Ozonolysis cleaves carbon-carbon pi bonds in alkenes and dienes; under reductive conditions, it produces aldehydes and ketones rather than carboxylic acids. For a diene with two double bonds, ozonolysis yields three products: two aldehydes from the terminal carbons and one ketone from the internal carbons.
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Ozonolysis Question: Alkenes and Dienes #alkeneAdded:
Eight. How many different products will form as a result of the following transformation? So we have this dyene and we have ozone. When you see ozone, you know you're doing ozonalysis.
That is a very easy one to remember. You see ozone, you're doing ozoneis. What does ozoneis do? Ozonalysis cleaves carbonarbon pi bonds. And we're going to pull apart the molecule wherever there is a carbonarbon double bond. And then because we're in reductive conditions, we're not going to get any caroxilic acids or anything. We're just going to get aldahhides and ketones. What we're going to do is we're going to cleave at the carbonarbon pi bonds. And now let's pull everything apart. So what do we get? This first fragment over here.
We're going to get a threecarbon aldahhide. Then let's get this fragment here. This will give us a twocarbon aldahhide. Just to be very clear, we will leave everything in the configuration as it looks on the starting material. Then let's take this other fragment here. This will have two carbonial on it because it has two carbons that were participating in pi bonds. So that will look like this. So we have one, two, three products as a result of ozoneis. So that will be C.
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