To solve logarithmic equations like log₅(x) = -2, exponentiate both sides with the base of the logarithm (5), which leverages the inverse relationship between exponential and logarithmic functions; since 5^(log₅(x)) simplifies to x, the equation becomes x = 5⁻² = 1/25.
Instala nuestra extensión para buscar dentro de cualquier video al instante
EXPONENTIATION to Solve log₅(x) = -2 (Using INVERSE Functions! 🔄 which UNDO Each Other!)Añadido:
Another way to think of it is to exponentiate both sides.
5 to the log base 5 of x = 5^(-2) which is 1/25. And then 5 to the x and log base 5 of x are inverse functions. This simplifies to x. They undo each other.
Videos Relacionados
A Number Plus 5 Is 12
MathGirlTutor
101 views•2026-06-03
Olympiad Mathematics | Indian | Can You Solve This One?
PhilCoolMath
650 views•2026-06-03
H2 Math June Holiday 2026 Intensive Revision | H2 Math Tuition by Achevas #singaporemath #h2math
AchevasTV
304 views•2026-06-01
Escaping the Fog
LogicLemurGaming
760 views•2026-06-03
slick TMUA geometry!
JPiMaths
109 views•2026-06-04
Edexcel IAL S2 Statistics June 2025 - Complete Paper Walkthrough | WST02/01
Math_Mind_1
140 views•2026-06-03
A Brutal Radical Expression Made Easy! The Shortcut Changes Everything.
tamoshop
112 views•2026-06-02
Is This Pentomino Tileable?
3cycle
241 views•2026-05-30
