This video teaches an ancient algorithm for calculating the square root of any number by hand, similar to long division. The method involves grouping digits into pairs from the decimal point, finding the largest perfect square that doesn't exceed the current number, subtracting, bringing down the next pair, doubling the current answer to create a base for the next divisor, and finding a digit that when appended to this base and multiplied by itself equals or is less than the current working number. The algebraic basis for this method is the binomial expansion of (a + b)² = a² + 2ab + b², where the doubling step represents the 2ab term. The video demonstrates this with examples including √2025 = 45 and √11.56 = 3.4.
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Calculate Square root of any number ( don't teach anyone )Added:
Want to calculate the square root of any number by hand to any decimal point?
Let's start by finding the square root of 2025.
First, prepare the number by grouping the digits into pairs, starting from the decimal point and moving left.
So, we mark off 25 and then 20.
We start with the group on the far left, which is 20.
Ask yourself, what is the largest perfect square that does not exceed 20?
That would be 4², which is 16.
Write four as our first quotient digit.
Subtract 16 from 20, leaving a remainder of four.
Bring down the next pair, 25, giving us a new working number of 425.
Here is the only tricky part of the process.
Take your current answer, which is four, and double it to get eight.
This eight becomes the base of our next divisor.
We're going to append a mystery digit to it.
Let's call it B.
And then multiply that whole new number by B.
We need to solve 80 + B all multiplied by B is less than or equal to 425.
Using some quick estimation, 80 * 5 is 400. So, let's try making B equal to five. 85 * 5 is exactly 425.
We subtract that, leaving a remainder of zero.
The process concludes, and we have our answer.
The square root of 2025 is exactly 45.
Let's level up.
Could you pass the MIT entrance exam from 1876?
The question is, find the square root of 11.56.
When dealing with decimals, pair the numbers moving outward from the decimal point.
So, we have 11 on the left and 56 on the right.
Start with 11.
The largest square without exceeding is 3 squared, which is 9.
Our first digit is 3.
Subtract 9 from 11 to get 2.
We have hit the decimal point, so place it in your answer.
Now, bring down the 5 6 to make 256.
Double our current answer of 3 to get 6.
We need a digit B so that 60 + B all multiplied by B is less than or equal to 256.
If you know your computer science numbers, you know 64 * 4 is exactly 256.
Our next digit is 4. No remainder. The answer is 3.4. Congratulations. You are going to MIT in the 1800s. But why does this digit-by-digit method work? It is completely based on the algebraic expansion of a binomial square.
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