Grade 11 MATHS ASSIGNMENT TERM 2 2026 | EXPLAINED PART 2

Hinzugefügt: 2026-05-12

[00:00:01]Hello grade 11 learners. Welcome back again to part two of our assignment practice assignment. We're going to look at question three. Now the question three that we are having. Let's go through it. Don't forget to subscribe to our channel and be part of us. All right. Uh the first question is sketch the graph of y. Okay. and showing the asymptotes and intercepts with the x axis. So rather with the axis not x with the axis. So what you're going to do you'll draw a line.

[00:00:43]Okay.

[00:00:46]You draw another line.

[00:00:49]All right. So with this one now you check your asim tote which is minus2. So you come to minus2 then you draw the broken line is asym tote. Now you look for x intercept. Okay you look for the x intercept on this graph. So which means you're going to say um 0 is = 3 /x - 2 2 = 3 /x.

[00:01:32]Therefore x = 3 / 2. So x will be at 3 / 2. You put a dot. We don't have the y intercept.

[00:01:43]Okay. Asmtote that's zero. So now what will be the graph?

[00:01:50]What will be the graph on this case?

[00:01:54]What type of graph the what type of graph that we're going to have?

[00:02:04]Uh x y =0.

[00:02:07]>> It's on the as it's on the asmtote. So remember that when a is greater than zero, the graph is on the first quadrant.

[00:02:21]Okay, the graph is on the first quadrant and the what? The first quadrant and the third quadrant. So now since y is the asim tote, so the graph won't touch this. it will be here. That will be the graph that you're going to have. All right? And then the other one it should be here.

[00:02:49]Just that the way I'm drawing it, my pen is not putting a nice curve. So, but this is how the graph should be.

[00:03:02]That is how you draw the graph. That is the answer for 3.1.

[00:03:06]Okay.

[00:03:08]All right. Now let's try to answer the questions and see 3.2.1 give the equation of the vertical asmtote. Vertical asmtote it's x is equal to z is the vertical one. Okay.

[00:03:28]x is equal to 0.

[00:03:32]All right. Horizontal asmtote it's y= minus2. When you draw this y it is a broken line it become horizontal.

[00:03:43]Right.

[00:03:49]Next graph that will result if you shift the graph two units upwards and two units to the right. So two units you're going to have 3 over 2 units to the right. it's minus upwards it's plus so that will be the new graph in this question write down the x intercept I told you that x is 3 / 2 that is the x intercept the x intercept of the graph all right that's all dearas uh let's go to the next question which is question four All right, question four. What does it says?

[00:04:32]It's talking about the parabola and the straight line. Okay, let's look at the question itself.

[00:04:42]4.1 determine the length of AB. So this is the X intercept and this one X intercept of the graph of G. So I will say 4.1 X intercept why it's zero. You don't let it's just zero. - 6x - 16. Therefore, we say x and x. Let's factoriize. It's 8 and 2. Minus and plus the value of x is 8 or x is minus 2.

[00:05:16]So, what are you going to do? The length you will say ab is equal to the bigger number minus the smaller number. So it's going to be 10 what units? That is how you answer the question. We are done with 4.1. Let's go to Q. What is Q? Q is the point of intersection where the two graphs are meeting. You see I put a green there.

[00:05:44]All right. What do you do? You equate the two graphs. You say f ofx is equal to g of x. Let me start with g.

[00:05:55]x^2 - 6 x - 16 is = - x - 2. Let's group x^2 - it will be - 5x because this one will be plus then it will be -4 is equal to z. Therefore you factoriize these ones that this was x and x 7 and 2 minus and plus. So x is = 7 or x = -2. You got the two answers. Which one are you choosing?

[00:06:31]Remember this minus2 is the same as a.

[00:06:34]So which means 7 is the one. So how do you deal with this one? Then you take seven and replacing any of the two. I can replace 7 here - 7 - 2 it's - 9. So the coordinate of qang it's 7 is to - 9.

[00:06:55]All right.

[00:06:56]Okay. Let's also go to the next.

[00:06:59]Remember this is 7 is to - 9. This is -2 is to 0. This is 8 is to 0. Okay. I believe that that one is clear. Okay, let's go to the next one. Determine the coordinates of Q. We did that. Show that the turning point is this one.

[00:07:23]Turning point that is 4.3. We say X is equal to minus B / 2 A minus what is B?

[00:07:32]It's - 6.

[00:07:36]What is A? It's 1. So x is three. Okay, x is three. Then you replace it up there in the original.

[00:07:47]3^ 2 - 6 into 3 - 16 is equal to what?

[00:07:53]Let's press our calculator. We're going to get - 255. So the coordinate of the turning point is 3 is to minus 25. I believe that one is clear for you dear learners.

[00:08:07]All right.

[00:08:09]Now the next question is for which values of x where f is above g. f is the straight line. So this straight line you see from here it's above up until this part. So you will say from minus2 up until 7. That's where it's above. Okay it's above from here. Check g is below this one is above from minus2 up until 7. Right? Now uh determine the value of for which value of k is x^2 - 6 x + k + 4 = 0. We'll have two equal roots. When we talk about equal roots, k should be equal to the y value of the turning point. So this thing you say x^2 - 6 x um + 4 is equal to minus k.

[00:09:24]Okay.

[00:09:31]What is the turning point? It's minus 24.

[00:09:38]All right. Now this k we are talking about you can see this side we're having a four. So we want this side to have a minus 16. So we're going to say x^2 - 6 x for me to get a -6 there I should I should say + 4 - 20 you see is equal to - k - 20 I'm subtracting both sides by minus 20 so I'm having x^2 - 6 x - 16 is equal to - k - 20. Therefore, - k - 20 is equal to - 255. You you must equate it to the turning point every time. Less you equate it to the turning point. So this one will go this side. It will give you a minus five. So the value of k will simply be a five. That's how difficult the question was. The issue was two equal roots. You equate two equal roots. You equate to the turning [music] point. That's all learners. Till we meet on the next video, don't forget