To solve exponential equations like 4^x + 1 = 40, first isolate the exponential term (4^x = 10), then apply logarithms to both sides (log(4^x) = log(10)), use the power rule to bring down the exponent (x·log(4) = log(10)), and solve for x using the change of base formula (x = log_4(10)). The solution can be verified by substituting back into the original equation.
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Math Olympiad | Exponential Equation | Germany | Can you solve this?
Added:Hi everyone.
Let's provide the solution to this one here.
4 to the power of x + 1 = 40.
So, what we are going to do is to um work on this using one of the laws of indices that we know.
This will be 4 to the power x * 4 to the power of what? To the power of 1. And this is equal to 40.
Remember, if you want to pick one of the bases from the left-hand side, you are going to have um to pick four and then add the powers.
So, from here now, this is the same as having 4 * 4 to the power of x, which is equal to 40.
So, from here, we have to remove this four by dividing both sides by the same four there.
And here, we do the same so that this will remove this four of us.
And now, we have 4 to the power of x to be equal to 40 / 4, and that is going to be 10.
Guess what I will do.
Since we are not having the same base, just take the log. And you have log 4 to the power x to be equal to the log of what? 10.
The next point, I know that log 10 is the same as um one, but I prefer working with that log 10 so that I can bring the power down to give me x log 4, which will be equal to log uh 10.
Divide this by log 4 so that x will be free, and the same thing will happen here.
These will cancel out.
But, from the right, we cannot cancel anything. So, we write our X to be equal to log 4 log 10 rather divided by log 4.
Now, from these points From these points, what do we do? We can apply change of base.
Do you know about change of base that says that if you have B that is raised to the power of A to the same base of B. Like, everything here is equal to A.
Do you see that? So, if that is true, then what we have right now can be written like this, X equals log 10 now to the base of Okay, I think it's a different law that I explained. It's a different law that I explained. I'll use that law later.
Now, [snorts] this law here says that if you have log M divided by log B that everything you have here, let me try to show it. Everything you have here is the same thing as log M to base B.
See that?
So, this B now becomes the base to M.
So, the same thing is what will happen so that 4 here becomes the base to the 10.
As simple as that.
So, at this point, we have our value of X in terms of log.
Now, we will not stop here. Let's go very quickly to the original equation.
So, this is the original equation and our value of X is log 10 to base 4.
Log 10 to base 4, right?
Okay, let me write this better.
We have log log 10 to base 4 is our value of X.
So, in place of X there now, put this value. So, we have 4 to the power of log 10 to base 4 + 1.
This is one, right?
And then, if we continue, we are looking for what this will give us. If it does not give us 40, then we are not correct.
So, this is the same thing as 4 to the power of log what? Log 10 to base 4 multiplied by 4 to the power of 1.
From one of the laws of indices, so that I explained this law before.
Log to base 4 and this 4 will cancel out. So, here we have 10.
Multiplied by 4 to power 1, which is the same as 4.
10 * 4 is 40.
So, this means that we are very correct because we were looking for the 40.
So, we are saying that our X to be what?
Two.
No, our X to be equal to log 10 to base 4 satisfies this very equation.
4 to the power X + 1 = 40.
Thank you for watching.
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