To solve complex radical expressions like (√2 - 1)^6, substitute the radical expression with a variable (let X = √2 - 1), then systematically eliminate the radical by squaring both sides and applying algebraic identities such as (A+B)² = A² + B² + 2AB and (A-B)² = A² + B² - 2AB, ultimately substituting back to find the final value.
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Germany | Can you solve this? | Math OlympiadAdded:
Hello, friend. You're welcome to solve this nice math problem, which is the square root of 2 - 1 ^ 6.
Now, let's provide a solution from here.
The first step is we can let square root of 2 - 1 be equal to X.
So, the question is what is X ^ 6?
Now, since we have this, let's call this equation one.
Now, we have square root of 2 subtract one. This is equal to X.
Now, let's take -1 on the right-hand side so that we have root two.
This is equal to X + 1.
This is X + 1. So, this is the same thing as X + 1.
This is equal to root two.
So, let's square on both sides from here.
So that now X + 1 ^ 2, this is in the form of A + B raised to the power of two, so that we have A ^ 2 + B ^ 2 then + 2 AB.
Let's apply this algebraic identity so that now we have X ^ 2 + 2X then + 1.
This is equal to Now, let's eliminate the square root sign here. This is equal to two.
So, this is to mean that we have X ^ 2.
Let's take 2X + 1 on the right-hand side. So, this becomes 2 - 2X -1.
So, we have X ^ 2. This is equal to 2 - 1. This is 1 then - 2 X.
So, X ^ 2, this is equal to 1 - 2X.
Let's call this equation two.
The next step is to square on both sides.
So that now this becomes we have A X ^ 2 ^ 2, this is X ^ 4.
This is equal to 1 - 2X raised to the power of two.
So, we have 1 - 2X ^ 2. This is in the form of A subtract B raised to the power of two, which can be expressed as A ^ 2 + B ^ 2 subtract 2 AB.
Applying this algebraic identity, then we have X ^ 4.
This is equal to 1 ^ 2.
Then we have plus. This is 2X ^ 2.
Then we have minus 2 * 1 * 2X.
So, this is X ^ 4. This is equal to 1 squared, this is 1 then plus.
This is 2X ^ 2. So, this becomes 4X ^ 2 then minus 2 * 2X, this is 4X.
Now, this is X ^ 4. This is equal to 1 + 4X squared. This is the same thing as 2 * 2X ^ 2.
-4X.
But we have X squared. X squared, this is equal to 1 2X. So, let's substitute where we have X squared with 1 - 2X. So, we have X ^ 4.
This is equal to 1 + 2 * 2, this is 4 into the parenthesis.
This is 1 - 2X.
-4X.
So, this is X ^ 4. This is equal to 1 + 4 * 1, this is 4.
That is + 4 * -2X. This is -8X then -4X.
So, we have X ^ 4. This is equal to 1 + 4, this is 5.
-8X -4X, this is -12X.
Now, the question is what is X ^ 6?
Now, let multiply X ^ 4 here.
Multiplying by X ^ 2, this is equal to 5 -12X multiplying by X ^ 2.
X ^ 4 * X ^ 2, this is in the form of A ^ N * A ^ M, which we can express as A ^ N + M.
Applying this exponent property, this means that we have X ^ 4 + 2 and this is equal to 5 - 12X multiplying by X ^ 2. X ^ 2 is 1 - 2 X.
So now, here we have X ^ 4 + 2. This is equal to 6 and this is equal to 5 - 12X * 1 - 2X. So, we have 5 multiplying by 1 - 2X.
Then -12X into the parenthesis. This is 1 - 2X.
Now, this is X ^ 6 and this is equal to 5 * 1, this is 5 -5 * -2X. This is 10X.
Then -12X * 1, this is -12X then -12X * -2. This is +24 X ^ 2.
So, this is X ^ 6. This is equal to Now, we have 5 -10X -12X.
This is -22X.
Then +24X ^ 2.
The next step is that if you recall X ^ 2, this is the same thing as 1 - 2X.
So, let's substitute X squared with 1 - 2X.
So, this is X ^ 6. This is equal to 5 subtract 22X.
Then +24 into the parenthesis. This is 1 2X.
So, this is X ^ 6. This is equal to 5 subtract 22X.
Then +24 * 1, this is 24.
24 * -2X. This is -48X.
So, we have X ^ 6. This is equal to 5 -22X -48X.
This is -70X then +24.
So, we have X ^ 6. This is equal to 5 + 24 and this is equal to 29 -70X.
Now, again we have if you recall we had said that we let square root of 2 - 1 be equal to X.
So now, here we have square root of 2 - 1 raised to the power of 6. This is equal to 29 -70 multiplying by square root of 2 1.
So here, we have square root of 2 subtract one raised to the power of 6. This is equal to Now, we have 29 here.
-70 * square root of 2. So, this is -70 root two.
Then -70 * -1. This is +70.
So, we have that square root of 2 - 1 ^ 6 This is equal to 29 + 70. This is equal to 99 -70 square root of two.
And this is the solution to this square root math problem.
So, kindly follow the steps.
Like this video and kindly subscribe. Please like this video and kindly subscribe.
See you in the next video.
Bye-bye for now.
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