Labeling such a trivial equation as "Olympiad" level is a clear case of academic clickbait. While the explanation is accessible, it lacks the rigor and complexity expected from high-level competitive mathematics.
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Olympiad Mathematics | Find X | Can You Solve This?Added:
Hello everyone, you are welcome. Today we have a very interesting exponential math problem.
What is the value of x here in x raised to power x is equal to x squared?
So let's start our solution. So how can we solve this beautiful exponential and algebra math problem?
First of all, here we will divide both sides by this one expression. So this one equation will become this is simply x raised to power x divided by x squared is equal to and the right hand side will become x squared divided by x squared.
And in the right hand side, this x squared and this x squared will be cancelled. And the left hand side in both numerator and denominator, both the bases are same.
Here we will use same base exponential method property. That is here we can write a raised to power m divided by a raised to power n as a raised to power m minus n.
So using this exponential method property here, this left hand side will become this will become x raised to power x minus 2 is equal to and this will become 1.
Here we will take natural log on both sides. So this expression and this one equation will become ln of x raised to power x minus 2 is equal to ln of 1.
And in the left hand side, we will use a log property. That is here we can write natural log of x raised to power a as a times natural log of x.
So using this log property here, this left hand side will become this will become x minus 2 times natural log of x is equal to here natural log of 1.
This is equal to 0.
So, we will replace this with 0.
Here the product of these two expression is 0. So, here either this expression will be 0 or this one will be 0.
So, from here we will get x - 2 is equal to 0.
Or ln of x is equal to 0.
So, let's solve this one equation first.
Here we will take this two to the right hand side. This gives x is equal to 2.
So, this is our first real solution.
And we will try to find out the value of x from this one equation. So, how can we solve this one equation?
Here we will take e in the base in both sides.
So, this will become this will become e raised to power ln of x is equal to e raised to power 0.
And here we know that e raised to power ln of a is equal to a and e raised to power 0 is equal to 1.
So, using this result here this one equation will become this will become x is equal to 1.
So, this is the second real value of x.
So, finally here we have two values of x in this problem.
x is equal to 1 and x is equal to 2.
And we will try to verify these values of x that as these value of x verify this interesting algebra and exponential equation or not.
So, first we will try to verify x is equal to 1.
To verify x is equal to 1 here we will write our equation again.
Our equation is simply x raised to power x. This will become 1 raised to power 1 is equal to 1 raised to power 2.
1 raised to power 1 is simply 1 is equal to and 1 squared is again 1.
Here both sides are equal, so it means that x is equal to 1 is the exact and correct value of x.
And we will try to verify x is equal to 2.
So, our equation will become that will become 2 raised to power 2 is equal to 2 raised to power 2.
2 raised to power 2 or 2 squared is simply 4 is equal to 4.
Again, both sides are equal, so it means that x is equal to 2 is also the exact and correct value of x.
So, finally, x is equal to 1 and 2 are the exact and correct solution of this interesting algebra and exponential math.
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