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Math Olympiad | Solving the Exponential Equation {3^m - 2^m = 65}
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134 Aufrufe7Likes5:16Learnandplay_1Originalveröffentlichung: 2026-05-27

To solve exponential Diophantine equations like 3^m - 2^m = 65, one can use algebraic substitution by rewriting the equation as (3^(m/2))^2 - (2^(m/2))^2 = 65, then applying the difference of squares formula to factor it into (3^(m/2) + 2^(m/2))(3^(m/2) - 2^(m/2)) = 65, and solving the resulting system of equations to find m = 4.

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