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A Tricky Algebra Challenge You Should Try!
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252 views14likes3:33Learnandplay_1Original Release: 2026-05-29

To solve exponential equations like x^x = 2^(8+2x), apply index laws to simplify both sides: first expand 2^(8+2x) as 2^8 × 2^(2x) = 2^8 × 4^x, then divide both sides by 2^8 to get x^x / 4^x = 2^8, which simplifies to (x/4)^x = 2^8. By expressing 2 as 8/4, we get (x/4)^x = (8/4)^2, and by comparing bases and exponents, we find x = 8.

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