To solve exponential equations where the unknown is in the exponent, apply the law of indices to separate terms, isolate the unknown by dividing both sides by the same exponential expression, use the quotient rule to combine bases, and then take logarithms of both sides to bring down the exponent, allowing you to solve for the unknown variable.
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Why Everyone Is Failing This Simple Olympiad QuestionAdded:
how to solve this math Olympiad question.
This is very simple to solve and I want you guys to pay close attention.
Because by the end of this video, you will know the solution to this equation.
So, let's get started.
Now, from the law of indices in the left-hand side, if you have a to the power of x plus y, this can be split and it can be written as a to the power of x multiplied by a to the power of y.
So, in application of this in this expression, this become 5 to the power of x multiplied by 5 to the power of 1 to be equal to 6 to the power of x.
So, 5 to the power of 1 is 5. So, we shall have 5 to the power of x multiplied by 5 to be equal to 6 to the power of x.
Now, there's something I want to do to this equation. Very interesting. Watch.
I want to shift this unknown to one side.
So, how can I achieve that? I can achieve that by dividing both side by 6 to the power of x.
So, if I divide here by 6 to the power of x, also divide here by 6 to the power of x.
Okay? So, I want to separate this this left-hand side.
This can be written as 5 to the power of x divided by 6 to the power of x multiplied by 5 to be equal to 1.
Because this divide this is 1.
So, what next?
Um there's a law of indices that state that if you have um a to the power of x divided by b to the power of x, this is the same thing as saying A over B all to the power of X.
So, in the application of this law in this place, we shall have five over six all to the power of X multiplied by five is equal to one.
Now, watch this.
I don't want this five to be in the left-hand side. So, what can we do?
Let's multiply or let's divide both side by five.
So, if we have five over six all to the power of X multiplied by five is equal to one.
If we divide here by five and also divide here by five.
Okay?
So, this will cancel out. We're going to leave it five over six all to the power of X will be equal to one over five.
Now, we cannot express the base to be in the same form.
What do you do? You introduce log to both side. That's logarithm to both side.
So, we shall take the log of both side in base of five over six.
So, we shall have the log of five over six all to the power of X in base of five over six will be equal to the log of one over five in base of five over six. As you can see, I am introducing log of five base six to both side.
So, what we are going to do is that there's a law of logarithm that state that if you have um the log of A to the power of B multiplied by A, this is the same thing as saying B log of A base of A. Of course, the log of A base of A is equal to one. So, we shall have B times one which is equal to B.
So, X will multiply the whole this, which become X multiplied by the log of 5 over 6 base of 5 over 6 will be equal to the log of 1 over 5 base of 5 over 6.
So, the whole of this become 1 according to this. So, we shall have X times 1 is X. So, which become X will be equal to the log of 1 over 5 base of 5 over 6.
And this happens to be the final answer.
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