To find the nth highest salary employee, use SQL's RANK() function with ORDER BY salary DESC to rank employees by salary in descending order, then filter for the specific rank value provided by the user. The Java implementation involves reading user input for the rank number, constructing the SQL query with RANK() window function, and executing it to retrieve the corresponding employee information.
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Find Nth Highest Salary Employee: Java SQL Explained #shortsHinzugefügt:
So now I want to explain the last example related to aggregate functions.
How to find nth nth highest salary employee information. Suppose if you end user entered one, first highest. If end user entered two, second highest salary employee information like So have you observed So application number 20.
Select nth highest salaried employee information. That is about my requirement right, okay? So java.sql.star java.util.star.
Why I'm taking util? Can you please guess?
Why I'm taking util? Scanner. Scanner class is present inside util package.
That's why right, okay? So now So class.forName connection statement all these things are same. So observe scanner sc is equal to new scanner of system.in. So I want to read end user provided number, okay? Enter number.
Enter number. int n is equal to sc.nextint.
What is that So int n is equal to sc.nextint.
So string SQL query. The behavior already I explained. Have you remembered right, okay? So select a star from So select e number e name e sal year e address and a rank. So order by over order by e sal. So we have to select all rows according to descending order of salary and for that result I have to give the rank. Are you getting? I have to give the rank.
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