To solve exponential equations where the variable appears in the exponent, convert all bases to a common base, combine exponents using the property a^m × a^n = a^(m+n), then take logarithms of both sides and apply logarithm laws (log(a^b) = b·log(a) and log(a×b) = log(a) + log(b)) to isolate the variable. For the equation 9^(x+1) × 3^x = 30, the solution is x = (1/3)(log₃(10) - 1).
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Olympiad Mathematics | This is beautifully and carefully solved
Added:Okay, so if you're ready, let's solve this one here.
It looks simple, right? But I bet you you will not be able to solve it.
Okay? And if you think you can, let's work this together and see the steps.
This is 9 to the power of x plus 1 multiplied by 3 to the power of x all equal to 30.
What do we do from here? Still on the left-hand side, we know we can write 9 as 3 squared. So, we have 3 squared.
Then we have x plus 1 the power for 9.
Then this is multiplying 3 to the power of x and everything equals 30.
This is 3 to the power of 2x.
2 * 1 is 2.
Then multiplying 3 to the power of x as everything equals 30.
From here now, what do we do?
Remember that we are multiplying these two and we can decide to take one of the base, which is um 3.
Then we have 2x plus 2 plus x.
Right? Once you pick one of the base or one of the bases, you're going to add the powers.
And this is equal to 30.
So, if we take a step, we're going to get 3 to the power of 2x plus x.
That is 3x and we have plus 2 and it's equal to 30.
Now, 30 cannot be written in the base of 3.
Right?
Okay, this is 3 to the power 3x plus 2 being equal to 3 * 10. 30 is just 3 * 10.
So, the only thing we can do right now is to take the log of both sides.
And we have log 3 to the power 3x + 2 equals log 3 * 10.
Okay?
Now, we have log 3 to the power of 3x + 2.
And it's equal to Do you know that we can split what we have here to get log 3 + log 10?
Okay, if you do not know by now, I believe you know.
We are adding them now because of the multiplication. If it was division here, we subtract this. We're going to subtract this.
And then apply one of the laws that has to do with the power.
Okay, the law that has to do with the power is um like this. Log A to the power B can be written as B log A.
Right? So, this is very, very possible.
So, we're going to use this to bring the power down.
And then we now have 3 x + 2 to multiply log 3.
Then we have log 3 + log 10 on the other side.
And by the way, we know that log 10 is the same thing as 1, but we'll prefer working with the log 10 there.
So, we divide this by log 3 so that this will be on the left hand side alone.
Divide by log 3.
Then divide this by log uh 3.
This will cancel this out and this will take this out.
Now, this is what we have left.
>> [snorts] >> Okay, so this is what we have left after canceling out the log 3.
It's only appearing here now. But to remove this log 3, we can even make 3 to be the base to 10.
And we'll have 3 x + 2 equals 1 + log 10 to base 3.
Okay. So, the next step is that I should take this two to the other side.
And I'll have 3 x to be equal to 1 + log 10 to base 3.
And then the two becomes minus two here.
Now, we have 3 x to be equal to 1.
Okay, the one will go because we are going to have 1 minus log We're going to have 1 minus 2.
1 minus 2 is minus 1.
So, this is what we have.
And to continue with this, we are going to get the value of x by multiplying both sides by 1 over 3.
So, we have 1 over 3 multiplying 3 x.
Then on the other hand, we have 1 over 3 multiplying log 10 to base 3 minus 1.
Can you see that?
So, the next um three will take this three out and we have x.
So, our x is now equal to 1 over 3 multiplying log 10 to base 3 minus 1.
So, if we want, we stop here and this is the value of x in terms of log.
Right?
Now, let us go back and put this value into the equation that we have solved.
The equation that we have solved is 9 to the power of x plus 1.
Right?
Multiplying 3 to the power of x equals 30.
So, this means that if we put our value of x now, we should have 30.
If you put your x now, you you're going to go a long way to prove this.
So, the next thing you should do is you simplify the left-hand side.
This is 3 to power 2, but the 2 will multiply x to give us 2x.
The 2 will multiply 1 to give us 2.
Then, this is multiplying 3 to the power of x and all of this will still be 30.
Now, if you pick one of the bases, you have 3.
Why are we picking one of the bases?
Because we are multiplying them.
Then, we add 2x plus x. That will give us 3x.
Then, we have plus 2.
And this is still equal to 30.
So, at this point, what do you do?
Put in the value of x.
So, we're going to have 3 to the power of 3 into the value of x, which is 1 over Okay, let me turn this one.
Okay, so we have this 1 over 3 multiplying log 5.
Let me be sure of that. It is log 10 by the way.
Okay, so multiplying log 10 to base 3 and we have minus 1.
So, this alone is 43 x. Close this and we have plus 2.
I hope you you will not be confused here.
This 3 is this one.
The whole of this is for the x. This plus 2 is over there.
So, that to continue with this since this is this multiplying everything you can just cancel out and this will go.
So, that we now have just 3 to the power of log 10 to base 3 minus 1 and we have plus 2 there.
If you go on, you have 3 to the power of log 10 to base 3 then minus 1 plus 2, that will give us plus 1.
Now, our duty now is to simplify this until we have 30.
Okay, so let's do that.
Okay, so this is where we are and um let's apply one of the laws of indices here.
This is 3 to the power of log 10 to base 3 then multiply by 3 to the power of 1.
I have applied multiplication because of the addition.
Once you have addition between the powers you can split it by multiplying and they will have the same base.
Base 3, base 3 because of this one.
Then from one of the laws of indices this and this will go because they are the same. Log 3 to base 3 can cancel out. So, the only thing left here is 10.
And then it's going to multiply 3 to the power 1. 3 to the power 1 is 3.
And at the end of the day we have what?
30.
No wonder the equation that we have solved is 9 to the power of x plus 1 multiplied by 2 to the power of x it's 3 multiplied by 3 to the power of x equals 30.
The same 30 that we just had.
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