NEET 2026 Question Analysis || Physics || Zawlbuk Zirna Run

Added: 2026-05-09

[00:00:13]Hey analyze optics wave. Electromagnetic waves.

[00:00:51]System of particle and rotational motion.

[00:01:07]Question number one.

[00:01:12]Laws of angular motion shortcut for explanation. A full explanation.

[00:01:38]Hey, the angular speed of flywheel is increased from 600.

[00:01:56]1200 revolution per minute.

[00:01:59]Hey velocity angular velocity number omega angular theta is equal to hey omega Average into ta omega is equal to omega omega average to 600 plus 12 0 Number of revolutions. Revolutions.

[00:03:15]100 RPM is equal to heymech.

[00:03:47]10 by 60 RPM 1200 RPMs.

[00:04:13]Yani Yang double slit experiment using monochromatic light of wavelength lambda lambda wavelength. So intensity of light at a point on the screen where the path difference is lambda intensity path difference.

[00:04:45]constructive interference at the center of the screen.

[00:04:51]constructive.

[00:04:58]I maximum constructive I cos square theta by 2 by 2 by 2.

[00:05:17]I mix.

[00:05:19]I constructive interference.

[00:05:23]I mix I minim is equal to phase difference 2 pi 2 pi del x parents is equal to cos²<unk> del x I max is equal to cos² phase difference lambda by del x phase Deference del by Fore by 16 to 1 by 2 1 by two square k by 4.

[00:07:28]by number one in interference and defraction. The light energy is redistributed.

[00:07:46]Interference.

[00:07:48]Interference.

[00:07:50]Dark friends. Bright friends.

[00:07:54]Redistribution.

[00:07:55]Redistrib.

[00:08:06]and bright.

[00:08:18]Energy is conserved.

[00:08:49]Hey, conservation of energy.

[00:08:57]Defraction interferency in character exhibited only by light waves.

[00:09:04]Defractionally interferenc Lightwave interference.

[00:09:20]False.

[00:09:24]A is true but B is false.

[00:09:34]One. Hey, concave lens.

[00:09:53]answer. Hey for questionaveinc.

[00:10:31]F12ave diverging lens.

[00:10:45]Imagine follow link.

[00:11:36]Moment of incarcia.

[00:11:44]Oh, density.

[00:12:10]Density mass is mass per unit length.

[00:12:14]Low density.

[00:12:27]Length.

[00:12:29]Moment of moment of inertia of ring.

[00:12:40]Ring about diameter aboutpend passing through the center perpendicular to the plane about ten about moment of inertia t by 2 m r² r2 l by 2.

[00:13:09]So t by 2 m i m l i l by 2 pi square by 8 square m by<unk>² square 8 square for traveling harmonic wave.

[00:14:03]Equation x into t is = 2 cos 2 pi omega t Omega angular frequency 2 pagation constant. Propagation 2 by lambda path difference 2 by lambda path difference= 2 pi by lambda del x relation between path difference and phase difference. Hey phase difference is equal to 2 pi by lambda k x 2 angular frequency.

[00:15:47]0.0080 0 08 0 into 2 pi 2 piation 2 pi into 0 into 0.5 the difference del x path difference separated by a distance 0.5 5 0.5.8 rad.

[00:17:10]0.5 refracted ray base of the prism.

[00:17:27]Minimum deviation minimum minimum deviation is equal to 2 I - A 60 50 - 60 40° Simple pendulin period kinetic energy of simple pend= half m a² - x² + Five USUS.

[00:18:54]Oh.

[00:18:56]Potential energy. P= K X².

[00:19:28]Electromagnetic wave.

[00:19:40]Microwave Electrons emit light radioactive vibration of A4 B1.

[00:20:07]foreign.

[00:20:33]Question.

[00:20:34]The sum of kinetic energy and potential energy k 0.02 02.

[00:20:49]The speed of simple pendulum speed equilibri.0 Half direct MV² 0.02 V V square. Hey V2 Valal<unk>2.41 41. Answer two. Hey root2 root five.

[00:22:16]A room heater is rated 400 watt 220 volt. If the supply voltage to drop to 200 volt, what will be the power consumed? Approximately uh 220 volt 400 watt power 20 volt.

[00:22:53]resistance = V² by Resistance R = V² by P.

[00:23:10]V 220 220² divided by 400. Resistance.

[00:23:29]Power drop.

[00:23:47]P= V² by 400 200 bread at around 3:30. Welcome.

[00:24:32]Welcome.

[00:24:38]321.

[00:24:41]Next, an electric heater supplies heat to a system at a rate of 100 watt. If the system performs work at a rate of 75 JW per second, then the rate at which internal energy increase will be at the heat supply to the system work done by the system.

[00:25:05]internal energy.

[00:25:09]First of the physics work done by the system positive.

[00:25:33]Heat supply to the system.

[00:25:41]Hey 75 heat supply as work done. Work done by the system 75.

[00:26:12]Uh this one 100us 75.

[00:26:23]This one 25.

[00:26:30]Chemistry.

[00:26:36]Chemistry.

[00:26:53]Heat supply done by the system consistency 100= U plus 75 consistency chemistry physics approach.

[00:27:42]Uh hey match the following equal henceal energy of photon wave four nature. Dal interference interference verify one uh Uh, A4, B3, D2, C1.

[00:29:00]Option A4, B3, C1, D. Option number four.

[00:29:10]Option number four five capacitors of capacitance C1 C2 equal to C2 equal to C3 equal to C4 equal to 10 microfarad and C5 equal to 2.5 microfarad are connected as shown along with a battery of 50 volt hey C1 C2 C3 C4 series connect C5 Five capac 1 by C equivalent equal to 1x C1 + 1 by C2 + 1 by C3. But hey, micro 2.5 microfarad C equivalent and 2.5 microfarad C5 2.5 microfarad equivalent capacial 50 Uh, C1, C2, C3, C4.

[00:31:18]for C5 Q5 Q5 equal to uh C5 um V5 and Q= to CV for hey 2.5 and yeah 2.5 microfarad voltage equivalent 50 volic micro I 125. That's okay.

[00:32:42]1 to 5 micro.

[00:32:48]This one Q C equivalent uh V uh 2.5 microfarad 50 microo C5 means equivalent 12 C1 C2 C3 C4 C5 microo 125 Micro on all capacitors.

[00:33:49]Option number two on all capacitors.

[00:34:04]equivalent 2.5 microfarad plus 2.5 microfarad microfarad.

[00:34:33]Hey, capacitance 5 microfarad 1 to5 mic on all capacitors.

[00:34:55]Consider two uncharged capacitors of equal capacitance 200. One of them is charged by 100 volt supply and disconnected. How this capacitors is connected to the uncharged capacitors.

[00:35:06]Amount of electrostatics energy loss in the process.

[00:35:27]100 volt.

[00:35:46]Disconnect energy.

[00:35:50]U equ= to half CV².

[00:35:56]equal to half capac 200 voltage 100 square you can solve one uh 200 100 into 10 power 4 5 6 10 - 50% reduced 50% = 1us sorry jewel U into U= 1 into 10 - 6 50% 50% 0.5 into 10 - 6 U - U1 0.5 into 10 - 6 June 50.

[00:38:14]Hey diagram S2 C1 C2 battery connect V1 + C2 V2 / C1 + C2 Center of mass formula M1 X1 + M2 X2 divided M12 potential 100 C2 V2 potential zero C1 plus C200 Plus 200 50 volt voltage 50 energy new potential Cap V prime square.

[00:40:20]200 400 C1 C2 50 square 0.5 into 10 power - 6 June 0.5 into 10 minus 61 0.5 into 10 - 6 loss 0.5 0.5 U prime 1 into 10^ - 6 - 0.5 into 10^ - 6 0.5 into 10 - 6 0.5 into 10 - 6% Four statements are given. A is volume of a nucleus is proportional to A1 by cube. The volume of a nucleus is proportional to A. The difference in mass of and its nucleus is called mass defect. The difference in mass of a nucleus and its constituent is called mass defect. H.

[00:42:10]volume 4x3 pi r cube nuclear radius formula r a1 by 3 nuclear radius r here r a1x 3 this one volume 2 4x 3 pi I R A constant R conant value to 1.2 into 15 is proportional to a volume is proportional to mass number.

[00:43:05]Option number one.

[00:43:11]The volume of nucleus is proportional to A. Volume is proportional to A. The difference in mass of the atom and it nucleus is called mass.

[00:43:33]Electron.

[00:43:38]The difference in mass of nucleus and its constituent is called mass effect.

[00:44:01]B and D are true but A and C are false force four 17 A resistor is connected to a battery of 12 volt EMF and internal resistance 2 ohm if the current in the circuit is 0.6 6 amp. The terminal voltage of the battery is direct formula terminal potential difference V= to E minus I R R small internal resistance potential E is 12 12 volus 0.6 Six internal resistance are true. So 12 minus 1.2 108 vol 10.8 volt an unknown nucleus has a nuclear density of 2.29 into 10^ 17 kg per meter cube and mass of 19.926 into 10 - 27 kg. It mass number is approximately 1.2 temple 15 mass by density.

[00:46:01]volume mass number = 4x3 r = 4 by 3<unk> r cube Mass volume equation two 4x 3<unk>i r q a = mass by density this one a m by 4x 3 pi r cube row a = mass of the nucleus 19.926 into 10^ - 27 4 pi 12.56 / 3 into r 1.2 2 into 10 - 15 density 2.3.

[00:47:34]2.29 29 into 10 shortcut.

[00:48:05]A = mass of the nucleus by one atomic mass.

[00:48:14]A= m 19.926 into 10 power - 27 kg. Yeah.

[00:48:30]So to 1.665 into 10^ minus 27 kg one divides one 12.

[00:48:49]Awesome.

[00:48:56]Awesome.

[00:49:08]connection.

[00:49:11]A flux containing argon and chlorine in the ratio of two by two ratio 1 by mass.

[00:49:16]The temperature of the mixture is 27°C.

[00:49:19]The ratio of root mean square speed of the molecule of the two gas v argon RMS by V chlorine RMS is atomic mass of argon is 40 atomic mass unit u and atar mass of chlorine is 17.0 mass unit uh VMS formula root over 3r Two is to one by mass in time of mass.

[00:50:10]Number of moles.

[00:50:31]300 V argon RMS by V chlorine RMS value of argon by RMS value of chlorine root over R value 40.

[00:51:06]This one uh chlorina R 300 by uh 70. Yeah.

[00:51:29]Sorry.

[00:51:36]Hello.

[00:51:41]Roo<unk> 1 by 41 to 1 by 2 1 by<unk> 7 denominator denominator roo<unk> 7 by 2 roo<unk> 7 by two option number one roo<unk> 7 I true h con for a metal of w function 6.60 6.6 6 volt. Which of the following wavelength of incident relation does not give rise to the photoic Photographic Wavelink does not give rise at it wavelength.

[00:52:59]200 nanome.

[00:53:05]Which can give Energy Hus in terms of wavelength energy equal to H uh C by lambda minus F Electric effect.

[00:53:48]Work function.

[00:53:53]Work function. Work function.

[00:53:56]Few not In terms of wavelength, HC by lambda threshold wavelength.

[00:54:17]to HC by 5 threshold wavelength in terms of nanome 1240 electron volt nanome 52 6.6 electron volt 6.6= Uh 187 something 187 something nome in terms of wavelength electric effect 187.

[00:55:24]Heat.

[00:55:41]Heat.

[00:56:16]187.

[00:56:21]187 photo electric in terms of frequency MCQ.

[00:56:50]In the first excited state of hydrogen atom, the energy of its electrons is minus 3.4 electron volt. The radial distance of the electrons from the new hydrogen nucleus in the case is approximately first orbit second orbit. Oh, in the first excited state that is one first excited state that is one second orbit n= 2.4 Radius of hydrogen atom formula r equal to 0.53 n² by z.53 far as excited state electron That means 2 square one uh four 2 square to four uh 0.53 12 5 TR 5 for 20 to 1.

[00:58:24]Oh 2.12 into 10 minus 10 m option number option number Fore.

[00:58:59]A uniform metallic wire having resistance 4 ohm is bent to form a square loop. A B C D.

[00:59:07]C figure a resistance of 2 ohm is connected between points B and D and a battery of 2 volt is connected across points A and C as shown in the figure.

[00:59:15]Now the value of current I is I bridge AD resistance 1 C in resistance 1 ohm wisdom bridge B QR SQ.

[01:00:11]So equivalent resistance A B C D 1 1 ohm A B C in series equivalent Two 2 ohm 2 ohm. 2 ohm.

[01:00:58]Equivalent 1x r 1 by 2 + 1x 1.

[01:01:12]Okay.

[01:01:13]Uh money.

[01:01:41]So we have Ohm's lawm I = V by R. So V is 2 vol. R is 1. 1 2 A.

[01:02:00]Option number one.

[01:02:16]In a bridge experiment, the portions of a cell E and G are interchange.

[01:02:41]in a balance bridge.

[01:02:55]Option number.

[01:03:36]Option number four, both right side and left side deflection and at balance point no deflection. Option number four.

[01:03:58]Option number four.

[01:04:02]Which of the following statements are correct? Inside the conductor, the electrostatic field is zero.

[01:04:15]Inside a conductor, electric field is zero. Continue. electro statics conductor equipial surface in terms of potential electric field equal to minus dv by drot equipotential surface equipotential surface potential constant deration of constant is zero. Electric field zero electric field at the surface of a charge conductor does not depends on its surface charge density. electric field uh at the surface. The conductor expression equal to sigma by epsilon.

[01:05:37]It depends on charguctor can have no excess charge in the statics uh situation.

[01:06:11]charging.

[01:06:22]At the surface of a charge conductor, the electro field must be normal to the surface at every point.

[01:06:31]Electric field.

[01:06:35]Normal vector. Surface normal vector.

[01:06:37]Surface normal vector.

[01:06:43]Surface normal vector.

[01:06:48]Electric field.

[01:06:54]The electric field must be normal to the surface of the point. Electric field.

[01:07:09]The electrostatic potential is zero everywhere inside a charge conductor.

[01:07:13]Electrostatic potential zero conductor potential surface conductor potential surface that means potential zero conant.

[01:07:34]So A C D A C and D only option number uh Elimination force by area by change in length by original I elimination.

[01:08:53]A submarine is designed to withstand an absolute pressure of 100 uh atmospheric pressure. How deep can it go below the water surface?

[01:09:09]P absolute atmospheric pressure plus God's pressure.

[01:09:29]God's atmosphere atmosphere.

[01:09:40]1800 atmospheric ATM 99 atmospheric pressure into 10^ due to liquid P 99 4 10 990.

[01:11:23]When the ruler falls vertically, What is the correct order of distance traveled by the ruler for each person?

[01:12:02]person gavity gt² 0.2 2 seconds 0.12 0.01 0.1 It increases above a certain threshold voltage at the current increases significantly.

[01:13:33]Forward.

[01:13:56]Increases significantly.

[01:14:06]This current is called reverse saturation.

[01:14:19]So this statement A is true but statement B is false.

[01:14:29]Next box of mop stationary.

[01:14:45]Okay.

[01:14:53]box here 0.12.

[01:15:02]Oh, this one keeping the box uh in stationary state over the maximum acceleration with which the trolley can be moved horizontally.

[01:15:23]Limiting Max resistance times.

[01:16:05]Next one. MG acceleration * 0.12 Rectifier in DC.

[01:16:55]The voltage appearing across the diode.

[01:16:57]The voltage appearing across the resistor.

[01:17:07]Option diode.

[01:17:28]Number four.

[01:17:58]Reverse bonus.

[01:18:27]perpendicular force. Oh, 90°.

[01:18:42]Acceleration 6 + 8 square resultant resultant acceleration. Oh, mult square.

[01:19:53]force.

[01:19:59]Hating Halloween.

[01:20:29]perpendicular by base perpend= inverse of 3x 4 8 Newton 3x4 option acceleration.

[01:21:21]diitverse.

[01:21:44]Reverse resistance connection equivalent.

[01:22:09]Oh, are equivalent to 1x 4 + 1 by 2.

[01:22:20]Now in 1 + 2 3x 4 equivalent resistance 3x4.

[01:22:35]Therefore, the current through the circuit is current by R.

[01:22:54]by 15 by two.

[01:22:58]15 by two empty option.

[01:23:04]Option four.

[01:23:30]A variation of the velocity. Oh, with time speed velocity velocity with time of vertically upwards and then falling back.

[01:23:49]Foreign speech. Foreign speech. Foreign speech.

[01:24:20]Hey.

[01:24:25]Oh.

[01:24:35]V.

[01:24:44]Straight line convention. Standard sun convention.

[01:25:17]Oh, then Max.

[01:25:42]C. Option D.

[01:25:54]tablet.

[01:26:01]See only 20 VDal is division of length.

[01:26:32]MSD2 MSD one MSD one VSD 1 BD = 16 by 20 16 by 20 MSD LCM 20 MSD two 1 by 5 md 1 mm 1 mm 22 0.2 mm 0.02 02 option number three x.

[01:28:21]Oh.

[01:28:43]5.580 k.

[01:28:47]This one 9.0 9.0 into 100 number of significant figures.

[01:29:15]for significant 7.654 into 10 power 3.

[01:30:19]55 7.7 Seven.

[01:30:40]This one.

[01:31:08]60 seconds.

[01:31:15]Oh extreme position one to two seconds simple.

[01:31:50]2 pi roo<unk> over square t² = 4 pi square.

[01:32:10]This one square.

[01:32:17]This one.

[01:32:29]Option four.

[01:32:36]Speed of light. Mistakiness. Unity.

[01:32:47]This one. If light takes 6 minute and 40 seconds to reach the earth from the sun, the distance between 6 minute 40 seconds.

[01:33:15]6 into 60 second plus 40 seconds.

[01:33:21]360 + 40 400 seconds.

[01:33:28]One 400 seconds.

[01:33:33]Option 37. Now circular coil 100 tons. Oh, n = 100 radius c 5 cm magnetic field magnetic moment.

[01:34:35]Loop center magnetic field to mu I by 2 in 2 B r by mu not N Fore into 10 ^ -3 4<unk> 10 - 7 10^2 amp 2.5 amp 2.5 amp magnetic moment magnetic moment to m = I a 2.5 area circle p<unk> r² - 2² into 100 100 square he approximate 1.9 625 1.92 2 amp me².5 option to number Four.

[01:37:02]Hey.

[01:37:08]Hey. Radius distance.

[01:37:20]potential to change potential surface to potential minus G M by R2 final G M by R + H Yeah. H2 R + R2 2R change in potential final minus initial minus G M by R - G M M by 2 RA in terms of capital G capital small convert G M by R² R M 1 - 1 by 2 bracket G R M by 2 and G RM by Two two number four. Hey option two.

[01:39:00]Next question. Oh, hey Pu.

[01:39:04]I will power two MGH by M key 10 to the^ 3 G 9.8 H key 20 time key 10 cancel 9.8 into 22 19.6 10^ 9.6 kilowatt Next resonance frequency 1 by 2 pi roo<unk> over LC L2 millia mill 10 - 3 C2 capacitor 10 -1 0.1 - 7 - 5 Resonant frequency not equal to 1 by 2<unk> 10 ^ - 5 ^ - 2 2<unk>i into 10 ^ 3 50 52 by<unk> into 10 ^ 3 approximation 3.14 Four approximate 16 15.9 number Inside Magnetic field proportional to distance from the center Max inversely directly number one. Number one.

[01:43:22]The peak value of current is value I = I sme F 0 to 5 sin 2 pi ft = 1 2 pi f2 by 2 * 2 1 by 4 F F to 60 1 by 4 into 6 P2 1 by 2 4 0 1 by 2 4 0 next resistance IG G I - I maximum current resistance 10^ minus G2 - 10 - 3 0.001US 01 approximating 1 10 - 2 10 - 2 0 1 rectangle Magnetic field inward length 8 cm cm 0.3 0.3 vector velocity perpendicular.

[01:46:56]Hey, normal to the solder magnetic field equal to B LV B2 0.3 L2 normal 3 cm 3 cm 3 cm V cm per second.

[01:47:29]2 into m/ secondhip 0.9 into 10 ^ 4 into 2 and next one it's 1.8 10 ^ -4 oh 4 1.8 8 into 10 ^ - 4 WhatsApp Monday to Saturday. foreign.

[01:48:52]Hello