In dilution problems, the mass of the solute remains constant while only the total volume changes; to solve, calculate the solute mass from the initial solution, then determine the new total volume needed for the target concentration, and finally subtract the initial volume to find how much solvent to add.
Deep Dive
Prerequisite Knowledge
- No data available.
Where to go next
- No data available.
Deep Dive
Adding Water Doesn't Change the SALT | GRE Dilution Trick in 60sAdded:
Most students get this GRE quant question wrong. Let's tackle a dilution problem that trips up a lot of students.
A chemist has 100 ml of a 20% salt solution. How much pure water must be added to dilute the mixture to a 5% salt solution? First, track what stays constant. Adding pure water doesn't change the salt mass, it stays fixed.
Next, find the salt mass. 20% of 100 ml means we have 20 g of salt. Now, we need a 5% solution. So, 20 g divided by 0.05 gives us 400 ml total volume. Subtract the starting volume. 400 ml - 100 ml means we need 300 ml of water to dilute it. Remember, on dilution problems, anchor to what stays constant. Here, the salt mass is key. Want more tips like this? Hit that subscribe button.
Related Videos
A Number Plus 5 Is 12
MathGirlTutor
101 views•2026-06-03
Olympiad Mathematics | Indian | Can You Solve This One?
PhilCoolMath
650 views•2026-06-03
Escaping the Fog
LogicLemurGaming
760 views•2026-06-03
H2 Math June Holiday 2026 Intensive Revision | H2 Math Tuition by Achevas #singaporemath #h2math
AchevasTV
304 views•2026-06-01
A Brutal Radical Expression Made Easy! The Shortcut Changes Everything.
tamoshop
112 views•2026-06-02
V : jee main /advance class 11 mathematics : Binomial Theorem class-1 ( 29 may 2026 )
dcamclassesiitjeemainsadva9953
125 views•2026-05-29
Is This Pentomino Tileable?
3cycle
241 views•2026-05-30
This Sudoku Has Many Lines!!
CrackingTheCryptic
2K views•2026-05-29











