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[00:00:56]Hello, hello.

[00:00:59]Hello, everyone.

[00:01:55]>> [sighs and gasps] >> Namaskar, Jai Jagannath. Welcome to the online platform of The oxidation number of iron in Na2Fe(CN)5NO sodium nitroprusside sodium nitroprusside ligand to maybe charge this is the total number of new maybe cation, maybe anion equivalent sodium respective charge maximum to maximum video session iron complex minus one nitros nitros onion plus one positive charge and negative charge organometallic linear structure of main structure for electron count charge the plus one plus one equal to zero It has to be a plus two minus five minus three plus one minus two plus two plus two two minus three plus number B question the correct answer number B oxidation number base for the the question CEO EN whole two 83 bridging ligand NH2 NH with OH cobalt EN whole two a plus three plus three question with some more stuff cobalt oxidation number cobalt oxidation terminal terminal cobalt bridging bridging terminal EN EN CH2 CH2 NH2 NH2 EN bidentate neutral neutral and bidentate ligand important important neutral neutral the respective the respective last ethylene the charge the charge complex a bridging NH with OH bridging NH with OH H positive H positive NH2 NH2 the minus one charge the again with H release NH2 negative a point H positive remove nitrogen with a three negative the charge the NH imido minus two with OH minus one a basis oxidation number the respective cobalt minus two minus one minus three minus three as you go along cobalt X negative X ethylene diamine again plus zero equal to plus three equal to plus three X plus X two X two X minus three equal to plus three that means X two X plus six two X plus six X plus three plus three cobalt cobalt oxidation number oxidation plus three number B plus three cobalt oxidation number question ligand terminal bridging next question again question correct answer number oxidation number question ligand some ligand charge ligand denticity ligand denticity coordination oxidation number the solution the question coordination number oxidation state of the element in the complex a complex coordination oxidation number ethylene ethylene diamine the denticity the denticity ethylene diamine data donor side denticity oxalate or oxalate C double bond oxygen with C double bond oxygen donor side donor side that means denticity it is simple a two denticity two containing ethylene diamine two times the number coordination number formula summation number of ligand number of ligand into density of ligand into density of ligand Coordination number six four eliminate quality Four which eliminate quality coordination number six degree daily Next question oxidation number simple Oxidation number calculation by The mango corn generator with a document The charge basis of the movement of a complex that E E N whole two C two O four Then what you doing among the NO2 NO2 negative Positive charge A basis of the money by equation Ethylene diamine two into zero charge Oxalate by charge money one into minus two Oxalate by the money to minus two Equal to one plus one liquid A basis of the X charge of the money plus three is you X charge of the money plus three The money the money coordination number six and oxidation number three Coordination number six and oxidation number three Option number D I do money number D Perfect answer Promote in the south Perfect answer Saloni with the perfect answer Live representation Answer comment section of the Next question IUPAC nomenclature The money is series Design IUPAC Question paper Isomerism Question paper Nomenclature Question paper Oxidation number Coordination number Balance bond theory Hybridization Balance bond theory Question paper Crystal field theory Question paper Application Question paper Sub part You would have exam Most important Some of the try IUPAC Name to the keyboard IUPAC Name First point The first Caterer By name of a name Second point Caterer Simple Caterer Simple caterer Simple Money potassium Potassium Chlorine Chloride Money simple Simple Without numerical prefix Without numerical prefix Numerical prefix Without numerical Simple caterer Simple Anion More than one Simple K4 Potassium Potassium Tetra potassium The same Simple caterer Simple Simple Third point Complex A complex Ligand Then central metal Then oxidation State to bracket Oxidation number Ligand Alphabetically Alphabetically Using numerical Numerical prefix Numerical Alphabetically Jodie Ligand Die try I'll see you multiple Times Two times Three times Three Central metal Log Complex Caterer You are neutral You are complex Anionic The complex Anionic Metal The A T E E case Normal name Normal Normal The complex Anionic Iron Ferrite But you are the complex You are neutral Normal ferrous I would have oxidation number Oxidation number Bracket Bracket with the oxidation Number Comment Section answer I would have the Complex Dissociate Two K positive That's CR CN whole two Both important Compound Oxygen Whole two I would have the O2 That's NH3 I would have the Complex Charge Two negative Jodie Caterer Simple Caterer Simple caterer Money Potassium Potassium Potassium Potassium Next Complex Complex Anionic Complex Anionic Chromium Chromate Chromate Chromate The sub Option Chromate A T Chromate A T chromate Option Eliminate Exam Time Elimination Most important Oxidation number Oxidation number Calculate Potassium Two plus one Plus Plus Two into minus one Important A O2 A O2 Important Different Chemical different Oxide Oxide I would Peroxide Peroxide I would have the Oxide Charge is Minus two Peroxide Charge is minus two A the important Oxidation Number No way to A basis NH3 Charge is zero Plus A T O2 Oxygen Two Oxygen Two oxygen Oxide Two into minus two Plus Peroxide One into minus two Plus Ammonia Charge Zero Equal to zero A T Solve A basis X Value A the plus two A the minus two Plus two Minus two Cancel A the minus four Minus Minus six That means X Plus six Important Compound Jodie chromium Maximum Oxidation State Plus six Maximum Oxidation State plus six The Chromate Plus six Chromate Plus six Chromate Plus six Chromate plus The money A Option eliminate A the money Normal Approach Compound Potassium The Ligand Arrange Alphabetically A the sub Amine Amine That would Amine Amine Die Die A T Call you Call you The die Perfect Die The perfect A basis Question the correct Answer Option number Option number Question the Correct Answer The oxo Peroxo Chromate Chromate That means Question The correct Answer Option number One A the Important Oxidation Number Exam Oxidation Number The The sub Call you Oxygen That would Charge is minus O2 Call you Mention Mention Charge Minus two You are cool Oxo Oxide Oxide Oxo Call you That would You are cool Peroxide Peroxo Peroxo A the Inorganic I would O2 Minus Superoxide Superoxide I would have Point Next question Next question Next question Question One of the According One of the According A point First point Ligands Are connected The Metal Ions Covalent Bond Second Secondary Valencies Directional Properties Secondary Valencies Non Ion Isable Of the state Of the Statement The Correct The Correct That The try Answer Comment section The One of the Theory One of the Theory One of the Theory Central Metal Atom Complex Central Metal Atom Type of Valencies Primary Valency I would have Secondary Valency Primary Valency Ion isable Secondary Valency Non Ion isable Non Ion isable Non Ion isable A the primary Valency According to Modern terminology Oxidation Number I would have the Secondary Valency Coordination Number A the Point Most important A the primary Valency Ion isable Oxidation Number I would have the nature Non Directional I would have Non directional Nature But you Nature Directional I would have Directional I would The mango Structure Geometry Explain Structure Geometry Explain Explain Secondary Valency You explain I would have I think Point The try I think Point The try A basis Approach Question The correct Answer Secondary Valency Directional Properties Perfect Secondary Secondary Non Isable Perfect Second Third Correct Second Third Correct One Ligands Are connected The Metal Covalent Bond Covalent Bond C Coordinate Bond Coordinate Bond First Option First No wrong Option Number B Question the Correct Answer Option Number B Question the Correct Answer Only Only Saloni Promote in the Perfect Answer That's the Promote in the Perfect Answer Next question Next question A question The Both Question I would have The Maximum Mistake How many Moles Of A C Would be produced How many Moles Of A C Would be Obtained When 100 ML When 100 ML Of 0.1 Molar C O NH3 Whole five C L three Treated With Of A G NO3 A question Actually One of the Theory One of the Theory A question But Jodie Solution I would Idea Question Solution Idea Question Attend I would have I would have Try Answer Comment section one last thing precipitation precipitation complex excess reaction I'll get you more precipitated precipitated precipitated and number of chlorine coordination square square and number chlorine precipitated ionizable ionizable chlorine chlorine ionizable more precipitated first point clear clear how many more would be obtained when 100 concentration compound structure complex complex platinum complex some neutral complex neutral complex coordination number co coordination number maintain that means I don't know what reaction ionizable precipitated compound one more compound two precipitated compound molarity volume compound molarity 0.1 volume 100 100 volume number more number more more precipitated easily calculate maximum number 0.03 question correct more molarity number more volume I'm going number more molarity volume volume little volume milliliter little convert 100 divided by 1000 100 divided by 1000 little 0.1 little 0.1 little and number molarity volume molarity volume 0.1 0.1 0.01 molar 0.01 more substance one more compound two more precipitated 0.01 into two 0.02 more precipitated compound how many more would be obtained get the more obtained option number the point comment section mention clear some more comment clear point some actually solution molarity volume molarity volume more volume ml millimole little convert directly more one more more more more more precipitated 0.01 more two 0.01 that 0.02 more precipitated present some point clear next question next question one last question some definition question solution chapter connect related question every application question conductance that means part one last electrochemistry solution chapter more concept more important topic one last some question correct answer what you may say following one and two some list equivalent conductance I would formula the compound simple conductance conductance directly proportional number ion number ion more number ion conductance value conductance value compound complex positive three negative you know dissociate complex positive two negative you could dissociate complex positive plus you could dissociate dissociate complex positive four negative every some some simple number ion directly proportional guess charity ion second ion ion we ion get the number ion equivalent conductance I would maximum equivalent conductance four maximum four by maximum value 229 97 404 523 four by value 523 when extra extra extra eliminate extra eliminate extra any data value 404 404 data 1.404 that means one one hour one eliminate one correct answer number you want number say perfect some more perfect answer any question approach option time waste but I still any ion any data ion 229 oh yeah I do not total 97 any question approach I would some more concept clear next question a complex already CPT 2025 question CPT 2025 related question important compound important compound details discuss coordination compound copper not see you and S3 and S3 whole four two positive some more comment section first compound hybridization a compound hybridization geometry some more comment mention geometry hybridization some more comment section mention question question correct some more some more copper copper two plus that means complex D9 D9 that weak field D9 complex first second third fourth fifth sixth seventh eighth ninth coordination number four weak field again behave other chance nine electron so the first I don't know question SP3 hybridization SP3 hybridization you don't have incorrect tetrahedral structure so do some of the tetrahedral eliminate you don't tetrahedral eliminate details complex discuss a complex square complex square planar complex important square planar hybridization DSP2 but compound DSP2 hybridization compound SP2D hybridization you ready S orbital plus and py plus minus y squared dx minus y orbital involved hybridization most important a new one appeared electron as it is present that means electron present the square complex one electron square complex one electron bill cool perfect it is all electrons are paired some more electron square planar one electron bill cool perfect I don't know magnetic moment 1.73 more magneton I need verify unpaired electron I would some more point you want option number be bill cool perfect you want option number be bill cool a complex I don't important complex next question start some more question correct try comment section some more question die positive metal [clears throat] ion of transition series forms octahedral complex octahedral complex form with magnetic moment 4.9 more magneton magnetic 4.9 more magneton unpaired electron number unpaired electron simple unpaired electron value nearly magnetic moment 1.73 magnetic moment 2.8 two by magnetic moment 3.92 and the four magnetic moment 4.92 and if five any basis we got magnetic moment 5.93 any value data 4.9 more magneton we got any number unpaired electron four number of unpaired the first octahedral complex octahedral complex that means number unpaired electron four complex number of unpaired electron four Another octahedral complex which is diamagnetic.

[00:30:02]The metal ion a dipositive A dipositive forms an octahedral complex with magnetic moment 4.9 4.9 Bohr magneton diamagnetic number number number electronic configuration plus two state 3d6 configuration configuration configuration normal pairing pairing diamagnetic strong field weak field diamagnetic diamagnetic number unpaired electron magnetic complex diamagnetic paramagnetic even number of electrons even electron even electron strong field ligand complex diamagnetic important odd electron odd electron odd electron always always paramagnetic always paramagnetic diamagnetic oxidation x equal to x x strong field ligand strong field second third fourth fifth sixth diamagnetic VBT VBT number complex diamagnetic strong strong field ligand neutral ligand neutral ligand orbital coordination number dsp3 dz dz trigonal bipyramidal diamagnetic donor ligand donor strong field electron d6 d6 diamagnetic diamagnetic maximum correct next next next complex correct answer maximum equal correct correct complex magnetic complex 5.92 5.92 number unpaired probable geometry complex geometry weak field ligand number unpaired question octahedral complex weak field ligand octahedral metal weak field ligand number electron coordination square square complex tetrahedral complex d5 configuration d5 weak field first second third fourth fifth fifth electron sp3 sp3 hybridization possible tetrahedral tetrahedral tetrahedral magnetic number unpaired magnetic 5.92 magnetic number number unpaired trigonal sp3d sp3d possible possible number number perfect number comment comment comment possible possible possible comment comment comment What is electronic arrangement metal metal complex complex with configuration configuration pairing greater pairing less pairing greater pairing complex complex complex strong field ligand strong field complex complex weak field ligand weak field ligand octahedral complex octahedral octahedral pairing pairing pairing pairing pairing second third fourth second third fourth weak field ligand weak field ligand number octahedral complex electron configuration stabilization simple calculation crystal field splitting energy CFSE calculation for octahedral complex number of electron in T2G 0.4 delta O delta O number of electron in easy 0.6 delta O plus X number of pairing energy crystal field splitting diagram that high spin complex DG high spin D6 high spin D6 money first second third fourth fifth sixth low spin D4 low spin D4 money corner first second third and fourth electron low spin D5 low spin D5 first second third and fourth and fifth pairing hello high spin D7 high spin D7 money unpaired electron open the electron faster than 67 not someone that people T2G set rate T2G set rate get get the basic CFSE maximum 80 to my first electron electron by extra CFSE as 80 charge the electron electron respect to CFSE 80 corner the electron respect to CFSE 80 basis calculate maximum CFSE option number B low spin D5 complex low spin D5 option number B second CFSE zero CFSE zero what it would you D5 high spin quota second D10 quota D5 high spin or D10 quota CFSE zero also CFSE zero 80 to my exam CFSE move over next next question the structure let's be related every just the structure of the complex CU(NH3)4 ClO4 2 and CU(NH3)4 ClO4 in solution respectively do the A complex ClO4 operate ClO4 charge that the minus one answer to my complex receive all CU(NH3) whole 4 2 positive complex receive all that 80 complex complex that receive all CU NH3 NH3 whole 4 positive complex as well 80 complex copper 2 plus state receive all 80 or A state copper that come on the plus one state as simple copper plus one money D10 complex D10 coordination number four D10 coordination number four money SP3 hybridization or by the D orbital the D hybrid orbital S to start on the SP3 SP3 money tetrahedral geometry already D9 configuration also SP2D hybridization also square planar complex also square planar that means first a square planar second a tetrahedral first a square planar second a tetrahedral first a square planar then second a tetrahedral option number first first compound that receive all square planar 80 hybridization number SP2D second tetrahedral hybridization SP3 do you want to be option perfect next question that next question most expected to be CPT 2026 energy level diagram for you what are you the order of increase energy of different D orbital for square planar bunch of the D orbital which what is the side of tetrahedral what is the side of octahedral do you want to be tetrahedral find draw the A state T2G state I told you the D the orbital that they say what would you be axial I didn't know an axial D orbital non axial D orbital DXY DYZ DZX I didn't know an axial DX square minus Y square or DZ square 80 tetrahedral octahedral money told you that they will non axial orbital axial DX square Y square or DZ square 80 DXY DYZ and DZX 80 octahedral further splitting further splitting square planar complex as yeah or splitting yeah or splitting cross coordinate or XY energy energy DX square minus Y square that by energy DXY that by energy DZ square that by D DYZ quota DYZ ZDX DYZ or DZX the support to highest energy quota DX square minus Y DX square minus Y square support to highest DX square minus Y square highest 80 that will eliminate all move over the XY XY axis to the orbital energy that high DXY that by DXY that by DZ square that by DXZ and DYZ option number D perfect perfect option number D perfect perfect perfect option number D next question next question consider the following reaction complex ABC simple if you see AG plus first solution comparison for you move over the complex complex by the new iron see the respect to the money AGCL give me AG halide precipitate money suppose what the bromine precipitate money suppose what the chlorine AGCL precipitate money one more AGCL what the what the bromine chlorine one more AGCL one more AGCL one more AG BR precipitate money but A one more theory comparison isomers with you isomers isomers that try to be answer corner comment section get to get try to get answer comment section see what you see COCL2BR 5 minutes complex structure the first compound structure cobalt bunch of the ammonia bunch of the ammonia not the money that you square bracket that the money not the chlorine what the bromine the money that the structure structure one more AGCL one more AG precipitate money that means square bracket what the chlorine what the bromine give me what the chlorine what the bromine what the chlorine first compound structure first compound structure first compound compound what the compound AGBR precipitate AGBR precipitate compound money first compound what the A compound second compound second compound two more AGCL precipitate complex molecular formula same two more AGCL precipitate CL2 CL2 compound formula CO NH3 whole NH3 whole or that bromine or that bromine third compound third compound only one more AGCL precipitate molecular formula changes charge that ammonia charge that ammonia charge that what the AGCL precipitate what the chlorine what the bromine square bracket what the chlorine square bracket 80 80 compound 80 that complex what the correct what the correct someone that the compound A and B ionization isomer A or B compound what the A compound what the B compound 80 that compound molecular formula exactly same molecular formula perfect 80 that CL minus BR minus you only CL minus different ions the perfect ionization isomer perfect option number statements MSQ question MSQ question first the correct second conductivity compound A and compound B are almost same A or B by molecular conductivity how would you depend number of ions depend 80 that you but 80 ions CL minus BR minus only CL minus different ions molecular conductivity different the money perfect same almost ions same but ions CL bromine only chlorine conductivity next compound A B and C do not geometric do not what the compound ABC A geometric isomerism what do you B that what do you do A what do what the B geometric isomerism perfect what do just a second A B A A5 money metal I would you ligand five times I would you ligand I would you money ligand one day 80 that money geometric isomerism 80 that geometric isomerism 80 that geometric isomerism what do you A option incorrect what do you 80 that you compound next order of CFSE delta A delta B greater than delta C support to cobalt nitrogen ligand 80 strong field the first bunch of the bunch of the ammonia second that bunch of the ammonia 80 charge that no doubt A or B or C or that the C minimum perfect C that support to minimum A A and D Both A and D B Next question A square planar complex is formed by hybridization of which Square planar complex S orbital Px orbital Py orbital x squared minus y squared orbital dx squared minus y squared orbital Square planar complex mainly formation Question the correct answer is option number B. Do you want the option number B?

[00:50:57]The ticket on a library present continuously Something catchy Next question Next question going to be the one One mole of the complex compound this gives three moles ions. Simple they have three moles ions.

[00:51:15]Three moles ions Dissolution in water One mole of the same complex react with two moles of AgNO3.

[00:51:23]React with two moles To yield two moles of AgCl Keep two moles Two moles of AgCl Two moles of AgCl The ionization Ionization Chloride Repeat Complex The complex Two moles Chlorine The chlorine Chlorine Chlorine Chlorine Chlorine Second Three ion gives three Moles of ions Three moles ion Square bracket over Two positive Two chlorine negative Three moles ions Option number C and option number D the same DDC C and D C and D C and D Just a second Co(NH3)5Cl3 Co(NH3)5Cl3 Just a second Co(NH3)5Cl3 NH3 whole five NH3 whole five NH3 whole five Chlorine Chlorine Chlorine Chlorine Molecular formula Co(NH3)5 Option number Option number Option number Chlorine Co(NH3)5Cl Chlorine Next question Next question Identify the correct statement For the behavior of ethane 1,2-diamine Question Ethane 1,2-diamine Ethylenediamine Ethane 1,2-diamine Nitrogen Nitrogen Donor site Donor site Donor site The density get the so The density The density Two Bidentate Kitchen Charge and neutral Bidentate Perfect It is a chelating ligand Chelating ligand Chelating ligand Metal Metal Nitrogen Carbon Carbon Nitrogen With a five membered ring money ball With a five membered Chelating ligand Unidentate Ligand Unidentate Bidentate One, two, three Perfect Do you want the option A Perfect Do you want the option A Perfect I think it's almost Ethane 1,2-diamine Correct statement Next question Simple question What kind of isomerism What kind of isomerism are exhibited by octahedral The octahedral Complex The type of Isomerism Compound Co(NH3)4 Br2 I mean the good complex Complex draw octahedral Give me a good complex draw Co(NH3) Whole four Chlorine Chlorine Bromine Complex I mean MA4 B2 MA4 BC A type of Complex Geometrical isomerism This is trans iso Second molecular Ions Chloride Bromide Molecular formula Ionization Ionization Geometrical Geometrical and ionization Option number A Option number A If the molecular formula Different ions Ionization Molecular Four BC MA4 B2 Geometrical Geometrical Option number A I think Some of the Next question Next question Short information Weather Good weather Just be in case Class End of the session In case The session The session Question Question Question the correct answer Which is in an octahedral structure The pair of D orbitals Involved in d2sp3 hybridization d2sp3 Orbital involved dx squared minus y squared And a dz squared D orbital Axial Orbital The question Option number D dx squared minus y squared and dz squared dz squared Next question Next question Again Question Which of the following Ions which has The highest paramagnetism Highest paramagnetism Highest paramagnetism Number of unpaired electrons More the number Electron The magnetic Moment more Paramagnetism The simple Chromium Neutral ligand Chromium three positive Chromium Number 24 24 4s1 3d5 4s1 3d5 s1 d5 Electron Complex d3 Complex Complex with three Unpaired electrons Next to the copper Two positive Copper Two positive d9 Complex d9 Unpaired Electron Question fast Next Fe2+ Weak field ligand Fe2+ Fe2+ d6 Complex d6 Complex Unpaired electron Three unpaired Electron Complex Three unpaired Eight cases Zinc Two plus Zinc two d10 Configuration Three unpaired Electron Second option The second option Perfect Option number B Perfect Option number B Perfect The next Again good Simple question Out of the following the hexadentate ligand Hexadentate The density The density The density Ethylenediamine tetraacetic acid You know EDTA Ligand Four negative The density actually The density The density Important Charge EDTA Three negative The density The EDTA Two negative EDTA Two negative The density The EDTA Negative EDTA Negative The density The EDTA Neutral EDTA The density The density I mean the ligand The density Change Those are known Flexidentate ligand The money ball Flexidentate Ligand The money ball Option number B Ethylenediamine tetraacetic acid Perfect perfect The money ball Charge EDTA Three negative EDTA Two negative The density The density The money ball Next question Next question Next question What is the coordination number Good simple question Directly The money ball Ethylenediamine Bidentate Ligand Two into two plus The chlorine Monodentate ligand Two into one Coordination Number Two into two Four plus two six Coordination Number Six Coordination Number Six Option number C Perfect The next Next question Next question Next question The formula For Sodium nitroprusside Already Discuss The question Already Discuss The question already Exam Directly Sodium nitro Formula sodium nitroprusside sodium nitroprusside complex nitrate nitrate oxidation oxidation process iron neutral positively s04 overall equal x charge iron option option maximum maximum option complex sodium nitroprusside sodium nitroprusside brown brown Prussian Prussian Prussian complex compound question question according postulates Werner's theory coordination coordination primary secondary secondary secondary primary secondary non ionizable and only primary valence is question a question primary ionizable secondary non ionizable first primary primary ionizable maximum primary ionizable secondary non ionizable try maximum effective atomic number effective atomic number nickel simple effective atomic number plus x minus plus x minus plus atomic atomic plus oxidation number y number electron plus plus if it's simple oxidation oxidation negative number number electron donated donated by all simple oxidation oxidation positive oxidation 2 cobalt minus negative oxidation minus minus a subtract oxidation positive minus oxidation negative oxidation nickel number nickel number plus oxidation each carbon electron 28 plus 36 effective atomic number rule stable stable stable complex second important atomic number complex effective atomic number noble atomic number effective atomic number number example example suppose whole four simple it is iron oxidation plus iron number plus plus plus the 26 minus 24 plus effective atomic number as well complex minus v minus carbon neutral negative scandium vanadium atomic number minus plus one plus carbon 6 2 a basis 24 plus 12 36 effective atomic number that is a point e a n e a n a point effective atomic number effective atomic number >> [snorts] >> move next question next question IUPAC of this compound simple some of the first oxidation number minus one minus one zero minus one minus cobalt plus three cobalt cobalt cobalt last chloride chloride chloride a compound chloro nitro ethylene but important important some of same but chloro chloro nitro important ethylene ethane one but important 2 start >> [clears throat] >> start alphabetically yeah cool alpha consider consider the support first then the nitro chloro then nitro chloro nitro not bis ethylene nitro cobalt three chloride option number question option number question because number bis alphabetically consider next question compound are example a man type of isomers isomers difference difference a video a minute do that ambidextrous a minute ambidextrous a minute donor a o donor data different nitrogen donor side oxygen donor a minute a different ambidextrous a minute isomers isomers isomers a minute isomers question number number isomers isomers question next question coordination number four question question most four four four two four a complex most important a trick classes class long long long long chlorine carbon chlorine tetrahedral carbon tetrahedral a o a minute square planar square planar and I tetrahedral first option first option correct exam time a tutor a point a tutor a minute square a minute a minute square planar and chlorine a carbon tetrahedral number correct question correct option number lucky field chlorine field a minute strong field carbon strong field next question hybridization a fee k four a basic compound a fee whole four negative four negative iron plus two state plus two state plus two state complex d six strong field pairing pairing electron first fourth data orbital coordination number d two hybridization a o octahedral orbital a o orbital orbital a o low spin complex low spin complex a o pairing low spin complex a o number electron magnetic moment zero a complex magnetic configuration t two e g zero c f c calculate c f c calculate value minus zero point four the six minus zero point four minus two point four delta plus pairing energy d six d six normal first fourth already extra pairing extra plus two pairing energy variable coordination number oxidation number hybridization geometry inner orbital orbital low spin number of unpaired electron magnetic moment paramagnetic magnetic electron CFT through the configuration of CPC each and every coordination compound move next question next question the magnetic moment of cl4 2 cl4 2 negative tetrahedral complex the if you do the complex oxidation number nickel plus two possible D8 complex D8 complex only not tetrahedral complex tetrahedral total e plus T2 everything will be the approach fill up first second third fourth 6 7 and 8 because the data unpaired electron data unpaired electron 2.82 board magnet also data unpaired electron also value 2.82 board magnet also I suppose point that clearly will be live representation move next question next question what would you for for a D4 metal ion in an octahedral field the correct electronic configuration simple D4 either Delta or greater than zero to go Delta or less than zero to go Delta or greater than zero pairing up or down if you do pairing first second third fourth second T2 first second third and fourth electron will go if you do Delta or less than pairing energy less than Delta or less than pairing energy pairing energy less than pairing energy that will be not pairing up or down first second third and fourth a type of complex also only to go if you do the configuration T2G4 easy zero if you do T2G3 easy one data Delta or greater than pairing energy Delta or less than pairing energy if you do Delta or less than pairing energy T2G4 easy zero eliminate column T2G3 easy one Delta or less than pairing energy perfect to achieve next T2G3 easy one Delta or greater than pairing energy to achieve e unsymmetrically filled as you want unsymmetrically filled as you want option number C you want to go so only perfect answer you want to go option number C you want to go so only perfect answer you want to go perfect answer correct answer option number C you want to go next question to next question what is the correct electronic configuration of the central atom electronic configuration central atom to go crystal field theory basis again same complex Fe2 plus oxidation number it will be D6 complex if you do cyanide like it strong feeling strong feeling pairing strong feeling money always Delta or greater than pairing energy Delta or greater than pairing energy octahedral complex crystal field splitting diagram only T2G plus easy total electron total electron so first second third pairing fourth fifth sixth money T2G6 configuration easy zero T2G6 easy zero T2G6 easy zero money option number B perfect you want to go option number B you want to go concept that clearly T2G6 easy CFT money money if you do CFT calculation money minus 2.4 Delta plus two pairing energy also money money pairing energy value given Delta value given CFT get if you do put CFT calculation money money I suppose money money clearly money money next question to next question what kind of isomerism represented by data who type of isomerism they do again molecular formula same so money so money try to >> [clears throat] >> MFA B type of complex optical isomerism given linkage ambidextrous ligand again ambidextrous ligand present coordination isomerism if you do the coordination complex or you have to go with interchange interchange that will be coordination isomerism if you do eliminate if you do the calculation sulfate with the data bromine with the data bromine with the data sulfate money molecular formula same but different ions different if you do ionization isomerism money if you do ionization isomerism I suppose point that clearly option number C question the correct answer you want to go next next question the complex that can show facial and meridional face and more isomer they do it simple if you do exam question geometrical MFA4 B2 data who type of isomerism coordination number six cis trans isomerism you have to go if you do MFA3 B3 type complex a type of complex who type of isomerism facial and meridional facial meridional so money check MFA3 B3 molecular formula MFA3 B3 molecular formula 22 achieve nine if you do 42 achieve it will be nine if you do 33 equal option number C facial meridional they do important if you do geometrical isomerism they do it equally geometrical isomerism if you do cis platin trans platin if you do DSP2 hybridization that will be the square planar complex square planar complex if you do MA2B2 MA2B2 formula square planar complex that will be cis trans isomerism they do if you do cis trans isomerism they do it if you do geometrical isomerism they do cis trans isomerism MFA4B2 formula they do if you do symmetrical bidentate ligand MAA whole two or B2 if you do geometrical isomerism if you do cis trans cis trans also if you do cis optically active D option cis optically active I suppose point that option number C question the correct answer you want to go next question ticket speed maximum question try cover up around 40 to 50 question money you want to go money so that you want to go coordination compound full up clearly you have to go money so money ready to go organometallic compound bioinorganic chemistry next session discuss organometallic compound bioinorganic chemistry so money try to go money comment section so money try to go they do a type data who type of isomerism they do if you do chlorine three total water chlorine with the data water with the data money data molecular formula same but water exchange coordination sphere coordination sphere if you do water exchange water shifting who do transfer coordination sphere coordination sphere you have to solvate hydrated isomerism you have to go option number C solvate hydrated money water sphere with the data you have to money test money concentrated reaction money money who type isomerism solvate hydrated isomerism you want to next question next question so money again try question correct answer comment section you have to IUPAC full compound first time oxidation number charge they do zero you have to go two into minus one NO3 you have to go minus one equal you want to go zero to X plus minus two minus one X to charge they do plus three oxidation number plus three oxidation number plus three plus three two you have to eliminate oxidation number last nitrate equal perfect if you do money I will go amine if you do then chloro tetra or di alphabetically check they do to I will go amine that will be chloro di chloro chromium chromium complex option number B question correct answer option number B question correct answer you want to go question approach you want to go direct question solve I will go cation money followed by name equal oxidation number chromium check that will be alphabetically money amine if you do di chlorido chloro to amine I will go then chloro option number B question correct answer option number B question correct answer I will go last almost 40 question you want to discuss I will go so money so money question discuss so money clearly you want to go live present you want to comment section you want to comment so money you want to live present you want to comment section comment so that you want to go so money you have to go help you want to preparation class starting you want you want to you want to money you want