value closer to what you get.

[00:46:25]Do you get it now, Emmanuel?

[00:46:32]We are going to pick the one that's very close to it. I think you understand it now, manual.

[00:46:43]All right. Now attempt that question.

[00:46:46]All right. All right. I Yes, you understand. Very good. Now attende that question.

[00:46:54]It is not blur. It is your own side that is blur.

[00:46:58]It is your own side that is blur. Maybe it's your phone. Maybe it's network.

[00:47:02]This is very very okay.

[00:47:07]So we have scholars. Ftoria pick C.

[00:47:13]Okay. Larry also pick C.

[00:47:17]We also pick C. All right.

[00:47:34]So how about like this? Can you sit like this?

[00:47:42]All right.

[00:47:44]Okay. Now, let's go. I think C is the correct answer because people are getting C. Let's check it.

[00:47:55]Let's check this.

[00:48:08]very good at you guys now. So I think most of you pick what you pick C right >> okay we are coming let's quickly solve this question solution solution solution now we have um Okay, look at that questions maybe.

[00:48:50]Okay, now we have a 4 33 cm cube of a 0.675 molar solution of sodium sulfite contains what mass in g of solute. Now it says that we are given the volume.

[00:49:16]Our volume is what? Is 433 cm cube.

[00:49:23]And this is the concentration. You see anywhere you see capital m this can be the same thing as mo per dmq is the same thing I now. So that means my c is what is 0.6. 6 75 mo dmq is the same thing. Do you get so the same thing now? So what mass? My small mass small m is unknown. My small m is unknown. What m is unknown. So do you know that I can calculate my capital m? I can calculate my capital m. No I was given what I was given sodium sulfite.

[00:50:08]That means I'm going to calculate my was my capital M here. Now I want to know my capital M. So how many sodium do you have here? Two sodium that is two into brackets. What's the mass number of sodium? 23. You get plus what the mass number of sulfur? 32 plus what is the mass number of oxygen is what is 16.

[00:50:35]That means what? my mar mass before the now this one this one is what 46 + 32 plus 48.

[00:50:48]So add everything together was 4 6 + 3 2 + 4 8 that is 26.

[00:51:04]So that's my my capital M. So which formul to use now that is mass over mass equal to CV since is in cube we are dividing by 1,000.

[00:51:20]What's the mass? We are looking for mass is unknown. What's my mass? 126 is equal to what is my C? 0.675 675 * what's my volume class? Volume is 433 F 1,000.

[00:51:40]So if multiply I'm going to have 1,00 m = Now multiply 126 * 0.6753.

[00:51:57]So divide by 1,000 by 1,000 that means m will be equal to now multiply together what I going to have to 6 * 12.6 75 * 433 over 1,000.

[00:52:20]So we going to get 36.8 26 g. So C is correct.

[00:52:30]So C is correct.

[00:52:34]C is correct.

[00:52:36]So see is correct. Now let's take a break. Let's take a break. C is correct.

[00:52:44]So let's take a break please. Now we are coming back again. So I want to go and attend something very very important.

[00:52:52]Then just give me like 15 minutes. We are coming back again. Thank you.