To solve exponential equations where the variable is in the exponent, apply logarithms to both sides and use logarithm laws to isolate the variable; for example, in the equation 5^x / 25 = 50, the solution is x = 4 + log_5(2), which can be verified by substituting back into the original equation.
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Solve for x in this nice Algebra equation | Math Olympiad MathematicsHinzugefügt:
In this video, we want to solve for X.
Given 5 raised to the power X divided by 25 is equal to 50.
We're given 5 raised to the power X divided by 25 is equal to 50.
First thing I'll do here will be to cross-multiply so that I have 5 raised to the power X times 1 is equal to 25 here times 50.
This will give us 5 raised to the power X is equal to 25 here is 5 raised to the power 2.
Then 50 is same thing as saying 25 times 2.
So we have 5 raised to the power X is equal to 5 raised to the power 2 times 5 raised to the power 2 times 2.
This is same thing as saying 5 raised to the power X equal to 5 raised to the power 2 raised to the power 2 then times 2.
Given P raised to the power A raised to the power M by law of indices, this will give us P raised to the power A times M.
So we can rewrite this equation as 5 raised to power x is equal to 5 raised to power 2 * 2, which will be 4, then * 2.
Let us divide both sides by 5 raised to power 4.
This here takes care of this, leaving us with 5 raised to power x divided by 5 raised to power 4 is equal to 2. Let us apply another law of indices to this left-hand side expression.
This expression is of the form p raised to power a divided by p raised to power m.
By law of indices, this will give us p raised to power a minus m.
Therefore, we have 5 raised to power x minus 4 is equal to 2.
What we have now is an exponential equation.
To proceed from here, let us take the logarithm of both sides.
So, we have log 5 raised to power x minus 4 is equal to log 2.
This here is of the form log p raised to power c and by law of logarithm, this will give us c times log p.
So, we have x minus 4 times log 5 is equal to log 2.
Let us divide both sides by log 5.
This here takes care of this.
Leaving us with x - 4 is equal to log 2 divided by log 5.
Log 2 divided by log 5 is of the form log a divided by log b.
And by law of logarithm, this will give us log a base b.
Therefore, we now have x - 4 is equal to log 2 base 5.
I'll transfer -4 to the other side.
It will become positive. So, we have positive 4 then plus log 2 base 5.
This will then be the final answer to this problem.
Before we conclude, let us do a quick check to confirm that the solution is correct.
And to do that, we'll simply substitute this value of x back into the given problem, which was 5 raised to power x divided by 25 is equal to 50.
This will imply 5 raised to power x is 4 plus log 2 base 5 then divided by 25 to give us 50.
Let us separate these powers by law of indices given P raised to power A plus C.
This will give us P raised to power A times P raised to power C.
So, this becomes 5 raised to power 4 times 5 raised to power log 2 base 5.
All of that divided by 25 to give us 50.
Then this is 5 raised to power 4.
By law of logarithm given P raised to power log M base P this will always give us M.
Therefore this right here will give us 2.
So, that we now have 5 raised to power 4 times 2 divided by 25 is equal to 50.
So, 5 raised to power 4 is going to give us 5 times 5 times 5 times 5 then times 2 divided by 25 to give us 50.
So, 5 times 5 is 25. That takes care of this. So, we have 5 times 5 times 2 to give us 50.
This will give us 50.
There we have 50 is equal to 50.
Therefore, the left-hand side balances the right-hand side. And that confirms that this solution we got for X here is absolutely correct.
Thanks for watching. Please like and share, and also remember to subscribe to my channel if you have not done so already. And I will see you in my next video.
Bye.
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