In JavaScript, when a closure is created inside a for loop, the loop variable is function-scoped rather than block-scoped, meaning the closure captures the final value of the variable after the loop completes rather than the value at the time the closure was created, which can lead to unexpected behavior if not properly understood.
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What happens when you use a closure in a for loop?
Added:This is because the variable I is scoped to the function and not the block. So, when the timeout function is called, the loop has already finished and the value of I is five.
This is a classic example of a closure in a for loop and how it can lead to unexpected behavior if not understood properly.
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