The video provides a masterclass in algebraic efficiency, turning a daunting radical equation into a clean exercise in strategic substitution. It is a precise and logical guide that prioritizes procedural clarity over unnecessary complexity.
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An Outstanding Irrational Equation | Can You Solve This?
Added:Welcome to InfyGyan, my dear friends. We have one very interesting irrational equation. It looks complicated, but a clever substitution makes the solution surprisingly simple.
So, let's begin.
I will take this whole bracket to the denominator of 10.
So, I can write equation square root x + 6 + square root x + 8 = 10 over square root x + 20 + square root x + 10.
Now, we will rationalize our denominator.
So, we need to multiply and divide by the denominator's conjugate square root x + 20 square root x + 10.
In the numerator also, square root x + 20 - square root x + 10.
Now, we have a + b * a - b form in the denominator.
So, we will use difference of two squares identity.
So, our numerator will become 10 * square root x + 20 - square root x + 10.
And in denominator we'll use difference formula and we'll write square root x + 20 whole square square root x + 10 whole square.
Now, a square root and a square will get canceled out from the denominator.
We will get 10 times the square root x + 20 minus the square root x + 10 over x + 20 minus of x + 10. So, minus x minus 10.
Plus x minus x will over.
We will cancel numerator 10 with the denominator 10 because denominator is 20 minus 10. So, I can cancel numerator also and denominator will become one.
So, we'll write here the square root x + 20 minus the square root x + 10.
And in LHS, we have the square root x + 6 plus the square root x + 8.
I will take this negative term to the left-hand side.
So, we can write our equation the square root x + 6 plus the square root x + 8 plus the square root x + 10 equal to the square root x + 20.
Now, we will use substitution. Let's consider x + 8 suppose equal to u.
So, x + 6 will become u minus 2.
And x + 10 will become u + 2.
In center, we'll write the square root u.
In right-hand side, we have to write the square root U + 12.
Now, we'll take the square root U to the RHS.
So, we have the square root U minus 2 plus the square root U plus 2 equal to the square root U plus 12 minus the square root U.
Now, we have to square both sides.
We'll put power 2 in LHS and in RHS.
Now, we'll be using A + B whole square and A - B whole square identities.
So, I will get the square of the square root U minus 2, U minus 2 plus the square of the square root U plus 2, U plus 2 plus two times the square root of U minus 2 times U plus 2. We will use difference of two squares formula and we can write U square minus 2 square, which is 4 equal to the square of the square root U plus 12, U plus 12 the square of the square root U, U minus two times the square root of U times U plus 12.
Now, we will subtract 2U from both the sides.
So, 2U will be over from both the sides.
Plus 2 minus 2 will get over.
In LHS, we'll write two times the square root U square minus 4 and in RHS, there will be 12 minus two times the square root of U times u plus 12.
Now, our equation is divisible by two.
So, let us divide LHS by two and RHS by two.
Two over two will become one.
12 over two will become six. Two over two will become one.
So, we will get a square root u square minus four equal to six minus a square root u times u plus 12.
Now, we will rearrange the terms.
So, we can write a square root u times u plus 12 in left-hand side.
And in right-hand side, there will be six minus a square root of u square minus four.
We have a square root in LHS.
So, we'll be squaring both sides. We'll put power two in LHS and RHS.
A square root will be over with a square in left-hand side. So, there will be u times u plus 12 in LHS.
In RHS, we'll use a minus b whole square identity. Six square is 36 plus a square root a square is a square root free term u square minus four minus two times six 12 times a square root u square minus four.
We'll write here u square plus 12 u equal to u square 36 minus four 32 minus 12 times a square root u squared minus four.
Now, we will subtract u squared from both the sides.
So, we'll be writing here 12 u in LHS.
In RHS, there will be 32 minus 12 times the square root u squared minus four.
Now, our equation is divisible by four.
So, let's divide LHS by four and RHS by four.
12 over four will be three.
32 over four will be eight.
12 over four will be three.
So, we can write three u equal to eight minus three times the square root u squared minus four.
Now, we'll take this negative term to the LHS and three u to the RHS.
So, we will get three times the square root u squared minus four in left side and in right side, there will be eight minus three u.
Now, we have only one is square root in LHS. So, we have to consider a squaring for the last time.
We will get eight minus three u whole squared.
It is a square of right hand side, which I am writing in left hand side.
And in RHS, we will write our LHS, which is three times the square root u squared minus four whole squared.
Now, we have to use a minus b whole squared formula here.
We will get eight squared is 64 plus three u whole squared is nine u squared.
2 * 8 * 3 48u = 3 ^ will be 9 u ^ - 4 which can be written as 9u ^ - 36 In LHS we'll write 9u ^ - 48u + 64 Now we will subtract 9u ^ from both the sides.
Now we'll take -36 to the LHS and -48u to the RHS So there will be 64 + 36 in LHS and 48u in right hand side.
100 will be equal to 48u We can divide our equation by 4. So let's divide both sides by 4.
We will get 25 in left hand side and we will get 12u in RHS. So I can write 12u = 25 Now we have to divide by 12 to find the value of u.
So 12 over 12 will become 1. u will be equal to 25 over 12.
u will be 25 over 12 Now u was our substitution x + 8.
So in place of u we can write x + 8 = 25 over 12 Now we'll subtract 8 from both the sides.
So, plus eight minus eight will get over.
We will write X will be equal to 25 over 12 minus eight can be written as with denominator 12 96.
Now, in numerator there will be 25 minus 96 over 12.
Which will give us our answer minus 71 over 12.
Now, we have to check whether it is true as per our domain or not.
So, we will find domain of the equation.
So, I can write our equation is square root X plus six plus square root X plus eight plus square root X plus 10 equal to square root X plus 20.
Radicands must be non-negative, greater than or equal to zero.
Greater than or equal to zero.
Greater than or equal to zero.
Greater than or equal to zero.
So, from first inequality we will get X should be greater than or equal to minus six.
X should be greater than or equal to minus eight.
X should be greater than or equal to minus 10.
X should be greater than or equal to minus 20.
And if we will take intersection of all the inequalities, we are going to get X should be greater than or equal to negative six.
And our answer is minus 71 over 12, which is true.
So, we will accept as per our domain.
Our only real solution is -71 over 12. I hope friends you will like this video.
Thank you so very much for watching.
Do not forget to like, share, and subscribe. Bye-bye.
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