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Germany | Can you solve? | A Nice Exponential Maths Problems |
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161 Aufrufe13Likes6:44rashel1Originalveröffentlichung: 2026-05-09

To solve exponential equations like 2^(x+1) + 2^(3-x) = 17, apply index laws (a^(n+m) = a^n × a^m and a^(-n) = 1/a^n) to rewrite the equation as 2×2^x + 8/2^x = 17, then substitute u = 2^x to transform it into a quadratic equation 2u² - 17u + 8 = 0, which factors to (2u-1)(u-8) = 0, yielding u = 8 or u = 1/2, and finally solve for x by recognizing that 2^x = 8 gives x = 3 and 2^x = 1/2 gives x = -1.

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