10TH PRELIMS STAGE-2 MATHS ANALYSIS (18/07/2026) | 10th Prelims CancelledExam | Kerala PSC

[00:00:00]Welcome to Study Win PSC. We are discussing the Maths questions of the Prelims Stage 2 exam that were not held yesterday. Those who could not write the exam yesterday, do not worry. PSC will be conducting this exam soon. So, everyone should study well for that. Okay, first question is 5600 divided by bracket of 22pa 5 e 6 my 50 y by a a i a e equal to how many solution. Solve this.

[00:00:34]5600 divided by 22pa 5 e6 minus 50 wide by 5 e how many equal to how many calculations. All the calculations should be solved by setting the Bodmas rule. Bodmas bracket of division, multiplication, addition, subtraction, that is, if there is any calculation in the bracket, it should be done first. All the calculations should be done by division first, division then multiplication then Addition and subtraction should be in this order.

[00:01:08]Look here.

[00:01:10]The calculation inside the brackets should be done first. There are two brackets here. If there are more brackets, the calculation inside the innermost bracket should be done first. Look here. What is the calculation inside the innermost bracket?

[00:01:23]Then that should be done first.

[00:01:26]Here it will be like this. 5 00 Divide by What is inside the brackets?

[00:01:32]22 Paa Naa Iu 6 Minus 50 Divide by What should be inside this bracket?

[00:01:39]What should be done first? Ia 25 When the calculation inside the brackets is done, you will get that bracket.

[00:01:45]Look here.

[00:01:48]25 That bracket is gone.

[00:01:51]Now you have to do it inside this bracket.

[00:01:56]Here you have to do 56 00 Divided by What should be done first. You have to do the division.

[00:02:04]Ia 50 Ba 25 What will be two. Then what should be done after the division is done. Multiplication Ia 30 will be done. Look here. Inside the brackets, we get 22x30 minus two, which is 5600.

[00:02:29]Now what should we add here? So 22+ 30 52 52 -2 So this is 5600 times 52, how much is 50? So when all the calculations in this bracket are done, the bracket is gone.

[00:02:45]Look at 5600 Y by 50 zero zero cut off 12 60 112 5600 by 50 112 The answer is answer option B.

[00:03:11]Next question If M stands for division, N stands for multiplication, Q stands for addition, and P stands for subtraction, then how many solutions are there for 125MA 5 cubeA 4 pi? Just sign it as given and solve. Okay, what is 125MA cubeA 4 pi p two M? M stands for Harana.

[00:03:49]Give M the division sign. What is Q?

[00:03:53]Q is addition, so add Q. N is multiplication. So multiply by n. P is subtraction, so minus P.

[00:04:06]So it comes out like this 125 divided by 25 is a minor Now all these calculations have to be solved by applying the bottom rule.

[00:04:23]We have said this before, but let me tell you one more time Bottom bracket of division multiplication addition subtraction That is, if there is any calculation in the bracket, it should be done first All calculations should be done first division then multiplication then addition then subtraction This should be done in this order Look here what division comes first 125 ba 25 Then what is needed after division then multiplication then what comes 6 is 24 How does this come out 25p 24 minor Now what is addition here Let's add 25 more How much will it come out 49 Will come out 49 Mar Last subtraction 49 Minor 47 47 is the answer option A Question three and two one plus one four minus one Two-thirds equals one. How many solutions?

[00:05:21]Solve this.

[00:05:23]Three and two-thirds plus one-fourth minus two-thirds. So here is the calculation of the mixed fraction.

[00:05:36]Once the mixed fraction comes, the trick to do it is to separate the calculation of the numbers in it and the calculation of the fractions. Then solve it. Okay. Okay. So look here. When you calculate the numbers, what are the numbers?

[00:05:51]Three are there? My Ra. Then look, minus two one.

[00:05:54]Now what is the calculation of the fractions? What are the fractions? Two-fourth plus one-fourth minus one- third. Okay. We need to find the LCM. Two-fourth three. Two-fourth two-fourth. Then what is the LCM?

[00:06:36]LCM equals two-fourth So what will happen here? Write 12 in the denominator of the Lasagna. In the numerator, the Lasagna will be divided by the denominator and multiplied by the numerator. So what will happen? 12/2 6 *O 6 plus 12/4 3 *O 3 minus 12 /3na 4 iona Here, if six and three are taken from the left by four, then I get five out of 12. Then look how it will come out. When I did the calculation of the numbers, what did I get? When I did the fraction, I got five out of 12. How will this come out?

[00:07:21]One plus 12 out of 12, that is, one out of 12 is five out of 12. Answer Answer option B The fraction between one third and three fifths Solution The trick is to find the fraction between one third and three fifths. This is the numerator of the given fractions.

[00:07:47]Add the denominators together.

[00:07:49]That's all there is to it. The program is to look at it. Add the numerators together.

[00:07:56]Divide by the denominators. Let's make four out of eight into one.

[00:08:03]Two. Then it will come out as one out of two.

[00:08:06]Then this The fraction between one third and three fifths is one in two. Answer option A is the next question.

[00:08:21]How many solutions are there to solve?

[00:08:26]P2 E P3 E P4 This is the multiplication of a decimal number. In the multiplication of this decimal number, the number of places after the decimal point in the given numbers will be the same. When multiplied, it should also appear in the answer. So look here.

[00:08:54]How many places are there after the decimal point in these given numbers?

[00:08:56]One, two, three, four, and six places. When multiplying this, the answer that is obtained should also have six places after the decimal point.

[00:09:04]So look at the option D that has six places after the decimal point.

[00:09:10]Look at the option D that has one, two, three, four, and one place after the decimal point. So, here is the answer to the option itself. Answer option D. Now let's talk about how to do this, that is, as mentioned earlier. To multiply the given numbers, there will be as many places after the decimal point in the given numbers as there are places after the decimal point in the multiplied answer.

[00:09:36]So the first thing to do is to multiply the number there without considering this decimal point.

[00:09:41]Look here and you will get 2 IMA 6 * 4 24. Now, look at how many places there are after the decimal point in the numbers given to multiply. So many places, just move the odd place of the answer obtained by multiplying to the left and put a dot. Then look here.

[00:10:04]How many six places were there in the numbers given to multiply?

[00:10:11]Without considering the decimal point obtained by multiplying, just move the odd place of the answer obtained by multiplying to the left and put a dot.

[00:10:17]Look here. There is only one odd place. There are only two places. Since there are no more places left, put a zero there. So two places are not that place. There are two.

[00:10:27]Now, put four more zeros. Put a dot. The answer is given. What is zero?

[00:10:36]Okay. The next question is. The question paper I took was not very clear, so I have changed it. That is why you see that these two questions are the same question.

[00:10:49]Okay. The question is this. If a person sells a product for Rs. 3250 and gets a profit of Rs. 750, what is the profit percentage? Solution. The formula for finding the profit percentage is profit.

[00:11:05]Percentage equals profit divided by cost price, that is, the profit percentage is equal to profit divided by purchase price, that is, 100 cost price, purchase price profit profit, okay, look here, what is given here, if a product is sold for 3250 rupees, then a profit of 750 rupees is obtained, then what is the profit percentage? What is given here, what is the selling price, the selling price? It is given as 3250 rupees, and the profit is also given. The profit is 50 rupees, so from this, we have to find the cost price. Purchase price profit is equal to sale price minus cost price. Then what will be the cost price? Cost price equals sale price minus profit, that is, the purchase price equals sale price minus profit. Look here, we have to find the cost price.

[00:12:11]What is the selling price minus profit? 3250 by What is 750? If 750 is subtracted from 3250, it becomes 2500. 2500.

[00:12:26]Now, if we substitute, we can get profit passage, profit by cp, 100.

[00:12:33]Look, what is profit percentage?

[00:12:35]What is profit? 750 divided by the purchase price, 2500 divided by 100 is 30 percent. Profit percentage is answer option C.

[00:12:52]Question: In the annual examination of class 8, the average marks of 20 children in mathematics were 75, but the mark of one child was incorrectly recorded as 60 instead of 50.

[00:13:06]What is the correct average mark of the children in that class in mathematics?

[00:13:09]Solution: Here, the average marks of 20 children in mathematics were 75. Then the total marks of 20 children are equal to the average in the number. The total marks of 20 children are 20.

[00:13:33]This means that the average in the number is 75. When 150 is 20, when 75 is 20, the total marks of 20 children are 1500. Here, the mark of one child is incorrectly recorded as 60 instead of 50. If so, the question here is what is the correct average mark of the children in that class in mathematics. Then look here, what is the total? The average mark of 20 children was 75. Then what is the total? 1500.

[00:14:04]So what is here?

[00:14:06]The mark of one child is incorrectly recorded as 60 instead of 50.

[00:14:08]So what is here?

[00:14:13]You need 50 marks out of 500. But why is 60 marks recorded incorrectly?

[00:14:19]Then add what is needed and subtract what is recorded incorrectly.

[00:14:23]So the total will be 1500 plus 50 minus 60, that is, the marks that are not required, add that, subtract the wrongly recorded marks from the total, that's all there is here, 1500 plus 50 minus 60, now divide this by how much, so there were not 20 children in total, if you divide by 20, you will get the correct average marks, look, what is it, okay, dad, what is it here, 1500 minus 150 minus 60 divided by 20, what will it be? When you say 550 minus 60, 1490 divided by 20, 2A 14, then 2A points will come within nine, dad, when it comes to 10, 2A 74 goes, that's the correct average, dad, answer option A, question, all the children of class 10th, D division, together, donated Rs. 2401 to the Chief Minister's Relief Fund, and each child will receive the same amount as the total number of children in the class.

[00:15:42]If a child contributed, how much did he contribute? Solution: Here, we need to find out how much did a child contribute. The total amount contributed by all the children in a class is 2401 rupees.

[00:16:01]Here, the total number of children in the class is the same.

[00:16:04]Each child contributed the same amount. If the total number of children in the class is X, then that is the amount given by one person. If the total number of children in the class is X, then this X will be the amount given by one person. So, what is this total T called? x is equal to x squared x squared. From this, the value of x will be found. If a child contributed, then [cheating] what will be x x squared 2401?

[00:16:34]What will be x?

[00:16:41]Find the square root of 2401. This is the trick to finding the square root of a number. First, we need to change the odd number by two digits and divide the number into two parts. First, look here. In the odd position, we have one. Here, we have two digits and divide the number into two parts. This is the first part. This is the second part. In the first part. We need to take the square root. In the second part, we need to take the odd digit of the given number. The square root of the first part. The first part is 24. Since 24 is not a perfect square, we cannot take its square root directly. Then we need to take the square root of the maximum of 24, that is, the perfect square immediately below 24.

[00:17:25]Then the perfect square immediately below 24 is the square root of 16. Here, four in the first part.

[00:17:34]Now, using the second part, we need to find the odd digit. Then, look, there is one in the odd digit of this given number. Then, what will be the odd digit in its square root? If not one, it will be nine.

[00:17:46]So, what do we need to do to know whether one or nine comes from the odd digit in this square root here?

[00:17:54][Cheers] Here, there is this number that we got in the first part.

[00:17:58]This square root is the big number next to it. First multiply this by the number, then what is the larger number next to this four, which is five, then multiply four by five, and you get 20. Now, see if this number in the first part is greater or smaller than this number obtained by multiplying it. If it is greater, then the larger number in this will be in the odd position. If it is smaller, then this smaller number in this will be in the odd position.

[00:18:26]Then look at this first part. You need to compare it with 24. To get this multiplication, then 24 is greater than 24 20. So what will come out?

[00:18:37]This one or nine will be the larger number in this will be in the odd position.

[00:18:41]So what will come out?

[00:18:44]49 49 is the square root of 241.

[00:18:52]How much did each child contribute here? 49 Answer option D A detailed video of the trick to find the square root is on our channel. So everyone go and watch it and learn. There are detailed videos of the trick to find the square root and cube root on our channel.

[00:19:08]Look at it and you all learn, okay? The question is, Sarah has three ribbons of length 42 meters, 49 meters, and 63 meters.

[00:19:17]Sarah cuts this into ribbons of the same length.

[00:19:22]What is the length of each piece?

[00:19:41]Solution: If you give her something of different lengths and ask her to make it into pieces of the same length, all you have to do is find its HCF. If you give her something of different lengths and ask her to make it the same length, you will find its HCF.

[00:19:44]So look here. We have to find the HCF of 42 41 o 63. That is, Utsah. Let me tell you a trick to find the HCF. That is, if all the remaining numbers can be divided by the smallest number in the given numbers, that will be its HCF. If it is not possible to take it that way, then it will be the largest number by which all these given numbers can be divided. Let me tell you the HCF again. If all the given numbers can be divided by the smallest number, that will be its HCF. If it is not possible to take it that way, then all the given numbers can be divided by the smallest number. The largest number that can be divided will be the HCF. If it is a small number, you can easily find the answer by using this trick.

[00:20:36]Look here. 42 49 63. This is the smallest number of numbers. 42.

[00:20:43]Can 42 be used to divide 49 63 and 49 63? No.

[00:20:46]42 is not the HCF.

[00:20:48]Then we need to look at the largest number that can divide all these given numbers.

[00:20:53]Its HCF. Here, the largest number that can divide 42, 49, and 63 is seven. So what is the HCF? Seven is seven. So what is the answer? Option B. If you don't understand this, you can find the HCF as usual. In the normal method, look at 42 49 63. There is seven. 7 6 42 7 49 79 63. What is the HCF here? Only seven years. Since the answer is 7, the answer is 7 meters. Okay.

[00:21:28]Question: Arun travels from Thrissur to Kozhikode at a speed of 100 km per hour and from Kozhikode to Thrissur at a speed of 60 km per hour.

[00:21:36]So what is the average speed on that trip? Solution The formula to find the average speed is Average speed equals one divided by one divided by two. The given speeds are: Average speed S equals one divided by two.

[00:22:13]Substitute the value of 100 km/h and 60 km/h into the formula Average speed s = 2 100 * 60 by 100 60 160 Remove the zero and see if it is 2 16 2 2 2 2 2 7 75 Average speed is 75 km/ h Answer Option D Question The sum of the even numbers between one and one hundred Solution The formula to find the sum of the n consecutive even numbers starting from two is SumS equals one. The number of consecutive even numbers starting from two is The formula for finding the sum of numbers is A. The number of numbers is A. So here we need to find the sum of even numbers between one and 100, that is, we need to find the sum of even numbers from two to 24, and so on up to 98. So here we first need to find N. We know that there are 49 numbers from two to 98, so let's take N = 49. Now those who don't know that, use the formula and find out, that is, what is the formula for finding N, the number of numbers in an arithmetic progression? What are even numbers?

[00:23:58]Arithmetic progression is a parallel series. So, just use this formula to find the number of numbers. N is the last number, the first number, and the common difference. Okay, then look here. The last number is 98 minus the first number. Two is 98.

[00:24:22]What is the common difference? What is the common difference of numbers? Two plus two will come plus one.

[00:24:27]Look at 98. 96. 96. 2. 1. 96. 2. 1. 96. 2. 48. 48. 49. 50. 45. 20.

[00:25:12]2450.

[00:25:15]Answer option C. Question: What is an odd number?

[00:25:22]120. 170. 101. 145. Solution: If we say that an odd number is an even number, then all the other numbers will have a common property except for one of the given numbers.

[00:25:32]That common property will not be present in the cover.

[00:25:36]Look at this. There are four numbers given here. Three of them will have a common property. One of them will not be seen. That one will be an odd number.

[00:25:43]The numbers given here are 120. 170. 101.

[00:25:50]145. Let's see what the general nature here is.

[00:25:54]Look, if we say 170 170, then 13 squared is 13 squared plus 13 squared plus 13, that is, what is the square of 13? 169 169 o 170 Similarly, look at 101, what is the square of 100? Add one to the square of 101, that is, what is the square of 100? 100 p o n 101 Now look at 145, what is the square of 12 plus one, what is the square of 12? 144 144 p o n 145 121 Does it come like that?

[00:26:48]121 cannot be taken like that, that is, one is subtracted from the square of 11. 120 What is here, one is added to the square of a number, that is the general nature here, 13 squared plus 10 squared plus 12 squared plus one, that is, to the square of a number. The common feature here is adding one more. So which one does not have that common feature is 120. So which one is the odd one here is 120. Answer Option A If you can write a clock as XOLXP in a code language, how can you write a watch using the same code? Solution The code of a clock is XOLXP.

[00:27:28]Similarly, we need to find out what the code of a watch will be.

[00:27:35]So look here and see that the letter C is X. So the letter C is the third letter in the English alphabet. If we look at the position order of the English alphabet, C is the third letter in the order. Similarly, we know that in the reverse order of the English alphabet, X comes in the third position in the reverse order. Because XYZ comes last. So it comes in the third position in the reverse order. X comes in the last position in the reverse order. So this is what happened. When I saw these X and X, I understood what it is. Its code comes in the same position in the English alphabet, both in the order and in the reverse order. So, there are codes to easily remember the positions in the order and reverse order of the English alphabet. When we say the order of the English alphabet, it comes from A to Z, that is, from one to 26, and so on.

[00:28:29]The code to remember the positions of the English alphabet in the order is 10 15 20 25, that is, in this fifth position, J 10 O 15 T 20 Y 25 and so on.

[00:28:44]Up, you remember the code to remember the position order of the English alphabet, Ejoria 10 15 20 25. Listen, now in reverse order, how does it come when it is in reverse order? Eramath comes first. That is the reverse order.

[00:29:22]Eramath Ezard comes first. That is the code to remember BGL QV 25 20 15 10A. The code to remember the English alphabet in reverse order, when you say reverse order, Eramath and Ezard come first. So how does it come to BGL L QV 25PAA?

[00:29:29]That is, B is the 25th G, the second L, the third Q, the fifth OK, look now, okay, now there is no need to check this on the clock.

[00:29:44]Listen, because look here, look inside the clock, where C comes. See, here where there are three, X has come, it has come, now there is no need to look for O, L, or K. Okay, let's find the code of the watch. If we put the code of the watch, what is in the case? If it comes third, C.

[00:30:05]Anyway, C is what we got here, inside the clock.

[00:30:08]What is X in the third position in the order? In reverse order, if the order is third, C is third, then X is third in reverse order.

[00:30:16]Now look, A is the first position in reverse order, which is the first in reverse order? Z is the first in reverse order. When it comes first, Z is the first. Okay, now we need to have W, T, and E together.

[00:30:32]T is the twentieth in order. In reverse order, the twentieth is G. The 20th G is OK in reverse order.

[00:30:52]Now when we say W W, what comes 23rd in the order? In reverse order, what comes 23rd in the reverse order? If it is 25 B, what comes 25 B? When we say 24 23, what comes CD?

[00:31:20]23 In reverse order, what is 23? The 23rd position is D. Now what is H in the order? H is in the 8th position. In reverse order, what comes 8th position? Okay, Q Q is 10th, then when Q is 10th, what comes 8? When we say A, what comes 8th in the reverse order?

[00:31:51]What comes 8th in the reverse order? What comes 8th in the reverse order? Then what comes D, 217 double 63 how many solution 35 uity 17 double is 63 su how much look here find out how this came about first set 35 217 this came about if we put 35 what is the square of my i.e. what is the square of 6 36 36 my o 35 look like this if we put 21 17 217 what is the cube of 6 216 that father if we add one to the cube of 6 we get 217 up what is the cube of 6 216 plus one7 father what have we done here subtract one from the square of 6 add one to the cube of 6 i.e. subtract one from the square of the same number add one to the cube of the same sum then we should get 63 look at it to get 63 the number that comes with it then what is the first thing we have to do is subtract one from the square of a number 63 How do you get the square of 8? Isn't it 64? If you subtract one from 64, you get 63? Then subtract one from the square of 8. Look, 64 is my one, 63 is the same. What is 63?

[00:34:02]What is the next number to add to the cube of 8? The cube plus one is 512, 512, and 513. The answer is answer option C. For a competitive exam, memorize the squares of the numbers from 1 to 30 and the cubes of the numbers from 1 to 15. When you see all this, the idea of ​​it will come to your mind immediately. Did you hear that it is like this? Okay, the question is, five years ago, Radha's age was three times that of Sita. After three years, it will be twice as old.

[00:34:42]But what is Sita's current age? The solution is the same type of problem.

[00:34:47]This was also in stage one of prelims.

[00:34:49]I explained it in detail then, okay, so what is here? There is a simple formula to find the current age of the youngest person in this type of problem. If we look at this type of problem, the times given here are the times a few years ago and a few years later.

[00:35:12]The formula to find the current age of the youngest person in the question is: y1 i1 my1 plus y2 i1 my1 divide by y2 Let me explain this type of problem again, that is, if the times given are given a few years ago and a few years later, the formula to find the current age of the youngest person is: y2 i1 my1 plus y2 i1 divide by y2 Here, y2 means years, times means times. Okay, look at this, here, five years ago, Radha's age was three times the age of Sita. So what does that mean? Sita is the younger person here. Radha's age is three times that of Sita five years ago. What is this Sita who is the younger person here? Then what is Sita's current age? When we use this formula, that is, the question is the same. The question is, what is Sita's current age? Then what is the age of the younger person in this type of problem?

[00:36:30]Then look here. What is y1y15? Tiva is three. Viva is the corresponding number. Tiva is the corresponding number. What is the corresponding number? There are two numbers.

[00:36:55]Now, we just need to substitute the value. Viva is the difference of the times. That is, 3 is the difference of the times. When we say 2 is the difference of the times. What is the difference of the times? There is only the difference of the times in the denominator. If there is anything negative there, don't be afraid because this is an age problem. When it comes to an age problem, there is nothing negative there. Okay, the difference in times comes in the denominator. So look here. How much will it cost?

[00:37:42]Plus, it is 2 times or 3 times. What is this?

[00:37:56]Divide by 13. 13 times. What is 13?

[00:38:03]Sita's age is 13 years. Answer option D. Have you studied this formula? It is a simple formula. The difference in times in the denominator comes in the numerator.

[00:38:22]Okay, question 4. If the numerator is 2 plus the bracket of 14, then the numerator is equal to 13. What is the solution to this?

[00:38:36]Solve 4 IU by 2 plus 14 Barapama Iuma All calculations should be solved by using Bodamas' rule.

[00:38:51]Bodamas' bracket of division, multiplication, addition, subtraction, that is, if there is any calculation in the bracket, it should be done first. All calculations should be done first, division, then multiplication, then addition, then subtraction.

[00:39:04]So here, first do the calculation in the bracket.

[00:39:08]Then look, it will come up like this. IU byra plus do the calculation inside the bracket.

[00:39:16]What is 14 by 2? What should be done first inside the bracket?

[00:39:19]Division and addition.

[00:39:21]So first you need to do the division. Then look, what is 14ba2? Seven. Okay, Dad, Seven.

[00:39:27]Now look here.

[00:39:35]What is inside the bracket of IU byra plus, seven. When you have done the calculation inside the bracket, you will get that bracket.

[00:39:40]Okay, Dad. Here is the seventh number, now look at it, now what is it here, IOBA2PA IOBA, now what do we do here, what do we do first, division, right?

[00:39:54]So if we divide IOBA2 and say 9/2, how much 4.5 will we get? To make it easier, let 's write it like this: IOBA2 is 4 IOBA2, if you take it like this, after taking it like this, you can quickly do 4BA2. It's 4 by 2. Okay, let's write it as 4 IO 9/2PA 10 IOBA. Or when you do IOBA2, how much 4.5 will we get?

[00:40:27]Then it's easier than multiplying 4.5 by four.

[00:40:29]Here's 4 IOBA2.

[00:40:32]So look at it, let's divide four by two, let's divide four by two. Let's do division first.

[00:40:38]Look, if we say 4BA2, how much two will we get? Look, look at this, we get 2 IOPL 10 IOBA. What do we do here?

[00:40:46]Multiplication is what you need to do. One is 18p 10 im 30 18p 30 48 48. The answer is answer option B. Okay. A is B's brother. B is C's daughter. C is D's son. So who is A's? Solution This is a family relation problem. So first, let's understand the symbols. To represent a male person, we will use a plus sign. To represent a female person, we will use a minus sign. To represent a couple, we will use a sign like this.

[00:41:21]Now, if it is the upper generation, someone will go up. If it is the lower generation, someone will go down. If it is the same generation, someone will go in the same direction. Okay, just understand all these things. Now let's draw a figure. A is A's brother.

[00:41:41]So A and B will be on the same line. When A is A's brother, what happens when A is also a male person?

[00:41:49]Plus Sign given B is the daughter of C is the daughter of B. So B minus B is female so C is the son of D. So C is the son of D.

[00:42:12]So C is male so C is the son of C. So if this is the case, the question is who is D of A. I looked at the figure and drew it and understood from the figure that B is the daughter of C. B is the brother of B. What is A? So what is it that A and B are the two children of C. I understood that C is the son of D.

[00:42:48]So who is the father or mother of this C?

[00:42:51]D is not given whether D is male or female. So the question is who is D of A. So the two children of this C are A and B.

[00:43:00]The person who says C is the son of D. So who is D of A?

[00:43:07]Because D is the son of C. The two children of C are A and B. The person who says D is A's grandfather or grandmother. The person who says D is A 's grandfather or grandmother.

[00:43:15]There is a grandfather in the given option so the answer is grandfather. Option D is grandfather. Okay question 35 If Meera's position from the front is 16, what is Meera's position from the back?

[00:43:30]Solution: Look here. If Meera's position from the front is 16, what is Meera's position from the back?

[00:43:44]So what is the total here? There are two directions here. So the position in the direction from the front is given. The position in the direction from the back is the position to be found here. So if you give two positions in opposite directions, then the total is called this opposite direction. Add one to it and subtract one. So if you take the two opposite directions as M and M, then the total is called T. M plus N is my one.

[00:44:18]Look here. Here is the total.

[00:44:22]The position from the front and back is given here. Dad, I have given a position here. What can I take as M, it is 16. If so, N is the value to be found here.

[00:44:33]Substitute 35 to 16.

[00:44:41]Look at the equation. If you go from 16 by one, how much is 15? What is 15?

[00:44:50]What will be 35? What will be 35 minus 15?

[00:44:54]What is 20? Then Meera's position from behind is 20. Answer option B [corrects throat] Question: A man walked 100 meters south from his house and then went 200 meters to the left, because the road was blocked. He turned right and walked 300 meters and then turned right again from there and walked 200 meters.

[00:45:17]Now in which direction is he from his house?

[00:45:19]Solution: This is a direction problem. So first let's understand what direction is.

[00:45:27]Here, above is North, below is South. On the left side, West, on the right side, East. This is how the direction comes. Above is North, below is South. This is something that everyone knows very well. When we see West and East, there is a confusion. West comes. There is a similarity when we say west and left. Just remember that. West left, west left, west left, west comes from the left side and east comes from the right side.

[00:45:53]Okay, then to turn right from one direction, you have to move in a clockwise direction. To turn south from one direction, you have to move in an anti-clockwise direction. Up, remember that. To turn right from one direction, you have to move in a clockwise direction. To turn left, you have to move in an anti-clockwise direction. Okay, Dad, let's draw a figure. If a person walks 100 meters south from his house. If this is someone's house [clears throat], he walks 100 meters south from his house, that is, 100 meters south, then 200 meters left, what should he do to turn left counterclockwise? Move in the direction anticlockwise.

[00:46:44]He turned right and walked 300 meters because the road was blocked for 200 meters in the anticlockwise direction. Then, to turn right, what should he do? To move in the clockwise direction, he turned right for 300 meters and walked 200 meters from there. To turn right, what is the clockwise direction?

[00:47:03]Then here is the counterclockwise direction.

[00:47:09]Now, how far is he from his house?

[00:47:11]Look, he left here and arrived here. When he says, "Which direction is this south?", then he understands that he is in the south direction. Now, how far is he? That is, the person who left here has arrived here. So, look, this distance is this distance. We need to find this distance. So, look, this distance is 100 meters. This distance is 100 meters. Now, we need to find this distance.

[00:47:45]What is this distance? Look, this is 200. This is 200. If these two are the same, then these two will be the same. If this is 200. This is 200. If this is 200.

[00:47:59]Look, this is 300. So, this is 300. What is this distance here? It will be 300. So look, how many will it be from here to here? 300 plus 100 400 300 plus 100 400 meters. It will be 400 meters in the south direction, right? 400 meters south, that is, 400 meters south. Option C Question: If five times the fifth term in a parallel series is equal to nine times the ninth term, what is the fourteenth term? Solution: If M times the Mth term in a parallel series is equal to A times the Mth term, then Mpae will be equal to zero.

[00:48:44]Remember, if M times the Mth term in a parallel series is equal to N times the Nth term, then Mpae will be equal to zero. So what is five times the fifth term? If it is equal to nine times the ninth term, how many zeros will the fourteenth term be?

[00:49:16]Look, that is, what is M times the Mth term, that is, Ffive times the fifth term of the Mth term, then If equal to nine times the eighth term, that is, Ekna is equal to M times the M term, if Mpae is equal to zero, that is, what is Eana plus O, that is, the fourteenth term, the fourteenth term, everyone will be zero.

[00:50:00]What is the answer here?

[00:50:02]Zero is not given in the given option.

[00:50:04]So what is the answer here? The option D is nothing.

[00:50:09]Okay, if we talk about this exam, the 20 questions in Maths were easy, but if we take our time, we can do this. I heard that Maths questions were very easy, but it took some time to do it. Overall, if we talk about this one exam that was canceled, it seemed easy because GK and current affairs were very easy. So, don't worry about the second stagers who did the exam and canceled it.

[00:50:36]You will have to take the PSC exam soon.

[00:50:38]It was the easiest one.

[00:50:42]Let's pray that the exam will be easy, right?

[00:50:43]You are studying well.

[00:50:47]Okay, then all the very best to everyone. If you like this channel, subscribe, support, share, and there is an option called Hype below this video.

[00:50:57]Click on that and support.

[00:50:58]Those who are interested, join the Telegram channel of Study Win PSC. Important notes are available on the Telegram channel.

[00:51:03]And one more thing, Study Win PSC is planning to start a crash course for village field assistants. If you are interested, let me know. For that, the first thing you need to do is join the Telegram channel of Study Win PSC.

[00:51:19]Listen, then all the details are there. The course fee is a very small fee, just 600 rupees. All the subjects and classes are there because GK, Current Affairs, English, Malayalam, Maths. I will take all of this, sir. It will be based on previous year's questions. Those who are interested, join the Telegram channel of Study Win PSC. Those who are interested in joining the course, too. Okay, sir. Thank you all.