To solve exponential equations like 9^(2x) = 72, apply logarithms to both sides and use logarithm properties (power rule, product rule, change of base) to isolate the variable, yielding x = (2 + 3 log₂(3))/4.
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The Viral Math Olympiad That Stumped Many! | Can You Solve It?
Added:Hello, you're welcome. I want to solve this nice exponential problem to find the value of x here.
Solution from here.
And what we have which is 9 raised to the power x times 9 raised to the power x equals to 72.
First step here, this follows what we have. A times A which is A squared. Also, same thing multiplying can write it as 9 raised to the power x squared equals to 72 on this side.
That is From here, this follows the law of indices. When we have A raised to the power M raised to the power N is the same thing as A raised to the power M N.
That is this power multiplies, we have 9 raised to the power 2x equals to 72 here.
Next step, we take the log on both side here. We have log 9 raised to the power 2x equals to log 72 from here.
And this follows the power law of logarithm. When we have log M raised to the power P is the same thing as P log M.
Then here, this becomes 2x log 9 equals to log 72 on this side.
Next step, we divide both side by log 9.
Divide this side by log 9.
Also, divide this side by log 9.
That is here, log 9 cancels with each other here.
And we have equals to log 72 over log 9.
We can rewrite 72 as 9 * 8.
And what we have becomes 2x equals to log 9 * 8 over log 9.
And this follows the law of logarithm.
When we have log a base b, it's same thing as log a plus log b.
And this here, we have 2x equals to log 9 plus log 8 over log 9.
Okay. This follows when we have a plus b over c, which is same thing as a over c plus b over c.
Then here, this becomes 2x equals to log 9 over log 9 plus log 8 over log 9.
And this log 9 cancels each other here. We have one left, which becomes 2x equals to 1 plus log 8 over log 9.
Then [snorts] from here, we can write 8 as 2 raised to power 3.
And also nine raise three raise to power two.
This equation becomes 2x equals to 1 + log two raise to power three over log three raise to power two.
Apply the power rule of logarithm here.
Three comes here, two comes here. This give us 2x equals to 1 + three log two over two log three.
Which also can be written as 2x equals to 1 + three over two times log two over log three.
And when we apply change of base, this when we have log A over log B, this is same thing as log A to base B.
Then what we have here becomes 2x equals to 1 + three over two log two base three.
I can bring everything to one side to one fraction. This one over one. We have 2x here equals to the LCM and that's two.
This becomes two plus three log two base three.
Then multiply both sides by one over two.
Multiply this by one over two.
So, multiply this by one over two.
Here, two cancels each other here. We have X equals to two plus three log two base three over two times two here, that's four.
So, we have the value of x in this problem in terms of logarithm. Then, let's check if this satisfy this given problem.
That is, we substitute the value of x here, which is x equals to 2 + 3 log 2 base 3 over 4.
Then, this equation already can write as 3 * 9 raised to power x.
Sorry.
That's 9 raised to power 2x rather.
It's multiplication here.
This equals to 72.
So, when we substitute x here, this becomes 9 raised to power 2 * 2 + 3 log 2 base 3 over 4.
Is it equals to 72 on this side?
Then, yeah, since this power multiplies, 2 goes there 1, 2 goes there 2.
And we have 9 raised to power 2 + 3 log 2 base 3 all over 2.
Is it equals to 72 on this side?
Also, 9 same thing as 3 squared.
It is raised to power 2 + 3 log 2 base 3 all over 2. Is it equals to 72 on this side?
And this power multiplies as well. 2 cancels each other here. We have 3 raised to power 2 plus 3 log 2 base 3 is it equals to 72 on this side.
This follows law of indices. Can write as 3 squared times 3 raised to power 3 log 2 base 3 is it equals to 72 on this side.
Then 3 squared is 9.
Then we reverse this 3 whole. We have 3 raised to power log 2 raised to power 3, which is 8 base 3 is it equals to 72 on this side.
Then this becomes 9 times this follows and we have a raised to power log b base a, which is equals to b.
This here we have 8.
Is it equals to 72 from here.
Then 9 times 8 equals 72, which is equals to 72 here.
Left hand side equals right hand side.
And therefore we conclude that the value of x which is 2 plus 3 log 2 base 3 all over 4 satisfy this problem. Thank you for watching.
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