This video demonstrates how to solve a geometry problem by extending a line to create an isosceles triangle, using angle relationships to prove side equality, and applying the Pythagorean theorem to find the unknown length X = 5.
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Norway Math Olympiad | A Very Nice Geometry Challenge
Added:Can you find the length X?
If we extend CB to point Q such that BQ is X.
And join AQ then in triangle ABQ It is a B Q AB is X. BQ is X.
That means these two angles they will be equal. Suppose alpha and this angle is two theta.
So alpha plus alpha is two theta.
That means alpha is theta.
So this angle is theta.
And this angle is theta.
And now angle ACQ is theta.
And angle AQC is also theta.
That means AQ and AC, they will be equal.
And AC is 8.
That means AQ it will be also 8.
And now in any isosceles triangle ABC if it is an isosceles triangle from point A if we make a perpendicular on BC suppose this point is P then it will bisect the base.
And also it will bisect angle A.
And we have AB is X and PB is X.
That means ABP is an isosceles triangle.
So from point B if we make a perpendicular on AP suppose this point is M then AP is 6.
That means AM it will be 3 and PM it will be three and also angle ABP is two theta.
That means this angle is theta and this angle is theta.
And also AB is X and BQ is X.
So from point B if we make a perpendicular on AQ we have AQ is eight.
And suppose this point is N then AN and QN they will be AQ divided by two.
So AN is four and QN is also four.
And now in triangle ABM angle at M is 90° angle at B is theta.
So this angle it will be 90° minus theta.
And now in ANBM it is A N B M this angle is 90° This angle is also 90° and angle at A is theta minus 90° minus theta that is also 90° That means this angle it will be also 90° That means it is a rectangle and AN is four so BM it will be also four BM is four and now X is squared it will be four is squared minus three is squared X is squared is four is squared minus three is squared so X is squared is 25 That means X is five >> [music]
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