This video demonstrates how to simplify complex surd expressions by rationalizing denominators and applying algebraic identities. The key technique involves using the sum of cubes identity (a³ + b³ = (a + b)(a² + ab + b²)) to factor and simplify expressions containing cube roots. The process includes rationalizing denominators by multiplying numerator and denominator by the appropriate radical, finding common denominators using LCM, and combining like terms to arrive at the final simplified form.
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Olympiad Mathematics Trick | Surdic expression | Can you?
Added:Hi everyone.
Here we have a serious one. We have to evaluate what we have here.
So, what do we do?
Solution.
Okay, um I'll just go straight to the point, right?
So, from the first term here, we are going to have 1 over Okay, 1 over 2 root 2 multiplied by root 2 over root 2.
So, what I'm doing is rationalization.
Right? To rationalize it, you're going to pick this this sort and it multiplies both the numerator and the denominator.
The power of 3 will still come down.
Plus, we do the same thing there. We have 1 over the square root of 3 and it multiplies root 3 over the square root of 3 and the [clears throat] cube will still come down.
This is interesting, right? So, if we multiply this, we have root 2 over 2 multiplied by root 2 * root 2 will give us 2.
So, this is what we have in the first um bracket.
Right? This 2 is this one, then root 2 * root 2 is 2.
Then we go over to the other one. 1 multiplied by root 2, just like 1 * root 2 give us this root 2, right?
>> [snorts] >> So, 1 * root 3 will give us root 3 and it's over root 3 * root 3 will give us three.
So, this still has the power of three.
So, at the end of from here now, we are going to have square root of two over four to the power of three.
Then, we have plus the square root of three over three to the power of three.
So, the next question is how then do we simplify this?
And I have an idea. I would like us to simplify this using the addition of two cubes.
Yes, addition of two cubes. You heard me. Remember that a cube plus b cube is what we call the addition of two cubes.
And this identity is equal to a plus b multiplied by a squared plus ab plus b squared.
And using what we have already, our a is root two over four.
Our b is root three over three.
Yes, that is what we have at this point.
And what do we do?
We will just put them into this identity.
So, if you are ready with me, let's go.
a plus b becomes root two over over four plus root three over three.
This will be in the first bracket for this one. Then, I'm going over to that.
a squared that's going to be root two over four.
This will be squared because of the square on the a.
Then, we have Oh, this identity is not it. We are supposed to have negative here, right?
That is for the addition of two cubes.
So, this is equally negative. So, our A is square root of two over four.
And we multiply it by B, which is square root of three over three.
Then we have plus B squared. What is our B?
B is square root of three over three.
And there's a square on it.
So, you square it, just like that.
You square it, and then we're going to close this.
Right? What do we do?
From here, you know you can find the LCM. What is the LCM?
The LCM of four and three is um 12.
So, you do this.
12 / 4 is 3. 3 * √2, that'll be 3 √2.
Then plus 12 / 3 is 4. 4 * √3, that'll be 4 √3. So, this is in the first bracket.
Then in the second, we square this.
√2 squared is two.
Then 4 squared is 16.
Minus we multiply these two. √2 * √3, that'll be √6.
And then it's over 4 * 3, which is 12.
Then we have plus √3 squared is also three.
And 3 squared is nine. So, we close this.
Okay? So, this is interesting, right?
Now, what do I do from here?
We're going to reduce Let's reduce this and this. So, we have three root two plus four root three divided by 12 in the first.
Then in the second, we have two into two is one, two into 16 is eight.
Then minus we have root six divided by 12.
Then plus three into itself is one, three into nine is three. Then we close this.
Let's continue.
Okay, so um we're going to simplify this as well.
So, let's write three root two plus four root three divided by 12.
Then to simplify that we have to get our LCM, right?
The LCM of eight 12 and three is 24.
Right? Then we do this.
24 divided by eight is three. Three times one is three.
Minus 24 divided by 12 is two. Two times root six, that'll be two root six.
Then plus 24 divided by three is eight. Eight times one is eight.
Then we close this.
From here, we still have this three root two plus four root three over 12.
Okay.
Okay, so we have this.
Then from here, three plus eight that'll give us 11.
Then we have minus two root six.
All of this is over 24.
And we close it.
So, guess what we'll do from here.
At this point, we have to multiply. So, let's multiply very quickly.
So, we have three root two multiplied by 11. That will give us 33 root two.
Then, three root two multiplied by um two root six. Three times two, that is six. Then, root two times root six, that will be root 12.
I'm going over to four root three.
Four root three multiplied by 11, that will be 44 root three.
Right? Please take note of that.
We have 44 root three. Then, 44 root three multiplied by Okay, four root three multiplied by two root six.
That will give us negative. Four times two is eight.
Then, root three times root six, that will be root 18.
Okay, so we have root 18.
And all of this will be over 12 multiplied by 24, and that is 288.
Okay, this is interesting, right?
So, what should we do now?
You know, we can break this root 12, and we can break root 18.
So, let's break it. We have three root two minus six root In place of root 12, I'll put four times three.
Then, plus 44 We have root three minus eight root In place of root 18, I'll put 9 * 2.
And all of this will be over 288.
So, the next thing I will do is to do this. We have 3 root 2 minus Now, I would like to jump a step so that the video will not be too long.
Now, look at this. Square root of 4 is 2. So, 2 * 6, that will give 12.
Then we have root three.
Then plus, we have 44.
We have root three minus this. Square root of 9 is 3. 3 * 8, that is 24.
Then we multiply by root two.
And then all of this will be over 288.
Now, what do you think we can do?
We have this and this, right?
Okay, so we have this and this.
We have this and this to bring together, right?
Oh, this is 33. So, here is 33, not just three.
33. So, we have this and this to bring together, right?
So, I will now have 33 root two minus 24 root two.
These two will be together. Then these and these will be together, but let me write this positive first. So, we write 44 root three.
Then here we have minus 12 root three.
Everything is over 288.
Okay, so what do I do from here?
Um this minus this will give us what?
That's going to give us 9. So, we have 9 root 2.
Yes, we have 9 root 2.
And then this minus this is going to give us 32 and it's positive. So, we write plus 32 root 3 and this is all over Okay, by the way, this is 32.
So, write 32 root 3 and everything is over 288.
Now, you look at this. The left-hand side I mean from here.
9 and 32 do not have any common factor.
Okay, so that means this is um the best we can do.
And this also means that let's finish it here.
This means that 1 over 2 root 2 to the power of 3 plus 1 over root 3 to the power of 3 is equal to 9 square root of 2 plus 32 plus 32 square root of 3 all over 288.
Yes, thank you for watching and um if you're new to this channel consider subscribing for so that you can get to see more of our interesting videos.
Thank you. See you in the next video.
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