The video elegantly distills spatial relations into basic similarity ratios, making a standard textbook problem feel like a clever discovery. However, what it labels a "trick" is simply the fundamental beauty of Euclidean geometry at work.
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Added:Welcome back. Today we've got a really elegant geometry puzzle. At first, it doesn't look like there's enough information, but with a couple of clever observations, everything falls into place. Let's take a look at the figure.
We have a square A B C D. Point E lies on the left side A D. Point F lies on the top side D.
joining E, F, and B forms triangle E FB inside the square. We're given two side lengths. EB is 10 units. FB is 8 units and the angle at F is exactly 90°.
Our goal is to find the side length of the square. Let's call that unknown length X. We'll start with triangle E FB.
Since it's a right triangle, we can apply the Pythagorean theorem.
E F2 plus FB 2= E^2.
Substituting the numbers gives E F 2 + 64 = 100. Subtract 64 from both sides and we get e f2 = 36.
Taking the square root we find e f = 6.
Now let's look at point f. Since D F and F C lie on the same straight line, the three angles around that straight line add up to 180°.
The angle inside triangle E FB is 90°.
So the other two angles together must also total 90°.
Let's call them alpha and beta.
That means alpha plus beta equals 90°.
Next, look at the small triangle E D F.
It has a right angle at D. One of its acute angles is alpha. So, the remaining acute angle must be beta.
Now look at triangle F CB.
It also has a right angle this time at C. One acute angle is beta. So the remaining angle must be alpha.
That means these two corner triangles have exactly the same three angles. So they are similar triangles.
The hypotenuse of the left triangle is E F which is 6. The hypotenuse of the right triangle is FB which is 8. So the similarity ratio is 6 to 8 or 3.
Now let's use that ratio.
In the right triangle, the side opposite angle beta is c, which is the side of the square. So its length is x.
In the left triangle, the side opposite angle beta is d.
Therefore, df equals 34s of x.
The entire top side of the square DC also has length x.
So fc equals x - 34 of x which is 1/4 of x.
Now we're ready for the final calculation. Look at right triangle F CB.
Its legs are FC which is 1/4 of X and CB which is X. Its hypotenuse is 8.
Applying the Pythagorean theorem, the quantity 1/4 of X^2 + X^2 = 8^2.
That becomes 116th of x^2 + x^2 = 64.
Combine the two terms we get 17 / 16 * x^2 = 64.
Multiply both sides by 16 and divide by 17. So, x^2 = 64 * 16 / 17. Finally, take the square root of both sides. The square<unk> of 64 is 8. The square<unk> of 16 is 4. 8 * 4 is 32. So, the exact value of x is 32 / the square<unk> of 17. And that's our final answer.
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