States of Matter | Part 03 | Live session | Sahyadri Tutorials

[00:00:15]Okay, great, okay, okay, present, everyone's got it, I'll see later, why did I start the live stream now?

[00:00:23]Before that, I was checking your attendance.

[00:00:26]Okay, as usual, the children are joining. The most important question was the session in the afternoon, which was on current and electricity.

[00:00:35]Your response was very good. Very, very, very good.

[00:00:39]But what happened in the middle? It was cloudy. There was an internet issue here. And stream A happened. Well, but even then, the children joined. What did you notice in the afternoon? Do you know that the numerical value in the book was repeated once, not once, not twice, three times. That question was repeated, that is, fraction of current flow, the goniometer. And what did we learn in the afternoon? Do you know that there will be a lecture tomorrow afternoon? Well, it will be physics. It will be at 2:30 in the afternoon. What did you learn? Let me tell you what did you learn? The book is the main thing. The test book is the main thing. Do you want to study the CD? The book is the main thing? Okay, as usual, there are still 935 We are going to start the lecture okay okay now many children must have gone to Jaywala's house okay join immediately okay Shailesh sir's student is always equation X Vibha Jadhav hi ok okay we need to solve the problems of the textbook right Shambhu Kadam okay great okay let 's start and today we are not states of matter third lecture okay at the beginning I am going to do a little revision let's think a little on the convergence factor you and after that I am going to take an important law okay very very one minute everyone is present Siddhi Kadav Swaroop Sonmale good as always your Palak Khan Shaurya Salunkhe okay from standard Shaurya notes okay and we should get together to answer these questions anytime ok if you have any questions how long the session will last today let me tell you the session will be completed today itself in less than an hour if you look at it like that what I discussed with some children in the afternoon okay when here Numericals come in front of you like a one second saw but if I go at that speed you will feel a little scared oh you will think you did not understand anything so I am going to leave it slowly today too but what I want is that as soon as possible you ok golu after the lecture after the lecture I will call you myself p download your and power golu name so that I will know well or type power and message me there I will know the number etc. I will call you on that number ok because you are getting civil engineering in NIT Surat I will definitely guide you we will definitely talk after the live lecture well why is it possible to talk to you so much ok today is going to be very good well why golu COP CS ok I will tell you honestly I have made a video on the same topic tomorrow morning whether we are getting mechanical in COP or CS in VIT this question everyone has got the same question everyone has got the same question that if you go in core branches vs tech tech the cutoff is very high Okay and when we go to core, what should we do to get a top college?

[00:03:31]Take note of the moderate questions. It is absolutely correct to start. It is absolutely correct. I will wait for a minute or two more.

[00:03:38]You can also share the link with as many children as possible. Why should as many children as possible join as soon as possible and watch the lecture till the end? Yashraj Chavan Okay Vedant Kenjale Hi, are you alone? I have a call in two places. Okay Anushka Maan. Every question should be answered on time. Pranav Bhatresi. Okay Prithviraj Raj. Navghere.

[00:03:56]Navghere. Vedant Kenjale. All the children have joined.

[00:04:00]Let's take note of the question. Let's start, children. Let's start.

[00:04:05]What should we do today? First, keep your pen close.

[00:04:07]First, keep your pen close. Raghav, I have n't forgotten you. Baba, okay, let's make a separate video on this. Why should Uday Samant, who was the education minister from 2020 to 2020, tell everyone that 50% of the board should be brought. Mark C 50 percent mark but it has not been implemented yet how many years have passed it has not been implemented yet but it seems to be but it has not been done yet well first thing is what do I want ideal gas equation what do I want ideal gas equation let's type ideal gas equation and tell me ok at first let's do a little bit well why don't we let the answer come to you remember present started baba prajwal how many times do you apply present started once became five present ok answer this answer people call me dropper oh name change do n't think about people what people are saying we should show success people have to shut up remember I am waiting for ideal gas equation p e at anushka mane golu golu I feel good but still studying well let's p e nt ok then p e tell me number of mole formula given mass a such formula tell me number of moles I don't have to write number of moles formula tell me number of moles formula gun Mass A everyone said the answer is good why ideal gas equation P E AT I want the formula of number of moles Given mass I call it double I divide it by how to type it Given mass A molar mass Anushka again said ok Given mass A molar mass OK Now what do I do I am crossing a little I am bringing Ik Well okay and I am taking it here I am crossing it Let's go Well why mass stay here but volume Ik OK One two three four five six Six terms are here But mass A volume means density I got the formula of density Pum Rti got the formula of density What did I get Pm terms are correct This formula in it molar mass is constant R is constant Temperature But if it is constant Constant temperature Density Pressure will be directly proportional Write all this with me Cut Constant temperature Density and pressure are directly proportional If the temperature is constant, then the molar mass is constant, but if the molar mass is constant, then the molar mass does not change. Note that OK, come on, the number of students has almost doubled and we have to attend till the end. Remember the formula for the density of the gas: PM A RT PM A RT OK, very good, very good, remember PM A RT OK, understand what I am telling you, try to pay attention carefully. Now, look at what I am doing. First, I write the formula for the density. What am I writing?

[00:07:25]PM/ RT. Let's say pm divided by r.

[00:07:35]Tell me how I divided r. Then I am going to divide this also by the same.

[00:07:38]OK, tell me what I divided R by N. Type in what A means.

[00:07:44]Tell me what A means.

[00:07:47]OK, Aryan Pawar, we are taking Physical Chemistry, then I have to take Solid State, then Numerics, then Thermodynamics, then I have the solution. After that, I will tell you.

[00:07:59]Electrochemistry is chemical kinetics is ionic I am going to take PY Q of all of them OK Shlok Patil Present give a good answer Number Now I am asking you I am asking you Look OK Tell me Even after dividing the constant number, we get a constant Name that constant OK A Name this constant A This is also a constant Constant is going to get a constant but what is the same name R A OK Number K B Soham Ghadge is absolutely correct Bolen constant means R A This is the formula of Eq Bowman constant and understand Note that when I divide the molar mass by number, I get the mass of one molecule and I am going to call it small A Mass of one tum Call it one molecule and hence the formula of density of the gas is obtained Pm A kT Pm A kT Now you say Sir, above you wrote K Why did you write KT below I found this formula in the MCQ of CT I saw So now tell me you What's going on since afternoon? Our PYQ is also important. Who is P or K?

[00:09:24]Write it down. If you have written it down, message me as Dun.

[00:09:25]I will ask you what the formula is. What is P? A capital. A is capital. Capital.

[00:09:34]Malar mass. That is, remember that A is a molecular mass. A KT is also a formula.

[00:09:44]Thank you sir. Very much Atharva. 84% of my friends, definitely follow me. Thank you Atharva. Thank you. Thank you. Okay. Vedanta Kendra is very good. Bodsman Consent. If you have written it down, message me as Dun. If you have written it down, message me as Dun.

[00:09:59]Okay. Let's write it down. Tell me.

[00:10:02]Then what is the formula of density? Pm Aarti but M capital is required and Pm A KT M small is required. Note that OK. And this MCQ has been repeated twice. Then where to find it? Search in PYQ. Then after this lecture, you should search. Note that after this lecture, OK.

[00:10:21]Shlok Patil New College D Division is New College, our offline college in Kolhapur. Student is good why don Kendra Tanishk don ok Mahesh I remember yes we always remember Shlok Patil don ok now oh wait I have to take the conversion good why but what am I doing now look understand that you were writing this ideal gas equation I am erasing this and I have to take the revision today pressure says ok 1 newton per m² means one pascal means these are S units good why note what kind of unit is this SI unit is good one atmospheric now I am telling 1.013 xv3 10 f newton per meter s one bar if I think about it then it is only 10 re f newton per meter scr m me one atmospheric if I say I write 1.0v3 xv then I can write bar next to it and instead of it I can write par but one atmospheric means 760 millimeters of H write on me quickly you write it you also write it write it write it write your Practice was done, remember and one tur is the unit that is equal to millimetre of H, one millimetre of H is all the units, why are all the units of pressure here, write your ok, you also come with me, Achal Raipure sir, I am a dropper, there is no issue, you have a chance, December attempt is a big chance, remember dropper children, because now these children are joining us, they are doing it without proper planning, but I saw that now children come to me for 12th admission, now their basic is not yet clear, but you gave CT not once, not twice, you need to revise them quickly, why one centimeter cube means 1 ml and e 10-6 m K means S unit, why now one dm cube means one liter means 10 re-3 meter cube, okay now one dm cube bar means 100 water and one liter atmospheric means 101.3, everything is important, no screenshot, write after writing, done, not before, okay and one newton Per meter scr ex centimeter scr write it down OK write it down one minute OK when you write it down message me done Well can you give me the PDF of this question Why do you have to write it down Take note of everything I want to write it down I don't want a PDF We have to write it down and practice it like that Open the book Open the application to see these questions I move aside a little Write it down slowly OK Hi Sir When did the class start Just now Five minutes ago I have n't taken any questions yet Revision is going on Rahul Birkul Done Done Done Okay Done Done Later Done Come on Now let's move on to the question We are not MCQs This is a question in the test book You have to convert Convert it You say Convert 1.5 Atmospheric to Pascal Do n't do it yourself Don't do it I tell you what it is See if it is a question 1.5 Who is Atmospheric Multiply it by 1.013 013 10 F Do n't write Pascal, let's have a verbal discussion. Let's convert 89 kilo Pascals to Newtons per meter squared.

[00:14:23]Actually, I do n't want the kilo factor. I'm telling you that for kilos, I have to take 10 times. Look, there are a thousand grams in a kilogram, so multiply to get kilo Pascals. Because Pascals have to take Newtons per meter squared. Okay, but I want to convert kilo Pascals to bars. This is difficult. Now listen, I'm telling you. It's very easy. But understand. Let's write meters. That means that Pascals became kilograms. I took out kilograms.

[00:14:51]Okay, now I'm dividing this. That means I take 1.013 01325.

[00:14:58]If I divide this by 100, I have to multiply it by 100.

[00:15:00]Pascals are Newtons per meter squared. And remember, if I do n't write this, it's converting to bars. It's converting to bars. Look, it's easy. It's a little faster, but let's do Celsius and Kelvin. Add 273 to it, that is, D is 273, but it is already minus H, that is, 3 answers will come, how many answers will come?

[00:15:26]173, children, you forgot to like, you should note that 3 crosses should be noted, let the fluctuation go a little, but increasing and F, children liked it, like it quickly, OK, now you have to convert this to temperature, listen to it, then Z4 is the same as T, there are millimeters of H, and if you want to convert millimeters of Hg to temperature, you have to divide it by 76, golu, nice, divide immediately, the P, children listened, like it immediately, OK, great, I am requesting the rest, like the video, share it, if you are new to the channel, subscribe, YouTube algorithm checks these things, OK and clearly says, subscribers are increasing every day, new children are coming, and this is possible only because of live.

[00:16:20]So there will be a live session in the afternoon, we will take it and show it, let's tell you now, I will not solve the atmosphere, how will the atmosphere be multiplied by Pascal, how will it be multiplied by Newton per meter, the same value is needed to calculate the atmosphere, but this value is needed, look, one atmosphere is 1.013 times 10 atmospheres, this value will come, remember this, remember this, okay, sir, please make a video before going to engineering college, what topics and basics should be covered in math, physics, chemistry, definitely, tomorrow, tomorrow, tomorrow, let's do it, 173 people answered, Rathod, okay, Jadhav, everyone, it's great, the revision has been done, so far, only the revision has been done, what has been done, the revision and today, you have to solve MCQs on the same concept, and that I have n't taught the concept yet, I'll start teaching now, everyone, come on, let's start, comment like this, let's start and a completely different law, I'm going to take it, okay, okay, okay, I'm not taking it for physics, oh, I'm taking it, Vedant Joshi, I'll take physics in the afternoon, remember, I'll take it after that tomorrow, there will be a live tomorrow afternoon, Rathod, and sir, the range is not coming, okay, I have a clearly range here, okay, why is yours here, see, click, check, what does Sayali say, sir, please tell me, how should I study, Rao, see the painful session in the CT details today, I want to prepare for the board, I want to book a test, I want to solve my numerical problems in the book, in math too, and see, why did the questions come, I want to find them, okay, Kendra, Tanish, let's start, okay, I'm telling you, I'm starting, pay attention, okay, I have four grams of hydrogen, okay, who is four grams of hydrogen, and I have 80 grams of nin, nin, okay, just type and tell me the molar mass of hydrogen, what is the molar mass of hydrogen, what is the nin, how much is it? Tell me, let me check it, tell me what is the molar mass of neon.

[00:18:52]Vedant Joshi, I want to change this concept in the minds of children. This concept of children that whatever has to be done separately, the board has to be done separately for CET is wrong.

[00:19:02]First, the board has to be done. Once the board is done, then the preparation for CET will be done. It is not like this.

[00:19:07]These problems have to be solved.

[00:19:11]Watch the live session this afternoon. The second part in it is the problems in the book.

[00:19:15]Note that OK, 20 is correct. Note that 20 is correct.

[00:19:23]Divya, this is basic. Note that it is basic.

[00:19:26]Listen, everyone. And I will need this for the NAT and I will also need it for the NAT.

[00:19:32]Now what do I do? Calculate the number of moles of hydrogen. What is the given mass? A2. Number of moles.

[00:19:37]A molar mass. Then I got two moles of hydrogen here.

[00:19:41]Okay, look, we are going to go very basic.

[00:19:45]And after taking that law again, you will understand everything. Well, now let's calculate the number of moles of neon. What is the given mass? A molar mass means how many moles of it are there? Now the most important thing is that I will use the symbol X. Mole fraction.

[00:20:01]Now, the mole fraction of hydrogen. Let me show you the first mole fraction of hydrogen.

[00:20:05]If you want to calculate the mole fraction of hydrogen, take the mole of hydrogen above. Take the mole of the mole fraction you want to calculate and take the mole of the mole fraction above and below. The total number of moles of hydrogen is what is the mole of hydrogen and what is the total mole. How come two, four, six moles of hydrogen are a mixture? Let's think about the mixture. Okay, so the answer is coming here. Bath, I want to take the term mole fraction. Today I will need it in all the MCQs. Today I will need which term in all the MCQs. Tell me the term mole fraction.

[00:20:43]Okay. After waking up in the morning, after taking a bath, I will definitely pray to God. Why should I study while studying? Do n't take it as anger. Remember, after taking a bath, I say Ram Raksha. I say Maruti Stotra.

[00:20:55]I do all the things. Why should I do everything? Okay. Study should be done during study time. Ok I want questions in the comments or I want answers like this. I don't want to say customer. Take note. Now I will calculate the mole fraction of hydrogen. Now I will calculate the mole fraction of nin. If I have to calculate nin, take the mole of the mole fraction that I want to calculate and in the denominator, the total number of moles. Ok wait here for a minute. Here nin will come. Take note. Ok.

[00:21:23]How much is nin mole? How much is the four total?

[00:21:25]How much is the sensor? Bath means nin and hydrogen mixture. If hydrogen mole fraction and bath are nin. Bath is nin. Let's have fun. Let's calculate the mole fraction of hydrogen plus mole fraction of nin. Let's calculate the mole fraction of hydrogen. How much is the hydrogen mole fraction and bath is nin. 2. Did you get one? If you have a mixture of hydrogen, neon, oxygen, all together.

[00:21:51]You calculated the mole fraction separately and what did you do with it? Then you will get one.

[00:21:56]Now tell me first. Do you understand mole fraction?

[00:22:01]Dalton's law is going to be studied in 11th and its next step is going to be in Ra Malate. Do n't ask if it is cut or not. Just complete it. OK one one one one mole fraction.

[00:22:14]Tell me. Did you understand it? OK Shambhu Kadam. Did you understand the cut? Is it CT? Yes, this is for CET.

[00:22:22]Divya. Continue the lecture. It is very important.

[00:22:30]Real Vardhu. There is no problem.

[00:22:32]Just pay attention here, okay? It's not afternoon, then record it, if you record it, it will work, right? Not everyone can watch live.

[00:22:40]Now our children are not able to watch Joshi sir's live, but all the toppers, all the sincere students, sincerely watch recorded lectures of sir and must watch for 99%, you must follow the physics channel yourself for 99%, Harsh Nigadkar topper, ok, I will tell you, after that you must watch equation X, you must watch 99, ok, come on, you will know the mole fraction, you have noticed the mole fraction, well, now let's do a task, I have a container and in the container there are two gases, A and B, let's think, who are A and B, tell me, it is a gas, ok, now in the same container, their volume is going to be the same, how is the volume going to be the same, the ideal gas equation will be P, AT, did you remember PV = what came to mind? NRT, again understand PV, NRT, ok, now understand that P means A, pressure and P. So the pressure of B is then the total pressure, which means the dish of these two is going to be done. The total pressure means what will happen to these two? Let's dish the two. Well, why do I get this after dishing?

[00:23:53]Plus P B and I dished these two and here I am going to get A P A B and RT Equation one Equation two and Equation three. Look at the ideal gas equation.

[00:24:08]Well, why do I just do it? The pressure of A is different. The pressure of B is different. It means that both of them have different pressures.

[00:24:16]Both contribute individually, but when they are dished, we get the total pressure. When we dish them, we get the total pressure. If we dish the total pressure, this is the total pressure. So, should I do this now? Okay, let's see. I divide Equation one by Equation three. I get the equation. + pb. Did you notice, kids? If we divide by one, v will cancel out. If we cancel out by one, then na will come up and na will come down. NB na will come down.

[00:24:45]Understand A B. Take this is p this is times that e is the mole fraction I am boxing it, look at the moles of na are above and the total moles are below, that is, the mole fraction of which is above is the same, that is, I have to subtract the partial pressure of p while subtracting the partial pressure of p while subtracting the partial pressure of p, the mole fraction of a will have to be multiplied by the total pressure and the same thing is next in r which we will see later but this is an important formula on which I want to solve PYQ then use your head let's see suppose I had divided the number two by the number three then v would have been cancelled out a would have been cancelled out a would have been over b that is x would have been over b that means if I want to subtract the partial pressure of b then I have to multiply the mole fraction of b by the total pressure kids I am going to take today's numerical very slowly but first write down all this basic Dalton's law I did not tell you, why kids I The statement is not stated. What is Dalton's law? What is the statement of total pressure? If you want to calculate the total pressure, then plus p b plus p c plus p d dot dot. What do you have to do with the individual partial pressure of the gases?

[00:26:07]Dishon means that everyone is contributing individually.

[00:26:11]Write it in the total pressure. When it is done, send a message as done. Okay, sir, don't you think that it is going very slowly? This is what is wrong. The children have to change everything. I want to perfect what I have to do. Okay, this is what was the problem. Tell me, where is the fast teaching for JE?

[00:26:35]Everyone should understand. Everyone should understand.

[00:26:39]Okay, tomorrow, Mayur Kulkarni will be live tomorrow. Why will it be? At 2:30 pm, my rank one came. Aarti Sonawane came. Where did rank one come?

[00:26:46]The rank has not been declared yet. Well, okay.

[00:26:50]Tanishka Gulane has joined. Has brother joined? Tell me, let's see. Is Tanishka's brother?

[00:26:56]Okay, Tanishka is an old student. Her brother is also. He is talented, I think he is in 10th, that's okay, great, sir, you are very important. The thumbnail is very heavy. Okay, thank you. Thank you. Sameer. Okay, done.

[00:27:12]Let's write it down. It will take time to solve all the numerical questions. Take it very slowly. Take it very slowly. I have to explain everything to you.

[00:27:20]First numerical question. Do n't rush at all. Let me solve it for you. Don't rush at all.

[00:27:30]Pay close attention. F moles of nitrogen gas One mole of oxygen gas 1 F moles of hydrogen gas and the total pressure is given 18 bar and asked partial pressure of 2 Listen while calculating partial pressure of 2 take mole fraction f and multiply it by total pressure was given formula now let's see now let's take the mole fraction of which we want to calculate above let's see how many moles of oxygen are there look above understand everyone will know take the mole fraction of which we want to calculate above did by total number of moles let's total the mole of nitrogen is z5 oxygen mole one means 1.0 hydrogen is 1.5 same is fzv happened and here two three four four coming here means I got one by four total mole I got four oh no four kids how did it happen four carried one here three m total mole I got three note ok and now what is the total pressure 18 Divide by three, six answers are coming. Option Beat 6 question number is very easy. Just type it and tell me. Sir, the question is very easy. I want to see it in the comments. Sir, it is easy. It must be easy.

[00:28:57]You have got it. You have got it very well. Very good. Okay, Amrita, I got it wrong earlier. Why are you counting but now it is correct? Okay, you have understood the question. You will understand the answer. It is a different joy. Prithviraj Nalawade is right. Arya is very good.

[00:29:16]Very good. Rajvardhan Kulkarni is right. Very good.

[00:29:22]Okay, Vikram Salunke, sir, when are you coming to Kolhapur? It is coming. It is coming. It is coming.

[00:29:24]Now it is my birthday on the 12th. This Sunday. Why. After that, I will definitely come in the next week. It is very easy. It is very easy. Okay, thank you, sir. GPT. Thank you. So simple. So simple. So simple. Very good. Okay, wait. Ranveer Singh Rajput.

[00:29:48]Understand the concept of moles in class 9th. Slowly. Why. What was asked? Partial pressure. The mole fraction of which we want to calculate the partial pressure is multiplied by the total pressure.

[00:29:57]When calculating the mole fraction, we take the mole fraction of which we want to calculate the mole fraction above the total. Let's see next. Now we have five grams of hydrogen and one gram of helium. We don't want to solve 50 grams of carbon dioxide and 20 grams of the following. Listen to the minimum partial pressure. OK. To calculate the partial pressure, we have to multiply the mole fraction by the total. OK. I write one one.

[00:30:35]Now we want to calculate the mole fraction whose moles are divided by the total number of understand. Please, please, don't rush. Well, why? Please, do n't rush? There is a shortcut. OK. Then tell me on whom this pressure depends. Only the number of moles depends. That is, the pressure is directly proportional to the number of moles. Total pressure is constant.

[00:30:54]Total pressure is going to be constant.

[00:30:56]Total number of moles. Everyone's dish. Let's do something that will be constant. Let's find the number of moles. Divide this.

[00:31:02]Hydrogen is the molar mass of hydrogen.

[00:31:08]Divide this by four. The moles of carbon dioxide will be 44 divided by 50.

[00:31:15]1 pau something will be 1 pau something.

[00:31:18]Divide 20 by 20. 1 will be Now the one whose mole is the least will have the minimum partial pressure. Let's say exhaust. You and I think the moles of carbon dioxide are 1 pau something.

[00:31:30]Wait a minute, this is the least of these. This one point of neon is only one.

[00:31:37]Option D is correct. D is correct. Well, why is Balanody correct? A is not Amrita Shinde. OK. D is correct. Thank you Sherlock. Happy birthday in advance. OK. OK. Did I understand option D? Look, did you understand?

[00:31:56]Pay close attention. Rajput, while calculating pressure, while calculating partial pressure, we calculate mole fraction.

[00:32:00]Total is to be multiplied Total pressure is constant Which mole fraction to be calculated is to be taken above Total is also constant This means that it is directly proportional to this Then the number of moles is the lowest The pressure is also the lowest How to calculate the number of moles Even mass A molar mass The molar mass of hydrogen is two Divide five by two This is four Divide eight by four This is 44 1 pot Something will come 1 point But then I saw that you have neon's molar mass 20 Divide one by 20 One and option D is coming Come on All DD Golu My but wrong Golu Has it gone wrong We are getting confused Why hope Silly mistakes are made Why OK Parag Mahale Sir When are you coming to Pune It is after the rains in Pune stop OK Let's go Next question This type of questions are Equal masses of helium and oxygen are mixed in the MT We don't need the container temperature. Wt is the fraction of total pressure exerted by helium. That is, the pressure exerted by helium is done by total pressure. They asked and to calculate it, I will only have to do the mole fraction. If you have done the lecture in the afternoon, I will know whether it is or not. What fraction of current flow is the same as here? What did they ask? What fraction of total pressure is a by helium? I take helium above, take the total below, and in the formula, I take the total here. Let's take the number of moles. Now, to calculate the mole fraction of helium, I take the moles of helium above, and the moles of helium below, plus the moles of oxygen.

[00:33:38]Okay, but helium and helium have equal masses. They have equal masses. One minute, one minute. The atomic mass number of helium and oxygen is four. Okay, so its molar mass is four. I mean, remember and the molar mass of oxygen is 32. Now understand what I am doing. Let us take 32 moles of helium and also 32 moles of oxygen.

[00:34:05]What I said, don't solve it.

[00:34:08]We have to cover one type. And if this Dalton is satisfied, tomorrow the root law will be satisfied. Everything will be fine.

[00:34:14]Then, success was saying, will it happen every year? Don't worry, just pay attention to this. Why did I take 32 moles?

[00:34:22]Because now I have to calculate the number of moles. I have to divide this by four. I get eight moles of helium.

[00:34:29]And I put one value of oxygen. I get eight moles of helium. I get eight moles of helium. Plus one of oxygen. That is, I get 8 by no. Option C is correct. Ankita Chavan is very good. Very good.

[00:34:49]After him, Soham Gadge is the topper.

[00:34:52]Sakshi Mane has improved a lot. Sakshi says, Ankita Chavan is right. Okay, Latur.

[00:34:58]Nanded, Eni Yash Kadam, are you from Latur?

[00:35:01]Thank you for watching from such a long distance.

[00:35:03]It is very nice to follow. Children, this partial pressure seems complicated to everyone. Let it seem a little easier. Do you remember why I took 32? Children, I took 16 gum. I would have continued. I would have continued.

[00:35:14]But I would have taken 32. But I would have gotten a fraction. What do they say about equal mass? Consider 32 gum and helium. And did you remember how important molar mass is? CO2 is 20. Helium is 60. Whose is urea? 180. Whose is glucose? 342. Sugar? 40. Whose is NaOH? 122.5. Whose is potassium chloride?

[00:35:43]74.5. Whose is potassium chloride? One one one.

[00:35:47]Whose is it? Tell me just one one one.

[00:35:49]Tell me whose molar mass is it? Children, well done.

[00:35:52]Very nice. Okay. C. C. is right.

[00:35:58]Okay. I You have been asked a question that one one one one has a molar mass. Tell me, OK, option C. Option C. Your correct answer will be repeated. Next time, I will take the next question. This question has come in 202 questions. Why are there children from Wardha? Calcium chloride is correct. Calcium chloride is correct. It is from Sambhajinagar. But children are from Chhatrapati Sambhajinagar. Okay, let's think about the next question. Okay, there are four grams of hydrogen. Let's calculate the number of moles of hydrogen. Given mass upon molar mass, two moles are obtained. Okay, now I have helium. Given mass upon molar mass, one mole of it is.

[00:36:44]Okay, and I took a certain amount of Nin. I do n't know how much Nin was taken. But Nin mass is not given.

[00:36:51]But the mass of Nin is not given. So that partial pressure equals Nin equal to the partial pressure of Helium partial pressure of nin equal to partial pressure of helium Pay attention very slowly To get the partial pressure, you need to multiply the mole fraction of helium by the total pressure. That's right, to get the partial pressure of nin, you need to multiply the mole fraction of nin by the total pressure. That's the formula. To get the partial pressure, multiply the mole fraction by the total pressure. To get the partial pressure, multiply the mole fraction of nin by the total.

[00:37:43]Now calmly, what will happen to this total? These totals will cancel out.

[00:37:47]Okay, now pay attention carefully. While getting the mole fraction of nin, take the mole of nin above divided by the total number of moles. Here, take the mole above divided by the total number of moles.

[00:38:01]Now, what will happen to AT? It will cancel out. The formula for number of moles is: Given mass, a molar mass, a molar mass, a molar mass. Part Zal, take note and calculate the number of moles of helium.

[00:38:16]We have helium helium. Okay, here we have hydrogenated by mistake. The moles of helium are one.

[00:38:22]Okay, let one come here.

[00:38:25]Multiply by the wave and the answer will come.

[00:38:29]20 gum option D is correct. Now I am not taking anyone's name but please sir, explain it again. Type it immediately. If you find this difficult, then even if you say no, I will do it. But I want an answer from you. Sir, the formula of density is PM A KT and PM ARTI. I will tell you later. Why is this numerical? Tell me again. I got a comment. You have to explain. Why is this numerical? Okay, everyone understands. DDD.

[00:39:06]Repeat. Thank you. Mayur Kulkarni. Mayur. Now let's erase and I will show you. Pay attention. The first thing to remember is that while calculating partial pressure, not only partial pressure is calculated, but its mole fraction is calculated by its mole.

[00:39:21]Fraction to multiply by total pressure Same to Same formula Same to Same formula Solution Topic Remember in Raat Law and for gaseous gaseous phase Ok remember this Let's do it here Let's see partial pressure divided by nin Partial pressure divided by nin Equal partial pressure divided by helium Ok Partial pressure formula To calculate vapor pressure, multiply its mole fraction by total pressure Its mole fraction will be equal to the total pressure Total pressure will be equal to the fraction It will be While calculating mole fraction, take the mole of the mole fraction to be calculated Divide by total number of moles of helium Moles take by total number Total Total moles will be equal It will be cancelled Nin will be calculated Na m gun mass a molar mass lim Calculate molar mass four four gum four ch Cancel peacock Did you notice Kulkarni?

[00:40:28]Comment and tell me. Mayur Kulkarni did you notice it? Comment and tell me.

[00:40:33]Atharva is also there. Okay. Prathamesh Nalawade. Aryan is great. Okay. These are the kids who pay lakhs of rupees to offline and do not ask under pressure. I have explained again. Do you understand? Tell me. Okay.

[00:40:47]Now your messages will come. Well, remember that I have repeated all the steps so that you understand.

[00:40:51]This is the real beginning. This is the beginning of the problem. I wrote the basic formula of the given equal. I used the same term. They were canceled. Number of gun mass and molar mass became part. Please note that now the equation is absolutely fine. Sir. Okay. I am telling you that everything is fine. Everything is fine. Very easy. Okay. Now this seems easy.

[00:41:16]Dalton's law seems easy. Let's move on to the next question. Come on and try it.

[00:41:22]You try. Minimum partial pressure is equal masses. Equal mass is. Do n't take anything. Where is the equal mass? 32 32 Do n't take anything wrong, they did n't tell you to calculate the value.

[00:41:39]Now listen, the partial pressure is one. Okay, the mole fraction in the total will be constant.

[00:41:49]Now, while calculating the partial pressure mole fraction, you will have to take the first number of moles divided by the total number of moles. What is the total number of moles? The total moles will be constant.

[00:42:02]This means that the partial pressure is directly proportional to the number of moles. What is the formula for the number of moles? Given mass upon molar mass. Now, how is the given mass equal? ​​Equal means constant.

[00:42:19]In this case, the pressure is inversely proportional to the molar mass. I repeat, this is the formula for partial pressure. Okay, multiply the mole fraction of the partial pressure by the total. The mole fraction of the partial pressure is the same.

[00:42:38]Take the total number of moles per mole. Since the total number of moles and the total pressure are constant, the pressure is directly proportional to the number of moles. The formula for the mass of a mole is also equal to the molar mass. This means that the molar mass is the minimum partial pressure. If you want the pressure to be minimum, you need the molar mass to be maximum. The molar mass of hydrogen is two, helium is four, carbon dioxide is four. The more molar mass there is, the lower the partial pressure will be. And option C is correct.

[00:43:14]Okay, option C is correct. Okay, great. I'll tell you. On the left side, you can see the heart and so on.

[00:43:21]I can see it.

[00:43:23]Very good. Okay, I'll do it a little bit. Okay, great.

[00:43:27]Very good. Option C is correct. Wait, look where we're coming from. Why are we coming to this formula after going around and around?

[00:43:37]If I want to find the partial pressure of hydrogen, I have to take the mole fraction of hydrogen and that's it. Total pressure will have to be multiplied.

[00:43:47]When taking mole mole fraction of hydrogen, take mole of hydrogen above. Divide by total and see the times. Now this numerical has been remembered by you very clearly.

[00:43:58]Adarsh ​​OK Adarsh ​​Sir please tell me my name is OK Adarsh ​​where are you from. OK OK OK Shamal Walvekar OK Walvekar is a 10th standard topper student and this year the children should come first in Walvekar Gurukul.

[00:44:13]Okay sir, will there be lectures every day?

[00:44:17]Monday, Tuesday, Wednesday. Lectures will be held in the evening.

[00:44:19]Okay kids. But tomorrow I am going to take physics in the afternoon at 2:30 pm. Remember that the lecture is tomorrow. Before giving the lecture tomorrow, you should complete the lecture today. You should know that it is not yesterday, Syed. I have mentioned these steps. If any form constant is removed, then the proportional comes.

[00:44:38]Number of gun mass a mole mass but mass is constant. So, if mass is constant, then remove that too.

[00:44:43]This remaining molar mass is more pressure less minimum asked molar more answer it is coming Wardha ok great ok yes sir boys will top means girls do n't need to be upset every year girls come now this year boys come first our school is a very good school Gurukul school was having a little discussion about it note ok let's look ahead now look ahead now read the question container maximum partial pressure is required listen kids understand I came till here with Maga now solve whoever comes but for Farhan Syed I am telling again which other boy is there still there was another boy well why ok Farhan Syed and someone else with Maga explain well why I am telling you the formula of partial pressure is mole fraction in total pressure ok while calculating mole fraction mole divided by total mole ok this means if these two are constants if I remove them then I get proportional sai You have to take the number of moles directly.

[00:45:51]What is the number of moles? Gun mass is a molar mass. Look back. Equal masses are its constant. That is, pressure is a proportion of molar mass. Now, pressure is the maximum. I want the minimum. I want hydrogen.

[00:46:05]Molar mass is two helium. Four minimum. Whose hydrogen is where? Hydrogen.

[00:46:13]Option A is. Note that option A is.

[00:46:17]And many children have given the answer correctly.

[00:46:21]Farhan. Okay. Remember these things.

[00:46:26]Try to find the constant term in the formula. If you don't get it, ask me again later. Soham Khamkar is right. Riya Chaudhary is right. Okay. This is a 50- student group. Always. Always. Always.

[00:46:38]Remember. Now the rest will join in a short time. We don't want to register for attendance. But this is not the name. We read it every day. Shravani Bhosale.

[00:46:46]Soham Ghadge. Shambhu Kadam. Prajwal Hatte. Pranav Bhat. Hostel is. Well, why do children of this object join?

[00:46:52]Note that. Okay. Ideal.

[00:46:58]Take the last name Take the name OK OK Let me tell you why we have a custom of taking names, but why should we take the wife's name? Remember OK Full name Good Ideal Last full name What did you take Focus on your studies Please OK Please let's move on to the next question We are now coming to the end of the questions The lecture will end soon today You do it Let's solve it yourself OK I am also solving I am also solving What is the partial pressure of nitrogen Listen to me To calculate the partial pressure of nitrogen Take the mole fraction of nitrogen and multiply it by the total pressure and the total pressure is 20 bar So let's put the value of this Take the value of the mole fraction that you want to calculate above Divide by the total number of moles Calculate OK And what is the value of this Now I am calculating the value Pay attention I am going to calculate here The molar mass of nitrogen is one Divide me The mole of nitrogen will be one The mole of nitrogen will be one The molar mass of helium is four Divide eight by four, it gives two moles, nine molar mass is 20, 40 by 20, two will come, three nine helium and nitrogen, helium and nine are the same, right?

[00:48:17]Divide it by two, four and one will come, five, okay, and here is f, divide option C, did you get option B, why do you say four times B, why do you say five, no, the answer is not coming, kids, something is wrong, my answer is coming differently, my answer is coming four times, my option C came, Som Kamkar, C answer came, then the answer was, then the answer was, then the answer was, then it was not, remember, solve it properly, why, what must have gone wrong, do you know, the atomic mass number of nitrogen is 14, but the molar mass is mole helium got four moles, did two moles, C is right, Dhruv Pawar, C is right, okay, four times the answer comes, well, Pa, C is 20, okay, C, C, those who got it wrong, correct it, well, why Children, but you must have noticed the pattern. Listen to Soham Chavan. I asked a direct question about the partial pressure of nitrogen. I have to multiply the mole fraction of nitrogen by the total. Take the mole fraction of the mole fraction to be calculated. The moles of nitrogen are one and I took one. Or to calculate the total mole, I first calculated the moles of each separately. To calculate the total, everyone's dish was one and five. Okay, then the total pressure was 20 bars.

[00:49:39]He gave 20 for digestion. Option C is correct. Come on, now I will tell you.

[00:49:47]Okay, this is the same mistake. This is a mistake with nitrogen. Where do you start?

[00:49:53]Start with us. Let's do the next question. The trial is coming to an end. Children. And the same thing started repeating.

[00:50:00]Equal mass equals mass. Okay. Pressure equals the gas maximum for. Okay. Now don't mess around here.

[00:50:12]Try to leave.

[00:50:15]Okay. Then do you know what I'm saying? I will give you homework today. Okay, I saw it after a long time. Okay, let me go. I am giving you homework. Let me show you this question.

[00:50:24]Next, I will give you the last question. Okay, okay, after a long time. Okay, Amar Wakade. Okay, this live link goes to many children. Okay, I saw it after a long time. Thank you.

[00:50:39]Let's solve this question. Answer this.

[00:50:42]Okay, answer this. Answer this. Let's see. Calculate the partial pressure. Now, I will take it slowly for everyone. Okay, why did anyone ask about partial pressure? Whoever asked about oxygen, take the same mole fraction and multiply it by the total pressure. The bar is given.

[00:51:06]Take the same mole fraction as above and take the total mole below.

[00:51:13]Now, let's calculate the mole. Oxygen is 32 moles. The molar mass is 16. There are two moles of oxygen.

[00:51:20]What is the mole of oxygen? Two 80 moles. He said, he gave a molar mass of 40. 40 divided by 40, the answer is only two, four moles of hydrogen, hydrogen mole mass is only two, I divided four by two, again two came out, two moles of this, two moles of this, two moles of this, two moles of this, six moles, I think there is a bit of confusion here, okay, there are two moles of hydrogen, okay, ox, mistake, mistake, big mistake, then, golu, that was the same mistake, one mole is oxygen, five moles, five, five, a, five, the, two, four, option C is correct, option C is correct, Shambhu Kadam, look, don't make a mistake, the molar mass of oxygen is 32, then divide 32 by 32, one mole is the same molar mass, they gave you 40, then 80 got 40, two moles of hydrogen, four, the same molar mass is two, then four by two, four by five, total moles, five, total moles, how many moles were five and this total pressure, give five, five, the, two, two, five, the, two, two, two, five, five, the, two Four options C are here, Option C is here, the children who came and went came back but the regular present was to be seen. Attend the lecture properly and it is happening for about an hour.

[00:52:46]Remember, why did you forget the dioxygen? My OK, they ask different questions in my mind, sometimes mistakes are made. Let's solve the next question. Let's solve the question of the case. Same mass, same mass, earth, highest pressure.

[00:53:02]I am also going to give you homework. Why do I need this question? I want the lecture to end early today. Why do I need the homework question answer? Why do I need it later?

[00:53:13]Okay, Amar Wakde had 87. Without offline classes, to be honest, online classes are much better than offline classes.

[00:53:20]I agree. I have offline classes, but online classes are also available.

[00:53:24]Both of mine are the best. Now, look at offline classes.

[00:53:26]You have to do it. That is the main point.

[00:53:29]Parents, why do millions of parents pay lakhs of rupees in fees?

[00:53:31]Children are not doing it seriously. But if you have discipline, you can score good marks even by studying online. Let me tell you a joke, after going offline, even the online ones, everyone comes to online. You take the name of any big class in Pune, those kids come online in the end and there are a lot of options in online. I tell you, earlier there were no options, now let it be math, let it be physics, let it be chemistry.

[00:53:56]You have options. Let's get the answer.

[00:54:00]What did you ask? Calculate the partial pressure of oxygen. If you are asked the partial pressure of oxygen, multiply its mole fraction by the total pressure.

[00:54:10]Then here the moles of oxygen should come up. The total pressure is given below. 25.

[00:54:17]How much oxygen is there? I will not miss it now. 32 It means its moles are two. There are two moles of oxygen. Divide by 20. There are eight moles. There are two. There are two. There are eight and two.

[00:54:29]How many are the total moles? And this is 25.

[00:54:34]Divide 50 by five times. And I am so happy that the answer is here before me.

[00:54:41]And this was not easy. It was not easy.

[00:54:44]Note what happened. The problem was given in the book and it was not solved. I understand that what we are explaining to you is making it easier for you to remember. Even I admit that I am still studying. Okay, let me tell you the truth, which faculty is the best for chemistry in PWB?

[00:55:01]They have beards. Tell me in the comments, chemistry is okay, I'll tell you, pay attention, tell me the name of the best faculty for chemistry in physics.

[00:55:13]Okay, I'm waiting for your comment. Ok pandit sir check the paper.

[00:55:19]Okay, I'll give you a hit, the spelling of that sir's name starts with a pin, okay, bring that sir's lecture, it's green, why is there an old lecture on the white board, for chemistry, I have organic, inorganic, physical, everything is already there, the answer is B, C, no, okay, so complete the homework, Pankaj sir, okay, Pankaj sir, really good, Sowin sir, not in BW, Bano, Son sir's best, he has his own channel, what is the name of the channel, Son Sara, Sowin sir, chemistry, okay, what is the name of the channel, Pankaj sir, Pankaj sir, Pankaj sir is very heavy, Pankaj sir, he teaches in zero time, please note that there is no controversy, nothing, nothing, nothing, All About Chemistry, Son sir's channel is called. PGM is the name of N Mukesh sir's channel. Dinesh sir live study is from Dinesh sir and this is the top channel in Maharashtra. Note that there is also math for math, there is equation x but it is not immediately remembered.

[00:56:21]For physics, there is RG sir. I always tell you, I always tell you, RG sir. There is Sagar Jahan sir. Okay, for math, Shailesh Chavan sir, how will you remember? I forgot to remember. I am Joshi sir. For physics, one mole of oxygen. I was wrong before. Why was I wrong before?

[00:56:36]Now we are right. Let's see. There is still one question. Okay, this is the last question. Let's solve it. Let's solve it for me. Come on, we have to do session A.

[00:56:48]This question is solved for me.

[00:56:52]Physics is on top. Note that there is a number for physics. I want to talk to you.

[00:57:00]Download the app. Type the same name. I will call you. Pradeep Pandit sir. When the lecture is over, I want to talk to Golu.

[00:57:09]Well, why did you download the app? Download the app and the app is on top.

[00:57:14]Type your name, or if you are a little bit ready, message me that Hi I am Golu and I want to talk to you, I will call you immediately because the subject is different, Triple NIT Surat, another college, I want to do this, why do we discuss it?

[00:57:29]Okay, come, many children have come when the lecture is over, remember, okay, make it regular, okay, golden hands, I still have to take a lecture, yes, I want to take a lecture, but I have to work, okay, let me tell you a joke, I can solve these children now, you don't need to take a chemistry book, okay, cooker test book, okay, chemistry standard and the first second topic is the solution, well, I want to show you that we have done the same in Roots Law, okay, second topic, okay, okay, second topic solution 28, okay, do you solve the problem of the past, kids, okay, Henry's law, Henry's law, look here, look here, look carefully, this is the formula, look at it, if you have to calculate P1, this partial pressure, its value Fraction is multiplied by the total pressure.

[00:58:30]This is for gaseous. Vapor is for vapor.

[00:58:32]For vapor, y1 is y2. As we say x12, x12 is for liquid and y1 is for gas. This is the total pressure.

[00:58:43]Now, look at the statement in the table. The statement is exactly the same.

[00:58:46]I am using Dalton in the table.

[00:58:51]Now, let's tell you what is going on. Okay, let's take the lecture for you. Let's take it.

[00:58:57]Sir, make a video on this. CP NTC was made tomorrow. We made a video. We are done. Why should we take COP NTC? VIT IT. Tomorrow morning, we will watch the video of eight on the same topic. Let's see what is given. A closed container contains a mixture of A and B. Partial pressure of A and B. Let's see. Partial pressure of A is given as 4.5 bar and partial pressure of B is given as 5.5.

[00:59:33]Find the mole fraction of and B respectively. I have total pressure, not total pressure, what are you saying? Why is total pressure not working? I asked him, "Ok, but he said, "Ok, the mixer is not working."

[00:59:46]Stop.

[00:59:49]The value of P is x.

[00:59:53]Total pressure is ok. Okay, okay. What do I do? Let's see if I divide A by X. I will get total pressure. Similarly, I divide P by B by x. I will get the pressure of A. The pressure of A is 4.5 divided by x. Its pressure is 5.5 divided by x. B. But I don't want to write x. B.

[01:00:15]I will see in the beginning of the video that if we divide the mole fraction and the mole fraction of B, we get one. So, in place of x. B, we can write one mass x. Now let's do one thing. Let's cancel this point by point and divide it by 1. Okay, 11 will come here. Cross it and solve.

[01:00:38]Then you will get x first. When you get x, subtract x from one. You will get x. Do this too.

[01:00:44]But you didn't do that.

[01:00:47]Tell me, okay, I got a message from Utkarsh.

[01:00:49]My name is Adarsh. I am sending you a message and I am also telling Golu. Please send me a message so that I can get your number and I will call you on that number.

[01:00:59]Utkarsh. Okay, come on.

[01:01:01]Utkarsh. I just downloaded your app. No problem. Okay, Adarsh's name is Rahul Karekar. I spoke to him yesterday afternoon.

[01:01:09]Golu Golu. I am waiting for your message.

[01:01:12]Download the app and send me a message. I want to have an important discussion. Come on, tell me why this happened.

[01:01:16]Answer this quickly. OK, tell me the answer. Option C. Many people say 45. But why did you solve it like that? Why did you solve it like that? You solved it like that, not like I solved it.

[01:01:28]I also think that you should do the same. But total pressure is not given, total pressure is not given, let's take its value and compare it, okay? And do a little cross production, 9 * 1 is not going to come - 9 * x 11 * 11x minus plus, 11 will not come 20, that is, 20 will come, so add 20, that is, you divide nine by 20, zero point here 20 is 80, give 45 and 45, where is the first option, option C is correct, okay, Prithviraj, is Prithviraj Sujit the same, okay, is Prithviraj the same, we should see, remember, okay, great, okay, now we have to end the session, but before that, as Raj said yesterday, we want to chat with you for a few minutes, what do we want to chat about, is the textbook important, is the book important, base questions on the book, okay, sir, yes, so it is, yes, said, Prajwal, okay, okay, sir Thank you I was already there I just didn't chat I was eating but make sure to prepare the food Raj Ok sir When is your birthday Rathod My birthday is on 12th July Next week Ok Ankur Ankur Gurve Let's sleep I don't want to come early tomorrow I have school early tomorrow I have your class in the afternoon Happy birthday Sir Advance fun Thank you Sir Listen or listen Saurabh You speak just think Ajit Desale I don't understand No No I want to try I am taking it very slowly Why am I taking it very slowly Testbook is important When will you contact me I will contact you in front of you when this live session ends Ok Good night Good night Suhas Kamkar Good night Come early tomorrow on time Ok Many people do n't comment Why and like the video while going Kids there are 392 people 143 likes the rest but please like the video and subscribe to the channel Ok Live subscribers are increasing after the live the number is increasing Thank you very much Okay and the afternoon live also got 2000, both together, very good, okay, good night, good sir, chemistry should be started, do it on your own, and at the same time, you should complete 60 videos of your Viva Viva service, okay, Raj, I felt the registration form, now I am not relaxed, I should organize the college option form, I should fill the option form properly, if you take 89% partial drop, you have to pay a little fee, but 89% do not even have a partial drop, do not even take a drop, try to get a good college for 89%, try, okay, Prithviraj, are you not a Golu, okay, what's the problem, okay, is tomorrow a holiday, have you come to the group offline, what kind of holiday is it, we have not posted anything, what is tomorrow, what is tomorrow, who is the student, okay, no story, no name, nothing on holiday here, the call has stopped, kids, there is no 50% rule, why is there still no implementation, it has not been declared yet, okay, very good There are more children, many children have come to chat, Ankur Gurve, bye, okay, tell me about 50k, it has not been implemented yet, Uday Samant, if he was the education minister, he would have been the best, why?

[01:05:11]All the decisions were in the hands of the children and in the interest of 50. I have to say, do n't be afraid of 50%, it is not a very dangerous rule, on the contrary, it is good, you want to start, it is proper, start from here, Viva series, Viva series, 60 lectures for 15 days, complete three or four every day, sir, I saw you four years ago, seeing you and your voice, I felt very strong, oh wow, okay, thank you, there was an attachment with the children, well, remember, okay, the day before yesterday, I went to attend a child's wedding, I had not gone to my children's wedding, well, but the children in the class have gone to many programs, well, okay, there is GR, has the GR of Red Alert come, or not, don't give leave, those who are possible, they have to come to class. Is GR available?

[01:06:07]I am looking at which WhatsApp group. I have just arrived. I have not received GR yet. If you have it, please share it.

[01:06:18]Okay, sir. How to top chemistry? Chemistry is very easy. Do numerical and organic on me. Okay, there are 60 videos left. Everything is covered in them. Why am I afraid of numerical? I am afraid of numerical and organic. Children, if they get it, they go to chemistry. Happy birthday, Dawn. Thank you, thank you, thank you. Okay, wait for engineering now. Kids. I enjoyed it for two years. Dummy college and everything. Colleges like PI CT require almost 100% attendance. Remember that if there is no attendance in COP too, there are no marks.

[01:06:53]Okay, hello, sir. I am an old student. Okay, great.

[01:06:58]Saurabh Bhagat. Okay, sir. What does it matter if I typed WR instead of sir?

[01:07:03]Come on, bye, kids. Shravan Bhosale, come tomorrow on time. Everyone, like it while going to OK.

[01:07:09]Okay 154 kids liked the Java video, thank you all, take note, okay, and do n't get angry with those who were removed for wrong comments, okay, so you study, where can I get organic, now I'm going to take organic, take note, okay, I'm going to take organic too, come on, okay, I'm doing it, good night, see you tomorrow at 2:30 pm, all the best.