The clever use of auxiliary lines elegantly reduces a complex problem to basic geometric properties, showcasing the power of visual intuition. It is a concise and sophisticated demonstration of how classical construction can simplify mathematical reasoning.
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Super amazing trick to find the length XAdded:
Can you find the length X?
In triangle ACP It is A C P This angle is 30° This angle is 45° That means This angle It will be 45° - 30° That will be 15° This angle is 15° And Now From point P If we make PQ Such that This angle is 30° Angle PQC is equal to Angle PCQ That is 30° It is our construction Then Angle PCQ is equal to Angle PQC So PC It will be equal to PQ And PC is five So PQ It will be also five And In triangle APQ It is A P Q This angle is 15° This angle is 30° So this angle It will be 30° - 15° That will be 15° And These two angles are equal That means AQ and PQ They will be also equal And PQ is five So AQ It will be also five AQ is five And this angle is 15° And Now If we join BQ Then In triangle BPQ It is B P Q BP is equal to PQ That is five That means These two angles They will be equal And this angle is 45 + 15 That is 60° So these two angles They will be also 60° This angle is 60° And this angle is 60° And BQ It will be equal to BP That is equal to PQ So BQ It will be also five And now At point Q This angle is 60° This angle is 30° So this angle It will be 180° - 60° - 30° That will be 90° So this angle is 90° And Now In triangle ABQ AB is squared It will be AQ is squared + BQ is squared And AB is X is squared AQ is five is squared + BQ is five is squared So X is squared is five is squared times two So X It will be root under five is squared times two So X will be five times root two X is five root two >> [music]
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