When a point D on the base BC of triangle ABC satisfies BD = DC = AD, the triangle ABC is a right triangle with the right angle at A, and its area can be calculated as half the product of the two legs (AB × AC / 2).
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What's the Area of This Triangle? Most Get It WrongAdded:
Hello everyone.
In this video, I am going to solve an interesting geometric problem.
We have a triangle.
Consider this triangle is A B C The side length of AB is 12 unit and the length of AC is equal to 18 unit.
And there is a point to this base. Consider this point is D such that BD is equal to DC is equal to AD.
We have to find the area of this triangle ABC.
As BD is equal to DC is equal to DA, so we can draw a circle through point B A and C whose center will lies on point D.
Consider this circle is In this circle it passes through point B A and C and the center of this circle is D.
Because this BD indicate the radius of this circle, this DC is also radius and DA, this is also the radius of this circle.
So, BC is the diameter of this circle.
So BAC, this angle lies on semicircle, so this angle is a right angle.
That means this angle is 90°.
So, this ABC is a right angle triangle.
So, the area of triangle ABC is equal to half times base of this triangle. Consider this AB as base.
So, AB times height of this triangle is AC.
So, this is the area of triangle ABC.
Now, substitute the value of AB and AC, we'll get half times AB.
This is 12 unit, so 12 times AC. This is 18 unit.
is equal to this two and this 18 divided by two is nine.
And nine times 12 is 100 and eight.
And this is the area of this triangle ABC.
And this is the solution of our given problem.
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Thanks for watching.
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