12th Chemistry II Formation of haloalkane and Physical properties of haloalkane II Pandit sir

[00:00:21]What was there before? Let's welcome all the children to our Physics Bihar channel. I am your own Chemistry Gururaj Sir and today we are again going to talk about the formation of halogen.

[00:00:31]As we have already read some formations before.

[00:00:36]Like let's talk.

[00:00:39]What have we read? We have studied halogenation. How are haloalkanes formed in halogenation? Sir, what have we read? Here we have learned how halogens are formed from alcohol.

[00:00:49]Then we said, Sir, this is also due to alcohol. This is also due to your alcohol.

[00:00:54]And then I learned about alkene as well. By applying the Markbonics rule and also by applying the anti-Markbon rule. Then we learned what to make from what?

[00:01:04]We learned this from the reaction of PCL5 on ether.

[00:01:07]Let us move ahead and talk about what we have now.

[00:01:09]Ok? So today we will talk about halogen exchange reaction. We will talk about halogen exchange reaction. So once all the children have joined, they will write their names and also share the link of the video with the new child. Isn't it? Let go.

[00:01:25]Come on, every child who has joined the channel recently, please subscribe to the channel once and comment on the video and also like the video. Ok? Don't leave without liking it. Ok? You must like the video. It is full. So let us know about halogen exchange reaction.

[00:01:54]What is halogen exchange reaction? Let us know it, read it, understand it. Let's do everything in today's class. Okay, yes, okay, let's start. The first reaction that we are going to come across today is called Swart reaction. In the Swart reaction, finally, through this reaction, through this reaction, only alkyl fluoride is made. This is the process of making only and only alkyl fluoride.

[00:02:46]Under this, whether it is alkyl chloride or bromide or iodide, it is not made. Only alkyl fluorides are formed.

[00:03:00]Let's talk about it, let's talk about it here, if we have RCL, then if we react it with AgF, then AgCl will come out and will become RF. Ok? That is, if I react any type of haloalkane with AgF, then what does it prepare? He prepares alkyl fluorides. Let us take an example. So there's CH3, there's CH2 and let's say Br is over here.

[00:03:32]What is ours? This is our done ethyl ethyl bromide. Now let me react ethyl bromide with AgF. So what is this going to be like? So what will this become in CH3 CH2 F and plus? AgBr. Sir, what is this? So, this is your ethyl fluoride.

[00:03:53]What is ours? It is ethyl fluoride. So what do we call this type of reaction? Sword Anish Patel Hi Sir. Hello boy.

[00:04:01]Ok? All children are welcome to our channel.

[00:04:09]Start connecting all the children one by one, all your classmates and friends. Ok?

[00:04:12]Please share the video once and the children who are joining please subscribe to the channel. If you are new or old, please like and comment on the video.

[00:04:18]So what should we write here? So what will we write here? Here we will write that whenever any halo alkane is reacted with AgCl or AgF. Makes the reaction happen. If we make a reaction happen, what is formed?

[00:04:56]Alkyl alkyl fluoride is obtained. And what is this called?

[00:05:05]Ours is called the Swart reaction. Come on, all the children who have joined will write their names once and tell me whether they understood it or not.

[00:05:11]Has this topic become a topic of discussion for you? Is n't it sir? What to do in short reaction? This is a method of making alkyl fluoride. Through this special alkyl fluoride, keep one more thing in mind. There is no such reaction which would produce alkyl fluoride. Apart from this, it is made only from this. I have talked about as many reactions as you have before.

[00:05:30]Even if we have done halogenation. Whether we have applied mercuric, antimercuric to the alkene.

[00:05:37]Then I must have got it done for alcohol. Reaction must have been done on ether.

[00:05:39]Fluoride may not have formed anywhere. Fluoride is made only and only from Swart trition. Ok? So please be careful. So, please keep this thing in mind. Ok? Let us move ahead. Secondly, we will talk about halogen exchange reaction. The second one is called Can Not Can Fickelstein.

[00:06:05]Fickelstein will talk about the Can Fickelstein reaction.

[00:06:13]Alkyl iodide is formed through Cannabis.

[00:06:15]What is made? Alkyl iodide. That means what will you write in it sir?

[00:06:19]Will write that by this reaction alkyl iodides are prepared by this reaction. are prepared.

[00:06:40]That is, what is created solely and solely by this? So RI is formed. What is made?

[00:06:44]R.I. Let's go here Amit Yadav Hi Ganesh Kumar Hi Sir, let's go, very good, all the children who have joined will write their names once, right? What do we have to do in this, it is a very simple process, it is simple, so what will we do, we will bring RX, we will bring any halogen and let's go, there is one more boy Amit, let's go, what will we do with this, we will bring RX here and get it reacted with ni and acetone will be present, what will remain, our acetone, that is, the solvent of acetone.

[00:07:17]We are going to complete the reaction in that.

[00:07:19]Roshan Kumar ji is there.

[00:07:23]Well, after a long time Roshan Kumar ji has come to my class. Otherwise, what will happen to us from here? These Na x will come out. Na X What is left when you leave? RI What is left of ours? It is coming. For example, if we talk about an example, then it becomes CH3, CH2 and Cl.

[00:07:43]If I make Nai react, make Nai react, then see, if this Nai goes away from here, then what will happen here?

[00:07:51]Please keep acetone here. The reaction is going to take place in the presence of acetone. So don't forget to write down acetone. Ok? It is very important to write down acetone. So what did we do here? So Nai went out.

[00:08:03]Sorry NaCl was taken out and CH3 CH2 remained, what will be its name, so this was our ethyl chloride and the one which has been prepared, its name will be ethyl iodide, what will be our ethyl iodide, are you understanding the things, if things are clear to you, let's go RX, yes, very good Ganesh Kumar ji, every child should try to write in this manner, then your speed of organic will gradually improve. Is it okay sir? What to write in it? Sir, in this you have to write that when the haloalkane is converted to haloalkane with NaCl in a solvent like acetone.

[00:09:04]Carries out the reaction.

[00:09:09]Reactions are carried out in a solvent. If you get it done then get it done then ethyl iodide. Yes, if we get it done then what do we get?

[00:09:28]Alkyl iodide is obtained. What do you get?

[00:09:30]Alkyl iodide is obtained. is received. Understood? What will we get? Alkyl iodide will be obtained.

[00:09:39]Let's say the second reaction was of halogen exchange.

[00:09:42]First reaction: Our first reaction, as you might have seen in the background.

[00:09:46]Ok? What happened here was that the alkyl halide was reacted with AgF.

[00:09:51]We had found alkyl fluoride. Then what did we do? The second reaction to this came with Canode bringing Fingal Stein. Then what did we do in this? What did we do in this? Reaction of alkyl halide with NaI was carried out. So we got alkyl iodide.

[00:10:06]We will talk further. We will talk about it next and we will come in the next slide. The final reaction can be called the entire preparation process. The final reaction is with us. It became known as the Bordeaux Hundiskar Method. What is its name? Boredin Hundiskar Method.

[00:10:27]Sir, what should I do in this? In this we have to bring the silver salt of carboxylic acid.

[00:10:33]Silver salts of carboxylic acids. Here we have the silver salt of a carboxylic acid. What is carboxylic acid i.e. RCOOH? R COOH carboxylic acid. Sir, what is going to happen if it is reacted with AgCl? In this condition HCL will come out and RCOA will remain, this will be called carboxylic acid and this is the salt of silver, if we add any other metal to carboxylic acid then carboxylic salt is formed, silver salt of carboxylic acid is formed which is ready now. Now we will bring it, we will bring it. I will keep it somewhere. Please help me sometime later. Isn't it? Here you go. So what do we have to do now? What to do here? What we have to bring here is Br2. What do we have to bring? Keep in mind Br2 and CCl4 will be the solvent of CCl4. Sir, which chapters are you teaching offline right now?

[00:11:35]Alcohol is now going to be available everywhere offline. Ok? Alcohol is about to start everywhere. It is CCL4 and we will get it distilled. What will we get done?

[00:11:45]Distillation. Will get it distilled. Ok? This is hoaken we have finished the alcohol in offline which is going to start there, so here we will do the reaction, so see here there is R COOAg, cut it from here, give one BR to it, give one BR to it, you guys have to keep this in mind too, right, you guys have to keep this in mind too, right, let's keep this in mind too, give one R BR to it, this one is organic and here there is AgBr, so what will happen, our R Br became CO2 and AgBr became, okay, what happened, our AgBr, now what will we do here, we will get the reaction done, we will take it again as an example, whom will we take sir, look carefully CH3 CH2 and here it became COO and Ag.

[00:12:42]Okay, right? Now which of the carboxylic acids is this? This carboxylic acid is propanoic acid. Which one is ours? It is propanoic acid. So we will bring propanoic acid and we will get it reacted with Br2, so it will become your CCL4 and this will be distillation. What will happen? Distillation. Distillation will take place.

[00:13:06]So what will we do here? Yes Roshan Kumar ji, yes you are correct. It's very good. Keep writing and keep writing like this.

[00:13:14]Ok?

[00:13:16]Hello Satyam Kumar Jha is saying here, hello let's go hello aunt okay hello sir yes hello let's go what will we do here, one is our AgBr will be added and what will happen in the plus, one AgBr will be added with our CH3CH2, that means Br will be added, this is ready, see this is the product that was to be made and what will come out along with it is CO2 gas sir its language is very simple, now it depends on the writing sir what is that when the silver salt of carboxylic acid is treated with bromine, with which with bromine, yes Satyam Kumar ji we are reading your comment.

[00:14:07]Explain how CCL4 is distilled in solvent with bromine. What do you do? Get it distilled. Get distillation done.

[00:14:25]So what makes the one and only special?

[00:14:28]Alkyl bromide. This is the process of making alkyl bromides. Alkyl bromide is obtained. Come on, we would like to know from each and every child how many children are attending our live class.

[00:14:40]What is a one-time distillation? Can you guys write? What is the distillation process? Can you write it once?

[00:14:48]What is distillation? Distillation process, tell me what I did here? Here I did distillation of carboxylic acid with Br and we got alkyl bromide. But sir, what is this distillation?

[00:15:00]Any kids anyone kids anyone if there are any who can tell me about distillation.

[00:15:06]Sir, what is distillation? Distillation. Let me write it down here. Ok? I will write it down below.

[00:15:13]About distillation. Ok? Look, I will tell you.

[00:15:18]I want to know what this distillation is?

[00:15:21]Distillation. Let me tell you.

[00:15:27]I am looking at the comments. Anish Kumar ji, Amit Kumar ji, Roshan Kumar ji are there, right? Deepak Kumar ji is also here. Satyam ji is there. Please tell all the children, Sir, what is distillation? Write once about the sky.

[00:15:44]I am waiting for your comment. Isn't it? I am waiting for your comment.

[00:15:50]Can you tell me what the sky is? I think you probably don't know the answer to this. Isn't it? Look at the process of evaporation.

[00:16:00]Evaporation means that if you heat something, vapor will be formed. The phenomenon is called evaporation and condensation, that is, if you cool something, where will it come from being a gas? It will come in liquid. is answer.If you find any mistake in The formation of vapor from a liquid is called evaporation. And after cooling, if the gas is again becoming liquid then it is called condensation. And what will we say by combining both the verbs together? Distillation. It is called distillation here. Actually this is a practical method. You will also have to do practicals in this but whatever you get in the practical exam will not appear in the main exam.

[00:16:36]An instrument is required for practical.

[00:16:38]Every arrangement is required separately. So I will also conduct a practical for that. Please wait a little.

[00:16:42]So for that we need separate equipment. Meaning, I do n't know which instrument is required, sir. Look, no problem, we have already told you that if you mix both evaporation and condensation, it will be called distillation.

[00:16:54]If both processes happen simultaneously then it will be called distillation. Ok? Let go. So now we will do practical and what will we tell in practical that how we get the distillation done.

[00:17:02]How does the distillation process take place?

[00:17:04]What type of equipment is brought in it? Have you ever been to a practical room? If you have ever gone for practical then there will be a lot of wickers there.

[00:17:12]You will see that glass tubes will be kept there. Isn't it? There will be a lot of things. For example, let's say the hexagonal blades are even. There will be a lot of things. So if such things have to be brought here then it will be practical. Ok? Well, here our recipe for making it is over. Let us repeat it once.

[00:17:27]Ok? Because the child should remember the method of making it because you will definitely have to answer a two mark question from here in the exam. I will definitely come. Okay, right? First we will get halogenation done. Sir, what was the process? The hydrogen had to be removed.

[00:17:39]Halogen had to be installed. First process finished. Second, what do we have to do, sir? Will react with alcohol. The first reaction was named Grove reaction. In which we brought the Lucas agent for the Lucas test.

[00:17:49]Concentrated HCL and anhydrous ZnCl2 were brought. Then what did we do?

[00:17:54]After that you have to react bromine with HBr. Then got it done with HI.

[00:17:58]Then what did we do apart from this?

[00:18:00]Reactions have been carried out with PCL3. Got it done from PCL5.

[00:18:03]After that there will be another reaction of alcohol which was done with thionyl SOCl2 in the presence of pyridine. Thionil. Yes, yesterday there was a question about pyridine. If any child knows the answer then you can start writing it in the comment box. Ok? What happens? So reactions were done in Pirdin's present.

[00:18:19]So the name of the reaction that took place was Dargen reaction.

[00:18:23]What was his name? Tarzan's brother dtarzan reaction. After that, we should see the rule of Marcommary Copes that all the negatively charged atoms that you have, the anions, they got attached to the carbon having less hydrogen. Isn't it? Then we saw the reverse action. If the carbon with more hydrogen was connected to the carbon with more hydrogen, then we put antimark cof carbon.

[00:18:44]Then apart from this, we got the ether reaction done and just now I got the Swart reaction done. In halogen exchange reaction, Swart reaction was the first reaction in which I made alkyl fluoride by reacting it with AgF, then I made alkyl iodide by Connot Fingelstein and in this RI was made, then what we did was we made Brodine Hundsker here, in this RBr was made, what did RBr mean, sir, what alkyl bromide was made, we formed our alkyl alkyl bromide, so after knowing so much here, where does our method of making it end, what happens, it ends, we come towards the physical properties. Let's get into physical properties. So we have got a very lovely topic. Physical Properties of Physical Properties of Haloalkanes. Today we are going to study in detail about the physical properties of haloalkanes.

[00:19:40]Let us study the physical properties of haloalkanes today. There are those who know.

[00:19:46]If you have taken a copy then write each point in rough.

[00:19:52]You will remember a lot of things. We are going to know the first point first.

[00:19:54]In this, first of all we will learn about the number one physical state. Physical State: Learn about physical state.

[00:20:06]About whom? We will learn about the physical state, that is, physical state means whether it is solid or liquid or gas. They will know this. So, in very beautiful words, we would like to say and write that Sir, the carbon of C1 and the carbon of C2 are haloalkanes.

[00:20:30]Isn't it whose head? C1 and C2 which are haloalkanes. Haloalkanes are composed of one carbon.

[00:20:39]Sir, please give me an example.

[00:20:42]CH3CL CH3CH2Br carbon one and carbon two carbon one and carbon two which is a halo alkane. This haloalkanes are carbon one and carbon two which are haloalkanes. Isn't it sir, it is in gas state for you.

[00:21:03]Gas is in the state. Sir, it is in gaseous state. That is, if someone asks you in which state is CH3Cl? So it is in gaseous state. Seconds we talk. Let us discuss the second point. So sir, the number of carbons from C3 to C3 to C18 will be as much as the halo alkane. Like sir, if someone asks you that tell me C5H1, what type of haloalkane is it, Savita Kumar good evening sir ji good evening, okay pyridine is a carbonic chemical compound, it is structurally like benzene, yes but nitrogen is present in it, okay, so here C5H1 is asked which type of haloalkane is it, then this one of ours is in liquid state.

[00:22:02]whose? It is the heliocene of the liquid state. Isn't it? of the liquid state. very nice.

[00:22:08]Roshan Kumar ji is also giving good answers.

[00:22:09]Let's have a thumbnail for you. You are giving very good answers.

[00:22:12]Then after this, if we talk about, let's say, haloalkanes above C18. The above Halochain.

[00:22:24]If we talk about haloalkanes above C18. The higher the haloalkanes above C18, the more they will be in which state? It will be in solid state.

[00:22:34]In which will it be? In solid state. That means sir, what did we know? We learned in sweet words that all the hexocenes that are going to be formed from carbon one and carbon two will be in the gaseous state. It will be gaseous. And the alkanes that are going to be formed from Sir 3 to 18 will all be liquid and the ones after that, i.e. the haloane above C18, will be in solid state.

[00:22:59]Okay, very good sir, please speak a little louder, your voice is quite good. Here also I have kept it on and I keep watching my own video to see how I teach.

[00:23:15]So my voice is quite good and maybe I am speaking loudly too and maybe other children who need to hear my voice, is there anyone else who is having problem with their voice, okay, once again all the children I request you to write your name and all the children who are joining, please like the video once and go, do not leave it without liking, okay, right, tell me on the video, it gets so many views, right, 300-400 views are enough on the video, but when I see 10-15 likes, my soul starts crying that friend, why are the children not liking, what does it mean, you are not teaching properly, what does it mean, please like, friend, please like the video, go and like, do not go without liking, okay, please, I request you, I request you, without requesting you, like, let's move it a little up and write a note thing, what do you write about the note thing, sir, let's write it, so I will mix the color, okay, then I will write, come, let's write in the note, see Note Sir what is RBR which will be RBR and RI Hello Alkane Ajit Kumar ji Hello Sir Ji Yes Hello Okay Hello Sir Ji Hello Hello RBR and RI Hello Alkane which will be Hello Alkane Babu Re these will be coloured how will they be coloured they will be odorous the more RBR there is for example suppose it becomes CH3, CH2, CH2, Br, it becomes propyl bromide Ajit yes it becomes propyl bromide or whatever we take with Br and I all of them will be coloured and along with that what will be odorous a kind of smell will come out from inside it okay you can smell it if you reach there with your nose okay smell it comfortably so let me repeat it once again in physical state sir carbon one carbon two carbon one carbon two haloalkanes will be in gas state then haloalkanes from 3 to 18 will be in liquid state sir haloalkanes above C18 will be in solid state sir hello in alkane you will get alkyl bromide It is and alkyl iodide, what are these two sir, both of them are colourful and odorous, let's be clear, let's see once, all children, it is clear, I am reading the comments, all children please write, it is clear, I will read the comments, okay, all children please write, you must write once, okay, it is clear, I will read the comments, what is the comment of the child? Isn't it? Ajit Kumar ji has said yes.

[00:25:49]Ajit Kumar ji said yes. And any other children whose comments I am reading, please clear them all once. Is yours clearing up? Isn't it?

[00:26:15]Let's look at the comments.

[00:26:22]Come on, all the kids are joining in the comments here.

[00:26:24]Ganesh Kumar ji also agrees.

[00:26:27]Savita: Yes sir, sir it is clear. Anish yes sir. Rajdev Rai ji is saying sir yes sir.

[00:26:33]Let's be clear. So next I am going to bring properties. Let me talk about the next property, it is solubility. Second, what is our soliloquy? Sir, what is solubility? Solubility means solubility. Let me talk about solubility, sir, how much will it dissolve in water? Let me talk about solubility.

[00:26:56]Sir, if any child comes to the comment section and tells us about solubility, it will be a great favor from you. Isn't it? Sir, what does solubility mean, how much will it dissolve in water? So keep in mind that the halo alkanes, okay, are slightly soluble in water, what is it in water, slightly means at least we can say soluble in water, but sir, where is it soluble, so keep in mind that there are as many organic solvents as there are organic solvents. There are as many organic solvents. For example, in organic solvents, you should know the names of some organic solvents. Okay Ajit Kumar, good evening sir. Good evening, isn't it, let's say organic solvent, let's talk about it, like in organic solvent, let's say chloroform, which is the most organic solvent? Is it carbon disulphide? It has become benzene, etc. Take it, is n't it? In all these, what is there in organic solvent, do n't say much, what is written, it is slightly soluble in water, very good in organic solution, applause should be given for Ganesh Kumar, very good, very very good, etc. What is there in it, extremely, extremely, highly, it is soluble. What I mean sir is that this thing which is soluble in water sometimes does not catch me. Isn't it? What constitutes excessive? It is soluble. Sal dissolves in water and dissolves well. It dissolves in water and what happens? It dissolves well. Ok? CCL4 Yeah, great. It will also dissolve in chloroform.

[00:28:54]Ok? Look at organic solvents, the saying is simple, like dissolves like.

[00:28:59]You will see that only boys sit in boys' groups. If only girls sit in the girl group then organic compound will be suitable in the organic compound group. Therefore, it can be said that it can dissolve easily. Yes, for Ganesh, oh let me talk further.

[00:29:14]Ok? If any child makes a wrong comment, he will be blocked. Keep this in mind. Keep this in mind.

[00:29:20]Ok?

[00:29:24]If you behave like a fool in the class, then the children of your class remain silent.

[00:29:28]In online classes, your parents also watch your videos. Ok? So your comment may also be commented on somewhere.

[00:29:34]Therefore, the child who makes wrong comments can also be blocked.

[00:29:40]Sir, please block Amit Kumar Yadav. So close his comments. Of Amit Kumar Yadav. Let's talk about the third one.

[00:29:50]When we come to the third, when we come to the third, we will talk about density very well.

[00:29:56]In the third, that means Sir will talk about density. Let's say, do any children know anything about density? Do any children know anything about density? What does Sir know about density? We will write that the density of halo alkane is more than that of hydrocarbons.

[00:30:28]What is the density of a halo alkane compared to a hydrocarbon? It is more. You should already know this. What is the density of haloalkanes relative to hydrocarbons? It is more.

[00:30:36]Sir, what is the reason? Isn't it?

[00:30:40]What is the reason for this? So see, which bond is found between the molecules of hydrocarbons, which bond is found between the molecules of hydrocarbons, which bond is found between the molecules of hydrocarbons.

[00:31:12]Wonderwall bond is found. Okay, that's great.

[00:31:23]Wonder Wall bond is found.

[00:31:25]Dipole dipole force is found in haloalkanes. very nice.

[00:31:29]And in which dipole dipole attraction force is found between the molecules of halo alkane.

[00:31:58]Ok. Which action is found?

[00:32:03]Hydrocarbons have a higher dipole dipole density than haloalkanes. No no, this, this, this is very wrong, yes Amit Kumar Yadav ji, you can subscribe and unsubscribe and you can go. They can also block you.

[00:32:15]Your unsubscribe child will not earn here. The child who wants to study will study. This doesn't happen for a pickpocket like you.

[00:32:23]Ok? So what will we do here? Be careful here. Okay sir, please block him, what will he do by unsubscribing Amit Kumar, just block him and remove him, what is to be done here CH4 CH4 CH4, this is not a child who will read. This is going to be a gimmick. I think its result will also be filed. He says he doesn't read or write.

[00:32:54]Here it is CH4 CH4 CH4, right? So which bond will be found in between?

[00:32:58]Bond will be found in the middle of Wonderwall.

[00:33:01]Such a child does not read or write. He fails. Isn't it? And what will this boy do in the future? What is the tax going to be? Will be able to do something in life in future. This boy will not be able to do anything. Isn't it? This boy won't be able to do anything. Ok.

[00:33:15]His life will be ruined like this. What kind of useless donkey is this? Isn't it?

[00:33:24]So Wonder Wall Force is found in between this.

[00:33:26]See, Wonder Wall Force is a weak bond.

[00:33:29]Ok? The dipole dipole attraction force is strong. So what is the dipole dipole attraction force? It is CH3Cl.

[00:33:44]Which will be found between its molecules between its molecules? What will our dipole dipole force of attraction be found to be? Dipole dipole attraction force will be found. Ok?

[00:33:59]Yes, I do not teach in Kashipur. I have left the market and if you still want to study then you can study from us online.

[00:34:06]Yes, I am MD Furkun, whatever your name is. Ok. I do not teach in Kashipur.

[00:34:14]If you come towards Darbhanga, you will find it. I will meet you. Ok. Yes, I teach offline. But if you come to Darbhanga, not to Kashipur or Samastipur, we will meet. So what we have to do is we have to clear each and every concept about density.

[00:34:27]Okay, now see, actually we are telling you, you should understand this. People only tell that the density of haloalkanes is more than hydrocarbons. I have explained the region to you.

[00:34:36]What is the region? So, in hydrocarbons there is Wonder Wall F and in haloalkanes there is dipole dipole attraction F. The dipole dipole attraction F is much stronger than the Wonder Wall F, that is why it is okay.

[00:34:50]Let us move ahead. Next, any child will tell me which is the next property, which property is the next? Ok? Okay, tell me, I will quickly repeat it once more.

[00:35:00]What did we learn in this?

[00:35:02]What we learned from this is that it is soluble in Haloake but very little. But it is terribly soluble in organic solvents because it dissolves in similar solvents. Like dissolve like, right?

[00:35:13]Sir, where are you taking this class from? Yes Roshan Kumar is talking about melting point and boiling point. Ok?

[00:35:21]I will teach him. This online class of ours is being run from Neeraj Sir's place. And we are currently giving classes from Neeraj Sir's place.

[00:35:29]Ok? Isn't it? Let's talk if we can. Ok.

[00:35:35]We are going to talk further, so we will talk about four. Isn't it?

[00:35:39]What's in four, sir? Melting point Melting point And do you understand? The concept should be understood.

[00:35:47]If you understand the concept then it is very clear. Isn't it? The concept should be understood. Yes. MP M BP Melting Point and Boiling Point.

[00:35:58]Put a point here.

[00:36:00]Sir, we call this melting point.

[00:36:06]Melting point and sir this is called boiling point.

[00:36:11]Melting point and what else sir? Statement no.

[00:36:14]We will talk about melting point and boiling point. Understand.

[00:36:21][Sound of deep breathing] Look, write down each and every thing, it happens anyway. It is more than hydrocarbons. Please write down the MP and BP of haloalkanes i.e. melting point and boiling point of haloalkanes i.e. sir melting point and boiling point of haloalkanes, melting point and boiling point of haloalkanes, on which sir? The melting point and boiling point of haloalkanes are dependent on the molecular mass of the haloalkanes, i.e. on the mass, on the molecular mass, on what sir? Depends on the molecular mass. It depends on. It was very important to write this. That means what does it mean to say Sir?

[00:37:23]Hello, with the increase in the melting mass, speaking yes Roshan Kumar ji is saying that the melting point will increase, I have written that it depends on the atomic mass. So suppose if it is increased.

[00:37:37]Understand, understand directly. Atomic mass is atomic mass indirectly. Is n't that what it's for?

[00:37:48]Indirectly, for whom? So for melting point and boiling point. Understand the matter.

[00:37:55]If the mass increases, if the atomic mass increases, if the mass increases, then in that condition the melting and boiling point will also increase.

[00:38:06]If the mass increases then the melting point and boiling point will also increase. That means what will happen to the melting point and boiling point? It will increase.

[00:38:14]By increasing the mass. You should understand this. Keep this in mind. Now sir, if you please talk, I will take an example.

[00:38:21]Suppose sir, if you have RF, say alkyl fluoride and RCL and RBr and RI, then whose melting point and boiling point will be maximum. Which will have the highest melting and boiling points?

[00:38:37]Now know about this. Sir, first of all, there is one thing which is constant, sir. What is? RR is a constant. is constant. Meaning, whatever the mass of this R, the mass of this R will be equal to it. The mass of this R will be equal to all of it. But what is different, sir? Chlorine has a greater mass than fluorine. of bromine more than chlorine. of iodine more than bromine. Sir, if the mass is seen, whose mass is the most? RI Eye's.

[00:39:12]So the liquid boiling point of RI will also be maximum.

[00:39:14]BR has a little less than that.

[00:39:18]RCL has a little less than that. And who has less than that? RF's. That means sir, if seen according to the mass, the boiling point of RF is the lowest.

[00:39:33]Yes. So if we see, RF has the least mass, so its melting and boiling point will also be low.

[00:39:40]And what will be the melting point and balling point of RI? It will be more. Let me talk further. Ok?

[00:39:48]I will take one more example. Like example number two is CH3, Cl is CH3, CH2, Cl is CH3, CH2, CH2 and CL. There is no notification for online classes.

[00:40:08]I will see what the problem is with it.

[00:40:10]I don't know myself. I am also new to online so I don't have any idea about all this.

[00:40:15]You guys please tell me your idea so that I can know what the problem is. I will be able to deal with the problem, right? So here we have methyl chloride, ethyl chloride and propyl chloride. Now sir, if we see, the mass constant of chlorine is equal everywhere. Here one carbon, here two carbons, here three carbons, sir, whose three carbons have the highest mass. That means sir, it will have the highest boiling point. It will be less than that.

[00:40:44]That means Sir, whose melting point is going to be the highest? So it is going to come in which the number of carbons is going to be more.

[00:40:55]What will be the mass of the place where the carbon number is higher? Meaning it will be more and the one which has more mass, understand what will be its melting point and boiling point? It will be more. But pay attention here.

[00:41:04]Ok?

[00:41:06]Here is something you need to pay attention to.

[00:41:10]Sir, where? Here.

[00:41:13]Here, remember the next example, this example CH3CH2Cl Sir, take this example CH3 CH3 CH CHCl, then our CH3 CCH3 CH3 CL, now our logic is that with the increase in mass, the boiling point and melting point will increase, the logic of hexadecane will flop here, sir, sir, how come the number of carbons is two. The number of carbons is three. The number of carbons is four. So where will the mass be more? So your mass should be more here.

[00:41:52]Where is the lowest? Should be within 1°.

[00:41:55]This is 1°. This is 2° and this is 3°.

[00:41:59]So the maximum mass is in 3°. And where is ours the least? It is in 1°. So 3° carbon should have a higher melting point than the balling point.

[00:42:08]And it should be less than 1 degree.

[00:42:11]But this does not happen logically here.

[00:42:15]Now what happens here is that the lowest here is 3°. It is more than that by 2°. And which has the highest boiling point? Of 1°. Now Sir Reese knows.

[00:42:27]What is the reason for this? What is the reason? Now let's check the reason sir. So, the reason is that you come here. Pay attention here. Ok? Isn't it? At 1 degree it is creating a long chain. As we are coming closer, what is happening in peace? The sphere is rotating.

[00:42:43]And when we came here, this entire circle had rotated.

[00:42:46]Like chain chain, when the entire sphere rotates, then the spherical part, why is it a sphere? Do you know what Reese is? The reason for something to be spherical, like a liquid, is surface tension.

[00:43:00]What happens inside it? Surface tension. So here the rule of surface tension is working. The surface tension is increasing here. It is decreasing here. This is happening between the two of them. So due to high surface tension here, its melting point and boiling point have decreased. Look, it's done.

[00:43:17]And due to the reduction in surface tension here, its melting point and boiling point have increased. Now sir, please tell me what is surface tension. Isn't it? So the use in liquid is that property of liquid which wants to minimize its size. It is called surface tension or the force applied per unit length is called surface tension. So this happens due to surface tension. Isn't it? Well, if you want to know more explanation then you should read about surface tension once. Isn't it? Sir will also teach in the physics class. Okay, right? Please come and attend his class. Isn't it? After this his class is about to start so he keeps explaining there what bathing is.

[00:43:52]If we look closely, our physical properties have ended here.

[00:43:56]So I would like to tell the class what do you do? Let's pause. Isn't it? So let's go ahead and drag the class out a little longer. I am telling you a little more. Let's check out the dipole moment today for any meaning of HaloCain. Look, you should keep the dipole moment at 100 by CO. You must be a student of some place, so I know that you must be memorizing that which of the following has more dipole moment, but Guruji, today we will not stop memorizing, we will bring the concept to you, we will fix each and every neuron of your forehead, from the neuron it will go to your cerebrum, if it goes to the cerebrum then it will remain there for life time, come on, every child, please comment once again, who are the children, Sir, your voice is coming very low, your voice is coming low, what is it, is n't it? So let us talk about the dipole moment.

[00:44:47]Come on, what do you guys know in general about the Dupol Moment?

[00:44:52]What do we call a dipole moment? is called the dipole moment.

[00:44:57]Sir, what do you know?

[00:45:05]Which children know about dipole moment? Please comment. Come on, every child has started writing their Dupole moment. Which children know about the dipole moment? Let me say in simple language, if you have studied in physics that if you want to find the electric field at any axis point, if there is any charge for it, then you will have to find it for the uniaxial point.

[00:45:30]Then you will have to extract at any point. You might remember that it must have happened there. Isn't it? f must have come out equal to 4 0 q1 q2 / r², it must have come out square of r + l, but here the definition of dipole moment will remain the same, will it remain, sir, the charges which exist, the charge, the distance between the charge and the charge, the distance between the charge and the charge, the distance between the charge and the charge, what do we call the product of this, it is called dipole moment, sir, in chemistry it is indicated by μ and μ is equal to q * l, what is our q * l and sir, its unit is given as dy in chemistry, its unit is given as dy, which is also called Kalam meter, what is it called, Kalam meter, not centimeter, it is not centimeter, it is Kalam meter, what is our Kalam meter, so sir, here we will take an example which comes in the exam. Is n't it sir? What comes in the exam? The question arises that which of the following has zero dipole moment.

[00:46:57]What happens? It becomes zero. Every child will have the answer to this. We know. Isn't it? Have you even started writing the answers?

[00:47:04]Yes. Every child will know the answer somewhere or the other. But today we will find out how it came about. Will find out.

[00:47:12]So look at the first example. Let's move on to option number A. It is CH3Cl. Let's move on to option B. CH2Cl2 is. Let's move towards C. CH is CHCl3. And as we move to the Fourth, there's CCL4. That means, if we talk about it sir, then monohalogen is haloalkanes. Dihalogen is haloalkanes.

[00:47:38]Trihalogen is haloalkanes and polyhalogen is haloalkanes. See, Roshan Kumar ji's answer has come. CCL4 We already said that.

[00:47:46]Whatever is on the tongue of every child, there will be an answer to this.

[00:47:48]But Babu, we have come to explain the concept.

[00:47:49]Ok? You must also know the concept sir. As far as we feel.

[00:47:54]Just look at what is there, I will tell you one thing, whether it is an offline platform or an online platform or any other platform, your only aim should be to improve your preparation.

[00:48:10]No matter from which platform you prepare, from where you prepare, you have to improve your preparation. Let's go here NRR drama this is the first time you are coming to our class children please write your name so once okay CCL4 yes sir it is the same yes I am saying the right thing that offline online any platform you have but you have to prepare better in our time in our time there was no online system it was so offline whatever guruji used to teach we used to study and come back I am telling the reality I am saying in this class like today I am dealing with organic the guruji did not teach us like this how guruji used to teach us organic he brought the language, wrote it down and gave a reaction as an example we came back after studying like this but today see how much change has come, the way of studying has changed in learning the reaction we wanted to memorize the reaction at that time we got good marks by memorizing it you can understand what is the condition of learning so the same thing is here if you are taking classes somewhere, in any coaching and you are not getting the concept clear there then you should take an online class once But go check out that concept, right? You just have to keep in mind that your concept should be clear. From whom is it becoming clear?

[00:49:22]From which teacher are you studying to get it clear? This should not come to mind.

[00:49:26]Come to the online platform. We would say that here each and every concept of Physics and Chemistry will be clear to you. Isn't it? Be it us or our Neeraj Sir, whoever comes here will come here to butter up the concept. Let's go here is the tribal Chhara.

[00:49:40]Wow, where have you come from? We feel like we have come from the forests of Madhya Pradesh. Greeting sir. Isn't it? Hello hello. Let us now understand logically here that this is carbon.

[00:49:53]This is H. This is H. This is H and this is Cl.

[00:49:59]Seconds. Let's talk about seconds. This is C.

[00:50:01]This is H. This is H. This is Cl. This is Cl. Let's talk about the third one. This is H for third.

[00:50:09]This is Cl. This is Cl. This is Cl. Let's talk about Fourth. This is Cl. C is. Here Cl here Cl here Cl have to be checked. Is from MP.

[00:50:22]very nice. You have to check that if different elements are connected in front of each other. That's how you're connected.

[00:50:30]Consider that if this is carbon, such an element is attached. If there are different elements in front then there will be some duple moment. Understood? His Dupol moment will be something or the other.

[00:50:41]If you want to know more about Dupole Moment then do not miss a single class.

[00:50:50]I will write down the value of each negativity of electronegativity and you can subtract it from it and find out the remaining value but it will be costly for you because in that you will have to remember each value one by one. You should keep this method in mind, you can solve any kind of question, but where it comes to lone pair electron, this concept is not going to work there.

[00:51:08]Understand it logically, see here h is in front of h, so let's assume its dipole moment will be zero, but here Cl is in front of H. It will have some kind of Dupol moment. So let's assume that would be alpha.

[00:51:22]So its alpha dipole moment has arrived.

[00:51:25]Nothing came. He had some kind of dipole moment.

[00:51:27]Sir, let's talk here.

[00:51:30]Who is this in front? Cl is. There will be some kind of dipole moment in front of H. Let's assume alpha.

[00:51:37]Here, Cl is in front. The front is Cl. So what will be its dipole moment? It will become zero. If the CM is in front then he is zero. So let's say this is alpha.

[00:51:46]Look here, this is H in front and here Cl is alpha, what will happen here also, it becomes alpha, means these 2 alphas have some dipole moment, its alpha has become 2 alphas, its alpha has not become zero, but look here, in front Cl means sir, zero in front, Cl means sir, how much is zero and zero and zero, sir, zero means you got the answer, congratulations, you got the answer, what will be C CCL4? This will be the correct answer. You must have understood. Okay, now that you understand, all the children please start writing yes sir once. So let us end today's class here.

[00:52:32]How did you like the class, with all the children who joined? Please do give your feedback once.

[00:52:34]We will meet in the next class. Please give feedback once to all the children.

[00:52:38]I am reading all your child's comments.

[00:52:40]Ok? You guys must give your feedback. Ok?

[00:52:45]Okay, whatever is there in this, you guys should definitely start giving feedback and I get very few likes. I am saying again that till today 20 children have joined but the likes are so less, right? Yes Roshan Kumar Rajdev, what is this name, Rajdev Rai, the ID is of this girl, right? Okay, yes, it is correct, it is clear and children, tell me it is clear, tell me it is clear, it is clear, let's meet, in tomorrow's lecture, isomerism will be our topic and chemical properties will also be a topic, that's all for today, Jai Hind, Jai Bharat.