To solve exponential equations like 2^(x+1) + 2^(3-x) = 17, apply index laws (a^(n+m) = a^n × a^m and a^(-n) = 1/a^n) to rewrite the equation as 2×2^x + 8/2^x = 17, then substitute u = 2^x to transform it into a quadratic equation 2u² - 17u + 8 = 0, which factors to (2u-1)(u-8) = 0, yielding u = 8 or u = 1/2, and finally solve for x by recognizing that 2^x = 8 gives x = 3 and 2^x = 1/2 gives x = -1.
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Germany | Can you solve? | A Nice Exponential Maths Problems |Added:
Hello everyone. Welcome to Rasha's Classroom. Today we are solving a interesting German math Olympiad question which is 2 to the power x + 1 + 2 to the power 3 - x is equal to 17. x is equal to what? How to solve this interesting exponential math problem? So first of all, our math solution, I use Here, I use index law.
We all know that a to the power n + m which is a to the power n * a to the power m. And we know that other formula, a to the power - n which is 1 over a to the power n. I apply both formula here.
So this expression if I apply this math formula here, so it will be 2 to the power x * 2 to the power 1 then this is 2 to the power 3 * 2 to the power - x is equal to 17.
I apply this math formula here.
So this expression, it will be 2 to the power x * 2 + 2 to the power 3 which is 8 * but 2 to the power negative x, if I apply this math formula, it will be 1 over 2 to the power x is equal to 17.
Then this is 2 * 2 to the power x, 2 * 2 to the power x then + 8 * 1, this is 8 over 2 to the power x is equal to 17.
Now, this is 2 to the power x, this is 2 to the power x.
So at this moment, let let 2 to the power x is equal to u.
Now, I substitute this value here.
If I substitute this value here, so this expression it will be 2 u plus 8 over u is equal to 17.
Now, this is uh u this is u, so I take here is least common value is u. So, this divided this here is one one divided u u times 2 u it will be 2 u squared.
And this u divide this u it will be one one times eight this is eight is equal to 17.
Now, I multiply both side by u, so it will be 2 u squared plus eight then here 17 u.
Now, we are find out a nice quadratic equation uh which is 2 u squared minus 17 u. I just move on this 17 in this side it will be negative 17 plus eight is equal to zero. Now, at this moment I do here is middle factor because of that it is a nice quadratic equation. So, this is 17, but this is eight times two this is 16. So, this is 2 u squared minus 16 u minus u plus eight is equal to zero.
Now, here is 2 u is common. So, if I take u is common this divide this this is u minus this divide this this is eight minus one is common this is u minus eight plus minus this is minus is equal to zero.
Now, this is u minus eight this is u minus eight. So, at this moment you can say here easily u minus eight is common then this divide this this is 2 u this divide this this is minus one is equal to zero.
Then, here u is u - 8 is equal to zero.
Then, 2 U - 1 is equal to zero. Then, U is equal to 8. And, you can say easily here, U is equal to If I move on this -1 in this side, it will be positive 1.
Then, if I divide both side by 2, we are find out 1 over 2. So, at this moment, remember that we are substitute here is U is equal to 2 to the power X.
So, I take this value here because of that our target X is equal to what? So, U is equal to 2 to the power X. But, this 8 it will be 2 to the power 3.
Now, according to exponential formula, this is two, this is two, base is same, so exponent is equal, so X is equal to three.
But, this is 2 to the power X. But, this is 1 over 2, this is 2 to the power -1.
Now, at this moment, you can say here X is equal to -1.
So, we are find out X is equal to three, X is equal to -1. This is our final answer in this tricky exponential maths problem. Let's verify. We are find out X is equal to three and X is equal to -1.
But, our question it will be 2 to the power X + 1 + 2 to the power 3 - X is equal to 17.
Then, I take X is equal to three. So, if I take X is equal to three, so 2 to the power 3 + 1 + 2 to the power 3 - 1. Sorry, X is equal to three.
Then, is equal to 17.
Now, at this moment, this is 2 to the power 4 and this is 2 to the power 0 is equal to 2 to the power 4, this is 16 and 2 to the power 0, this is 1. 16 + 1, this is 17. So, left hand side and right hand side both side is equal.
Now, if I take -1, okay? Now, at this one I take here is -1. Let's verify.
This is 2 to the power -1 +1. Because of that x is equal to -1.
I take this one here + 2 to the power 3 -x. But x is equal to -1. So I take -1 here is equal to 17.
So at this moment our left hand side which is 2 to the power 0 + 2 to the power minus minus this is plus I can say easily this is 3 + 1. This is 4 and is equal to 17.
Now this is 16. 16 + 1 because of that a to the power 0 it will be 1. 1 + 16 this is 17 is equal to 17. So left hand side and right hand side both side is equal.
So our answer is x is equal to 3, x is equal to -1. If you enjoy this math problem please subscribe my YouTube channel. Thank you everyone.
Have a good day. Take care everyone.
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