Amines | Full Marathon | RE-NEET 2026 Revision Series | Saravanan Sir

Added: 2026-05-27

[00:00:03]All right, good afternoon everybody.

[00:00:09]Good evening. Good evening everybody.

[00:00:11]How is everybody doing today guys?

[00:00:14]Da da ha how are you? Lea we are waiting. Yes sir. Welcome welcome guys welcome. Maya are you preparing for neat? Of course we are all preparing for rene 2026. Am I audible? So means chapter.

[00:00:38]In the meantime, I just want to also um uh encourage you to click the link in the description. Okay.

[00:00:50]And the link you can enroll for free for this entire reitvision course.

[00:00:57]Chemistry and physics daily full syllabus test. Okay. Full syllabus doubts 247.

[00:01:13]All right. So maybe after some time we will I will show you how that works also. Okay. Ha dash. Hi welcome. Ha. Okay. So topic am okay. So let us straight away go for it.

[00:01:35]H am is also an important chapter. Okay. So nitrogen containing compounds actually organic compounds containing nitrogen.

[00:01:55]Okay.

[00:01:59]Organic compounds containing nitrogen welcome. Yes. Good afternoon to you too.

[00:02:14]So give me some time. All right. Okay.

[00:02:19]All right. Okay. So let us start guys.

[00:02:22]Let us start with this first question 2026 2026.

[00:02:35]So they're asking select the reagent that reduce nitrals. Nitrals now CN are the nitrals. Okay.

[00:02:44]Excuse me.

[00:02:47]Yeah.

[00:02:49]CNL cyanide is also nitral reagent based question organic chemistry reagent based chemistry. Okay. Reagent based chemistry. So lithium aluminium hydride is a very good reducing agent. Complet this will work. All right. Tin HCl or metal HCl it's uh not completely operative on nitrals nitro compounds but cyanide cyanide it's not very good.

[00:03:38]So we will keep a dot over there. And then hydrogen sodium amalgam and ethanol.

[00:03:53]Okay.

[00:03:58]Okay.

[00:04:00]And the best three reagent will be A, C and D. Option B is the right answer.

[00:04:06]Yes. Dasha. Well done. you also got the right answer.

[00:04:11]Okay. So, first reagent based chemistry. Okay.

[00:04:25]Okay.

[00:04:30]All right. All of you got the answer.

[00:04:33]Good. Let's move on to the next question. So option B is indeed the right answer. Okay. Next. Following two reactions gives the same foul smelling product. Foul smelling product isocide.

[00:04:48]Okay. The isoccyanide following two reactions.

[00:04:54]Okay. So two sequence of reactions.

[00:05:03]Where is X?

[00:05:05]Where is X?

[00:05:13]We will based on this we will see what can be done.

[00:05:16]Mistake.

[00:05:18]So based on this we will see. So bromine sodium hydroxide degradation reaction.

[00:05:23]So you will get ethylamine C2H5 NH2 and ethileamine chloroform is C2 H5 C N C2 H5 N C so Z C2 H5 NC okay this is correct this is wrong this is wrong it can be correct so answer option A okay um ah I think I Got it right? I think I got it. So there must be another reaction where you have something like C2 H5 Br and then you have to treat it with X and then it will give you C2 H5 and C.

[00:06:06]Okay. KN Agn let's take one example. K CN will give you K plus and CN minus.

[00:06:22]and CN minus.

[00:06:26]So it will not give you NC it will give you CN C2 H5 Brina in the presence of KN alcoholic KN you will get C2H5 CN you will not get NC because Agnitrogen is the nucleophilic atom.

[00:06:50]Okay.

[00:06:53]Okay. Okay. Option A is the right answer.

[00:06:56]Okay. Nice. Nice. Nice. Nice question.

[00:07:03]Nice.

[00:07:04]All right. So, next question.

[00:07:07]uh most of the A means question uh we are able to see that it is based on the reagent and the reagent.

[00:07:20]Okay. So let's see two products X and Y are formed in the following reaction. Okay.

[00:07:26]So X and Y. Okay. Benzene methyl chloride dilute HNO3 plus dilute H2SO4 and warming.

[00:07:50]Okay. Nitration answer comes to oh the question question nice that's okay but we will see why that is the answer that we will see okay nitric acid plus sulfuric acid protein nitration so toine upon nitration maybe the answer is also we'll see okay towine upon nitration will give you ortho nitroine and paranitral.

[00:08:27]Nitration can occur at the orthoposition or paraposition. Parosition major product but x and y identify. Yes. Identify what is the method of separation for both of these products and get return welcome batch assignment test more than enough definitely dropping what do you mean I don't understand sheet let me let me know. Okay. So either I will need fractional distillation sublimation differential extraction it should be soluble in two different yeah formula yeah okay so continuous extraction fractional dissation there will be a small difference in boiling point that is fractional distillation. Okay.

[00:09:41]All right. So let's do another question.

[00:09:50]This is neat 2026.

[00:09:57]Done. Very good.

[00:10:01]AC.

[00:10:05]All right. Let's see this question. Need 2026 question options.

[00:10:13]>> [laughter] >> options but let's see major product Z formed in the following reaction sequence is okay CH3 single bond CH3in UV correct you got it right need one shot for organic MC full organic MC Okay, we'll see.

[00:10:50]Need one shot for organic chemistry. We will find out how much interest is there.

[00:10:57]Okay. So, UV CH3 CH2in.

[00:11:09]So, this is correct. Ammonia.

[00:11:13]Ammonia itself is a nucleophile.

[00:11:16]Ammonia itself is a nucleophile. So ammonia can attack this carbon. Chlorine can leave. This will result in the primary amine subsequent secondary primary am.

[00:11:40]Okay. Next.

[00:11:45]Okay.

[00:11:48]H2.

[00:11:50]The way to look at it is like this. N bond single bond O. Okay.

[00:12:01]In the entire set of nitrogen gas.

[00:12:07]So the product will be PH3 CH2 O plus N2 plus H2O H2O.

[00:12:18]Okay. So ethanol the actual answer.

[00:12:23]Okay. Ethanol is the answer teaching is so good. So one two one shut. Okay. Sure we will see that H. All right. So ethanol is the answer. Indeed that is being given as the answer. Okay. Option C is ethanol.

[00:12:44]Okay.

[00:12:46]Direct questions 2026. We have already done three questions. Wow.

[00:12:52]Nice. Okay.

[00:12:56]Okay. So, three questions.

[00:12:59]Well done. Next. 2025.

[00:13:04]It's a important chapter.

[00:13:08]number of questions because you can make so many questions out of it. Next 2025 2025 2025 was one of the toughest paper in neat exam. So basic decreasing basic strength.

[00:13:28]Okay. So am basic nature always alifhatic amines alifhatic amines are more basic than aromatic amines.

[00:13:42]Number one.

[00:13:46]Next solution.

[00:13:58]Okay. Fine.

[00:14:02]Okay, let's just go with this. Okay, so secondary ethanamine this is primary amine.

[00:14:16]This is actually aromatic and benzinamine is actually analine only. Okay, benzinamine is analine only.

[00:14:25]Aneline is also aromatic in nature.

[00:14:29]This seems to be the right answer.

[00:14:38]So correct.

[00:14:44]Okay, this is correct. I will draw the structures also.

[00:14:50]Question.

[00:14:55]Okay. Primary amine is always less basic than secondary amine. All right.

[00:15:11]Secondary primary after option A is correct. Good evening Tagar.

[00:15:23]Good evening. Welcome. Welcome, welcome, welcome. Okay, so a means let us [clears throat] continue. All right, so answer is option A. Option A is correct.

[00:15:32]All right, so [clears throat] yeah, statement based question.

[00:15:38]Statement based question. Good evening.

[00:15:41]Good evening. Welcome. All right, statement based question. Let's see.

[00:15:44]2025 question. Benzene dasonium salt is prepared by the reaction of analine with nitrous acid.

[00:15:53]correct statement.

[00:15:56]Okay. Nitrous 273 278.

[00:16:03]It decomposes easily in the dry state.

[00:16:08]Dry state not necessary.

[00:16:23]Dry ether. Yeah. Yeah. Dry ether. So I think uh I don't like the statement.

[00:16:30]Decomposes easily in the dry state. Not necessary. Temperature mostly issue not in the dry state. Okay. Next. Insertion of iodine into the benzene ring is difficult and it is hence iodenzene is prepared through the reaction of benzene salt with K.

[00:16:50]Statement two is correct. Statement one dry state at higher temperature.

[00:17:00]Okay. Higher temperature dry but low temperature it is actually stable only. Okay. So no no I I'm just going to slightly change the question.

[00:17:14]Higher temperature dry state it doesn't make sense. Higher temperature correct.

[00:17:21]Okay. Dry state correct. Dry statement one is correct.

[00:17:28]Higher temperature statement one is uh sorry dry statement one is incorrect. Higher temperature statement one is correct.

[00:17:41]Yeah. You are right only we understood that. Okay.

[00:17:48]I'm so curious. We didn't do a program on bits, but question previous questions.

[00:18:00]How was it?

[00:18:02]Okay, let me know. All right. So, here we are going to say that high temperature both statements are right.

[00:18:10]All right.

[00:18:12]Lit. Okay. Nice guys. 5 minutes time.

[00:18:16]Huh? I'll just be back. Give me exactly 5 minutes.

[00:18:21]I'll put a timer and go. Okay. Timer for 5 minutes.

[00:18:33]5 minutes. I'll be back now.

[00:24:34]Hide. Hide her. Hide her.

[00:24:36]Ka.

[00:24:40]All right, let's continue guys. Let's continue quickly.

[00:24:44]Thank you for waiting. Haida. Haida.

[00:24:47]Okay. [clears throat] Zimi, welcome.

[00:24:49]Welcome.

[00:24:54]Okay. Okay. Thank you.

[00:24:57]Let's continue.

[00:24:59]Just not a feeling well a little bit but it's okay. We'll finish it off. Um okay. Let me let me talk to you d after this live. I will have a conversation with you.

[00:25:15]Okay. Okay. Okay. So this is chlorination acid chlorination.

[00:25:26]So whenever there is an activating group and a deactivating group this is activating and uh this is deactivating activating.

[00:25:38]So activating group.

[00:25:41]Okay. So, so let us just take orthoposition as our um chlorination happening. Okay, is where the chlorination is going to happen.

[00:25:57]But second, NH2.

[00:26:05]Okay. So NH2 so this is after the second reagent N2 chloride NH2 N2.

[00:26:23]So you will get C2H5 CL N2 CL potassium in the position potassium.

[00:26:36]So I think this is directly the right answer. Option C is the right answer.

[00:26:42]Okay. So, option C is the right answer. Very good.

[00:26:57]Abinh also got it right. Okay, nice.

[00:27:00]Let's move on to the next question. 2024 2024 compound that does not undergo Fredelcraft's alkalation but gives a positive carbamin test. Freedelcraft's alkalation Okay.

[00:27:30]Highly deactivated an which is highly reactive towards Louis acid catalyst reagent reagent is L acid.

[00:27:50]Okay. So analin is a definite candidate.

[00:27:55]It will not give either of these reaction. Does not undergo falcraft but gives you primary amine. Uh it gives carbalamin test.

[00:28:04]Okay. It may as well undergoation.

[00:28:09]It's also a base. Okay.

[00:28:19]Carbamine.

[00:28:23]Carbamine primary secondary.

[00:28:28]Tryamine is tertiary amine. Definitely option A is the only answer possible.

[00:28:34]Ah, correct. AB and hydra3.

[00:28:40]So option A is the right answer. Very nice. Okay, we are still in 2024.

[00:28:46]Statement one, statement two based question. Okay. Analin does not under calculation 2024 question.

[00:28:57]True.

[00:29:01]Okay. Cannot be prepared through Gabrielide synthesis.

[00:29:08]Oh, of course. Sorry.

[00:29:11]Gabriel it is true. Okay. Gabriel nucleophile create in order to do that you use potassium hydroxide or something. So this will give you nucleophile and that will attack your alky and create a R group. So finally okay this has to attack the alkalide aromatic aromatic partial double bond character nucleophilic substitution on aromatic highlight does not work.

[00:30:19]So this is absolutely correct. Both are true statements. Option A is correct.

[00:30:29]I A and I have to myself check out what is the format and everything. So, okay. Chemistry 140.

[00:30:44]Yes. Keep solving questions. That is the most important thing in the time.

[00:30:53]Okay. That is the most important thing.

[00:30:55]Okay. So, let's move on to 20 23. Okay.

[00:30:58]23 on the down 24 actually it is supposed to be an easy paper but 23 it was okay standard paper only. Hi sir video by J welcome Jri welcome. All right identify the pro product in the following reaction. Okay. Dasonium chloride C2 Br2. This is sandme reaction.

[00:31:21]Broine first bromoenzene.

[00:31:35]So product after the second set of reagent is mgbrard reagent.

[00:31:54]Okay.

[00:31:59]Hey, wait, wait, wait, wait, wait. What am I saying?

[00:32:10]Okay, it will create phenile nucleophile and that will take up the hydrogen from water. Okay, phenol benzene.

[00:32:27]So if I take this in the hydrogen so answer is benzene not phenol.

[00:32:40]Okay. So J question numbers J means difficulty level difficulty level number.

[00:33:08]Okay.

[00:33:11]Okay.

[00:33:13]A is correct. Very good. Next. Identify the product in the answer option. A is correct. Let's move on to the next question. Which of the following reactions will not give primary amine as a product? Primary amin.

[00:33:26]Okay.

[00:33:29]>> [cough and clears throat] >> Lithium aluminium hydrate primary am you will get CH3 CH2 NH2 primary am definitely but is reagent secondary amino CH3 NH CH3 this is secondary amine this is the answer okay this is amide amide again gives you primary amine CH3 CH2 NH2 this is primary amine and broine In either halfman bromide degradation reaction you will only get CH3 and H2 but this is also primary amine. Among the given options this is also primary amine. Okay option B is definitely the right answer.

[00:34:09]Well done guys. Abines Dasharan very good.

[00:34:13]Okay. Option D is option beta. Beta is correct. Next 2022 question.

[00:34:20]Product formed from the following reaction sequence. Okay.

[00:34:30]Acetilation.

[00:34:32]Okay. So, first CO NH2.

[00:34:39]Okay. NH2 COH3 CH3 NH2 NH capping. Okay.

[00:34:52]CH3 CH2 NH2 okay that's it so any amide upon reduction with lithium aluminum hydride in the CH2 so you will get NH CH2 CH3 option B is the right answer complicated option B is less straightforward the right Answer them. Next question guys. H you guys are following right?

[00:35:27]Okay. Good. Good. Okay. Good. Which of the following sequence of reaction is suitable to synthesize chlorobenzene?

[00:35:33]Chlorobenzine.

[00:35:37]All right. Reaction.

[00:35:40]Benzene. Chlorine and FCL3 chlorination direct chlorination. Benzene you will definitely get chlorobenzine only.

[00:35:49]Answer option A.

[00:35:53]Phenol C.

[00:35:59]Okay. Phenol nitrous acid. Nitrous acid Citrus you will get but nothing. It'll still not give you chlorobenzene phenol but not phenol. Okay. Okay.

[00:36:22]Benzene HCl.

[00:36:27]Okay.

[00:36:31]Okay.

[00:36:33]Then chloride no this is also not give option A is the only answer option A definitely option A there's no other thing okay Vasant H welcome preparation.

[00:37:03]Maybe some specific mechanisms.

[00:37:19]Okay. All right. Let's see this [clears throat] physical chemistry. Of course, physical chemistry.

[00:37:28]Okay. All right. Statement based question. Let's see. Statement one.

[00:37:33]Statement two. Primary alifhatic means reacts with HNO2 to give unstable dasonium salt. Alipatic means unstable salt. True. Aromatic salt decomposes react with HNO2 to form diasium salt which are stable even below 300 even above 300.

[00:38:03]This is false.

[00:38:05]273 to 278 Kelvin state stable. So either one false statement two incorrect. Statement one is correct.

[00:38:13]Option C is correct. Class 12 chapter 8 need okay I don't think CBS question previous questions there is nothing special about these questions okay for example Okay.

[00:38:53]Check out first live session organic chemistry.

[00:39:03]Okay.

[00:39:05]Okay. We will see whatever it is we will see. If you have any question also you can give ma. We will handle it in live class.

[00:39:12]Okay, we will discuss.

[00:39:25]Okay guys, in the question 2022 question already benzoit lithium aluminium hydrate. So what we will get? We will easily get benzylamine CH2 NH2 alcohol. This will give you benzyl alcohol CH2O water.

[00:39:57]There's nothing else to do this do with this. Option D is the right answer.

[00:40:03]Straightforward.

[00:40:06]chapter.

[00:40:13]Okay. So, identify the compound that will react with Hinsburg reagent.

[00:40:17]Hinsburg benzene sulfanyl chloride. The Hinsburg reagent.

[00:40:23]Okay.

[00:40:24]Benzene uh sulfanile chloride.

[00:40:31]Okay. So to give a solid which dissolves in alkali you need a primary amine.

[00:40:39]Primary amine hinsburg reagent will give a solid that will dissolve in alkal option C is the right answer in the dissolves.

[00:40:52]Suppose which does not dissolve secondary.

[00:40:56]Suppose which does not react with hinsburg.

[00:41:01]Okay. Okay. So, option C is the answer here. Very good. Hinsburg reagent is also a very important reagent. Which of the following am I will give a carbamine test? in the car already previous.

[00:41:20]So carbon primary am primary amines will give you carbamin test and the isocyanide foul smelling substance and all those things primary amine option D2 or no that's okay so either secondary either tertiary ether secondary so primary option D is the only answer got it Right. Yes. Okay. Well done. Well done.

[00:41:52]Well done. Let's move on.

[00:42:05]That is not a big deal also gives you answer. Okay. So remember that.

[00:42:16]Next.

[00:42:18]Ah guys.

[00:42:36]Who can tell which reaction this appears in?

[00:42:41]Starting point.

[00:42:46]Yes, Abin got it right. This is the starting point of Gabrielide synthesis.

[00:42:55]acid.

[00:43:04]CO NH2 CH2 heating strong and you will get Gabrielide synthesis and the procedure reagent.

[00:43:23]This hydrogen is acidic also.

[00:43:26]Okay. So, option D is the right answer now.

[00:43:31]Okay.

[00:43:38]Okay.

[00:43:43][clears throat] Yes. Option D is the right answer.

[00:43:47]Gabriel talamite synthesis starting reagent creator. Remember DJ Okay, let's move on. All right, 10 questions. We'll finish it off. Okay.

[00:44:07]2019 correct order of basic strength methile substituted methile substitute secondary greater than primary greater than tertiary. Okay.

[00:44:24]So, secondary is here, primary is here.

[00:44:27]Option C is the right answer. NCile substituted means two primary secondary primary tertiary ethile substituted means propile substitutary tertiary primary.

[00:44:52]Okay.

[00:44:55]So it is a fair question to ask. Option C is the right answer.

[00:45:00]Okay. Yes. 231. All right. So, let's move on to NE 2018 2019 questions standard questions. It was rivaling that of J questions Jack baby. Uh okay. Good boy. Nitration of aneline and strongly acidic medium also gives metitroan because acidic medium ion is metadirecting in nature almost 49% 47% metitron option D is the right answer Yes, Abin that is got it. That is correct.

[00:45:53]Also got it right. Well done. Okay. So the special points.

[00:46:07]Okay. So in the NCR line okay already 2018 question. So let's see 2017 question. Which of the following reaction is appropriate for converting acetamide acetamide CH3 CO NH2 methanamine CH3 NH2 in the CO group?

[00:46:55]What is the reaction?

[00:46:57]Halfman bromide degradation reaction also called as half man hypo bromide reaction. Option A is the right answer.

[00:47:06]Okay.

[00:47:11]So, degradation reaction number of carbons.

[00:47:17]Okay. All right. Nice. Next question.

[00:47:21]2016 question.

[00:47:25]Okay. We'll just keep going.

[00:47:27]Given nitrogen containing aromatic compound A reacts with tin HCl to and followed by nitrous acid to give in unstable compound B. I think this has to be nitroenzine nitroenzine tine you will get a benzene dasonium chloride. So Benzin diochloride N2 CL this has to be B on treatment with phenol beautifully colored compound C with the molecular formula C2 is the coupling reaction. Okay coupling reaction. So very obvious option Bin reaction reduction of nitroenzene to analine reducing agent is a very rare reagent specifically used for nitroenzene to analine conversion.

[00:48:29]Okay.

[00:48:35]Okay. Good. So option B is the right answer.

[00:48:40]Okay, next question. Which of the following nitro compounds does not react with [clears throat] nitrous acid?

[00:48:48]Nitrous acid actually.

[00:48:54]Okay, simple examples. Let us say I have C H2 NO2 H double bond H import this will give you H2O. So you will get C double bond N O nitroic acid.

[00:49:23]Okay. So primary this is primary R group. This is primary nitro compound that will give you nitroic acid.

[00:49:31]secondary.

[00:49:34]CH2 H2O. So what you will get is C single bond N double bond O NO2. Okay. So this is from Victor Mayor's method.

[00:49:57]So primary react.

[00:50:04]So tertiary will not react does not react with nitrous. Victor last.

[00:50:12]Okay.

[00:50:23]All right. So that is the methodology.

[00:50:25]Option C is indeed the right answer.

[00:50:28]Okay. Primary red victim method. Very important method.

[00:50:36]Okay. Next question. Product formed by the reaction of an alihide with primary amine.

[00:50:43]So alihide C double bond O H or R group.

[00:50:49]If I treat it with primary amine NH2, this will undergo addition elimination.

[00:50:56]Okay, addition elimination. A you will get RCH double bond N single bond R dash.

[00:51:05]Okay, this is called as shifts base am means shifts base. Option C is the right answer.

[00:51:17]Okay. On the entire table, ammonia derivatives with alihides and ketones.

[00:51:23]Okay.

[00:51:28]I think I remember.

[00:51:32]Okay. So, option C is the right answer.

[00:51:34]Nice. Very good. Dash doing well. Okay.

[00:51:39]Need 2016 correct statement regarding basicity of Ariel amines.

[00:51:45]means are weekly basic. Okay.

[00:51:54]More basic less basic than alkal means because the nitrogen lone pair electrons are deoized by interaction with the aromatic ring pi electron system. The answer C is direct answer. Okay. Nice.

[00:52:13]All right. Okay, next question. Okay, so the number of structural isomers possible for molecular formula C3 H9.

[00:52:24]So C3 H9N it can either be like this CH3 CH2 CH2 NH2.

[00:52:33]Okay.

[00:52:39]Okay.

[00:52:42]Second position.

[00:52:44]CH3 CH CH3 NH2.

[00:52:50]Okay.

[00:52:56]So, no problem. So, primary.

[00:53:00]Um next I think we have to go for the secondary aminos.

[00:53:06]So let's move on to secondary amine.

[00:53:08]First CH3 CH2 NH CH3 secondary amine. All right am possible.

[00:53:21]That's it. This is the only secondary amine possible. Next tertiary. So nitrogen attached to three methile groups.

[00:53:32]Okay, so we got two primary amines, one secondary amine and one tertiary amin.

[00:53:38]No other possibility exist for the given formula. So option D is the right answer.

[00:53:45]Okay, four structural isomers are possible based Question systematrim longest chain.

[00:54:18]Okay.

[00:54:20]Next four is the right answer. Four is the right answer. Next question.

[00:54:26]Method by which analin cannot be prepared.

[00:54:32]Benamide you will get CO NH2 degradation of benzamine.

[00:54:44]So this method will give you analine reduction of nitroenzene with hydrogen paladium and ethanol.

[00:54:54]Other side products.

[00:54:57]Okay.

[00:54:59]But hydrogen paladium will give you next potassium salt of talomide.

[00:55:10]Hey, welcome welcome welcome welcome. Anelin cannot be prepared by Gabriel Salate synthesis because you need this kind of a group but it is not possible substitution nucleophilic substitution on this ring is very very difficult to do. So Gabriel synthesis phenile isocyanide with acidic solution will give you an yeah phenile isocyanide NC.

[00:55:56]Okay, option D is also correct. Okay, so C is the answer that you have to mark.

[00:56:05]Okay, last two questions guys. Last two questions for the day. Let's see. So, benzole chloride treat. So, analin is a nucleophile. It can attack this position and chlorine can be removed. That's what is happening here. So, shorten B reaction. Fact based question 2015 fact.

[00:56:35]Okay. No problem. shorten reaction elimination.

[00:56:41]Okay. But shorten reaction. Okay. All right.

[00:56:48]I am not sure. But 2015, 2013, 2015, 2017.

[00:57:08]Okay. So, SH reaction is correct. Last question for the day. Electrolytic reduction of nitroenzene in strongly acidic medium. medium describe this will give you paraminophenol electrolytic reduction of nitroenzene strongly amino acidic medium will give you paramophenol all right we will stop here we will see very good very good we will see biomolelecules okay let me confirm Let me see.

[00:57:52]Suppose I will do it on the class. So not an issue.

[00:58:10]Okay. Okay. So just yeah we don't have a class tomorrow. Day after we'll have a class 28th we will do.

[00:58:40]Okay. Biomolelecules will be on 28th.

[00:58:45]28th 4:30.

[00:58:47]All right.

[00:58:49]11th mock test PDF 11th standard syllabus test.

[00:58:59]You message me. Okay.

[00:59:04]Don't mind me. Okay.

[00:59:07]Physics also no class.

[00:59:10][laughter] So Anush I will see I will see the message. Okay. All right guys we will continue our session um day after tomorrow. I'll see you all then. Take care everybody. Bye-bye.