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Can You Find ALL Real Solutions to This Tricky Exponential Equation?
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709 vues25J'aime5:14Learnandplay_1Version originale : 2026-05-20

To solve exponential equations like 2^(x-1) = 3x + 1, one can use algebraic manipulation by rewriting the equation to create common factors, then substituting a new variable (y = x-1) to simplify the equation into 2^y = 3y + 4, which can be rearranged to 2^y - 3y = 4. By comparing terms on both sides (2^y = 2^4 and 3y = 3×4), we find y = 4, and substituting back gives x = 5.

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